Hi all,
I have an object that looks (roughly) like the following:
l - list(a = matrix(rnorm(9), 3), b = matrix(rnorm(9), 3), c =
matrix(rnorm(9), 3))
l$a[3,] - sample(c(Message 1, Message 2, Message 3))
l$b[3,] - sample(c(Message 1, Message 2, Message 3))
l$c[3,] - sample(c(Message 1, Message
Try this:
subset(as.data.frame(do.call(rbind, lapply(l, [, , 1))), row3 == Message 1)
On Tue, Aug 23, 2011 at 1:28 PM, Lara Poplarski larapoplar...@gmail.com wrote:
Hi all,
I have an object that looks (roughly) like the following:
l - list(a = matrix(rnorm(9), 3), b = matrix(rnorm(9), 3), c
His is better, but you can also use a for loop...
out-data.frame(rows=1:3)
for(i in 1:3){
if(l[[i]][3]=='Message 1') {
out$V1[i]-l[[i]][1]
} else {
out$V1[i]-NA
}
}
but shouldn't if your list is very long
On Tue, Aug 23, 2011 at 9:35 AM, Henrique Dallazuanna www...@gmail.comwrote:
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