Thanks,
that helped!
Yours,
Kay
Zitat von Gene Leynes gleyne...@gmail.com:
I think that people are afraid to say You can't do that in R...
But I think the real answer is: you can't do that in R.
Although, it is helpful to understand Jeff's reply. I hadn't fully
realized why this particular
hi,
i'd like to install the package RGoogleDocs .
i downloaded to path E:/R/R-2.13.0/library/RCurl_0.91-0.tar.gz
i run R from an usb-stick and can't get the install.packages() prompt
to run correctly - can anyone help with this?
thanks,
kay
sessionInfo()
R version 2.13.0 (2011-04-13)
13:52, Kay Cecil Cichini wrote:
hi,
i'd like to install the package RGoogleDocs .
i downloaded to path E:/R/R-2.13.0/library/RCurl_0.91-0.tar.gz
i run R from an usb-stick and can't get the install.packages() prompt to
run correctly - can anyone help with this?
1. Why not use install.packages
successfully by call
install.packages(E:/R/R-2.13.0/library/RGoogleDocs_0.5-0.tar.gz,
repos=NULL, type=source)
thanks and sorry for my clumsiness,
kay
Zitat von Uwe Ligges lig...@statistik.tu-dortmund.de:
On 05.09.2011 14:52, Kay Cecil Cichini wrote:
internet connection exists - dont' know why
hello,
yes, thanks a lot - i noticed relevel() beeing very convinient for this
purpose.
having an authority at hand may i kindly ask, if you could reinsure me
that the contrasts below are set up correctly, supposing i want to test
the earlier mentioned hypotheses simultanously.
thanks,
kay
i test the null that the coin is fair (p(succ) = p(fail) = 0.5) with
one trail and get a p-value of 1. actually i want to proof the
alternative H that the estimate is different from 0.5, what certainly
can not be aproven here. but in reverse the p-value of 1 says that i
can 100% sure that
cannot prove that the
null hypothesis is true. All that is possible with a significance
test is that a small P-value can be taken as evidence that the
NH is false.
Hoping this helps!
Ted.
On 02-Sep-10 07:41:17, Kay Cecil Cichini wrote:
i test the null that the coin is fair (p(succ) = p(fail) = 0.5
felix,
thanks a lot for the hint!
i actually found another way by setting up a panel function by which i
can control every single panel with panel.number(). maybe there is
more efficient coding - i don't know. i also alternated tickmarks and
tick-labeling by panel-rows, which is nicer, but
exactly -
thanks a lot, richard!
kay
Zitat von RICHARD M. HEIBERGER r...@temple.edu:
Kay,
doe this do what you want?
dotplot(y1+y2 ~ facs$Treatment|facs$Sites,
outer=TRUE,
scales = list(x = list(rot = 90, tck=c(1,0))),
ylab=c(y1, y2),
xlab=c(Site 1, Site
Hallo List,
I'm trying to implemement a restricted permutation scheme in permutest(). More
precisely I have dependence in my data that should be allowed for in the
permutation - I simulated the problem in the example of the vegan documentation
p.24:
library(vegan)
data(varespec)
## Bray-Curtis
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