Hello,
Using the rgl package, I can set the device window to any dimension (that I
have tested):
par3d(windowRect=c(1,1,700,700))
With windows I can't get the window to span from the top to the bottom of
the monitor. In the following, no matter how large the ypinch value gets it
stops, leaving
Hello,
I'm looking for help putting an interactive rgl package 3d device on the web
so that it maintains full functionality. Where should I start? Is it
possible? Is there an example I can see? (Note: I'm also looking at putting
other normal plots on the web.) I'd like to stay within R as much as
Thanks Duncan! I wish I had the time to work on something like that, but I
have to stay focused on research.
Thanks again for your extensive help! Have a good weekend everyone!
Ben
On Fri, Oct 21, 2011 at 4:24 PM, Duncan Murdoch murdoch.dun...@gmail.comwrote:
On 11-10-21 3:38 PM, Ben qant
z y x v z w w z y
[3,] e d e a c c e a b b
enjoy
ben
On Wed, Oct 12, 2011 at 11:47 AM, Ben qant ccqu...@gmail.com wrote:
Hello,
This is my solution. This is pretty fast (tested with a larger data set)!
If you have a more elegant way to do it (of similar speed), please reply
, 2011, at 10:42 AM, Ben qant wrote:
Here is a more R'sh solution (speed unknown).
Really? The intermediate, potentially large, objects seem to be
proliferating.
Courtesy of Mark Leeds (I
modified it a bit to generalize it for a cnt input and get min and max).
Again, getting cnt highest
inmediate how to get the same for the smallest and build a function
to
calculate everything and return a list.
Regards,
Carlos Ortega
www.qualityexcellence.es
2011/10/11 Ben qant ccqu...@gmail.com
Hello,
I'm looking to get the values, row names and column names
Hello,
Does anyone know how to change the Tinn-R editor background color? White is
rough on the eyes...
Thanks,
Ben
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
Never mind: option color preference
Sorry...overlooked that 10 times I guess.
regards
On Wed, Oct 12, 2011 at 12:54 PM, Ben qant ccqu...@gmail.com wrote:
Hello,
Does anyone know how to change the Tinn-R editor background color? White is
rough on the eyes...
Thanks,
Ben
Hello,
There has to be a more R'ish way to do this. I have two matrices, one has
the values I want, but I want to NA some of them. The other matrix has
binary values that tell me if I want to NA the values in the other matrix. I
produce a third matrix based on this. I've also tried apply()
Hello,
I'm looking to get the values, row names and column names of the largest and
smallest values in a matrix.
Example (except is does not include the names):
x - swiss$Education[1:25]
dat = matrix(x,5,5)
colnames(dat) = c('a','b','c','d','c')
rownames(dat) = c('z','y','x','w','v')
dat
Excellent! Thank you!
Ben
On Sat, Oct 8, 2011 at 3:36 PM, Duncan Murdoch murdoch.dun...@gmail.comwrote:
On 11-10-08 11:04 AM, Ben qant wrote:
Thank you!
Sorry, I have a couple more questions:
1) How to I turn off the box shading completely? I figured out how to
lighten it up to a grey
,
col=c(white,black))
Thank you for your help!
Ben
On Sat, Oct 8, 2011 at 5:09 AM, Duncan Murdoch murdoch.dun...@gmail.comwrote:
On 11-10-07 2:32 PM, Ben qant wrote:
Hello,
I'm using the rgl package and plotting a plot with it. I'd like to have
all
the axes values auto-hide, but I want
Hello,
I'm using the rgl package and plotting a plot with it. I'd like to have all
the axes values auto-hide, but I want to plot a series of characters instead
of the values of the measurement for 2 of the axes. So in the end I will
have one axis (z actually) behave per normal (auto-hide) and I'd
,
Dennis
On Wed, Oct 5, 2011 at 8:11 PM, Ben qant ccqu...@gmail.com wrote:
Hello,
I'm trying to get the count of values in each row that are above and
below
quantile thresholds. Thanks!
Example:
x = matrix(1:30,5,6)
x
[,1] [,2] [,3] [,4] [,5] [,6]
[1,]16 11 16
Hello,
I'm trying to get the count of values in each row that are above and below
quantile thresholds. Thanks!
Example:
x = matrix(1:30,5,6)
x
[,1] [,2] [,3] [,4] [,5] [,6]
[1,]16 11 16 21 26
[2,]27 12 17 22 27
[3,]38 13 18 23 28
[4,]4
Hello,
Why does rm.outlier produce a list for me? I know its something about my
data because I can't make a mock up that reproduces the issue.
