x-c(1,4,9,20,3,7)
i want to get a serie c(5,13,29,23,10).
y - c()
for (i in 2:length(x)){
y[i-1] - x[i-1]+x[i]}
is there more simple way to get?
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On 14-Dec-2013 10:46:10 Ë®¾²Á÷Éî wrote:
x-c(1,4,9,20,3,7)
i want to get a serie c(5,13,29,23,10).
y - c()
for (i in 2:length(x)){
y[i-1] - x[i-1]+x[i]}
is there more simple way to get?
x - c(1,4,9,20,3,7)
N - length(x)
x[1:(N-1)] + x[2:N]
# [1] 5 13 29 23 10
Best wishes,
Hi,
Try:
x[-1]+x[-length(x)]
A.K.
On Saturday, December 14, 2013 5:46 AM, 水静流深 1248283...@qq.com wrote:
x-c(1,4,9,20,3,7)
i want to get a serie c(5,13,29,23,10).
y - c()
for (i in 2:length(x)){
y[i-1] - x[i-1]+x[i]}
is there more simple way to get?
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