Geoff,
I think you could write an if loop to solve this.
You could write:
for(i in 1:num_obs){
if(DAYS[i]=='Monday'){
DF$DAYS.BETWEEN[i]-1
}
}
Where 'num_obs' is the total number of temperature observations you have.
This would only be correct if you had no missing data on Fridays. Also, if
Hi all,
This is a very basic question, but I just can't figure out why R is handling
a loop I'm writing the way it is.
Here is the script I have written:
grid_2_series-function(gage_handle,data_type,filename)
series_name-paste(gage_handle,data_type,sep=_)
I knew it would be something simple. Thanks for catching that, Martyn.
Billy
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Didn't mean to snub you guys, Hugo and David. I didn't see your posts
before. Thanks for the advice.
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Hi all,
I am attempting to run through a large set of data and sort events by the
water year (1 Oct - 30 Sep) in which they occurred.
I have no problem doing this for each individual site I am looking at (so my
problem is not with most of the code, just one minor thing), but when I try
to loop
One thing I should have mentioned before is that pds_gagehandles is a
character vector that contains the site names that I am interested in. An
example of a site name is saho.
So with with the paste function, I am trying to get R to assign a variable
with the site name followed by _potwy. For
Hi all,
I am trying to write a script that will compute Kendall's tau for a 75 time
series (using the Kendall package) and will then write the tau and p values
from the Kendall test to a text file table that can be read into Excel.
I am having no problem calculating Kendall's tau and the
Hi all,
When I attempt to run a script, I keep getting the error message shown
below. I have seen from searching that the Use of save versions prior to 2
is deprecated could be an error resulting from a permissions problem, but I
have been unable to find anything describing the file has magnic
might be causing this error? Or is there a way
for me to see what line in the code results in an error?
Thanks again.
Billy
Philipp Pagel-5 [via R] wrote:
On Fri,
Mar 25, 2011 at 06:42:49AM -0700, armstrwa wrote:
gt; When I attempt to run a script, I keep getting the error message
Hi all,
I am trying to write a script that will automate the task of running a
Kendall's Tau correlation test on 75 time series that I am interested in.
The code I have written is:
for(i in 1:length(gagehandles)){
dates-get(paste(gagehandles[i],_amsd,sep=))
lt;!DOCTYPE html PUBLIC quot;-//W3C//DTD HTML 4.01 Transitional//ENquot;gt;
Thank you very much, Peter.nbsp; That does make it clearer.
Billy
Peter Ehlers [via R] wrote:
On
2011-03-21 14:16, armstrwa wrote:
gt; Hi,
gt;
gt; I am running a correlation analysis on a temporal
lt;!DOCTYPE html PUBLIC quot;-//W3C//DTD HTML 4.01 Transitional//ENquot;gt;
Thanks, Petr.nbsp; Your insight has helped me out a lot.
Billy
Petr Savicky-2 [via R] wrote:
On Mon, Mar 21, 2011 at 02:28:32PM -0700, armstrwa wrote:
gt; Hi all,
gt;
gt; Forgive me for this basic
Hi,
I am running a correlation analysis on a temporal dataset. I was wondering
if you would receive the same tau and p values running the function:
MannKendall(x), where x is the dependant variable that changes with time
as you would running:
Kendall(d,x), where x is the exact same dataset
Hi all,
Forgive me for this basic question. I've been doing some research and
haven't been able to figure out how to best do this yet.
I have 75 variables defined as vector time series. I am trying to create a
script to automate calculations on each of these variables, but I wasn't
sure how to
Hi,
I am trying to create a loess smooth from hydrologic data. My goal is to
create a smooth line that describes discharge at a certain point in time. I
have done this using the 'lowess' function and had no problem, but I'm
having some difficulty with loess. I am inputting the date ('date')
Yeah, I did look at the help(loess) page, but I wasn't really sure what to do
with that. I was inputting it as:
test-loess(date ~ q,data.frame(date,q),span=0.5)
test
Call:
loess(formula = date ~ q, data = data.frame(date, q), span = 0.5)
Number of Observations: 96
Equivalent Number of
, you've got them
backwards from what you've said you're trying to model.
armstrwa wrote:
Yeah, I did look at the
help(loess) page, but I wasn't really sure what to do with that. nbsp;I was
inputting it as:
gt; testlt;-loess(date ~ q,data.frame(date,q),span=0.5
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