Hi,
You could use melt from the reshape package to create a long format
data.frame. This is more easy to plot with lattice or ggplot2, and you
can then use facetting to arrange several plots on the same page. The
dummy example below produces 10 pages of output with 10 graphs per
page.
Hi,
It's not clear what you mean by summary text without a minimal
reproducible example. If your text is ordered as a matrix or a
data.frame, you might want to try this grid function,
gridExtra::grid.table(as.matrix(summary(iris)), theme=theme.white())
If your text has the form of a paragraph,
Hi,
I think you could use a concave hull from the alphahull package,
http://yihui.name/en/2010/04/alphahull-an-r-package-for-alpha-convex-hull/
It may be difficult to find the right parameters if the polygons
differ widely in edge lengths, though.
HTH,
baptiste
On 2 June 2010 03:53, Remko
Hi,
ggplot2 or lattice could help you in creating the plots. Adding a
summary will however require some play with Grid graphics; either
using gridBase to mix lattice / ggplot2 output with base R graphics
(e.g. textplot() from some package I forget), or you'll need to
produce the textual summary
Thank you for the explanation, and the fortune-ish quote,
“As the documentation for substitute() says, there is no guarantee
that the result makes sense.”
Best,
baptiste
On 19 May 2010 02:59, Duncan Murdoch murdoch.dun...@gmail.com wrote:
On 18/05/2010 4:36 PM, baptiste auguie wrote:
Dear
Hi,
See also ?lattice::xyplot and ?ggplot2::geom_point , either one can do
it automatically.
HTH,
baptiste
On 19 May 2010 12:24, Jannis bt_jan...@yahoo.de wrote:
Dears,
before I start programming my own function I would like to ask you whether
there is any function already available that
Dear all,
I got a couple of warnings using panel.levelplot.raster,
In panel.levelplot.raster(..., interpolate = TRUE) :
'y' values are not equispaced; output will be wrong
although I was quite sure my data were equally spaced (indeed, I
created them with seq()). A closer look at the source
On 18 May 2010 15:30, Deepayan Sarkar deepayan.sar...@r-project.org wrote:
Maybe a better test would be
isTRUE(all.equal(diff(range(diff(ux))), 0))
I'll try that out for the next release.
Sounds good (and works for me), thanks.
baptiste
__
Dear list,
I am puzzled by this,
substitute(expression(x), list(x = factor(letters[1:2])))
# expression(1:2)
Why do I get back the factor levels inside the expression and not the
labels? The following work as I expected,
substitute(expression(x), list(x = letters[1:2]))
# expression(c(a, b))
Hi,
Try this,
saveMyWork - .Last.value
HTH,
baptiste
On 17 May 2010 15:07, math_daddy math_da...@hotmail.com wrote:
Hello.
I ran a simulation that took a few days to complete, and want to analyze the
results, but have just realized that I (idiotically) did not assign the
output to a
Hi,
try this,
m = matrix(runif(2000*2400), nrow=2000)
library(grid)
grid.raster(m)
HTH,
baptiste
On 17 May 2010 20:35, tetonedge de...@tetonedge.net wrote:
I have a matrix that is 2400x2000 and I would like to display it as an image,
I have tried image(), but due to the size of the matrix
No, that's only true for lattice and ggplot2 graphics. The problem
here is with this line,
windows(width=5, height=5)
which shouldn't be there.
HTH,
baptiste
On 17 May 2010 22:23, Jun Shen jun.shen...@gmail.com wrote:
If you do plotting in a loop, then you need to print it to the device.
