Thank you!
-Original Message-
From: Chel Hee Lee [mailto:chl...@mail.usask.ca]
Sent: Friday, January 23, 2015 8:09 PM
To: Tan, Richard; 'r-help@R-project.org'
Subject: Re: [R] get latest dates for different people in a dataset
do.call(rbind, lapply(split(data, data$Name), function(x
Thank you!
-Original Message-
From: David Barron [mailto:dnbar...@gmail.com]
Sent: Saturday, January 24, 2015 7:56 AM
To: Tan, Richard; r-help@R-project.org
Subject: Re: [R] get latest dates for different people in a dataset
Hi Richard,
You could also do it using the package dplyr
Thank you!
From: William Dunlap [mailto:wdun...@tibco.com]
Sent: Friday, January 23, 2015 7:14 PM
To: Tan, Richard
Cc: r-help@R-project.org
Subject: Re: [R] get latest dates for different people in a dataset
Here is one way. Sort the data.frame, first by Name then break ties with
CheckInDate
On 2015-01-24 01:14, William Dunlap wrote:
Here is one way. Sort the data.frame, first by Name then break ties with
CheckInDate.
Then choose the rows that are the last in a run of identical Name values.
I do it by sorting by the reverse order of CheckinDate (last date first)
within Name,
dLatestVisit - dSorted[!duplicated(dSorted$Name), ]
I guess it is faster, but who knows?
You can find out by making a function that generates datasets of
various sizes and timing the suggested algorithms. E.g.,
makeData -
function(nPatients, aveVisitsPerPatient, uniqueNameDate = TRUE){
See inline;
On 2015-01-25 20:27, William Dunlap wrote:
dLatestVisit - dSorted[!duplicated(dSorted$__Name), ]
I guess it is faster, but who knows?
You can find out by making a function that generates datasets of
various sizes and timing the suggested algorithms. E.g.,
makeData -
Hi Richard,
You could also do it using the package dplyr:
dta - data.frame(Name=c('John','Mary','Sam','John'),
CheckInDate=as.Date(c('1/3/2014','1/3/2014','1/4/2014','1/4/2014'),
format='%d/%m/%Y'),
Temp=c(97,98.1,97.5,99))
Hi,
Can someone help for a R question?
I have a data set like:
NameCheckInDate Temp
John 1/3/2014 97
Mary 1/3/2014 98.1
Sam 1/4/2014 97.5
John 1/4/2014 99
I'd like to return a dataset that for each Name, get the
Here is one way. Sort the data.frame, first by Name then break ties with
CheckInDate.
Then choose the rows that are the last in a run of identical Name values.
txt - NameCheckInDate Temp
+ John 1/3/2014 97
+ Mary 1/3/2014 98.1
+ Sam 1/4/2014
do.call(rbind, lapply(split(data, data$Name), function(x)
x[order(x$CheckInDate),][nrow(x),]))
Name CheckInDate Temp
John John 2014-04-01 99.0
Mary Mary 2014-03-01 98.1
Sam Sam 2014-04-01 97.5
Is this what you are looking for? I hope this helps.
Chel Hee Lee
On 01/23/2015 05:43
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