Any ideas? My data goes in as a matrix and comes out as a list:
class(dat)
[1] matrix
dat = rm.outlier(dat)
class(dat)
[1] list
Thanks,
Ben
Hello,
I'm seeking ideas on how to remove outliers from a non-normal distribution
predictor variable. We wish to reset points deemed outliers to a truncated
value that is less extreme. (I've seen many posts requesting outlier removal
systems. It seems like most of the replies center around why do
Hello,
What is the best way to turn a matrix into a list removing NaN's? I'm new to
R...
Start:
mt = matrix(c(1,4,NaN,5,3,6),2,3)
mt
[,1] [,2] [,3]
[1,]1 NaN3
[2,]456
Desired result:
lst
[[1]]
[1] 1 3
[[2]]
[1] 4 5 6
Thanks!
Ben
[[alternative HTML
:
Try this:
alply(mt, 1, function(x) as.numeric(na.omit(x)))
The as.numeric() addition may be necessary to strip the extra attributes
na.omit() wants to add.
Michael
On Tue, Sep 27, 2011 at 4:02 PM, Ben qant ccqu...@gmail.com wrote:
Hello,
What is the best way to turn a matrix
Hello,
I'd like to 'do work' on data members upon construction (i.e. without
implementing it in a get method). Is this the best way to create data member
'z' upon construction? I'm thinking if .z=paste(x,y) below gets more complex
I'll run into issues.
setConstructorS3(MyClass,
is changed.
/Henrik
On Thu, Sep 22, 2011 at 10:18 AM, Henrik Bengtsson h...@biostat.ucsf.eduwrote:
On Thu, Sep 22, 2011 at 9:06 AM, Ben qant ccqu...@gmail.com wrote:
Hello,
I'd like to 'do work' on data members upon construction (i.e. without
implementing it in a get method). Is this the best
Hello,
I've posted something similar under a different subject and never received a
solution. Trying again with (hopefully) a better description.
Objective: Send a matrix of string data in an email message. The message
must have authentication and be sent via an R script.
I'm almost there!
That fixed it!! Thank you very much! I should have thought of that.
Thanks again,
Ben
On Wed, Sep 14, 2011 at 9:57 AM, Steve Lianoglou
mailinglist.honey...@gmail.com wrote:
Hi,
On Wed, Sep 14, 2011 at 11:44 AM, Ben qant ccqu...@gmail.com wrote:
Hello,
I've posted something similar
This fixed it: paste(errs, collapse=\\n)
Since that fixed it, I did not try anything else.
Thanks again,
Ben
On Wed, Sep 14, 2011 at 10:04 AM, Steve Lianoglou
mailinglist.honey...@gmail.com wrote:
Hi,
On Wed, Sep 14, 2011 at 12:01 PM, Ben qant ccqu...@gmail.com wrote:
That fixed
Hello,
I have a bunch of data files all with dbs file extensions. They are
generated via a SQL query from another program and source. Does anyone know
(or have ideas) how to get the data from a dbs file type into R (or into
some other format that can imported to R)? I've searched online for 4
with dbs files, but the foreign package might be able to help
you out.
Michael
On Sat, Sep 10, 2011 at 2:44 PM, Ben qant ccqu...@gmail.com wrote:
Hello,
I have a bunch of data files all with dbs file extensions. They are
generated via a SQL query from another program and source. Does anyone
definitely help in reverse-engineering the format or finding a way
to convert it.
In your example, are you really getting XX for all entries, or are you
obfuscating the data?
Sarah
On Sat, Sep 10, 2011 at 7:54 PM, Ben qant ccqu...@gmail.com wrote:
Recap: trying to get a 'dbs' extension file
Hello,
I'm attempting to return the date (in form '%Y-%m-%d') of the Monday
previous to the current date. For example: since it is 2011-09-02 today, I
would expect 2011-08-29 to be the return value.
I found the following in:
http://www.mail-archive.com/r-help@r-project.org/msg144184.html
Start
I didn't sort out the issue in my email below but here is a (not very
R'ish) solution:
pm = function(x) {
+ for(i in 1:7){
+ if(format(as.Date(Sys.Date()-i),'%w') == 1){
+ d = Sys.Date() - i;
+ }
+ }
+ d
+ }
pm(Sys.Date())
[1] 2011-08-29
On Fri, Sep 2, 2011 at 9:35 AM, Ben
+ }
pm(Sys.Date())
[1] 2011-08-29
On Fri, Sep 2, 2011 at 9:59 AM, Marc Schwartz marc_schwa...@me.com wrote:
On Sep 2, 2011, at 10:35 AM, Ben qant wrote:
Hello,
I'm attempting to return the date (in form '%Y-%m-%d') of the Monday
previous to the current date. For example: since
[4],''),sep=\n))
y
cat(y,\n)
-- Bert
On Mon, Aug 29, 2011 at 6:59 PM, Ben qant ccqu...@gmail.com wrote:
Unfortunately that didn't work. I just says the text is an invalid
argument.