Hi,
On 16 May 2010 03:31, michael westphal mi_westp...@yahoo.com wrote:
[ snipped ]
Any suggestions?
i'd suggest you
- read the posting guide
- upgrade your R to the latest version
- don't post to two mailing lists
- make your example minimal, self-contained, reproducible
- show the result of
Hi,
Lattice and ggplot2 are both ideally suited for this task. Consider
this example,
library(ggplot2)
d = data.frame(x=1:10, a1=rnorm(10), b1=rnorm(10))
m = melt(d, id =x) # reshape into long format
qplot(x, value, data=m, geom=path, colour=variable)
library(lattice)
xyplot(value~x, data=m,
Hi,
This idea was also discussed when Paul Murrell first announced the
grid.raster function to R-devel,
http://tolstoy.newcastle.edu.au/R/e8/devel/09/12/0912.html
My personal conclusion was that vector fill patterns are generally
better in terms of resolution and speed. Of course the situation
Hi,
Taking a wild guess, it looks to me that you might have overlaid
several times the same text,
plot.new()
text(0.5,0.5,rep(test,10))
HTH,
baptiste
On 20 April 2010 08:54, chrisli1223 chri...@austwaterenv.com.au wrote:
Hi all,
I have written a note near each of my graphs using mtext.
Hi,
Another option might be the tikzDevice package, which uses LaTeX to
process the fonts,
library(tikzDevice)
tikz(standAlone=T)
plot(1,1, type = 'n')
mtext(side = 3, line = 2, $\\mu$)
dev.off()
## system(/usr/texbin/pdflatex Rplots.tex)
HTH,
baptiste
On 20 April 2010 07:30, Prof Brian
I have seen pdf files with 3D objects embedded in it, using the U3D format,
http://en.wikipedia.org/wiki/Universal_3D
but I don't think there's a device for this in R; in fact there may
not even exist a third-party post-processing route available at this
time to bridge the gap between rgl and
Apr 2010, baptiste auguie wrote:
I have seen pdf files with 3D objects embedded in it, using the U3D
format,
http://en.wikipedia.org/wiki/Universal_3D
but I don't think there's a device for this in R; in fact there may
not even exist a third-party post-processing route available at this
time
Hi,
On 12 April 2010 22:07, Peter Jepsen p...@dce.au.dk wrote:
3. Are there R packages that can draw tables?
the gplots package has a textplot() function, and the gridExtra
package a tableGrob(),
http://rwiki.sciviews.org/doku.php?id=tips:graphics-grid:table
In theory it should be possible
(stringWidth(labels)), npc))
}
grid.arcText - function(...)
grid.draw(arcTextGrob(...))
set.seed(1234)
grid.newpage()
grid.arcText()
On 7 April 2010 23:13, baptiste auguie baptiste.aug...@googlemail.com wrote:
The following grob might be a starting point. I couldn't find a clean
way of orienting
try this,
install.packages(expm, repos=http://R-Forge.R-project.org;)
On 8 April 2010 17:28, arindam fadikar arindam.fadi...@gmail.com wrote:
On Thu, Apr 8, 2010 at 5:38 PM, David Winsemius dwinsem...@comcast.netwrote:
On Apr 8, 2010, at 1:45 AM, arindam fadikar wrote:
Dear users,
How
Hi,
Barry suggested a way to place the text labels; I would like to point
out the grid.curve() function that might help in connecting the labels
with nice-looking curves. I don't know of a base graphics equivalent
(xspline() might come close) so it might be best to opt for Grid.
HTH,
baptiste
, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Hi,
Barry suggested a way to place the text labels; I would like to point
out the grid.curve() function that might help in connecting the labels
with nice-looking curves. I don't know of a base graphics equivalent
(xspline() might come close
Hi,
One option with Grid graphics,
m -
matrix(c( 1667,3,459,
2001, 45, 34,
1996, 2,5235),
dimnames=list(c(Eric Alan, Alan,John David)),
ncol=3, byrow=T)
## install.packages(gridExtra, repos=http://R-Forge.R-project.org;)
library(gridExtra)
Hi,
On 24 March 2010 23:22, Paul Murrell p.murr...@auckland.ac.nz wrote:
Hi
baptiste auguie wrote:
Thanks Felix and Paul. I had overlooked grid.grabExpr, assuming that
one had to draw on a device before grabbing the output.
