Re: [R] simple question on data frames assignment

Hello, You're right, sorry, I missed the parenthesis: colordata$response <- (colordata$color == 'blue') + 0 Rui Barradas Quoting Michael Artz : > Fyi, This statement returned the following error   > 'Error in "Yes" + 0 : non-numeric argument to binary

Re: [R] simple question on data frames assignment

Hi > -Original Message- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Michael > Artz > Sent: Friday, April 8, 2016 3:50 AM > To: Hadley Wickham <h.wick...@gmail.com> > Cc: r-help@r-project.org > Subject: Re: [R] simple question on data fra

Re: [R] simple question on data frames assignment

ybe you shall use dput(yourdata) output together with desired result to help us better understand your task. Cheers Petr From: Michael Artz [mailto:michaelea...@gmail.com] Sent: Thursday, April 7, 2016 4:17 PM To: PIKAL Petr <petr.pi...@precheza.cz> Subject: Re: [R] simple question on data

Re: [R] simple question on data frames assignment

Why am I better off with true and false? On Thu, Apr 7, 2016 at 8:41 AM, Hadley Wickham wrote: > == is also vectorised, and you're better off with TRUE and FALSE > rather than 1 and 0, so I'd recommend: > > colordata$response <- colordata$color == 'blue' > > Hadley > > On

Re: [R] simple question on data frames assignment

Fyi, This statement returned the following error 'Error in "Yes" + 0 : non-numeric argument to binary operator' On Thu, Apr 7, 2016 at 8:43 AM, wrote: > Hello, > > Or even simpler, without ifelse, > > colordata$response <- colordata$color == 'blue' + 0 > > Hope this

Re: [R] simple question on data frames assignment

It all makes so much sense now On Thu, Apr 7, 2016 at 10:04 AM, Jeff Newmiller wrote: > lapply(colordata2[ -1 ], f ) > > When you put the parentheses on, you are calling the function yourself > before lapply gets a chance. The error pops up because you are giving a >

Re: [R] simple question on data frames assignment

lapply(colordata2[ -1 ], f ) When you put the parentheses on, you are calling the function yourself before lapply gets a chance. The error pops up because you are giving a vector of numbers (the answer f gave you) to the second argument of lapply instead of a function. -- Sent from my phone.

Re: [R] simple question on data frames assignment

If you are not using an anonymous function and say you had written the function out The below gives me the error > 'f(colordata2$color1)' is not a function, character or symbol' But then how is the anonymous function working? f <- function(col){ ifelse(col == 'blue', 1, 0) } responses <-

Re: [R] simple question on data frames assignment

Hello, Or even simpler, without ifelse, colordata$response <- colordata$color == 'blue' + 0 Hope this helps, Rui Barradas   Citando David Barron : > ifelse is vectorised, so just use that without the loop. > > colordata$response <- ifelse(colordata$color == 'blue', 1, 0)

Re: [R] simple question on data frames assignment

== is also vectorised, and you're better off with TRUE and FALSE rather than 1 and 0, so I'd recommend: colordata$response <- colordata$color == 'blue' Hadley On Thu, Apr 7, 2016 at 6:52 AM, David Barron wrote: > ifelse is vectorised, so just use that without the loop. > >

Re: [R] simple question on data frames assignment

Lapply is not a vectorized function. It is compact to read, but it would not be worth using for this calculation. However, if your data frame had multiple color columns in your data frame that you wanted to make responses for then you might want to use lapply as a more compact version of a

Re: [R] simple question on data frames assignment

Hi > -Original Message- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Michael > Artz > Sent: Thursday, April 7, 2016 1:57 PM > To: David Barron <dnbar...@gmail.com> > Cc: r-help@r-project.org > Subject: Re: [R] simple question on data fra

Re: [R] simple question on data frames assignment

Thaks so much! And how would you incorporate lapply() here? On Thu, Apr 7, 2016 at 6:52 AM, David Barron wrote: > ifelse is vectorised, so just use that without the loop. > > colordata$response <- ifelse(colordata$color == 'blue', 1, 0) > > David > > On 7 April 2016 at

