David,I appreciate you suggestion, but it won't work for me. I need to replace
the space for a period at the time the data are read, not afterward. My
variables names have periods I want to keep, if I use your suggestion I will
replace the period inserted when the data are read, as well as the
John,
I like using stringr or stringi for this type of thing. stringi is written in C
and faster so I now typically use it. You can also use base functions. The main
trick is the handy names() function.
example - data.frame(Col 1 A = 1:3, Col 1 B = letters[1:3])
example
Col.1.A Col.1.B
1
You can use gsub() to change the names:
dat - data.frame(Var 1=rnorm(5, 10), Var 2=rnorm(5, 15))
dat
Var.1Var.2
1 9.627122 14.15376
2 10.741617 16.92937
3 8.492926 15.23767
4 12.226146 15.19834
5 8.829982 14.46957
names(dat) - gsub(\\., _, names(dat))
dat
Var_1Var_2
1
Easiest? Use sub() to replace the periods after the fact.
You can also use the check.names or the col.names arguments to
read.table() to customize your import.
Sarah
On Mon, Jun 8, 2015 at 10:15 AM, John Sorkin
jsor...@grecc.umaryland.edu wrote:
I am reading a csv file. The column headers have
Then using Sarah's suggestion something like?
dat - read.table(text=
+ 'Var 1' Var.2
+ 1 6
+ 2 7
+ 3 8
+ 4 9
+ 5 10, header=TRUE, col.names=c(Var_1, Var.2))
dat
Var_1 Var.2
1 1 6
2 2 7
3 3 8
4 4 9
5 510
David C
From: John Sorkin
I've taken the liberty of copying this back to the list, so that others can
participate in or benefit from the discussion.
On Mon, Jun 8, 2015 at 10:49 AM, John Sorkin jsor...@grecc.umaryland.edu
wrote:
Sarah,
I am not sure how I use check.names to replace every space in the names of
my
On 08/06/2015 10:23 AM, Sarah Goslee wrote:
Easiest? Use sub() to replace the periods after the fact.
You can also use the check.names or the col.names arguments to
read.table() to customize your import.
Yes, check.names is the right idea. Use check.names = FALSE, then use
sub() or gsub()
On 08 Jun 2015, at 17:03 , Sarah Goslee sarah.gos...@gmail.com wrote:
I'd import them with check.names=FALSE, then modify them explicitly:
mynames - c(x y, x y, x y, x y)
mynames
[1] x y x y x y x y
mynames - sub( , ., mynames)
mynames
[1] x.y x.y x.y x.y
mynames - paste(mynames,
Sarah,
Many, many thanks.
John
John David Sorkin M.D., Ph.D.
Professor of Medicine
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology and
Geriatric Medicine
Baltimore VA Medical Center
10 North Greene Street
GRECC (BT/18/GR)
mynames
[1] x.y x.y x.y x.y
mynames - paste(mynames, seq_along(mynames), sep=_)
In addition, if there were a variety of names in mynames and you
wanted to number each unique name separately you could use ave():
origNames - c(X, Y, Y, X, Z, X)
ave(origNames, origNames,
10 matches
Mail list logo