Now I'm not sure if there's any difference between either
try this one,
`%ni%` - Negate(`%in%`)
Best,
baptiste
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
:
What's wrong with using grid.grabExpr?
p1 - xyplot(1:10 ~ 1:10)
g1 - grid.grabExpr(print(p1))
I can imagine there would be potential problems to do with the
plot-time aspect and layout calculations...
On 19 March 2010 21:51, baptiste auguie baptiste.aug...@googlemail.com
wrote:
Dear
Dear list,
I'm trying to arrange various grid objects on a page using a
frameGrob. It works fine with basic grobs (textGrob, gTree, etc.), and
also with ggplot2 objects using the ggplotGrob() function. I am
however stuck with lattice. As far as I understand, lattice produces a
list of class
Hi,
it's generally considered a bad practice but try this,
eval(parse(text=AA))
library(fortunes)
fortune(106)
HTH,
baptiste
On 10 March 2010 07:46, jq81 jingqia...@gmail.com wrote:
My question is represented by the following example.
For example, I have a character string a, which is
Dear all,
I'm trying to write tabular data to a text file, these data will be
the input of a Fortran program. The format needs to be
(i7,2x,7(e15.7,2x)). I have not been able to find a clean way of
producing this output with write.table. I searched for a
write.fortran function similar to
Hi,
last_plot() + scale_fill_grey()
should do it
HTH,
baptiste
On 10 March 2010 09:46, Johannes Graumann johannes_graum...@web.de wrote:
Hello,
I'd like to sitch to a monochrome/bw color-palette for the filling of
geom_bar-bars (produced via qplot as in the example below). Hours of
On Wednesday 10 March 2010 10:29:05 baptiste auguie wrote:
Hi,
last_plot() + scale_fill_grey()
should do it
HTH,
baptiste
On 10 March 2010 09:46, Johannes Graumann johannes_graum...@web.de wrote:
Hello,
I'd like to sitch to a monochrome/bw color-palette for the filling of
geom_bar-bars
Thanks, it is indeed a bit cleaner. I was hoping for a more generic
solution but I guess people use cat() and sprintf() in such cases.
Thanks,
baptiste
On 10 March 2010 12:46, Berend Hasselman b...@xs4all.nl wrote:
baptiste auguie-5 wrote:
This is a lot easier
for(k in
seq(1,nrow(m
, \n), c(1, 6, 1)), file = )
On Wed, Mar 10, 2010 at 7:52 AM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Thanks, it is indeed a bit cleaner. I was hoping for a more generic
solution but I guess people use cat() and sprintf() in such cases.
Thanks,
baptiste
On 10 March 2010 12:46
Hi,
try this,
data.frame(x,as.numeric(x %in% y))
HTH,
baptiste
On 7 March 2010 21:06, joseph jdsan...@yahoo.com wrote:
hello
can you show me how to create a data.frame from two factors x and y. column 1
should be equal to x and column 2 is 1 if it is common to y and 0 if it is
not.
c(x - 1:5, rev(x[-length(x)]))
On 5 March 2010 07:04, kensuguro magronb...@gmail.com wrote:
I'm just beginning R, with book Using R for Introductory Statistics, and one
of the early questions has me baffled. The question is, create the
sequence: 1,2,3,4,5,4,3,2,1 using seq() and rep().
Hi,
The 3 packages I load most often are my own; typically I make a new
package for every new job. It automatically loads other packages as
dependencies (top-ranked are ggplot2, reshape, plyr) as well as my
data and functions I'm currently working with.
If some functions evolve further towards a
Hi,
I think I would follow this approach too, using updatelist() from the
reshape package,
updatelist - function (x, y)
{
common - intersect(names(x), names(y))
x[common] - y[common]
x
}
myfunction=function(list1=NULL, list2=NULL, list3=NULL){
list1=updatelist(list(variable1=1,
Point well taken --- grid::gpar() is also a good example; I'll make
use of your suggestion in my future coding.
