Maybe this helps
par(mar = c(5,4,6,1))
plot(1:10, type = n, axes = F)
xticks = axis(1, at = c(1,5,9), labels =
c(1-1-2009,1-5-2009,1-9-2009)) #set axis manually
yticks = axis(2, at = 1:10) #set axis manually
abline(v = xticks, col = gray) #verticall lines
abline(h = yticks, col = gray,
Maybe this helps
par(mar = c(5,4,6,1))
plot(1:10, type = n, axes = F)
xticks = axis(1, at = c(1,5,9), labels =
c(1-1-2009,1-5-2009,1-9-2009)) #set axis manually
yticks = axis(2, at = 1:10) #set axis manually
abline(v = xticks, col = gray) #verticall lines
abline(h = yticks, col = gray,
Hi,
I'm trying to evaluate a character vector within pnorm. I have a vector
with values and names
x = c(2,3)
names(x) = c(mean, sd)
so that i tried the following
temp = paste(names(x), x, sep = =)
#gives
# temp
#[1] mean=2 sd=3
#Problem is that both values 2 and 3 are taken as values for
-help-boun...@r-project.org] On
Behalf Of Thomas Roth (geb. Kaliwe)
Sent: Friday, 17 July 2009 6:03 PM
To: 'r-help@r-project.org'
Subject: [R] how to evaluate character vector within pnorm()
Hi,
I'm trying to evaluate a character vector within pnorm. I have a vector
with values and names
x = c
Hi,
I was wondering what would be the best way to check if the three dots
argument contains any arguments (i.e. does ... contain any arguments or
not? )
#Example
test = function(x,y, ...)
{
#Wanted R-Code
# if(empty(...))
#do some calculation
plot(x,y,...)
}
Thanks
Thank you both.
Thomas
Dimitris Rizopoulos schrieb:
one way is:
test - function(x, y, ...) {
dots - list(...)
if (length(dots)) cat(\nnon-empty\n) else cat(\nempty\n)
}
test(1, 1)
test(1, 1, 1)
I hope it helps.
Best,
Dimitris
Thomas Roth (geb. Kaliwe) wrote:
Hi,
I
maybe this helps
x = \test\
plot(1:10, main = x) #heading contains
#or
cat(\test\)
Thomas Roth
Paulo E. Cardoso schrieb:
maybe a very basic question but I need to parse an SQL code into a GIS from
a ODBC conn.
The code includes a specific sentence
OPTIONS COORDSYS(Latitude /
in the legend there's x but not the value of x which actually should be
shown...
#does not work
x = 2
plot(1:10)
legend(4,4, expression(t[m] == x, t[n] == x))
#legend contains x but not the value of x
So this won't work
Zhiliang Ma schrieb:
On Thu, Jul 9, 2009 at 9:39 AM, Thomas Roth
Dear members,
Is there a way to put more than one mathematical annotation into a
legend together with a calculated value?
x = 2
plot(1:10)
#Works
legend(8, 8, substitute(t[m] == x))
#does not work
legend(4,4, c(substitute(t[m] == x), substitute(t[n] == x)))
Thanks
Thomas Roth
Hi,
I have the following problem. Calling wireframe within a loop results
into an empty window(s)
#generate some data
temp = expand.grid(A = 1:3,B = 1:3)
temp = cbind(temp, y1 = rnorm(9))
temp = cbind(temp, y2 = runif(9))
#plot y1 and y2 in two different windows
for(i in 1:2)
{
wireframe(y1
.
~ John Tukey
-Oorspronkelijk bericht-
Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Namens Thomas Roth (geb. Kaliwe)
Verzonden: woensdag 24 juni 2009 13:08
Aan: 'r-help@r-project.org'
Onderwerp: [R] lattice wireframe within a loop ???
Hi,
I have the following
Dear List,
Is it possible to build a package with 'names' method for a S4-Class?
The following works if directly pasted into R:
(a simple test class with 1 attribute that is returned by invoking 'names')
#class definition
setClass(test, representation = representation(name = character),
Sorry for mailing to you personally...
for types
read.csv(file.choose())
freqTable = table(types)
pie(freqTable)
##example for some data
temp = data.frame(types = 1:10)
pie(table(temp))
Thomas Roth
PS: use barplot instead of pie
DonkeyRhubarb schrieb:
Hi all,
I am looking to create a pie
#I used sink
?sink
#Thomas
Maxl18 schrieb:
Hello,
I want to import R-output via Rserve to Java, especially for the function
ctree from the package party.
Rserve is working properly.
Yet, I only get the predictions with the Java code
try{
RConnection c = new RConnection();
#Hi,
#
#For a given class test, an object of class test cannot be used as data
in the lm method although as.data.frame was implemented... where's my
mistake?
#
#Suppose i have defined a S4 class test
#S4 Class test containting a slot data
#which is of type data.frame
setClass(Class = test,
#Hi,
#
#somebody knows how to remove the outer box around a wireframe and
reduce the height
#
#
test = data.frame(expand.grid(c(1:10), c(1:10)))
z = test[,1] + test[,2]
test = cbind(test, z)
names(test) = c(x, y, z)
require(lattice)
wireframe(z ~ x*y, data = test, par.box = c(col =
= list(col = transparent)),
par.box = c(col = transparent) )
--sundar
On Wed, Mar 4, 2009 at 8:17 AM, Thomas Roth (geb. Kaliwe)
hamstersqu...@web.de wrote:
#Hi,
#
#somebody knows how to remove the outer box around a wireframe and reduce
the height
#
#
test = data.frame(expand.grid(c(1:10), c(1
Hi,
#There are a lot of examples for barplot if you just type
example(barplot)
# i altered one slightly to put the values on top of each bar
mp - barplot(VADeaths) # default
#tot - colMeans(VADeaths) #changed this line
tot = colSums(VADeaths)#wether you need max, min, mean , colSums
you could set them manually, if thats what you're looking for
plot(1:10, axes = F)
axis(1, at = seq(1,10 , length = 3))
mau...@alice.it schrieb:
Is there a way to force the number of ticks along an axis ?
I read the on-line documentation and tried many combinations of all available
parameters
First thing you need to do is, save the file with an .r ending. Tinn-R
will then come up with syntax highlighting (as far as i remember).
Options-Main-Application leads you to the r-configuration...
HTH
Thomas
Tibert, Brock schrieb:
Tibert, Brock schrieb:
Hi Everyone,
I was hoping
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