On Tue, 26-Jun-2012 at 11:57PM -0500, Erin Hodgess wrote:
| Hello again:
|
| Here is a solution to the dates without leading zeros:
|
| pou1 - function(x) {
| #Note: x is a data frame
| #Assume that Column 1 has the date
| #Column 2 has station
| #Column 3 has min
|
On Thu, 28-Jun-2012 at 06:27PM +1200, Patrick Connolly wrote:
| On Tue, 26-Jun-2012 at 11:57PM -0500, Erin Hodgess wrote:
|
| | Hello again:
| |
| | Here is a solution to the dates without leading zeros:
| |
[...]
|
| | This is not particularly elegant, but it does the trick.
|
| It's also
Hello again:
Here is a solution to the dates without leading zeros:
pou1 - function(x) {
#Note: x is a data frame
#Assume that Column 1 has the date
#Column 2 has station
#Column 3 has min
#Column 4 has max
library(stringr)
w - character(length=nrow(x))
Please don't change subject lines for follow-on comments. It messes up
threading in most readers: e.g.,
https://stat.ethz.ch/pipermail/r-help/2012-June/thread.html
Michael
On Tue, Jun 26, 2012 at 11:57 PM, Erin Hodgess erinm.hodg...@gmail.com wrote:
Hello again:
Here is a solution to the
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