You seem to have omitted a left quotation mark in (2): %H:%M:%S.
Regards,
Yihui
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Yihui Xie [EMAIL PROTECTED]
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Seems to work fine for me:
times - c(10:12:34, 14:23:15)
Ptime - as.POSIXct(strptime(times, %H:%M:%S))
Ptime
[1] 2008-10-05 10:12:34 GMT 2008-10-05 14:23:15 GMT
difftime(Ptime[2], Ptime[1], units='min')
Time difference of 250.6833 mins
You just have to be careful that all your times are
Hi
I have two columns of data with time in form of HH:MM:SS - representing
start time and end time of an activity. I am trying to calculate the time
difference (duration of the activity).
(1) I first tried
difftime(btime, etime, units = mins)
This however gave me the error - Error in
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