Good suggestion, and for my purposes, will solve the problem. Thanks!
On 3/18/2019 12:37 PM, Ben Tupper wrote:
> Hi,
>
> Might you replaced 'T' with a numeric value that signals the TRUE case
> without rumpling your matrix? 0 might be a good choice as it is never an
> index for a 1-based
Hi,
Might you replaced 'T' with a numeric value that signals the TRUE case without
rumpling your matrix? 0 might be a good choice as it is never an index for a
1-based indexing system.
hold=apply(test,1,which.max)
hold[apply(test,1,isUnique)==FALSE] <- 0
hold
[1] 1 2 0
> On Mar 17, 2019,
Solved --
hold=apply(test,1,which.max)
hold[apply(test,1,isUnique)==FALSE] <- 'T'
Now, all I need to do is figure out how to get <- 'T' from turning
everything in the matrix to a string.
On 3/17/2019 8:00 PM, Evan Cooch wrote:
Got relatively close - below:
On 3/17/2019 7:39 PM, Evan
Got relatively close - below:
On 3/17/2019 7:39 PM, Evan Cooch wrote:
Suppose I have the following sort of structure:
test <- matrix(c(2,1,1,2,2,2),3,2,byrow=T)
What I need to be able to do is (i) find the maximum value for each
row, (ii) find the column containing the max, but (iii) if the
Suppose I have the following sort of structure:
test <- matrix(c(2,1,1,2,2,2),3,2,byrow=T)
What I need to be able to do is (i) find the maximum value for each row,
(ii) find the column containing the max, but (iii) if the maximum value
is a tie (in this case, all numbers of the row are the
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