Hello Everyone,
I was wondering if someone could help me implement a function in R.
I want to pass a vector x to my function, peform some math, then output the
data. However, I want the output for x to be the *name of the vector
I am *using
as input.
For example, data-c(1,5,10)
Hello,
Maybe something like
data-c(1,5,10)
func1-function(x) {
nm - deparse(substitute(x))
y-x^2
z-x^3
out-data.frame(nm,y,z)
return(out)
} #function
func1(data[1])
Hope this helps,
Rui Barradas
Em 14-10-2014 19:12, Evan Kransdorf escreveu:
Hello Everyone,
I was
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On 12/02/13 08:30, Ian Renner wrote:
Hi,
I am trying to write a function which defines some arguments, then uses those
arguments as
arguments of other function calls. It's a bit tricky to explain, so a simple
example will have
to suffice. I
On Tue, Feb 12, 2013 at 7:30 AM, Ian Renner ian_ren...@yahoo.com wrote:
Where I am running into trouble is when I want to call function f1 within
function f2:
f2(x = 3, z = f1(x))
This returns the error:
Error in f1(x) : object 'x' not found
I'm not sure how to define environments
On Tue, Feb 12, 2013 at 09:38:19AM +0100, Rainer M Krug wrote:
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On 12/02/13 08:30, Ian Renner wrote:
Hi,
I am trying to write a function which defines some arguments, then uses
those arguments as
arguments of other function calls. It's
On 13-02-12 5:34 AM, Jan T Kim wrote:
On Tue, Feb 12, 2013 at 09:38:19AM +0100, Rainer M Krug wrote:
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On 12/02/13 08:30, Ian Renner wrote:
Hi,
I am trying to write a function which defines some arguments, then uses those
arguments as
arguments of
...@r-project.org [mailto:r-help-boun...@r-project.org]
Namens Ian Renner
Verzonden: dinsdag 12 februari 2013 8:30
Aan: r-help@r-project.org
Onderwerp: [R] Help with functions as arguments
Hi,
I am trying to write a function which defines some arguments, then uses
those arguments as arguments
On Feb 12, 2013, at 12:38 AM, Rainer M Krug wrote:
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On 12/02/13 08:30, Ian Renner wrote:
Hi,
I am trying to write a function which defines some arguments, then uses
those arguments as
arguments of other function calls. It's a bit tricky
Hi,
I am trying to write a function which defines some arguments, then uses those
arguments as arguments of other function calls. It's a bit tricky to explain,
so a simple example will have to suffice. I imagine this has a simple solution,
but perusing through environments and other help lists
Thanks Baptiste
On Fri, Sep 4, 2009 at 5:13 PM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Hi,
I think you've got a problem with environments,
testA-function(input=1)
{
dat - data.frame(A=seq(input,5), B=seq(6,10))
vec.names- c(a, b)
env - new.env()
Try this variation; might have something to do with scope:
testA-function(input)
{
dat- data.frame(A=seq(input,5), B=seq(6,10))
vec.names- c(a, b)
for(i in 1:ncol(dat))
{
tab- dat[,i]-1
assign(vec.names[i], tab)
}
do.call(rbind,
Hi all,
I have got 2 function (see bellow) which are simplifications of what I need
to do. These functions are precisely the same, except for the last line.
My question is, why doesn't function testA work in the same way as function
testB.
Both functions produce two objects, a and b that
Hi,
I think you've got a problem with environments,
testA-function(input=1)
{
dat - data.frame(A=seq(input,5), B=seq(6,10))
vec.names- c(a, b)
env - new.env()
for(i in 1:ncol(dat))
{
tab- dat[,i]-1
assign(vec.names[i], tab, env=env)
}
Looks like nobody answered so far.
If you want help: It is a good idea to say which package you are talking
about. In a clean R session I get:
specprop
Error: object 'specprop' not found
spec
Error: object 'spec' not found
hence no idea which functions from which package we are talking
I deal with mono-channel breathing signals sampled at 30[Hz] which are
non-linear and non-stationary.
My goal is to classify the signals according to common breathing patterns
Trend remotion is necessary for cluster analysis but quite challenging. In
fact, quasi-periodic patterns that span a
I will try to be clearer with what I wanted.
What I am trying to do is take a list, say defined as res, that has a size of
1000
For example:
res[[1]] res[[2]] .until
res[[1000]]
--
IdX Tick
I say again:
Build a simple example;
--
David Winsemius
On Mar 20, 2009, at 1:00 PM, Altaweel, Mark R. wrote:
I will try to be clearer with what I wanted.
What I am trying to do is take a list, say defined as res, that has
a size of 1000
For example:
res[[1]]
Agreed --- if you provided a working example it might be as simple as,
library(reshape)
recast(res, Id~Tick, fun=mean, id.var=c(Id, Tick),
measure.var=X)
which i had to test with this,
res - list(read.table(textConnection(
IdX Tick
1 2.2 1
2 3.1 1
1 1.2 2
Hi there,
I have a the following function which takes a name(fname), total number of
rows (Total), number of times to make a sample(nSample), number of
records/rows to be included in each sample(nPatient). then it generates
required samples and calculates the mean and standard deviation of the
Hi,
A repeatable example with data would help, as that way we could
see what was happening.
sampling=function(fname,Total,nSample,nPatient){
trans=t(A)
What's A? It isn't one of the arguments to your function.
And what's the transpose of a non-existent thing?
You may well have it in your
It might be your return statement. Look up 'return' in the help file
and you will see that you can only return a single value. If you want
multiple values returned, use a list:
return(listGmean,Gsd))
On Wed, Oct 22, 2008 at 11:53 AM, Alex99 [EMAIL PROTECTED] wrote:
Hi there,
I have a the
Dear Letticia,
Are you using R-help for your homework?
See your previous postings:
1. 15th September:
With a single R command complete the following:
create a vector calles seqvec that repeats the sequence 1, 3,6,
10,15,21.( I was trying to use c() but this does not work)
create a 5-row,
I think this might be what you want:
ex1.fcn-function(x){
h-4/(1+x^2)
return(h)
}
my.pi -
function(sample.size, sim.size, low, hi, func)
{
# create output vector
result - numeric(sample.size)
for (i in seq(sample.size)){ # loop for 'sample.size' times
my.rand.x -
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