Best,
baptiste
On 27 February 2010 15:02, Barry Rowlingson
b.rowling...@lancaster.ac.uk wrote:
On Sat, Feb 27, 2010 at 11:29 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
Hi,
A minimalist example using Grid graphics,
library(RGraphics)
bwImage - function(m, cols=c(white, black),
draw=TRUE, gp=gpar()){
g - imageGrob(nrow(m), ncol(m),
cols=cols[m+1], gp=gp)
if(draw)
grid.draw(g)
return(g)
}
m - matrix(rnorm(200) 0,
On 26 February 2010 11:12, Lorenzo Isella lorenzo.ise...@gmail.com wrote:
Thanks Augustine and Jim for the prompt reply.
You both answered my question. To avoid another post, I would simply like to
know if something along these lines is doable also with ggplot2.
Many thanks
Lorenzo
Hi,
If you are curious you might like to try a highly experimental Grid
function I wrote some time ago,
library(grid)
source(http://gridextra.googlecode.com/svn/trunk/R/patternGrob.r;)
grid.newpage()
grid.pattern(x=seq(1/6, 5/6, length=6), width=unit(1/8,npc),
height=unit(0.5,npc),
Hi,
just to make sure, you didn't forget to close the device with dev.off() ?
baptiste
On 21 February 2010 20:48, Karthik kwr...@gmail.com wrote:
Hello Tal,
This is the code.
hist(rnorm(100))
jpeg(histogram.jpeg)
---
Even when I decrease the
Hi,
Try this,
unlist(test)
or
do.call(c, test)
HTH,
baptiste
On 19 February 2010 15:19, statquant colin.uman...@barcap.com wrote:
Hello all
I am new in R and so easy stuff are difficult...
let say that I have a list
test - list(a=c(x,v),b=c(n,m))
how can I without a loop get test$a
Hi,
Try with bquote,
plot.new()
myText - some text
text(.5, .5, bquote(bold(.(myText
basically, bquote( .(myText) ) performs the substitution before
applying bold() (see ?bquote).
HTH,
baptiste
On 14 February 2010 17:36, Mark Heckmann mark.heckm...@gmx.de wrote:
# I want to plot bold
Hi,
it's hard to tell what's wrong without a reproducible example, but I
noted two things:
- AFAIK there is no plot method for ggplot2. You probably meant print(p) instead
- if you map x to factor(month), I think it will be incompatible with
your xlim values range(month).
HTH,
baptiste
On 14
Hi,
I believe it's lazy evaluation. See ?force
HTH,
baptiste
On 14 February 2010 20:32, Jyotirmoy Bhattacharya
jyotir...@jyotirmoy.net wrote:
I want to use lapply and a function returning a function in order to build a
list of functions.
genr1 - function(k) {function() {k}}
l1 -
Hi,
On 11 February 2010 22:14, Paul Murrell p.murr...@auckland.ac.nz wrote:
Hi
baptiste auguie wrote:
Hi,
You could try the grid.grab() function in R devel if your graphics use
the Grid package. It will read the graphical output as a bitmap which
grid.grab() does NOT grab a bitmap
Hi,
You could try the grid.grab() function in R devel if your graphics use
the Grid package. It will read the graphical output as a bitmap which
you can then export in a multipage pdf. It may not be really
flattening per se but that would definitely help with the viewing
speed.
HTH,
baptiste
Hi,
Adding two semi-transparent colours results in non-intuitive colour
mixing (a mystery for me anyway). Is it additive (light), substractive
(paint), or something else? Consider the following example, depending
on the order of the two layers the overlap region is either purple
or dark red. I
Dear list,
I cannot find an elegant solution to this problem. I have a factor f
containing several levels (5) and I wish to create a new factor of the
same length with fewer levels (2). This new factor should therefore
group together some levels of the original data. Ideally this grouping
would
As always the question seems silly after you've learned the answer!
