Thanks again!
I would like to construct 14 new 'year' dummy variables. I have 14 years:
1992:2006 with 231 observations pr. year. The year dummies should assign a 1
if the observation is within the specific year and 0 otherwise. So for
example: 1992dummyvariable=1 if year=0 and so on.
P
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Thank you David!
That was EXACTLY what I needed. I have one last question:
I want to create a mix of EMU and nonEMU country pairs. I have tried with:
EMUmix1-Reduce(``, lapply(countries,function(x,y){country1 %in% euro
country2 %in% noneuro}))
# Where euro are the EMU countries and
Hi
I am looking for a efficient way to estimate all parameters in your
data.frame set using a specific function:
for example
ln(T)=b_0 + b_1*ln(Y_i*Y_j) + b_2*ln()+ ... + etc.
Thanks,
Ph
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Hi RUI
Thank you so much ! I know I have a lot to learn : / sorry for that.
If I want to make a new data.frame where it is the NONEURO avgflows. how do
I do that ?
Ph
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Thank you!
Do you know why ifelse() sometimes returns NULL ?
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Hi
EMU1993-(for (i in 1:nrow(data)){
+ ifelse(year==1992,sum(avgflowEMU),0)
+ })
EMU1993
NULL
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The text below is a part of, some work I have to do, which is due in 2 days
and I am strung up with a lot of other stuff, so I was hoping someone would
take 5 mins and help me ??
Here is a part of my data.frame:
year country1 country2 contig comlangpop1gdp1
pop2
I have tried ifelse:
trade-data.frame(avgflow,EMU,stringsAsFactors=FALSE)
avgflowEURO-rep(0,nrow(trade))
trade1-(for (i in
1:nrow(trade)){ifelse(EMU[i]==1,avgflowEURO[i]-avgflow[i],NA)})
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Does mean(avgflow[EMU]) sum the avgflows for all countrypairs where
EMU[i]==TRUE and take the mean ? Practical question: is mean(avgflow[EMU]) =
mean(avgflow[EMU==TRUE]) ???
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Thank you Rui
Can you help me with my ifelse problem - I would like to add a list to my
data.frame where avgflow in those rows where ONLY my country pair both are
in euro
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Wow it works :) Thank you SO much!!
I am very new at R and was thinking if you would explain what these to codes
do:
countries-data.frame(country1,country2,stringsAsFactors=FALSE)
# I know this i a vector with both my county lists but what does
stringsAsFacors= FALSE do ?. What if I wantede a
So the lapply function checks every country pair row for row (in my country1
and country2 column) and send back a true if both countries are EU?
How do I get a 1 instead of true and 2 instead of false?
You have been a BIG help.
I have a WHOLE assignment to get done, so maybe I'll post some more
Hi
I have a data.set with 7 lists, with over 7000 observations in each list. to
of the lists contain country names.
like:
aus dnk
fra aus
usa aut
itlusa
.
.
.
etc.
My dilemma is that I want to add an extra column/list to my data.set. If the
countries are both european it should be
Hi Michael
Sorry it is a data frame where to of the columns are 22 countries arranged
in random. I now want to add and ekstra column that is 1 if the country par
for the specific row is both european countries and 0 if not.
Regards
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This is the first and last part of my data frame. There is 3465 (not 7000)
observations so the 1 or 0 column has to be 3465 rows long aswell
year country1 country2 contig comlangpop1gdp1
pop2 gdp2 rtadist avgflow
11992 AUS AUT 0
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