Hi,
I posted yesterday with a problem in a script. I still have the same problem,
but I think I found a better way to explain my problem.
I have a vector of character strings. Each string is unique, including numbers
and letters. In the real world they represent a list of codes, so each
See this example:
Str - c(345asd, 31qwe, 234tyu, 40kjhg)
grep(^3, Str, value = TRUE)
split(Str, substr(Str, 1, 1))
On Fri, Aug 28, 2009 at 7:29 AM, Carlos Gonzalo Merino Mendez
carlosgmer...@yahoo.com wrote:
Hi,
I posted yesterday with a problem in a script. I still have the same
problem,
Thanks, this what I was looking for.
From: Henrique Dallazuanna www...@gmail.com
Cc: r-help@r-project.org
Sent: Friday, August 28, 2009 1:42:25 PM
Subject: Re: [R] regexp help needed.
See this example:
Str - c(345asd, 31qwe, 234tyu, 40kjhg)
grep(^3, Str
Hello,
I have a vector of dates and I would like to grep the year component
from this vector (= all digits
after the last punctuation character)
dates - c(28.7.08,28.7.2008,28/7/08, 28/7/2008, 28/07/2008,
28-07-2008, 28-07-08)
the resulting vector should look like
08 2008 08 2008 2008 2008 08
Lauri Nikkinen:
Hello,
I have a vector of dates and I would like to grep the year component
from this vector (= all digits
after the last punctuation character)
dates - c(28.7.08,28.7.2008,28/7/08, 28/7/2008, 28/07/2008,
28-07-2008, 28-07-08)
the resulting vector should look like
Lauri Nikkinen wrote:
Hello,
I have a vector of dates and I would like to grep the year component
from this vector (= all digits
after the last punctuation character)
dates - c(28.7.08,28.7.2008,28/7/08, 28/7/2008, 28/07/2008,
28-07-2008, 28-07-08)
the resulting vector should look
On Fri, Nov 28, 2008 at 5:51 AM, Peter Dalgaard
[EMAIL PROTECTED] wrote:
Lauri Nikkinen wrote:
Hello,
I have a vector of dates and I would like to grep the year component
from this vector (= all digits
after the last punctuation character)
dates - c(28.7.08,28.7.2008,28/7/08, 28/7/2008,
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