Re: [R] simple question on data frames assignment

ifelse is vectorised, so just use that without the loop. colordata$response <- ifelse(colordata$color == 'blue', 1, 0) David On 7 April 2016 at 12:41, Michael Artz wrote: > Hi I'm not sure how to ask this, but its a very easy question to answer for > an R person. > >

[R] simple question on data frames assignment

Hi I'm not sure how to ask this, but its a very easy question to answer for an R person. What is an easy way to check for a column value and then assigne a new column a value based on that old column value? For example, Im doing colordata <- data.frame(id = c(1,2,3,4,5), color = c("blue",

Re: [R] SIMPLE question

I want to do a boxcox transformation, but I got this: Error: could not find function boxcox What can I do? Well, the recommended 'homework' in the posting guide would be a start. i) ??boxcox, if you have any packages installed that include something with that functionality. ii)

Re: [R] SIMPLE question

Hello, Try the following. install.packages(sos) #if not yet Then, library(sos) findFn(boxcox) There are several hits, maybe you could start with package car Hope this helps, Rui Barradas Em 12-02-2015 16:19, CHIRIBOGA Xavier escreveu: Hi everybody! I want to do a boxcox

Re: [R] SIMPLE question

Hi, Maybe the following link helps. http://r.789695.n4.nabble.com/box-cox-td4363944.html -- View this message in context: http://r.789695.n4.nabble.com/SIMPLE-question-tp4703176p4703180.html Sent from the R help mailing list archive at Nabble.com.

[R] SIMPLE question

Hi everybody! I want to do a boxcox transformation, but I got this: Error: could not find function boxcox What can I do? I am using R studio. Thanks!!! Xavier __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see

[R] simple question - mean of a row of a data.frame

Hi all, Simple question I should know: I'm unclear on the logic of why the sum of a row of a data.frame returns a valid sum but the mean of a row of a data.frame returns NA: sum(rock[2,]) [1] 10901.05 mean(rock[2,],trim=0) [1] NA Warning message: In mean.default(rock[2, ], trim = 0) :

Re: [R] simple question - mean of a row of a data.frame

numeric data frames. HTH, daniel Feladó: R-help [r-help-boun...@r-project.org] ; meghatalmaz#243;: Matthew Keller [mckellerc...@gmail.com] Küldve: 2015. február 11. 23:49 To: r help Tárgy: [R] simple question - mean of a row of a data.frame Hi all, Simple

[R] simple question on loop

Hi R Users. I have a simple question on a loop. The following loop works fine: r_t=list() for(i in 1:500) { r_t[[i]]=h_t_half[[i]]%*%matrix(*z_t_m*[i,]) } But indeed I need also that *z_t_m* varies. Let us suppose that *z_t_m* has 1000 replicates, I have written the following loop that

Re: [R] simple question on loop

Use mapply instead On Fri, Nov 16, 2012 at 5:01 PM, billycorg candi...@gmail.com wrote: Hi R Users. I have a simple question on a loop. The following loop works fine: r_t=list() for(i in 1:500) { r_t[[i]]=h_t_half[[i]]%*%matrix(*z_t_m*[i,]) } But indeed I need also that *z_t_m*

[R] Simple Question

Hi Everyone, I am trying a very simple task to append the Timestamp with a variable name so something like a_2012_09_27_00_12_30 - rnorm(1,2,1). Tried some commands but it doesn't work out well. Hope someone has some answer on it. Session Info R version 2.15.1 (2012-06-22) Platform:

Re: [R] Simple Question

Hi! 28.09.2012 09:13, Bhupendrasinh Thakre wrote: Statement I tried : b - unclass(Sys.time()) b = 1348812597 c_b - rnorm(1,2,1) Do you mean this: --- code --- df-data.frame(x=0,y=0) colnames(df) [1] x y colnames(df)[2]-paste(b,unclass(Sys.time()),sep=_) colnames(df) [1] x

