citation()
Error: $ operator is invalid for atomic vectors
In addition: Warning message:
In packageDescription(pkg = package, lib.loc = dirname(dir)) :
no package 'base' was found
sessionInfo()
R version 3.1.1 (2014-07-10)
Platform: x86_64-w64-mingw32/x64 (64-bit)
locale:
[1]
Because of the issue raised in
https://stat.ethz.ch/pipermail/r-help/2013-November/362896.html, I am
switching to R on Mac OS X (10.6.8) to create some plots. Using
CairoPDF(), however, the commands I use in Windows (7) to select my
fonts don't have any effect on Mac OS X, where the output .pdf
I'm using 'expression()' in R plots in order to get italicized text.
But it appears as if I cannot use Unicode symbols inside 'expression'
outside of ASCII characters. Is there some way I can work around this?
My goal is to get the 'fi' ligature in various labels in my R barplots
(together with
reorder() is probably the best way to order the levels in a vector
without manually specifying the order. But reorder() orders by default
in an increasing order: The levels are ordered such that the values
returned by ‘FUN’ are in increasing order.
Is there a way to do what reorder() does, but
.
- Original Message -
From: Sverre Stausland john...@fas.harvard.edu
To: r-help@r-project.org
Cc:
Sent: Sunday, July 22, 2012 12:27 PM
Subject: [R] Reorder in decreasing order
reorder() is probably the best way to order the levels in a vector
without manually specifying the order
B B F A A F C
B A
[39] E E D E E D D D D D E D D C E E E E D D C C E D C C E E C C C C C C
Levels: A B C D E F
A.K.
- Original Message -
From: Sverre Stausland john...@fas.harvard.edu
To: arun smartpink...@yahoo.com
Cc: R help r-help@r-project.org
Sent: Sunday, July 22, 2012
...@comcast.net wrote:
On Nov 14, 2011, at 11:49 PM, Sverre Stausland wrote:
Hi R users,
I end up with a list object after running an anova:
lm(speed ~ 1 + dist + speed:dist, data = cars) - Int
lm(speed ~ 1 + dist, data = cars) - NoInt
anova(Int, NoInt) - test
test - test[c(Df, F, Pr(F))][2,]
is.list
Hi R users,
I end up with a list object after running an anova:
lm(speed ~ 1 + dist + speed:dist, data = cars) - Int
lm(speed ~ 1 + dist, data = cars) - NoInt
anova(Int, NoInt) - test
test - test[c(Df, F, Pr(F))][2,]
is.list(test)
[1] TRUE
test
Df FPr(F)
2 -1 18.512 8.481e-05
Hi all,
I'm extracting the name of the term in a regression model that
dropterm specifies as the least significant one, and I'm assigning
this name to an object. However, when I use update(), it ignores this
object. Is there a way I can make it not ignore it? A reproducible
example is below:
to a string, pase
it with your term, and then reconvert it to a formula:
update(my.lm,formula(paste(.~.-, my.object)))
There may be a more elegant way via substitute(), but I think this works.
Cheers,
Bert
On Mon, Aug 15, 2011 at 1:44 PM, Sverre Stausland
john...@fas.harvard.edu wrote:
Hi
Dear helpers,
I'm trying out the embedFonts() to embed fonts into my pdf files.
However, when I inspect the new pdf with a program designed to look
for embedded fonts, I see that the fonts have in fact not been
embedded. Below are my calls.
R version 2.13.1 (2011-07-08)
Copyright (C) 2011 The R
Some of you might see that there's a tiny mistake in the embedFonts()
call. fontpaths = C/Windows/Fonts should of course be fontpaths =
C:/Windows/Fonts. I fixed this, but it didn't change the fact that
the new .pdf does not have its fonts embedded.
Sverre
On Tue, Aug 9, 2011 at 4:48 PM, Sverre
Dear helpers,
I can create a vector with the priority of the packages that came with
R, like this:
installed.packages()[,Priority]-my.vector
my.vector
base boot class cluster codetools
base recommended recommended recommended recommended
compiler
Dear helpers,
I'm trying to extract certain rows from a matrix according to the
values the rows have in a certain column. I've been googling for a
while without result.
Here's a reproducible example of a matrix (and the one I was playing
with initially):
myrepo-getOption(repos)
required by the posting guide.
Most likely this is a limitation of the locale you used (and failed to tell
us about) on the OS you used (...).
On Sat, 16 Jul 2011, Sverre Stausland wrote:
Dear helpers,
I'm trying to replace a character with a unicode code inside a data
frame using gsub
Dear helpers,
I'm trying to replace a character with a unicode code inside a data
frame using gsub(), but unsuccessfully.
data.frame(animals=c(dog,wolf,cat))-my.data
gsub(o,\u0254,my.data$animals)-my.data$animals
my.data$animals
[1] dɔg wɔlf cat
It's not that a data frame cannot have
funny.g- \u1E21
funny.g
[1] ḡ
data.frame (funny.g) - funny.g
funny.g$funny.g
[1] ḡ
Levels:U+1E21
I think the problem is in the data.frame code, not in writing. Data.frames
try to display things in a readable way, and since you're on Windows where
UTF-8 is not really
murdoch.dun...@gmail.com wrote:
On 15/07/2011 1:42 PM, Sverre Stausland wrote:
funny.g- \u1E21
funny.g
[1] ḡ
data.frame (funny.g) - funny.g
funny.g$funny.g
[1] ḡ
Levels:U+1E21
I think the problem is in the data.frame code, not in writing.
Data.frames
Dear helpers,
I am not able to export Unicode characters from R. Below is an example
where the Unicode character is correctly rendered as long as I am stay
within R. When I export it, the character appears only with its basic
code, and the same happens when I import it back into R . I'm using R
Dear helpers,
how can I extract only the values from a row in a data frame? Using
[X,] doesn't do the trick:
data.frame(letters[1:10],letters[11:20])-my.data
my.data[1,]
letters.1.10. letters.11.20.
1 a k
I would like to be able to extract only the values a and k
Great - thanks for the explanation and for the solution using
stringsAsFactors=FALSE in the data.frame function
Sverre
On Mon, Jul 11, 2011 at 3:57 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
Hi Sverre,
On Mon, Jul 11, 2011 at 12:48 PM, Sverre Stausland
john...@fas.harvard.edu wrote
Hello,
my question is triggered by an actual model I am running, but I will
pose it as a very general question with a hypothetical example.
Take the following regression model:
I have a binomial dependent variable Happiness, whose two values are
0 (=unhappy) and 1 (=happy). My two independent
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