hi everybody,
is this intended behaviour?
x - as.Date('0-01-01')
as.Date(as.character(x))
[1] 0-01-01
a - x - 365
as.Date(a)
[1] -1-01-01
as.Date(as.character(a))
Error in charToDate(x) :
character string is not in a standard unambiguous format
Is this a bug?
I found this, while trying
hi,
It is a good idea not to reply to existing messages, if you want to open
a new subject.
On Sun, Feb 28, 2010 at 06:33:00PM +, Amy Hessen wrote:
Hi,
After some runs to my program, I receive this error message:
?Error in sink(output.txt) : sink stack is full?
Could you
= 0, vjust = 0)
regards,
Stefan
On Sun, Feb 28, 2010 at 01:25:15PM -0800, John Kane wrote:
I had a problem annotating a graph last year ( see
http://n4.nabble.com/Putting-names-on-a-ggplot-td907158.html#a907158
for the discussion)
Stefan (smu) provided a solution using annotate
for example:
d = data.frame(gender=c(m,f,unkown), x=rnorm(300))
tapply(d$x,d$gender,mean)
f munkown
0.0787628409 0.0940534765 -0.0005323276
regards,
stefan
On Wed, Dec 09, 2009 at 04:50:37PM -0800, dolar wrote:
Hi there
I have a dataframe of a whole
matritz[is.na(matritz)] - 0
On Fri, Nov 27, 2009 at 04:15:45PM -0200, Romildo Martins wrote:
Hello,
how to replace the NA by number zero?
matrizt
[,1] [,2] [,3][,4]
[1,] 1.000NA NA NA
[2,] 0.6717685
hi,
it fails, when the NA is surrounded by double quotes, which is the
default way of quoting of the write.table command.
x - read.csv(textConnection('date,value
+ + 2009-01-01,10
+ + 2009-02-01,1
+ + NA, 3'), colClasses=c(Date, 'integer'))
Fehler in fromchar(x) :
character string is not in a
Hello,
x - c(3,5,7,3,9,7)
as.numeric(as.factor(x))
[1] 1 2 3 1 4 3
regards,
stefan
On Fri, Nov 20, 2009 at 12:02:59AM -0800, Chris Li wrote:
Hi all,
I have got a dataset like the following:
3
5
7
3
9
7
i.e. random numbers with some repeats.
I want R to classify them
P=data.frame(x=c(1,1,2,3,2,1),y=rnorm(6))
tapply(P$y,P$x,sum)
regards,
stefan
On Mon, Nov 16, 2009 at 09:49:17AM -0800, Gunadi wrote:
I am sure this is easy but I am not finding a function to do this.
I have two columns in a matrix. The first column contains multiple entries
of
hello,
sep=\n will seperate each column by \n which is not what you want.
I think a csv would be the best solution.
write.table(yourdataframe,sep=,)
or use write.csv directly.
regards,
stefan
On Mon, Nov 16, 2009 at 11:49:28AM -0800, anna_l wrote:
Hello, I am having trouble by using the
Hello,
I am searching for a function to calculate partial cumsums.
For example it should calculate the cumulative sums until a NA appears,
and restart the cumsum calculation after the NA.
this:
x - c(1, 2, 3, NA, 5, 6, 7, 8, 9, 10)
should become this:
1 3 6 NA 5 11 18 26 35 45
any
On Wed, Nov 11, 2009 at 08:53:50AM -0800, William Dunlap wrote:
Perhaps
ave(x, rev(cumsum(rev(is.na(x, FUN=cumsum)
[1] 1 3 6 NA 5 11 18 26 35 45
it takes some time to understand how it works, but it's perfect.
thank you,
stefan
On Sat, Oct 17, 2009 at 09:36:50AM +0200, Alfredo Alessandrini wrote:
Hi,
I've two dataframe:
snag_totale
AREA snag_ha
12 1.628128
23 10.274249
34 2.778503
45 73.764307
57 12.015985
log_totale
AREAlog_ha
11 22.29846
22 17.16889
33
hi,
On Sat, Oct 17, 2009 at 02:04:43PM -0700, John Kane wrote:
Putting names on a ggplot
p - p + geom_text(aes(x = namposts + 2.5, y = temprange[2], label = mlabs),
data = year, size = 2.5, colour='black', hjust = 0, vjust = 0)
you shouldn't use aes in this case since nampost,
abline(m1, col=red)
regards,
Stefan
On Thu, Oct 01, 2009 at 09:57:11AM -0400, Ashta wrote:
I am trying to plot a line graph for 3 or more regression lines
abline(m1)
abline(m2)
abline(m3)
Can I change the color of each line? if so how?
Thanks in advance
Ashta
hey,
On Mon, Sep 14, 2009 at 07:51:42AM -0700, John Kane wrote:
p - ggplot(bmm, aes(x=age, y=bm, colour=pp, group=pp))
p - p + geom_line()
remove the quotes and it will work:
ggplot(bmm, aes(x=age, y=bm, colour=pp, group=pp))+geom_line()
regards,
Stefan
hey,
I can not find a function for the following problem, hopefully you can
help me.
I have a vactor like this one
v = c(NA,NA,TRUE,TRUE,NA,TRUE,NA,TRUE,TRUE,TRUE)
and I would like to the TRUE values by the their local sequence
number.
This means, the result should look thike this:
On Thu, Jul 23, 2009 at 12:16:36PM +0200, Stefan wrote:
I want to compile R version 2.9.1 on debian stable but the make command
stops with this message:
...
begin installing recommended package VR
Error in library(Hmisc, verbose = FALSE) :
there is no package called 'Hmisc'
Execution
hey,
On Sat, Jul 18, 2009 at 01:52:34AM -0700, RON70 wrote:
Hi, suppose I have following codes :
library(zoo); library(ggplot2)
dat - matrix(rnorm(500*2), 500); dat - zooreg(dat, start =
as.Date(01/01/01, %m/%d/%y), frequency=1); plot(dat)
head(dat); month.no - format(index(dat), %m);
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