Re: [R] Simple Question

Hello, Try the following: b - unclass(Sys.time()) eval(parse(text=paste(c_,b, - rnorm(1,2,1),sep=))) ls() Regards, Pascal Le 28/09/2012 15:13, Bhupendrasinh Thakre a écrit : Hi Everyone, I am trying a very simple task to append the Timestamp with a variable name so something like

Re: [R] Simple Question

On Sep 27, 2012, at 11:13 PM, Bhupendrasinh Thakre wrote: Hi Everyone, I am trying a very simple task to append the Timestamp with a variable name so something like a_2012_09_27_00_12_30 - rnorm(1,2,1). If you want to assign a value to a character-name you need to use ... `assign`.

Re: [R] Simple Question

Many thanks Dr. Winsemius , Kimmo and Pascal All of them are working and really beautiful... Best Regards, Bhupendrasinh Thakre *Disclaimer :* The information contained in this communication is confidential and may be legally privileged. It is intended solely for the use of the individual

Re: [R] Simple Question

Hi Everyone, Sorry for coming back again with a new problem. Editing question, session info and data so you don't have to scroll till the end of page. *Situation :* I have a data frame and it's name is df. Now I want to add Time Stamp to the end of *name of data Frame i.e. df_system_time*.

Re: [R] Simple Question

Hi Everyone, Sorry for coming back again with a new problem. Editing question, session info and data so you don't have to scroll till the end of page. *Situation :* I have a data frame and it's name is df. Now I want to add Time Stamp to the end of *name of data Frame i.e. df_system_time*.

Re: [R] Simple Question

On 28-09-2012, at 18:40, Bhupendrasinh Thakre vickytha...@gmail.com wrote: Hi Everyone, Sorry for coming back again with a new problem. Editing question, session info and data so you don't have to scroll till the end of page. *Situation :* I have a data frame and it's name is df. Now

Re: [R] Simple Question

Thanks a ton Berend. That worked like a charm.. R comes with thousands of Sweet Surprises everyday Bhupendrasinh Thakre On Sep 28, 2012, at 12:00 PM, Berend Hasselman b...@xs4all.nl wrote: On 28-09-2012, at 18:40, Bhupendrasinh Thakre vickytha...@gmail.com wrote: Hi Everyone,

Re: [R] Simple Question

On Fri, Sep 28, 2012 at 11:15 AM, Bhupendrasinh Thakre vickytha...@gmail.com wrote: Thanks a ton Berend. That worked like a charm.. R comes with thousands of Sweet Surprises everyday -- Not for those who read the docs. :-o -- Bert Bhupendrasinh Thakre On Sep 28, 2012, at 12:00

[R] Simple Question About Exporting Back to Excel

All, Relatively new R user so this is probably an easy question to answer. I am able to generate a cluster for my dataset using hclust() then ploting the data with plot(). This results in an image with a dendrogram with my sample names along the bottom. Great! However, I now need a way to get

Re: [R] Simple Question About Exporting Back to Excel

On Wed, Sep 26, 2012 at 3:11 PM, RCar ryan.carst...@utsouthwestern.eduwrote: All, Relatively new R user so this is probably an easy question to answer. I am able to generate a cluster for my dataset using hclust() then ploting the data with plot(). This results in an image with a dendrogram

Re: [R] Simple Question About Exporting Back to Excel

- project.org] On Behalf Of RCar Sent: Wednesday, September 26, 2012 4:12 PM To: r-help@r-project.org Subject: [R] Simple Question About Exporting Back to Excel All, Relatively new R user so this is probably an easy question to answer. I am able to generate a cluster for my dataset using hclust

Re: [R] Simple Question About Exporting Back to Excel

Hello, In the help page for ?hclust you will see the return values. It has an element order, a vector giving the permutation of the original observations suitable for plotting. From the first example on that page: hc - hclust(dist(USArrests), ave) plot(hc) ix - hc$order

[R] Simple question about formulae in R!?

