How can one simplify the folowing?
t$aum[is.na(t$aum)] = 0; t$aum.core[is.na(t$aum.core)] = 0
t$num[is.na(t$num)] = 0; t$num.core[is.na(t$num.core)] = 0
Thank you.
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for (i in c('aum', 'num','aum.core','num.core')) t[[i]][is.na(t[[i]])] - 0
On Sat, Jan 30, 2010 at 3:34 PM, Dimitri Shvorob
dimitri.shvo...@gmail.com wrote:
How can one simplify the folowing?
t$aum[is.na(t$aum)] = 0; t$aum.core[is.na(t$aum.core)] = 0
t$num[is.na(t$num)] = 0;
look at plyr package
colwise (column wise) function
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