Thanks a lot,
baptiste
On 3 February 2010 15:06, Petr PIKAL petr.pi...@precheza.cz wrote:
# order levels
f.t-factor(f, levels=disorder)
# change levels
levels(f.t) - new.lev
all.equal(f.t,f2)
[1] TRUE
Regards
Petr
Murdoch murd...@stats.uwo.ca wrote:
On 03/02/2010 8:50 AM, Ken Knoblauch wrote:
baptiste auguie baptiste.auguie at googlemail.com writes:
Adding two semi-transparent colours results in non-intuitive colour
mixing (a mystery for me anyway). Is it additive (light), substractive
(paint), or something
later (I haven't found any documentation on
this so far).
Thanks,
baptiste
On 3 February 2010 16:38, Duncan Murdoch murd...@stats.uwo.ca wrote:
On 03/02/2010 9:38 AM, baptiste auguie wrote:
That makes perfect sense, thank you, except that I'm not sure where
the white comes from when I set
Thanks for this complementary information. My head itches slightly
when reading about these virtual layers with unidirectional absorption
and reflection properties but I guess that's imputable to my personal
background as a physicist.
I still have a few questions,
- is this behavior documented?
Hi,
Hadley recently proposed a strategy using plyr for a very similar problem,
listOfFiles - list.files()
names(listOfFiles) - basename(listOfFiles)
library(plyr)
d - ldply(listOfFiles, scan)
Even if you don't want to use plyr, it's always better to group things
in a list rather than clutter
code: I get an error like:
Read 2652 items
Read 3310 items
Read 1096 items
Read 2177 items
Read 11387 items
Read 12503 items
Error in list_to_dataframe(res, attr(.data, split_labels)) :
Results are not equal lengths
hmmh?
Maxim
2010/1/30 baptiste auguie
Hi,
Would this do as an alternative syntax?
g1 - quote(1/Tm)
mat - list(0, bquote(f1*s1*.(g1)))
vals - data.frame(f1=1, s1=.5, Tm=2)
sapply(mat, eval, vals)
HTH,
baptiste
On 29 January 2010 17:51, Jennifer Young
jennifer.yo...@math.mcmaster.ca wrote:
Hallo
I'm having trouble figuring out
Hi,
I remember asking a similar question some time ago, I don't know if
the matter has evolved since then,
http://groups.google.com/group/ggplot2/browse_frm/thread/a3df8a0d1ee335fb/e3bedd50fb9bd567?lnk=gstq=theme#e3bedd50fb9bd567
There's also set_default_scale, somewhat related to your
Hi,
It's easy with ggplot2,
cols = matrix(c(#F7FBFF, #DEEBF7, #C6DBEF, #9ECAE1, #6BAED6,
#4292C6, #2171B5, #08519C ,#08306B), ncol=3)
library(ggplot2)
m = melt(cols)
qplot(factor(X1),factor(X2),data=m, fill=value, geom=tile) +
scale_fill_identity()
HTH,
baptiste
2010/1/27 evgeny55
Hi,
Try this,
x - seq(0, 10, len = 100)
y - jitter(sin(x), 1000)
old.par - par()
par(bg=grey(0.5))
plot(x, y, new = TRUE, t = n)
lims - par(usr)
plot(x, y, col = 1,
panel.first = {
rect(lims[1], lims[3], lims[2], lims[4],
col = lightblue) })
HTH,
baptiste
2010/1/26
Hi,
Try this,
a = replicate(3, data.frame(x=1:10, y=rnorm(10)), simplify=FALSE)
lapply(a, [, y)
HTH,
baptiste
2010/1/22 Ivan Calandra ivan.calan...@uni-hamburg.de:
Hi everybody!
I have a (stupid) question but I cannot find a way to do it!
I have a list like:
SPECSHOR_tx_Asfc
$cotau
Hi,
One approach could be a while loop as follows. Note that your circle
should have radius 0.5 if I understood the problem correctly.