Good morning reader, I have encountered a, probably, simple issue with respect to the *formulae* of a *regression model* I want to use in my research. I’m researching alliances as part of my study Business Economics (focus Strategy) at the Vrije Universiteit in Amsterdam. In the research model

Re: [R] Simple question about formulae in R!?

10 augustus 2012 9:15 Aan: r-help@r-project.org Onderwerp: [R] Simple question about formulae in R!? Good morning reader, I have encountered a, probably, simple issue with respect to the *formulae* of a *regression model* I want to use in my research. I'm researching alliances as part of my

Re: [R] Simple question about formulae in R!?

. ~ John Tukey -Oorspronkelijk bericht- Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Namens Johan Haasnoot Verzonden: vrijdag 10 augustus 2012 9:15 Aan: r-help@r-project.org Onderwerp: [R] Simple question about formulae in R!? Good morning reader, I have

Re: [R] Simple question about formulae in R!?

Onderwerp: [R] Simple question about formulae in R!? Good morning reader, I have encountered a, probably, simple issue with respect to the *formulae* of a *regression model* I want to use in my research. I'm researching alliances as part of my study Business Economics (focus Strategy

Re: [R] Simple question about formulae in R!?

Aan: r-help@r-project.org Onderwerp: [R] Simple question about formulae in R!? Good morning reader, I have encountered a, probably, simple issue with respect to the *formulae* of a *regression model* I want to use in my research. I'm researching alliances as part of my study Business

Re: [R] Simple question about formulae in R!?

that a reasonable answer can be extracted from a given body of data. ~ John Tukey -Oorspronkelijk bericht- Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org ] Namens Johan Haasnoot Verzonden: vrijdag 10 augustus 2012 9:15 Aan: r-help@r-project.org Onderwerp: [R] Simple question

Re: [R] Simple question about formulae in R!?

R in general tries hard to prohibit this behavior (i.e., including an interaction but not the main effect). When removing a main effect and leaving the interaction, the number of parameters is not reduced by one (as would be expected) but stays the same, at least when using

Re: [R] Simple question about formulae in R!?

Sheesh! Yes. ... and in the case where B is a factor with k levels and x is continuous, the model ~B:x yields k+1 parameters, which in default contrasts would be a constant term, x, and k-1 interactions between x and the corresponding k-1 contrasts(which they aren't really) for B. ~B*x would add

Re: [R] Simple question about formulae in R!?

On Fri, Aug 10, 2012 at 9:16 AM, S Ellison s.elli...@lgcgroup.com wrote: R in general tries hard to prohibit this behavior (i.e., including an interaction but not the main effect). When removing a main effect and leaving the interaction, the number of parameters is not reduced by one (as

Re: [R] Simple question on finding duplicates

-project.org Cc: Sent: Wednesday, July 25, 2012 4:05 PM Subject: [R] Simple question on finding duplicates   I'm  trying  to find duplicate values in a column of a data frame. For   example, dataframe (a) below has two 3's. I would like to mark each value of   each row as either not being

[R] Simple question on finding duplicates

I'm trying to find duplicate values in a column of a data frame. For example, dataframe (a) below has two 3's. I would like to mark each value of each row as either not being a duplicate of the one before (0), or as a duplicate (1) - for example, as in dataframe (b). In SPSS, I

Re: [R] Simple question on finding duplicates

-bounces@r- project.org] On Behalf Of Jeff Sent: Wednesday, July 25, 2012 3:06 PM To: r-help@r-project.org Subject: [R] Simple question on finding duplicates I'm trying to find duplicate values in a column of a data frame. For example, dataframe (a) below has two 3's. I would like

Re: [R] Simple question on finding duplicates

Minor correction: duplicate - ifelse(c(0, a$col[-length(a$col)])==a$col, 1, 0) --- David -Original Message- From: David L Carlson [mailto:dcarl...@tamu.edu] Sent: Wednesday, July 25, 2012 3:23 PM To: 'Jeff'; 'r-help@r-project.org' Subject: RE: [R] Simple question on finding

