These are date and times in the format MMDDhhmmss. I would like
to take this column and make a chron object form them. I have tried a
couple of the split family of functions but they need character input
here is the data:
date.time - c(19851001001500, 19851001003000, 19851001004500,
Try this:
strptime(date.time, %Y%m%d%H%M%s)
On Thu, Aug 13, 2009 at 1:59 PM, stephen sefick ssef...@gmail.com wrote:
These are date and times in the format MMDDhhmmss. I would like
to take this column and make a chron object form them. I have tried a
couple of the split family of
I'm not sure that I understand your problem but if you want the vector in
character rather than numeric try:
library(Hmisc)
library(Hmisc)
time.date- Cs(19851001001500, 19851001003000, 19851001004500, 1985100101,
19851001011500, 19851001013000, 19851001014500, 1985100102,
Try this:
as.chron(date.time, %Y%m%d%H%M%S)
On Thu, Aug 13, 2009 at 12:59 PM, stephen sefickssef...@gmail.com wrote:
These are date and times in the format MMDDhhmmss. I would like
to take this column and make a chron object form them. I have tried a
couple of the split family of
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