My guess is that what you want probably is best done by using ecdf.
You might want to look it up in the docs.
1-ecdf(test)(x)
Will give you the percentage of values in test larger than x.
On 11/1/2010 2:24 AM, Changbin Du wrote:
Thanks Joshua! Yes, i is not going up sequentially by 1, as i
Thanks, Erich!
On Mon, Nov 1, 2010 at 4:55 AM, Erich Neuwirth
erich.neuwi...@univie.ac.atwrote:
My guess is that what you want probably is best done by using ecdf.
You might want to look it up in the docs.
1-ecdf(test)(x)
Will give you the percentage of values in test larger than x.
On
HI, Dear R community,
I have the following codes to calculate the commulative coverage. I want to
save the output in a vector, How to do this?
test-seq(10, 342, by=2)
#cover is a vector
cover_per-function (cover) {
for (i in min(cover):max(cover)) {print(100*sum(ifelse(cover = i, 1,
Hi Changbin,
The yek is that you need to save the results of your for loop rather
than just printing it. It also may be possible to vectorize your for
loop which might simplify things and speed them up, but I did not look
at that. Here is one way to save the results, see inline comments for
On Oct 31, 2010, at 8:35 PM, Changbin Du wrote:
HI, Dear R community,
I have the following codes to calculate the commulative coverage.
Not sure exactly what you mean by this. My guess is implemented below.
I want to
save the output in a vector, How to do this?
test-seq(10, 342, by=2)
On Sun, Oct 31, 2010 at 5:44 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
snip
#cover is a vector
cover_per - function(cover) {
## create a vector to store the results of your for loop
output - vector(numeric, length(min(cover):max(cover)))
for (i in min(cover):max(cover)) {
##
HI, David, Juan, and Joshua,
Thanks so much for your help! The following codes works. Appreciated!
test-seq(10, 342, by=2)
#data is a vector
cover_per-function (data) {
output-vector(numeric,length(min(data):max(data)))
for (i in min(data):max(data)) {
Thanks Joshua! Yes, i is not going up sequentially by 1, as i here is the
raw number of reads for each DNA base. Thanks so much for the great help!
On Sun, Oct 31, 2010 at 6:03 PM, Joshua Wiley jwiley.ps...@gmail.comwrote:
On Sun, Oct 31, 2010 at 5:44 PM, Joshua Wiley jwiley.ps...@gmail.com
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