Hi
AFAIK, this is issue of the preference of operators.
r-help-boun...@r-project.org napsal dne 16.11.2009 11:24:59:
Hi,
I want to apply ^ operator to a vector but it is applied to some of the
elements correctly and to some others, it generates NaN. Why is it not
able to
calculate
but with complex, I get complex numbers for the first and last elements:
(as.complex(tmp))^(1/3)
[1] 0.01969170+0.03410703i 0.03478442+0.i 0.03285672+0.i
[4] 0.08950802+0.i 0.05848363+0.10129661i
whereas for the first element, we get the followings.
Moreover,
On 16-Nov-09 11:40:29, Petr PIKAL wrote:
Hi
AFAIK, this is issue of the preference of operators.
r-help-boun...@r-project.org napsal dne 16.11.2009 11:24:59:
Not in this case (see below), though of course in general - takes
precedence over ^, so, for example, in the expression
On 11/16/09, Ted Harding ted.hard...@manchester.ac.uk wrote:
Not in this case (see below), though of course in general - takes
precedence over ^, so, for example, in the expression
-2^(1/3)
the - is applied first, giving (-2); and then ^ is applied
next, giving (-2)^(1/3). There is a
Hi,
You forgot to put the parenthesis in the way Petr told you :
(-6.108576e-05)^(1/3) and the result is NaN. What do you want to preserve?
Alain
carol white wrote:
but with complex, I get complex numbers for the first and last elements:
(as.complex(tmp))^(1/3)
[1]
Hi
r-help-boun...@r-project.org napsal dne 16.11.2009 13:27:03:
but with complex, I get complex numbers for the first and last elements:
(as.complex(tmp))^(1/3)
[1] 0.01969170+0.03410703i 0.03478442+0.i 0.03285672+0.i
[4] 0.08950802+0.i 0.05848363+0.10129661i
And
Hi
r-help-boun...@r-project.org napsal dne 16.11.2009 13:55:30:
On 16-Nov-09 11:40:29, Petr PIKAL wrote:
Hi
AFAIK, this is issue of the preference of operators.
r-help-boun...@r-project.org napsal dne 16.11.2009 11:24:59:
Not in this case (see below), though of course in
On 16-Nov-09 13:13:27, Liviu Andronic wrote:
On 11/16/09, Ted Harding ted.hard...@manchester.ac.uk wrote:
Not in this case (see below), though of course in general - takes
precedence over ^, so, for example, in the expression
-2^(1/3)
the - is applied first, giving (-2); and then ^ is
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