N - 5
npoints - 0
ntests - 0
points.in.circle - matrix(NA, ncol=2, nrow=N)
while (npoints N) {
test.point - runif(2, -0.5, 0.5) # generate new point in 2D
Hi,
try c.trellis() from the latticeExtra package.
HTH,
baptiste
2010/1/20 George Chen glc...@stanford.edu:
Hello,
I would like to juxtapose two lattice graphs with common X axes such that the
X axes line up. I am using plot right now but the edges are not neat and it
would be nice if
Hi,
You could play with the splitTextGrob() function from the RGraphics package,
string - Lorem ipsum dolor sit amet, consectetur adipiscing elit.
Quisque leo ipsum, ultricies scelerisque volutpat non, volutpat et
nulla. Curabitur consequat ullamcorper tellus id imperdiet. Duis
semper malesuada
Hi,
?eval seems like a good candidate
HTH,
baptiste
2010/1/15 Jiiindo jiin...@yahoo.com:
Hello all,
I want to call R from java. And I have a expression in Java as a String,
example : (variable 1 + variable 2)* variable 3 and i want R calculate this
expression. How can I do?
ex:
Java
Hi,
I think you could use iapply (search the archives) or the plyr package
to save you from transposing the result.
HTH,
baptiste
2010/1/19 marco salvini marco.salv...@gmail.com:
Can you please help on the issue?
I using the apply command on a matrix below the example:
Create a vector
x
It did take me a good night's sleep to understand it. I was stuck with
the exact same question but I see now how the remaining balls are
shared among all 8 urns (therefore cases with 11, 12, 13, ... 17 balls
are also dealt with).
Thanks again,
baptiste
2010/1/12 Rolf Turner
] On Behalf Of Brian Diggs
Sent: Thursday, December 31, 2009 3:08 PM
To: baptiste auguie; David Winsemius
Cc: r-help
Subject: Re: [R] expand.grid game
baptiste auguie wrote:
2009/12/19 David Winsemius dwinsem...@comcast.net:
On Dec 19, 2009, at 9:06 AM, baptiste auguie wrote:
Dear list
Hi,
Something like this maybe,
plot.new()
lab = expression(bar(T)*(*-x* ; *alpha*)-G*(*x* ; *alpha* , *J*))
text(0.5,0.5,lab)
?plotmath
HTH,
baptiste
2010/1/8 bernardo lagos alvarez blacert...@gmail.com:
Dear useRs,
How can I, writting the correct greek letter using postscrip or pdf
Hi,
Thank you for this fun package.
I recently posted a related question on R-help that seemed to pass
unnoticed. Basically, I suggested that the functionality of fortunes
could be extended to R FAQ entries, also allowing contributed packages
to provide their own (fortune or) faq data file. My
Hi,
Using backticks might work to some extent,
library(lattice)
`my variable` = 1:10
y=rnorm(10)
xyplot(`my variable` ~ y)
but if your data is in a data.frame the names should have been converted,
make.names('my variable')
[1] my.variable
HTH,
baptiste
2010/1/3 Jay josip.2...@gmail.com:
Hi,
You can set up a Grid layout with one viewport at the bottom and
another on the left and use grid.text to add your labels. An example
is given below using grid.pack.
The gridExtra package provides a convenient wrapper for these regular
arrangements of plots,
##library(gridExtra)
Hi,
Try print(p) instead of plot(p)
HTH,
baptiste
2009/12/29 Bryan Hanson han...@depauw.edu:
I¹m trying to build a simple formula interface to work with a function using
ggplot2. The following scheme ³works² up until the plot(p) request, at which
point there are complaints about xlim¹s and
Hi,
I think you can also use plyr for this,
dft - read.table(textConnection(P1idVeg1Veg2AreaPoly2 P2ID
1 p p 1 1
1 p p 1.5 2
2 p p 2 3
2 p h 3.5 4),
Hi,
Here is some artificial data followed by minimal ggplot2 and lattice examples,
makeUpData - function(){
data.frame(x=sample(letters[1:4], 100, repl=TRUE), y=rnorm(100))
}
datasets - replicate(15, makeUpData(), simplify=FALSE)
names(datasets) - paste(dataset, seq_along(datasets), sep=)
as a book.
