Hi!
On 08/24/2011 07:46 PM, David Winsemius wrote:
I was looking for an elegant solution ;) In the real case I have double
values and this would be quite inefficient then.
Still no r-code:
Then what about rank(order(...) , further-ties.method-argument) ?
I think that, as order() always
On Aug 29, 2011, at 15:39 , Sebastian Bauer wrote:
rr - data.frame(a = c(1,1,1,1,2), b=c(1,2,2,3,1))
ave(order(rr$a, rr$b), rr$a, rr$b )
[1] 1.0 2.5 2.5 4.0 5.0
Actually, this may be a solution I was looking for! Note that it assumes that
rr to be sorted already (hence the first
Hi!
On 08/24/2011 07:46 PM, David Winsemius wrote:
I was looking for an elegant solution ;) In the real case I have double
values and this would be quite inefficient then.
Still no r-code:
Then what about rank(order(...) , further-ties.method-argument) ?
I think that, as order() always
On Aug 25, 2011, at 7:56 AM, Sebastian Bauer wrote:
Hi!
On 08/24/2011 07:46 PM, David Winsemius wrote:
I was looking for an elegant solution ;) In the real case I have
double
values and this would be quite inefficient then.
Still no r-code:
Then what about rank(order(...) ,
Hello,
I'd like to rank rows of a data frame similar to what rank() does for
vectors. However, ties should be broken by columns that I specify. If it
is not possible to break a ties (because the row data is essentially the
same), I'd like to have the same flexibility that rank() offers. Is
On Aug 24, 2011, at 11:09 AM, Sebastian Bauer wrote:
Hello,
I'd like to rank rows of a data frame similar to what rank() does
for vectors. However, ties should be broken by columns that I
specify. If it is not possible to break a ties (because the row data
is essentially the same), I'd
Hi!
I'd like to rank rows of a data frame similar to what rank() does
for vectors. However, ties should be broken by columns that I
specify. If it is not possible to break a ties (because the row data
is essentially the same), I'd like to have the same flexibility that
rank() offers. Is
On Aug 24, 2011, at 1:11 PM, Sebastian Bauer wrote:
Hi!
I'd like to rank rows of a data frame similar to what rank() does
for vectors. However, ties should be broken by columns that I
specify. If it is not possible to break a ties (because the row data
is essentially the same), I'd like to
Hi!
in R? Basically, what I need is a mixture of order() and rank().
While the former allows to specify multiple vectors, it doesn't
provide the flexibility of rank() such that I can specify what
happens if ties can not be broken.
An example of this simple problem would clarify this greatly.
On Aug 24, 2011, at 1:37 PM, Sebastian Bauer wrote:
Hi!
in R? Basically, what I need is a mixture of order() and rank().
While the former allows to specify multiple vectors, it doesn't
provide the flexibility of rank() such that I can specify what
happens if ties can not be broken.
An
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