: Re: [R] integration of two normal density
Your intuition is wrong and R is right.
Why should the product of two probability density functions be a normalized
pdf also?
-- as is trivially seen with two uniforms on [0,2], with pdf= 1/2, product =
1/4 on [0,2] .
-- Bert
-Original Message
Biostatistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of bill.venab...@csiro.au
Sent: Friday, June 25, 2010 10:53 PM
To: carrieands...@gmail.com; R-help@r-project.org
Subject: Re: [R] integration of two normal density
Your
Ph. (410) 502-2619
email: rvarad...@jhmi.edu
- Original Message -
From: Carrie Li carrieands...@gmail.com
Date: Friday, June 25, 2010 11:29 pm
Subject: [R] integration of two normal density
To: r-help R-help@r-project.org
Hello everyone,
I have a question about integration of two
On Fri, 2010-06-25 at 23:28 -0400, Carrie Li wrote:
Hello everyone,
I have a question about integration of two density function
Intuitively, I think the value after integration should be 1, but they are
not. Am I missing something here ?
t=function(y){dnorm(y, mean=3)*dnorm(y/2,
Hello everyone,
I have a question about integration of two density function
Intuitively, I think the value after integration should be 1, but they are
not. Am I missing something here ?
t=function(y){dnorm(y, mean=3)*dnorm(y/2, mean=1.5)}
integrate(t, -Inf, Inf)
0.3568248 with absolute error
-help
Subject: [R] integration of two normal density
Hello everyone,
I have a question about integration of two density function
Intuitively, I think the value after integration should be 1, but they are
not. Am I missing something here ?
t - function(y){dnorm(y, mean=3)*dnorm(y/2, mean=1.5
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