Lattice also has a dedicated book, and a companion website with the figures,
http://r-forge.r-project.org/projects/lmdvr/
HTH,
baptiste
2009/12/29 baptiste auguie baptiste.aug...@googlemail.com:
Hi,
Here is some artificial data followed by minimal ggplot2 and lattice examples
Hi,
Try this,
x - matrix(1:9, ncol=3, byrow=T)
sca - c(2.5, 1.7, 3.6)
x %*% diag(1/sca)
HTH,
baptiste
2009/12/27 Muhammad Rahiz muhammad.ra...@ouce.ox.ac.uk:
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
x
Will this do?
temp - paste(m, 1:3, sep=,collapse=,)
HTH,
baptiste
2009/12/23 Knut Krueger r...@krueger-family.de:
Hi to all
I need a string like
temp - paste(m1,m2,m3,sep=,)
But i must know how many items are in the string,afterwards
the other option would be to use a vector
temp -
Isn't paste doing exactly this?
temp - c(November, December,Monday,Tuesday)
paste(temp, collapse=,)
# November,December,Monday,Tuesday
HTH,
baptiste
2009/12/23 Ted Harding ted.hard...@manchester.ac.uk:
On 23-Dec-09 11:08:02, Knut Krueger wrote:
Jim Lemon schrieb:
Not as easy as I thought
participated, I have learned interesting
things from a seemingly innocuous question.
Best regards,
baptiste
2009/12/21 Robin Hankin rk...@cam.ac.uk:
Hi
library(partitions)
jj - blockparts(rep(9,8),17)
dim(jj)
gives 318648
HTH
rksh
baptiste auguie wrote:
Dear list
Hi,
try this,
ylab = expression(Temperature~(degree*F))
?plotmath
baptiste
2009/12/20 Kim Jung Hwa kimhwamaill...@gmail.com:
Hi All,
I'm wondering if its possible to write degree in symbol.
I would like y-label as Temperature (degreeF). where degree should be in
symbols. Thanks in
Dear list,
I made the following example of a proto object that contains some data
and a spline interpolation. I don't understand why test$predict()
fails with this error message:
Error: evaluation nested too deeply: infinite recursion / options(expressions=)?
Best regards,
baptiste
test -
mean
to refer to stats::predict. Change the line that calls predict to:
stats::predict(.$spline(), x.fine)
On Sun, Dec 20, 2009 at 11:49 AM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Dear list,
I made the following example of a proto object that contains some data
and a spline
Hi,
Do you want a ternary plot?
http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=34
It's easy to rotate an axis with Grid graphics,
library(grid)
pushViewport(viewport(0.5,0.5, width=0.5, height=unit(3, lines)))
grid.xaxis(at=seq(-0.5,0.5,by=0.1), vp=viewport(x=1, angle=-60))
HTH,
Dear list,
In a little numbers game, I've hit a performance snag and I'm not sure
how to code this in C.
The game is the following: how many 8-digit numbers have the sum of
their digits equal to 17?
The brute-force answer could be:
maxi - 9 # digits from 0 to 9
N - 5 # 8 is too large
test - 17
2009/12/19 David Winsemius dwinsem...@comcast.net:
On Dec 19, 2009, at 9:06 AM, baptiste auguie wrote:
Dear list,
In a little numbers game, I've hit a performance snag and I'm not sure
how to code this in C.
The game is the following: how many 8-digit numbers have the sum of
their digits
)})
user system elapsed
34.050 1.109 35.791
I'm surprised by idx-c(idx,i), isn't that considered a sin in the R
Inferno? Presumably growing idx will waste time for large N.