Re: [R] Simple question on finding duplicates

College Station, TX 77843-4352 -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of Jeff Sent: Wednesday, July 25, 2012 3:06 PM To: r-help@r-project.org Subject: [R] Simple question on finding duplicates I'm trying to find

Re: [R] Simple question on finding duplicates

To: r-help@r-project.org Subject: [R] Simple question on finding duplicates I'm trying to find duplicate values in a column of a data frame. For example, dataframe (a) below has two 3's. I would like to mark each value of each row as either not being a duplicate of the one before (0

Re: [R] Simple question on finding duplicates

duplicate - c(0, diff(a[,col1]) == 0) Peter Ehlers On 2012-07-25 13:05, Jeff wrote: I'm trying to find duplicate values in a column of a data frame. For example, dataframe (a) below has two 3's. I would like to mark each value of each row as either not being a duplicate of the

[R] Simple Question?

Greetings, I am new to R, but trying to put in the time to learn. I have read the R manual and several other introductory texts; however, there is nothing like actually putting it into practice. So here is my problem, and its more of a learning exercise for myself than anything else, but I'm

Re: [R] Simple Question?

?? ggplot did not reorder the columns -- it just plotted them in the order of the levels of factor(chrom), which is exactly what you wanted afaics. There is no need to reorder to do what you want. Comment: ?dput to put reproducible data into an email that people can conveniently copy and paste

Re: [R] Simple Question?

Hello, Try the following. dd - read.table(text= chromlength 1 chr1 249250621 2 chr2 243199373 [... etc ...] 22 chr19 59128983 23 chr22 51304566 24 chr21 48129895 , header=TRUE) str(dd) dd$chrom - as.character(dd$chrom) dd$chrom - sub(chr, , dd$chrom) # This 'chrom' is NOT a

[R] simple question about max(x,y)

x - 3 y - 4 max(x,y) 4 how can i get the greater variable name y thanks -- View this message in context: http://r.789695.n4.nabble.com/simple-question-about-max-x-y-tp4630201.html Sent from the R help mailing list archive at Nabble.com.

Re: [R] simple question about max(x,y)

On May 15, 2012, at 8:42 PM, lapertem4 wrote: x - 3 y - 4 max(x,y) 4 how can i get the greater variable name y Option one: test - function(x,y) { c(x,y)[which.max(c(x,y))]} test(3,4) [1] y test(4,3) [1] x Option two: test - function(x,y) { xn -

[R] Simple question regarding domain restrictions/piecewise functions in R

I am a novice R user. I would like to be able to graph some simple piecewise functions/functions with domain restrictions in R, but I'm having trouble defining such functions. For example, I would like to define the following function: f(x)={x^2 if -1xx; 1 if 2x3} Notably, the function is

Re: [R] Simple question regarding domain restrictions/piecewise functions in R

Does f - function(x){ ifelse((-1 x x 1) | (2 x x 3),x^2,NA) } plot(f,xlim=c(-3,5)) give you what you want? cheers, Rolf Turner On 26/03/12 11:08, chad.mills wrote: I am a novice R user. I would like to be able to graph some simple

Re: [R] Simple question regarding domain restrictions/piecewise functions in R

Yes! Thanks. It was just the NA value instead of the as.null that does the trick. Correct code for the original piecewise I stated (for those who might be looking later) is: f - function(x){ ifelse((-1 x x 1),x^2,ifelse((2xx3),1,NA)) } plot(f,xlim=c(-1,3))

[R] Simple question regarding to specifying model

I have hunted around but cannot find the command which allows me to specify parameters of a model. For example, model.m1 - nls(y ~ alpha * x1/(beta + x1), data = data, start = list(beta = 20, alpha = 120), trace = TRUE) This will estimate the parameters, which allows to investigate the

