I am possibly in the market for a new laptop. Predominantly a Windows
user, I owned a macbook pro 10 years ago and am considering going that
route again. Does the standard advice still hold: Get the most
powerful processor (i7), most ram (16GB), and largest internal storage
(512GB), if affordable?
:50 PM, Dan Murphy chiefmur...@gmail.com wrote:
I am possibly in the market for a new laptop. Predominantly a Windows
user, I owned a macbook pro 10 years ago and am considering going that
route again. Does the standard advice still hold: Get the most
powerful processor (i7), most ram (16GB
, but I haven't discovered it yet. :(
Again, thanks for your help.
-Dan
On Mon, Oct 20, 2014 at 3:39 PM, David Winsemius dwinsem...@comcast.net wrote:
On Oct 20, 2014, at 2:34 PM, Dan Murphy wrote:
Good ideas, David.
1) By confirm that MS Excel honors that OutDec I mean that, in a
location
To Users of Excel:
Following advice from Brian and Markus, I created an RMarkdown vignette
that shows an example of how the pasteFromExcel function in the excelRio
package on github could be used by an actuary to transfer a triangle from
Excel to R. See today's post at
Winsemius
dwinsem...@comcast.net wrote:
On Oct 19, 2014, at 11:18 PM, Dan Murphy wrote:
To Users of Excel:
Following advice from Brian and Markus, I created an RMarkdown vignette
that shows an example of how the pasteFromExcel function in the excelRio
package on github could be used
20, 2014 at 10:56 AM, David Winsemius
dwinsem...@comcast.net wrote:
On Oct 20, 2014, at 10:29 AM, Dan Murphy wrote:
Nice.
So if someone were to offer a currency regular expression that works
in their locale, I should also ask them to give me the results of
Sys.getlocale(LC_MONETARY
for arithmetic on
user defined classes? Maybe the answer has to do with the error
message I did not understand.
Thanks,
Dan Murphy
sessionInfo()
R version 3.1.0 (2014-04-10)
Platform: x86_64-w64-mingw32/x64 (64-bit)
locale:
[1] LC_COLLATE=English_United States.1252 LC_CTYPE=English_United
States.1252
to capture the names of new objects created within?
On Fri, Apr 4, 2014 at 10:55 AM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
On 04/04/2014 1:32 PM, Dan Murphy wrote:
I just noticed this annoyance, but I'm not the first one, apparently
-- see
http://lists.r-forge.r-project.org/pipermail
I just noticed this annoyance, but I'm not the first one, apparently
-- see
http://lists.r-forge.r-project.org/pipermail/datatable-help/2012-May/001176.html
The thread never answered the OP's question Is this a bug? so I
assume the answer, unfortunately, is No.
If not a bug, do users of within
smartpink...@yahoo.com wrote:
Hi,
Try ?which.max() # unique values for the combination.
ddply(data,.(state),summarize,max_date=value[which.max(date)])[,2]
#or
ddply(data,.(state),summarize,max_date=value[date == max(date)])[,2]
A.K.
On Thursday, February 13, 2014 11:15 AM, Dan Murphy
I can do this in multiple steps with summarise, joins, etc., but can't
help thinking it can be accomplished in one plyr call.
Here's a small example:
require(plyr)
require(lubridate)
data - data.frame(
+ date = rep(as.Date(ymd(20140101 + (0:3) * 100)), 2),
+ state = rep(c(A, B), each =
In the lubridate vignette
(http://cran.r-project.org/web/packages/lubridate/vignettes/lubridate.html)
setdiff(auckland, jsm)
results in
## [1] 2011-06-04 12:00:00 NZST--2011-07-20 NZST
But if Hadley's mentor had been called away earlier, say, July 31st,
wouldn't the set difference have
Is there a way to determine which, if any, CRAN packages depend on my CRAN
package, mondate?
Thanks,
Dan Murphy
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
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PLEASE do
I have a vector of strings that contain mathematical expressions. E.g.,
x - c(5 = 7, z = 1+2)
and I would like to decompose each expression into its left- and
right-hand-side components etc., output something like
5 = 7
z = 1 + 2
Is there something built into the R language to accomplish this?
- function() x^2
do.call(f, list(), envir = e)
Error in (function () : object 'x' not found
Thanks in advance for clarifying my misunderstanding.
Dan Murphy
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PLEASE do read
9:32 AM, Dan Murphy wrote:
I am having difficulty understanding the envir argument of do.call.
The help page says
envir an environment within which to evaluate the call.
so I thought that in the following toy example x would be found in the
environment e and f would return 4 via do.call
:
On 25/06/2013 11:56 AM, Dan Murphy wrote:
So the trick is to put the function f into e and define its environment to
be e:
Putting f into e, and defining the environment of f to be e solve different
problems. Your toy example has both problems so it's a reasonable solution
there, but most real
The lubridate and seq solutions work because they rely on your
specification that the returned date be the first day of the desired
subsequent months. Without that requirement they would not always
work. For example, if you wanted to add Vec months to the last day of
March rather than the first
, POSIX objects and mondate's.
Here's your example with that package:
library(mondate)
d1 - mondate(2011-05-01 CEST)
d1 - 1 # subtract one month
mondate: timeunits=months
[1] 2011-04-01
Regards,
Dan Murphy
*Message: 1
*Date: Tue, 30 Oct 2012 11:25:39 +0100
*From: paladini palad...@beuth
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