Dear all and Pikal (in particular :))
Pikal, I’m sorry. It works!!!
Thank you very much :)
Best,
Rosa Oliveira
> On 1 Aug 2017, at 16:31, PIKAL Petr <petr.pi...@precheza.cz> wrote:
>
> Hi
>
> Keep your messages coppied to R helplist, others could give you answers t
ou help me on that task?
Thanks!
Best,
Rosa Oliveira
> On 31 Jul 2017, at 10:28, Martin Maechler <maech...@stat.math.ethz.ch> wrote:
>
>>>>>> PIKAL Petr <petr.pi...@precheza.cz <mailto:petr.pi...@precheza.cz>>
>>>>>>on Mon, 31 Jul 2017 0
I am trying to make a x-axis and y-axis titles with both a special character
and a subscript. I am not being able to do this. I think its just a placing of
my parenthesis, but I've tried (seemingly) everything.
Even more, when I try the blog users code it works.
Is it because I’m using
gt;
> point7$y_point7 <- point7$beta0_7 + point7$beta1_7*point7$time + point7
> $epsilon_7
>
> ggplot(point7, aes(time, y_point7)) + geom_line()
>
> HTH
> Ulrik
>
>
> On Wed, 19 Jul 2017 at 20:37 Rosa Oliveira <rosit...@gmail.com> wrote:
>
>> Hi everyone,
&
Hi everyone,
I’m trying to do a spaghetti plot and I know I’m doing all wrong, It must be.
What I need:
15 subjects, each with measurements over 5 different times (t1, ..., t5), and
the variable that I need to represent in the spaguetti plot is given by:
PCR = b0 + b1 * ti + epsilon
B0, -
FALSE)$out # find outliers
values to age 1 (example)
I attach the data.
Best,
Rosa Oliveira
__
Antes de imprimir este e-mail pense bem se tem mesmo que o fazer.
Há cada vez menos árvores.
Não imprima, pense na sua responsabilidade e compromisso com o MEIO
AMBIE
in positions 11 and 12 of ID, neither 11
in positions 11 and 12 of ID variable.variable.
So, it seems, that the code exclude all the conditions, as it was a OR (|)
condition in spite of AND (&) condition.
Can anyone help me please?
I attach the data.
Be
and therefore left out of coverage.
A. Is there a way of knowing which were the cycles that did not converge and
correct the estimates?
B. For this I have the "results” saved -
save.image("~/Documents/phd_april_v16.RData”) will this be useful for something?
Best,
RO
Atenciosamente,
Ros
d get the CI with confint(naïve) command, but with
probit I don't think so. Is there a way?
What should I do?
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com &
I would get the CI with confint(naïve) command, but with
probit I don't think so. Is there a way?
What should I do?
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit.
?
or simply concerning the risk of hiv among MSM
If yes, How?
Metafor? I’ve tried, but wasn’t succeed :(
Best,
RO
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Dear Michael (and all :))
Thank you very much.
I fixed my problem, I think ;)
Best,
RO
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin
ys<-data.frame(tas.6days[order(tas.6days[,1]),])
+ tas.6days$tas[tas.6days$tas==8|tas.6days$tas==9 ]<-NA
+
+ #mixed model for the longitudinal tas
+ lme.1 <- lme(tas~ time+1, random = ~ time+1 |i
Dear all,
I’m trying to compute Odds ratio and OR confidence interval.
I’m really naive, sorry for that.
I attach my data and my code.
I’m having lots of errors:
1. Error in data.frame(tas1 = tas.data$tas_d2, tas2 = tas.data$tas_d3, tas3 =
tas.data$tas_d4, :
arguments imply differing
ylab="")
abline(h = -.5, col = "gray60")
mtext(expression(paste(lambda)),side=1,line=2, cex.main=1.5)
screen(10)
par(mar=c(3,0,0,0))
# now the second set
n1000<-SE.alpha2$nsample==1000
matplot(x=SE.alpha2$lambda[n1000],y=SE.alpha2[n1000,3:5],
type="l",pch=1:3,
side=1,line=2, cex.main=1.5)
screen(10)
par(mar=c(3,0,0,0))
# now the second set
n1000<-SE.alpha2$nsample==1000
matplot(x=SE.alpha2$lambda[n1000],y=SE.alpha2[n1000,3:5],
type="l",pch=1:3,col=c(4,2,3),yaxt="n",ylim=c(0, 1.1))
abline(h = -.5, col = "gray60")
mte
x.main=1.5)
screen(2)
par(mar=c(0,0,0,0))
# plot an empty plot to get the coordinates
plot(0:1,0:1,type="n",axes=FALSE)
legend(0,0.6,c("OLS", "GLS", "Reg. Cal.", "true coefficient"),bty = "n",
lty=1:3,col=c(4,2,3,"g
a model and I’m trying to figure if it makes sense to add some
variables into the model.
Another doubt,
3. LMER only accepts categorical variables?
Best,
RO
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos
))
2nd lmer(yy~1+time+(time|id.pat)+(1|id.visit))
the problem remains:
variable lengths differ - for the first fixed effect in the model id.age in
the first or time in the second
Best,
RO
Atenciosamente,
Rosa Oliveira
help me?
1st problem:
how do I generate age so I can use it as a fixed factor?
2nd problem:
how do I insert age as a fixed factor?
3rd problem:
what if I wanted to insert a 2nd random effect based on age?
Best,
RO
Atenciosamente,
Rosa Oliveira
attach my previous graphs and my data, so you can see :)
I’m very naive and new in R :(
Thanks again for your help ;)
Atenciosamente,
Rosa Oliveira
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira
,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin: https://pt.linkedin.com/in/rosacsoliveira
, Was it me that made
something wrong?
I’m very naive and new in R :(
Thanks again ;)
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin
(Naive, Regression Calibration, Pseudo
Likelihood), bty = n,col=c(4,2,3),lty=c(4,2,3))
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin
;)
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin: https://pt.linkedin.com/in/rosacsoliveira
Dear Don and all,
I’ve read the tutorial and tried several codes before posting :)
I’m really naive.
what I was trying to : is something like the graph in the picture I drawee.
Is it more clear now?
Atenciosamente,
Rosa Oliveira
in sample, and all the other specificityies.
Best,
RO
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin: https://pt.linkedin.com
I should have 3 graphs each one with 3 lines
1 red to factor a, 1 blue to factor b and 1 green to factor c.
Do you all think is better?
Nonetheless I can’t do it :(
best,
RO
Atenciosamente,
Rosa Oliveira
--
Rosa
$Region[my.data$sample==50],my.data$factor.a[my.data$sample==50],col=4,type=“l”,xlab=“Region”,ylab=“factor)
Error: unexpected input in
plot(my.data$Region[my.data$sample==50],my.data$factor.a[my.data$sample==50],col=4,type=�”
I’m really naive, right?
Best,
RO
Atenciosamente,
Rosa Oliveira
.
Best,
RO
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin: https://pt.linkedin.com/in/rosacsoliveira
Thanks all off you ;)
I think I got it.
I was saving the workplace and loading it, but after that I wasn’t calling my
data ;)
really naive.
Thanks very much.
best
RO
Atenciosamente,
Rosa Oliveira
--
Rosa
). And my work is being delayed :(
Best,
RO
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin: https://pt.linkedin.com/in/rosacsoliveira
problem is that the function I use takes 3 days running, and just 500
simulations :(
Best,
RO
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin
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