Re: [R] Simple question regarding to specifying model

On Oct 12, 2011, at 2:25 PM, BvZ wrote: I have hunted around but cannot find the command which allows me to specify parameters of a model. For example, model.m1 - nls(y ~ alpha * x1/(beta + x1), data = data, start = list(beta = 20, alpha = 120), trace = TRUE) This will estimate the

Re: [R] Simple question regarding to specifying model

Tried this, it does not seem to work. It is really simple what I am trying to do. I have a pre-specified best-fit line, and wish to run some diagnostic tests for goodness of fit. I will play around with the predict function, thanks a lot David! -- View this message in context:

Re: [R] Simple question about symbols()

David Winsemius dwinsemius at comcast.net writes: On Apr 19, 2011, at 10:51 PM, murilofm wrote: Thanks for the answer; I see that col=c(blue,red)[inv$c+1] creates a vector of red and blue associated with the binnary c. But still I got everything red. If you want tested

Re: [R] Simple question about symbols()

The link to the csv file is http://www.filedropper.com/data_5 I use the d variable to create the radius: radius - sqrt( inv$d/ pi ) and i tried symbols(inv$a, inv$b, circles=radius, inches=0.35, fg=white, bg=red, xlab=aa, ylab=bb, col=c(blue,red)[inv$c+1]) Thanks for the help. -- View

Re: [R] Simple question about symbols()

On Apr 20, 2011, at 8:45 AM, murilofm wrote: The link to the csv file is http://www.filedropper.com/data_5 I use the d variable to create the radius: radius - sqrt( inv$d/ pi ) and i tried symbols(inv$a, inv$b, circles=radius, inches=0.35, fg=white, bg=red, xlab=aa, ylab=bb,

Re: [R] Simple question about symbols()

Thank you for the answer and sorry about the bad post i'll remember that in the future. By the way, the line code i used to read the data was inv - read.csv(data.csv, header=TRUE, sep=;) I tried before to use the bg, but for some reason it wasn't working out for me. But now i got it. Thanks

[R] Simple question

I am trying to convert a string to a vector, and I'm stuck! Suppose you have a string of numbers (string) that you want to convert to a vector (vec). I am able to split the string turning it into a list by using strsplit, but this makes a list, which I can't seem to access the way that I'd

Re: [R] Simple question

On Apr 19, 2011, at 3:19 PM, Steven Wolf wrote: I am trying to convert a string to a vector, and I'm stuck! Suppose you have a string of numbers (string) that you want to convert to a vector (vec). I am able to split the string turning it into a list by using strsplit, but this makes a

Re: [R] Simple question

On 20/04/11 07:19, Steven Wolf wrote: I am trying to convert a string to a vector, and I'm stuck! Suppose you have a string of numbers (string) that you want to convert to a vector (vec). I am able to split the string turning it into a list by using strsplit, but this makes a list, which I

Re: [R] Simple question

On Apr 19, 2011, at 4:08 PM, Rolf Turner wrote: On 20/04/11 07:19, Steven Wolf wrote: I am trying to convert a string to a vector, and I'm stuck! Suppose you have a string of numbers (string) that you want to convert to a vector (vec). I am able to split the string turning it into a

Re: [R] Simple question

On Apr 19, 2011, at 21:56 , David Winsemius wrote: On Apr 19, 2011, at 3:19 PM, Steven Wolf wrote: I am trying to convert a string to a vector, and I'm stuck! Suppose you have a string of numbers (string) that you want to convert to a vector (vec). I am able to split the string

Re: [R] Simple question

Seconded. Peter Ehlers On 2011-04-19 14:11, Marc Schwartz wrote: On Apr 19, 2011, at 4:08 PM, Rolf Turner wrote: On 20/04/11 07:19, Steven Wolf wrote: [...snip...] It sounds to me like you don't understand lists. If you are going to use R you really should understand them. They are a

[R] Simple question about symbols()

I'm new to R and i'm having some trouble with a bubble chart. Basically I have 3 series (a,b,c), but the third one is a binnary variable (assumes only 0 or 1 to the entire data). How can I use these binnary information to make 2 different colours in a bubble chart?. I.e., I'm using this code:

