Re: [R] number of items to replace is not a multiple of replacement length

2013-07-26 Thread Pascal Oettli
Hello, Once again, the matrix EWMA has not the correct size. Did you carefully read the answer by Thomas Stewart? https://stat.ethz.ch/pipermail/r-help/attachments/20130724/c454b0f7/attachment.pl Extract of his reply: When you expand the example to 5 stocks, there will be 15 elements (5

[R] number of items to replace is not a multiple of replacement length

2013-07-25 Thread G Girija
Hi All, I have 5 stock values and i am calculating EWMA followed the logic as given ind following link.[ http://www.orecastingfinancialrisk.com/3.htmlhttp://www.forecastingfinancialrisk.com/3.html ] library('tseries') returns[,1]-returns[,1]-mean(returns[,1])

[R] number of items to replace is not a multiple of replacement length

2012-06-29 Thread ascotilla
Hello, I'm a complete newbie to R so sorry if this is too basic..:-S I have to modify some scripts someone else did to make it work with my data. For some reason, one of the scripts which were supposed to work is not, and I get the error message number of items to replace is not a multiple of

Re: [R] number of items to replace is not a multiple of replacement length

2012-06-29 Thread MacQueen, Don
Here is an example to use as a starting point for what that error message means. x - 1:6 x[1:5] - 1:2 Warning message: In x[1:5] - 1:2 : number of items to replace is not a multiple of replacement length The expression x[1:5] - means that we are about to replace the first five elements

Re: [R] number of items to replace is not a multiple of replacement length

2012-06-29 Thread ascotilla
Thanks a lot, I thought I was moving forward because I got a different error, but it seems that I didn't move forward at all..:-S...It was quite basic, right...? That was very helpful, I'll try to sort out the dimensions problem now on my own...I want to fight a bit with it to see if I'm able to

[R] number of items to replace is not a multiple of replacement length

2011-11-18 Thread Gyanendra Pokharel
Hi all, following is my R -code and shows the error given below n - 100 k-2 x1 -c(1, 3);x2 - c(2,5) X - matrix(c(0,0), nrow = 2, ncol = n) for(i in 1:k) + X[i, ] - mh1.epidemic(n,x1[i],x2[i]) Error in X[i, ] - mh1.epidemic(n,x1[i],x2[i]):   number of items to replace is not a multiple of

Re: [R] number of items to replace is not a multiple of replacement length

2011-11-18 Thread Milan Bouchet-Valat
Le vendredi 18 novembre 2011 à 04:45 -0800, Gyanendra Pokharel a écrit : Hi all, following is my R -code and shows the error given below n - 100 k-2 x1 -c(1, 3);x2 - c(2,5) X - matrix(c(0,0), nrow = 2, ncol = n) for(i in 1:k) + X[i, ] - mh1.epidemic(n,x1[i],x2[i]) Error in X[i, ] -

[R] number of items to replace is not a multiple of replacement length

2011-09-28 Thread dunner
Please help with this error message drugbook is an 885 x 32 dataframe names(drugbook) [1] DRUG1 DRUG2 DRUG3 DRUG4 DRUG5 [6] DRUG6 DRUG7 DRUG8 DRUG9 DRUG10 [11] DRUG11 DRUG12 DRUG13 DRUG14 DRUG15 [16] DRUG16 DrugDose1

Re: [R] number of items to replace is not a multiple of replacement length

2011-09-28 Thread Jean V Adams
dunner wrote on 09/28/2011 08:43:32 AM: Please help with this error message drugbook is an 885 x 32 dataframe names(drugbook) [1] DRUG1 DRUG2 DRUG3 DRUG4 DRUG5 [6] DRUG6 DRUG7 DRUG8 DRUG9 DRUG10 [11] DRUG11 DRUG12 DRUG13 DRUG14

[R] number of items to replace is not a multiple of replacement length

2010-11-01 Thread Mipam Bruining
Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or

Re: [R] number of items to replace is not a multiple of replacement length

2010-11-01 Thread Ivan Calandra
Hi, I think you _*should*_ provide more: - the objects you have, such as parameterList and blaah: copy the output from dput(object) in your next e-mail - the _*relevant*_ code for how you've built them I guess you will get more and better answers if you give a clear and complete description

Re: [R] number of items to replace is not a multiple of replacement length

2010-11-01 Thread Mipam Bruining
Hello, here are the results from using dput() on the objects in question. dput(blaah) structure(list(Insert single selection box title here, Insert slider bar title here, SingleSelect, Slider, 1, 50, list(Option a, Option b, Option c), list(0, 100)), .Dim = c(2L, 4L), .Dimnames =

Re: [R] number of items to replace is not a multiple of replacement length

2010-11-01 Thread Mipam Bruining
Hello, I just wanted to say that I just stumbled upon the solution by accident! After your comment on lists I searched for some more information on vectors, lists and matrices. I read that using double ['s instead of singles drops the names of the dimensions used. I then gave

[R] bootstrapping error message Error in t.star[r, ] - statistic(data, i[r, ], ...) : number of items to replace is not a multiple of replacement length

2009-07-08 Thread Karina Boege
Hi, I am trying to run some bootstraps with the boot package. When I run it with 400 replicates it does it ok, but then I need to run the same analysis but with 89, 86, 102 and 106 samples (for four different environments), and then is when I get the error message: mybootstrap -