Dear All,
I have a bunch of data points as follows:
x 100
y 200
z 300
...
where 100, 200, 300 are the values. I would like to know the distribution of my
data? how can I fit my data into a distribution?
Thanks a lot,
Andra
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That MASS::fitdistr is used for the case when I have some sense about the
distribution of my data. When I do not know anything about my data, is there
any function that can I use to tell what distribution of my data is?
Thanks a lot,
Andra
From: R. Michael
Hi All,
I am plotting different lines in my graph and the problem I have is that if the
first plot has smaller y value than the second plot, I will not be able to see
the the top part of the graph. I do the following:plot(p1, avg=vertical,
lwd=3, col=red, main =all graphs)plot(p2,
Hi All,
After fitting a model with glm function, I would like to do the model selection
and select some of the features and I am using the step function as follows:
glm.fit - glm (Y ~ . , data = dat, family = binomial(link=logit)) AIC_fitted
= step(glm.fit, direction = both)
I was wondering is
Hello All,
I have used logistic regression glm in R and I am evaluating two models both
learned with glm but with different predictors. model1 - glm (Y ~ x4+ x5+ x6+
x7, data = dat, family = binomial(link=logit))model2 - glm (Y~ x1 + x2 +x3 ,
data = dat, family = binomial(link=logit))
and I
Hi All,
In order to compare two different logistic regressions, I think I need to
compare them based on their BIC values, but I am not sure if the smaller BIC
would mean a better model or the reverse is true?
Thanks a lot,Andra
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Hello All,
I have a data frame called train.data which has 100 columns. I am using an
statistical package to learn a model and the format of using that package is as
follows:
ex5 - stepFlexmix(cbind(y,1-y)~x|id2, data=NPreg, k=2,
model=FLXMRglm(family=binomial), nrep=5)
the
Hello All,
I have a data frame consisting of 4 columns (id1, id2, y, pred)
where pred is the predicted value based on the glm function and my data frame
is called all. data is another data frame that has all data but I want to
put together some important columns from my original data frame
Dear All,
I have two hidden classes for my data set that I would like to learn them based
on the Mixture of Binomial regression model. I was wondering if there is any
package that I can use for that purpose. Has any one tried any package for the
Mixture models?
Thanks a lot,
Andra
Hi All,
I have a data frame as follow:
user_id time age location gender
.
and I learn a logistic regression to learn the weights (glm with family= (link
= logit))), my response value is either zero or one. I would like to group the
users based on user_id and time and see the y values
Hello All,
I am trying to use FlexMix package for my two linear regression models:
http://finzi.psych.upenn.edu/R/library/flexmix/doc/regression-examples.pdf
y1 = w1 * x1 + w2 *x2 + w3 * x3 +beta1
y2 = w4 * x4 + w4 *x4 + w4 * x4 +beta2
and I would like to combine these two regression models
Hi All,
When modeling with glm and family = binomial (link = logit) and response values
of 0 and 1, I get the predicted probabilities of assigning to my class one,
then I would like to compare it with my vector y which does have the original
labels. How should I change the probabilities into
Hi All,
I have a fitted model called glm.fit which I used glm and data dat is my data
frame
pred= predict(glm.fit, data = dat, type=response)
to predict how it predicts on my whole data but obviously I have to do
cross-validation to train the model on one part of my data and predict on the
validation with glm?
To: Andra Isan andra_i...@yahoo.com
Cc: r-help@r-project.org
Date: Wednesday, August 24, 2011, 10:11 AM
What you describe is not
cross-validation, so I am afraid we do not know what you
mean. And cv.glm does 'prediction for the hold-out
data' for you: you can read
Hi All,
I have a set of features of size p and I would like to separate my feature
space into two sets so that p = p1 + p2, p1 is a set of features and p2 is
another set of features and I want to fit a glm model for each sets of features
separately. Then I want to combine the results of two
question
To: Andra Isan andra_i...@yahoo.com
Cc: r-help@r-project.org
Date: Monday, August 22, 2011, 9:54 PM
Hi Andra,
There are several problems with what you are doing (by the
way, I
point them out so you can learn and improve, not to be
harsh or rude).
The good news is there is a solution
Hi All,
I am trying to fit my data with glm model, my data is a matrix of size n*100.
So, I have n rows and 100 columns and my vector y is of size n which contains
the labels (0 or 1)
My question is:
instead of manually typing the model as
glm.fit = glm(y~ x[,1]+x[,2]+...+x[,100],
Hello All,
I have a question about glm in R. I would like to fit a model with glm
function, I have a vector y (size n) which is my response variable and I have
matrix X which is by size (n*f) where f is the number of features or columns. I
have about 80 features, and when I fit a model using
Hi All,
I am trying to run cv.glmnet(x,y,family=multinomial, nfolds =4) and I only
have 8 observations and the number of features I have is 1000, so my x matrix
is 8 by 1000 and when I run the following, I get this error, I am not sure what
is causing this problem.
Error in predmat[which, ,
Hi All,
I would like to create a matrix in R but I dont know the size of my matrix. I
only know the size of the columns but not the size of the rows. So, is there
any way to create a dynamic matrix of size NULL by n_cols? and then add to that
matrix?
I know for a vector, I can do this: x= NULL
Hi All,
I have been trying to use glmnet package to do LASSO linear regression. my x
data is a matrix n_row by n_col and y is a vector of size n_row corresponding
to the vector data. The number of n_col is much more larger than the number of
n_row. I do the following:
fits = glmnet(x, y,
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