Thanks,
baptiste
2009/12/19 David Winsemius dwinsem...@comcast.net:
On Dec 19, 2009, at 1:36 PM, baptiste auguie wrote
for the list]
2009/12/19 David Winsemius dwinsem...@comcast.net:
On Dec 19, 2009, at 2:10 PM, David Winsemius wrote:
On Dec 19, 2009, at 1:36 PM, baptiste auguie wrote:
2009/12/19 David Winsemius dwinsem...@comcast.net:
On Dec 19, 2009, at 9:06 AM, baptiste auguie wrote:
Dear list
Hi,
Excellent, thanks for doing this!
I had tried the 2D case myself but I was put off by the fact that
Octave's convhulln had a different ordering of the points to R's
geometry package (an improvement to Octave's convhulln was made after
it was ported to R). I'm not sure how you got around this
FAQ:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-do-lattice_002ftrellis-graphics-not-work_003f
you need to print()
HTH,
baptiste
2009/12/16 c...@autistici.org c...@autistici.org:
Hi,
i have a script how i launch lattice to make a densityplot.
in the script:
jpeg(file=XXX.jpg)
Dear list,
I'm not so familiar with the internals of the fortunes package, but I
really like the interface. I was wondering if someone had implemented
a similar functionality to parse the entries of the R FAQ
http://cran.r-project.org/doc/FAQ/R-FAQ.html . Say, if I was to
answer a question Why
Hi,
Try this,
apply(expand.grid(letters[1:3], letters[24:26]), 1, paste,collapse=)
[1] ax bx cx ay by cy az bz cz
?expand.grid
HTH,
baptiste
2009/12/14 Amelia Livington amelia_living...@yahoo.com:
Dear R helpers,
I am working on the scenario analysis pertaining to various interest rates.
`[[.data.frame`
and more generally see Rnews Volume 6/4, October 2006 Accessing the Sources.
HTH,
baptiste
2009/12/13 Guillaume Yziquel guillaume.yziq...@citycable.ch:
Hello.
I'm currently trying to wrap up data frames into OCaml via OCaml-R, and I'm
having trouble with data frame
2009/12/10 Charles C. Berry cbe...@tajo.ucsd.edu:
[snipped]
Many?
set.seed(1234)
ps - matrix(rnorm(4000),ncol=4)
phull - convhulln(ps)
xs - matrix(rnorm(1200),ncol=4)
phull2 - convhulln(rbind(ps,xs))
nrp - nrow(ps)
nrx - nrow(xs)
outside - unique(phull2[phull2nrp])-nrp
done - FALSE
Hi,
.NotYetImplemented gives an example,
function ()
stop(gettextf('%s' is not implemented yet,
as.character(sys.call(sys.parent())[[1L]])),
call. = FALSE)
environment: namespace:base
HTH,
baptiste
2009/12/11 Hao Cen h...@andrew.cmu.edu:
Hi,
Is there a way to get the enclosing function
-
baptiste auguie baptiste.aug...@googlemail.com wrote in message
news:de4e29f50912040550m71fbffafnfa1ed6e0f4451...@mail.gmail.com...
Hi,
Yet another one of my very naive ideas on the subject: maybe you can
first evaluate the circumscribed and inscribed
Hi,
Is the following close enough?
apply(set2, 2, function(x) x[is.na(x)])
HTH,
baptiste
2009/12/10 Andreas Wittmann andreas_wittm...@gmx.de:
Dear R-users,
after several tries with lapply and searching the mailing list, i want to
ask, wheter and how it is possibly to avoid the for-loop in
Hi,
try this,
barchart(1:2, ylab=expression(mu*g/m^3))
?plotmath
baptiste
2009/12/9 Peng Cai pengcaimaill...@gmail.com:
Hi All,
I'm trying to write ug/m3 as y-label, with greek letter mu replacing u
AND 3 going as a power.
These commands works in general:
plot.new()
text(0.5, 0.5,
201 - 300 of 724 matches
Mail list logo
