On 08/23/2018 06:15 PM, Ivan Calandra wrote:
Thanks all for the enlightenment.
So, it does make sense that mean() produces NaN and median()/sd() NA,
from a calculation point of view at least.
But I still think it also makes sense that the mean of NA is NA as well,
be it only for
Thanks all for the enlightenment.
So, it does make sense that mean() produces NaN and median()/sd() NA,
from a calculation point of view at least.
But I still think it also makes sense that the mean of NA is NA as well,
be it only for consistency with other functions. That's just my opinion
I think that one can usefully look at this question from the
point of view of what "NaN" and "NA" are abbreviations for
(at any rate, according to the understanding I have adopted
since many years -- maybe over-simplified).
NaN: Mot a Number
NA: Not Available
So NA is typically used for missing
Hi,
It might even be worthwhile to review this recent thread on R-Devel:
https://stat.ethz.ch/pipermail/r-devel/2018-July/076377.html
which touches upon a subtly related topic vis-a-vis NaN handling.
Regards,
Marc Schwartz
> On Aug 22, 2018, at 10:55 AM, Bert Gunter wrote:
>
> ... And
... And FWIW (not much, I agree), note that if z = numeric(0) and sum(z) =
0, then mean(z) = NaN makes sense, as length(z) = 0, so dividing by 0 gives
NaN. So you can see the sorts of issues you may need to consider.
Bert Gunter
"The trouble with having an open mind is that people keep coming
Actually, the dissonance is a bit more basic.
After xxx(, na.rm=TRUE) with all NA's in ... you have numeric(0). So
what you see is actually:
> z <- numeric(0)
> mean(z)
[1] NaN
> median(z)
[1] NA
> sd(z)
[1] NA
> sum(z)
[1] 0
etc.
I imagine that there may be more of these little
On 22/08/2018 10:33 AM, Ivan Calandra wrote:
Dear useRs,
I have just noticed that when input is only NA with na.rm=TRUE, mean()
results in NaN, whereas median() and sd() produce NA. Shouldn't it all
be the same? I think NA makes more sense than NaN in that case.
The mean can be defined as
Dear useRs,
I have just noticed that when input is only NA with na.rm=TRUE, mean()
results in NaN, whereas median() and sd() produce NA. Shouldn't it all
be the same? I think NA makes more sense than NaN in that case.
x <- c(NA, NA, NA) mean(x, na.rm=TRUE) [1] NaN median(x, na.rm=TRUE) [1]
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