Re: [R] Simple question about symbols()

murilofm murilofmoraes at gmail.com writes: I'm new to R and i'm having some trouble with a bubble chart. Basically I have 3 series (a,b,c), but the third one is a binnary variable (assumes only 0 or 1 to the entire data). How can I use these binnary information to make 2 different colours

Re: [R] Simple question about symbols()

Thanks for the answer; I see that col=c(blue,red)[inv$c+1] creates a vector of red and blue associated with the binnary c. But still I got everything red. -- View this message in context: http://r.789695.n4.nabble.com/Simple-question-about-symbols-tp3461676p3462013.html Sent from the R help

Re: [R] Simple question about symbols()

On Apr 19, 2011, at 10:51 PM, murilofm wrote: Thanks for the answer; I see that col=c(blue,red)[inv$c+1] creates a vector of red and blue associated with the binnary c. But still I got everything red. If you want tested solution, submit test data. -- View this message in context:

Re: [R] Simple question on eval

Here are two options that might work for you given the little bit you've said: ## If its the same parameter all 30 times ## say, for example, base = 4.5 to log for(i in 1:30) { print(log(1:10, base = 4.5)) } ## if they are different parameters, you could try lapply(X = c(1.3, 3, 2.2, 4, 5),

[R] Simple question on eval

Hi group, I did some searches about this very simple question. Hope someone can help me out. If I have the following: a - x - 2^2 a [1] x - 2^2 How do I evaluate the expression that gets me an answer of 4? I tried the following: eval(a) [1] x - 2^2 get(a) Error in get(a) : object 'x -

Re: [R] Simple question on eval

Hi Kel, Try this: eval(parse(text = a)) x Many times (though certainly not all), it may be easier/cleaner to rethink what you are doing (the step before you get a - x - 2^2) to see if there is a simpler way. Cheers, Josh On Tue, Nov 30, 2010 at 2:24 PM, Lamke lamk...@gmail.com wrote: Hi

[R] Simple question, name of the variable as string.

Dear R users, I have a very simple question and I've tried to search for the answer. (But failed.) there should be a function (func) that work like abc - c(1,2,3,4) func(abc) abc I would like to know the name of that function. Thank you very much for your help. Regards, CH -- CH Chan

Re: [R] Simple question, name of the variable as string.

On Sep 17, 2010, at 2:54 AM, C.H. wrote: Dear R users, I have a very simple question and I've tried to search for the answer. (But failed.) there should be a function (func) that work like abc - c(1,2,3,4) func(abc) abc func - function(xyz) deparse(substitute(xyz)) func(abc) [1] abc

Re: [R] Simple question, name of the variable as string.

On Fri, Sep 17, 2010 at 7:54 AM, C.H. chainsawti...@gmail.com wrote: Dear R users, I have a very simple question and I've tried to search for the answer. (But failed.) there should be a function (func) that work like abc - c(1,2,3,4) func(abc) abc I would like to know the name of that

[R] Simple question regarding name of column headers

names(miceTrainSample) [1] b_double KierA2KierFlex Q_VSA_POS pID50 In the above code, how do I delete pID50 column to store the resulting object without indicating column 5. The code below does the trick, but I wish to delete the column by specifying -pID50 instead of 5.

Re: [R] Simple question regarding name of column headers

Hi Addi, On Fri, Jul 16, 2010 at 3:22 PM, Addi Wei addi...@gmail.com wrote: names(miceTrainSample) [1] b_double  KierA2    KierFlex  Q_VSA_POS pID50 In the above code, how do I delete pID50 column to store the resulting object without indicating column 5.  The code below does the trick, but

Re: [R] Simple question regarding name of column headers

Anyway, I have often wished that something like new.mt.sample - miceTrainSample[, -pID50] would return miceTrainSample without the pID50 column. Here are three alternative ways to do it. # Method 1: Assign NULL to the column new.mt.sample - miceTrainsSample new.mt.sample$pID50 - NULL # Method

Re: [R] Simple question regarding name of column headers

subset(miceTrainSample, select = -plD50) On Fri, Jul 16, 2010 at 11:22 AM, Addi Wei addi...@gmail.com wrote: names(miceTrainSample) [1] b_double  KierA2    KierFlex  Q_VSA_POS pID50 In the above code, how do I delete pID50 column to store the resulting object without indicating column 5.  

