[R] I'm sure I'm missing something with formatC() or sprintf()

I have a four-digit string I want to convert to five digits. Take the following frame: zip 2108 60321 60321 22030 91910 I need row 1 to read '02108'. This forum directed me to formatC previously (thanks!) That usually works but, for some reason, it's not in this instance. Neither of the syntaxes

Re: [R] I'm sure I'm missing something with formatC() or sprintf()

Dunlap Spotfire, TIBCO Software wdunlap tibco.com -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of z2.0 Sent: Thursday, February 23, 2012 11:16 AM To: r-help@r-project.org Subject: [R] I'm sure I'm missing something with formatC

Re: [R] I'm sure I'm missing something with formatC() or sprintf()

You said that the values are already character - that's the key. Compare: sprintf(%05s, 2018) [1] 2018 sprintf(%05d, 2018) [1] 02018 Since they are already character, though, here's another option: x - c(2108, 60321, 22030) # part of your data ifelse(nchar(x) == 4, paste(0, x, sep=), x) [1]

Re: [R] I'm sure I'm missing something with formatC() or sprintf()

On 23-Feb-2012 z2.0 wrote: I have a four-digit string I want to convert to five digits. Take the following frame: zip 2108 60321 60321 22030 91910 I need row 1 to read '02108'. This forum directed me to formatC previously (thanks!) That usually works but, for some reason, it's not in