Available free for the typing are the functions for the default and
the dataframe methods of subset:
subset.default
function (x, subset, ...)
{
if (!is.logical(subset))
stop('subset' must be logical)
x[subset !is.na(subset)]
}
subset.data.frame
function (x, subset,
I wrote a dirty hack last time I faced this problem, I'll be curious
to see what is the proper way of dealing with the scoping and
evaluation rules.
library(datasets)
myfunction-function(table, extraction) {
table2-subset(table,extraction)
return(table2)
}
condition1 -
This thread may help?
https://stat.ethz.ch/pipermail/r-help/2007-November/145345.html
On Wed, 17 Dec 2008 20:07:08 +0100, GOUACHE David
d.goua...@arvalisinstitutduvegetal.fr wrote:
Hello R-helpers,
I'm writing a long function in which I manipulate a certain number of
datasets. I want the
On Wed, 17 Dec 2008 20:07:08 +0100, GOUACHE David
d.goua...@arvalisinstitutduvegetal.fr wrote:
argument which I will pass on to subset() somewhere inside my function.
I would use the example of .() function from plyr package in this case:
.-function (...){
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