Re: [R] Simple question on binning data

On Thu, 2010-05-13 at 17:31 -0400, Carl Witthoft wrote: It's very simple to write a binit() function. If all you want to do is e.g., bin 107 values into sums of 10 at a time, then write a loop that sums x[10*i:11*i-1] (not tested and not syntactically correct). The one I wrote for myself

Re: [R] Simple question on binning data

Wow! This definitely contributed to my evening. If you could indulge, I would like some clarification on this matter of binning and distortion, particularly wrt time series (perhaps related to long-memory processes?). I had thought binning was standard practice in spectral analysis and ANPOW.

Re: [R] Simple question on binning data

On 05/14/2010 07:35 PM, kMan wrote: Wow! This definitely contributed to my evening. If you could indulge, I would like some clarification on this matter of binning and distortion, particularly wrt time series (perhaps related to long-memory processes?). I had thought binning was standard

[R] Simple question on binning data

Hello everyone, I have a data set, and I need to bin my data using a bin width of say g(n). Would anyone be willing to tell me how to do this in R? Thanks -- View this message in context: http://r.789695.n4.nabble.com/Simple-question-on-binning-data-tp2202644p2202644.html Sent from the R help

Re: [R] Simple question on binning data

There would be several people who could help if you gave us a minimal, reproducible example like the posting guide asks for. If you have a vector of continuous data, and need to create a categorical variable (in R, a factor) from that continuous variable, then ?cut can help you.

Re: [R] Simple question on binning data

@r-project.org Subject: Re: [R] Simple question on binning data There would be several people who could help if you gave us a minimal, reproducible example like the posting guide asks for. If you have a vector of continuous data, and need to create a categorical variable (in R, a factor) from

Re: [R] Simple question on binning data

On 14/05/2010, at 9:54 AM, Frank E Harrell Jr wrote: SNIP snip Binning is seldom needed and usually distorts. It is the statistical equivalent of a former governor from Alaska. SNIP I nominate this for a fortune. cheers, Rolf Turner

Re: [R] Simple question on binning data

I second it! Made me lol :) Dennis On Thu, May 13, 2010 at 3:03 PM, Rolf Turner r.tur...@auckland.ac.nzwrote: On 14/05/2010, at 9:54 AM, Frank E Harrell Jr wrote: SNIP snip Binning is seldom needed and usually distorts. It is the statistical equivalent of a former governor from

[R] simple question

Hi All! I know that very primitive question, but that to grant it, that the drawing on the screen divided up onto which part draw for example: layout(matrix(1:4,ncol=2, byrow=T)) plot(x, y, ...) --- 1. screen plot(y, z, ...) --- 2. screen etc... Thank you! [[alternative HTML

[R] simple question

Hi how can I find, in a vector of characters, which is the most frequent one? Thanks Gabriele Zoppoli, MD Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University of Genova, Genova, Italy Guest Researcher, LMP, NCI, NIH, Bethesda MD Work: 301-451-8575 Mobile: 301-204-5642

Re: [R] simple question

Hello, What about test - c(rep(c(A,C,G,T), 20),C) table(test) I am not sure that is an apt representation of the data and problem you are trying to solve. It also occurred to me that each character may not be its own element in the vector. If that is so, you would need to do something a

Re: [R] simple question

Hi Gabriele, This is one way but I'm sure that there is an optimal way of doing so... x - c(A,B,C,C,C,C,C,B,B) name - unique(x) # get unique characters freq - c() for (a in 1:length(name)){ freq[a] - sum(x==name[a])}# get frequency out - cbind(name,freq) Muhammad

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