Indeed, as David pointed out, all the portion that used courier font (all the
good stuff) was absent from the email posting.
Thanks for your answers.
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Sorry about the nabble problem. At any rate, do require(Hmisc) then ?label
to see how to associate a vector of labels with all the variables in a data
frame at once.
Frank
do999 wrote:
Indeed, as David pointed out, all the portion that used courier font (all
the good stuff) was absent from
@r-project.org
Subject:
Re: [R] Labelling all variables at once (using Hmisc label)
Message-ID:
1313493727519-3746928.p...@n4.nabble.com
Content-Type:
text/plain; charset=UTF-8
Do
require(Hmisc); ?label to see the help file for label. It will show you
how to
do this:
Monsieur
Do wrote
: 11
Date: Tue, 16 Aug 2011 04:22:07 -0700 (PDT)
From:
Frank Harrell lt;f.harr...@vanderbilt.edugt;
To:
r-help@r-project.org
Subject:
Re: [R] Labelling all variables at once (using Hmisc label)
Message-ID:
1313493727519-3746928.p...@n4.nabble.com
Content-Type:
text/plain; charset=UTF-8
(Warning: data and labels are
not of
same length\n)
return(x)
}
Thanks
Message: 11
Date: Tue, 16 Aug 2011 04:22:07 -0700 (PDT)
From:
Frank Harrell lt;f.harr...@vanderbilt.edugt;
To:
r-help@r-project.org
Subject:
Re: [R] Labelling all variables at once (using Hmisc label)
Message-ID
] Labelling all variables at once (using Hmisc label)
On Aug 17, 2011, at 5:49 PM, Frank Harrell wrote:
I'm puzzled. I provided a solution that did not require looping.
Frank
Hi Frank;
Do you realize that some portions of your Nabble postings are not being
communicated to the ordinary mail
Do require(Hmisc); ?label to see the help file for label. It will show you
how to do this:
Monsieur Do wrote:
The labels can contain much more than just names. In my case, they are
variable descriptions (items from a questionnaire). I need to keep the
names as they are, hence the need for
I have a dataset and a list of labels. I simply want to apply the labels to the
variables, all at once. The only way I was able to do it was using a loop:
for (i in 1:length(data)) label(data[,i]) - data.labels[i]
I'd like to find the non-loop way to do it, using apply or the like... Any
On Mon, Aug 15, 2011 at 3:53 PM, Monsieur Do nonaupourr...@yahoo.ca wrote:
I have a dataset and a list of labels. I simply want to apply the labels to
the variables, all at once. The only way I was able to do it was using a loop:
for (i in 1:length(data)) label(data[,i]) - data.labels[i]
The labels can contain much more than just names. In my case, they are variable
descriptions (items from a questionnaire). I need to keep the names as they
are, hence the need for Hmisc's labels.
On Mon, Aug 15, 2011 at 3:53 PM, Monsieur Do nonaupourr...@yahoo.ca wrote:
I have a dataset and a
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