Dear all,
I'm learning R, with a classical programming background. Some hours were
necessary for me to programm the vector way.
Here is my dataset :
ds - data.frame( st=runif(100), st=runif(100),s1=runif(100),mp=runif(100))
I need to generate 2 new variables. First was easy :
ds$n1 -
Here's one way :
ds - data.frame( st = runif(100), s0=runif(100),
s1=runif(100),s2=runif(100),mp=runif(100))
ds - within( ds, {
n1 - 1*( st0.38 )
n2 - numeric( length( st ) )
n2[ is.na(st) | st = 0.38 ] - .25
n2[ s0 == mp ] - .25
n2[ s2 == mp ]
.
~ John Tukey
-Oorspronkelijk bericht-
Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Namens rafamoral
Verzonden: woensdag 14 januari 2009 23:32
Aan: r-help@r-project.org
Onderwerp: [R] Logical function to turn missing values to 0's
I have a dataset which
I have a dataset which contains some missing values, and I need to replace
them with zeros. I tried using the following:
x - matrix(data=rep(c(1,2,3,NA),6), ncol=6, nrow=6)
y - matrix(data=0, ncol=ncol(x), nrow=nrow(x))
for(i in 1:nrow(x)) {
for(j in 1:ncol(x)) {
y[i,j] - ifelse(x[i,j]==NA,
Hello rafamoral,
Try this:
ifelse(is.na(x),0,x)
On Wed, Jan 14, 2009 at 8:32 PM, rafamoral rafa_moral2...@yahoo.com.br wrote:
I have a dataset which contains some missing values, and I need to replace
them with zeros. I tried using the following:
x - matrix(data=rep(c(1,2,3,NA),6), ncol=6,
Dear rafamoral,
Try this:
x[is.na(x)]-0
HTH,
Jorge
On Wed, Jan 14, 2009 at 5:32 PM, rafamoral rafa_moral2...@yahoo.com.brwrote:
I have a dataset which contains some missing values, and I need to replace
them with zeros. I tried using the following:
x - matrix(data=rep(c(1,2,3,NA),6),
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