I also tried saving it in a variable name and passed that in, but that
didn't work. I get:
Error
with 'a test' as the msg body.
Any ideas?
PS - I received lots of suggestions. Thank you very much for your
effort/input.
Ben
On Mon, Aug 29, 2011 at 6:01 PM, Henrique Dallazuanna www...@gmail.comwrote:
Try:
paste(c(a, b, c), collapse = \n)
On Mon, Aug 29, 2011 at 8:56 PM, Ben qant ccqu
!
Ben
On Tue, Aug 30, 2011 at 11:24 AM, David Winsemius dwinsem...@comcast.netwrote:
On Aug 30, 2011, at 1:09 PM, Ben qant wrote:
Hello,
(Sorry if this is a dup post...)
I need to clarify, Henrique's suggestion worked great for getting the text
that I needed via cat(), but I haven't
Henrik,
Your last suggestion did not work for me. It seems like it does not allow me
to create a ClassB object with 3 arguments:
setConstructorS3(ClassA, function(A=15, x=NA) {
+ extend(Object(), ClassA,
+.size = A,
+.x=x
+ )
+ })
setConstructorS3(ClassB, function(..., bData=NA) {
+
Correction. My solution didn't work either Didn't return the correct
values. Can you post an example that takes three arguments? I'm working on
how to do this now.
thanks...sorry. Im new to R and R.oo.
Ben
On Mon, Aug 29, 2011 at 8:35 AM, Ben qant ccqu...@gmail.com wrote:
Henrik,
Your
Hello,
Does anyone know how to convert this:
msg
[1] a
[2] b
[3] c
To:
msg
a
b
c
In other words, I need to convert a character vector to a single string with
carriage returns for each row.
Functionally, I'm attempting to send an email of a character vector in a way
that is readable in
?
Thanks,
Ben
On Mon, Aug 29, 2011 at 6:01 PM, Henrique Dallazuanna www...@gmail.comwrote:
Try:
paste(c(a, b, c), collapse = \n)
On Mon, Aug 29, 2011 at 8:56 PM, Ben qant ccqu...@gmail.com wrote:
Hello,
Does anyone know how to convert this:
msg
[1] a
[2] b
[3] c
To:
msg
If someone is able, can you tell me if there is a better way to do this?
More specifically, do I have to rewrite all of the data members stuff and
extend stuff of parent class in the child class? See below. Thanks in
advance!
Example 1:
setConstructorS3(ClassA, function(A,x) {
I thought I would post an example of using R.oo with inheritance and pass by
reference for future searches. With PerMore I am inheriting Person. Then I
am changing an object data memeber of an object of PerMore class using pass
by reference ('mimiced' by R.oo) in an object of AgeMultiplier. I
AM, Ben qant ccqu...@gmail.com wrote:
Can someone show me how to modify one (R.oo) class's object inside another
(R.oo) class's method? Is that possible with the R.oo package? A quick
example or reference to an example would be outstanding...
Thanks,
Ben
[[alternative HTML version
Can someone show me how to modify one (R.oo) class's object inside another
(R.oo) class's method? Is that possible with the R.oo package? A quick
example or reference to an example would be outstanding...
Thanks,
Ben
[[alternative HTML version deleted]]
Hello,
I'd like to send an email from R using Windows Outlook.
The sendmailR package doesn't allow for authentication (usernames and
passwords).
Is there any other way to do this? From the Windows command line?
Right now I am using a .bat file to send an email via a program called Blat.
I'd
Hello,
I have two data frames. One is my dependent variable and the other is my
independent variable. For each row I'd like to split the independent
variable into fractiles (25 or more) and calculate the average value of the
dependent variable. Then I would like to plot the average of the
Hello,
I'm pretty new to R. Basically, how do I speed up the for loop below. Or
better yet, get rid of the for loop all together.
objective: plot two data sets column against column by index. These data
sets have alot NA's. Some columns are all NA's. I need the plots to overlay.
I don't like the
Hello,
Using the R.oo package, how do I throw an error if a field is not present
when the user of the class creates the object?
Using the example in the R.oo package:
setConstructorS3(Person, function(name, age) {
if (missing(name)) name - NA;
if (missing(age)) age - NA;
=name,
.age=age
)
})
/Henrik
On Tue, Aug 9, 2011 at 12:21 AM, Ben qant ccqu...@gmail.com wrote:
Hello,
Using the R.oo package, how do I throw an error if a field is not present
when the user of the class creates the object?
Using the example in the R.oo package
Hello,
First time posting to this mail list.
I'd like to use R in the most efficient way. I'm accomplishing what I want,
but feel there is a more R'ish way to do it. Just learning R.
*My goal: get ranks of value across rows with row names and column names
intact.*
I'm guessing one of the
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