Hi R users,
I have a dataframe in the below format
xyz 01/03/200715.25USD
xyz 01/04/200715.32USD
xyz 01/02/200823.22USD
abc 01/03/2007
Hi all,
I have a dataset consisting of 5 columns and over 5000 rows. Each row
gives information about an individual animal, including longevity, i.e.
at what age an animal died.
For the model I use I need to create n rows for each animal, n being its
longevity, and a new column 'survival' with a
Good Morning,
I am running R-2.6.1-1.rh5.i386.rpm under RED HAT Enterprise Linux 5, but I get
this message error
/usr/bin/ld/: cannot find -lgfortran when trying installing R CMD INSTALL
ade4_1.4-5.tar.gz.
Please help me to cope with this problem.
Best regards,
Souleymane
Can you please give me some additional informations.
I never created a .bat
I have no experience.
Peter Alspach wrote:
Kia ora unknown requestor
One option is to create a .bat file along the following lines:
path_to_R\bin\R CMD BATCH yourScript.R
Peter Alspach
-Original
On 3/20/2008 12:59 AM, מוטי אסולין wrote:
Hi,
I am a new R user (used SPSS for many years) and I need help.
I have a data frame mydata with 8 variables m2008:m2001
I wanted to add a new variable mydata$firstvalid that tells me what is the
first non missing variable for each case (without
Good Morning,
Please don't post twice!
Please don't post twice!
(The two R-help addresses you used are the same list.)
Did I mention that posting twice is counter-productive?
On Thu, 20 Mar 2008, Ndoye Souleymane wrote:
Good Morning,
I am running R-2.6.1-1.rh5.i386.rpm under RED HAT
On Thu, Mar 20, 2008 at 5:45 AM, [EMAIL PROTECTED] wrote:
Why do you think there is one? kmeans is an agglomerative clustering
algorithm, not a recursively dividing one.
Since there is no clustering hierarchy, so there is no dendrogram.
However, you could create a clustergram:
Is this close to what you want?
x - read.table('clipboard')
x
V1 V2V3 V4
1 xyz 01/03/2007 15.25 USD
2 xyz 01/04/2007 15.32 USD
3 xyz 01/02/2008 23.22 USD
4 abc 01/03/2007 45.20 EUR
5 abc 01/04/2007 45.00 EUR
6 abc 01/02/2008 68.33 EUR
x.m - melt(x)
Using V1, V2, V4 as id
Since you did not provide a sample of your data, here is an example of
how to take a vector and create a matrix with 5 entries for each
value, with the extra ones having a zero in the second column:
x - sample(1:7, 20, T)
table(x)
x
1 2 3 4 5 6 7
2 4 3 2 4 4 1
# create a matrix with 5 rows of
Hi!
I am trying to reorder a dendrogram via reorder.dendrogram. However, I
observed some problems with this, and I will illustrate them with an
example.
Take the following clustering problem:
datamatrix - matrix(c(2,2,2.5,2,1.5,2,2,1.5,2,2.5,
6,2,6.5,2,5.5,2,6,1.5,6,2.5,
Dear R users,
I'm trying since longtime to make an autolaunch of my code, but no results.
I have programmed three codes. And depending on my data(logfile collected
from another source) I have (frequently) to run one of the three codes.
I'm looking for a better solution that run on of the codes
Oups ... sorry, actually I found the problem.
The problem lies not with the reordering but with the construction of
the dendrogram: if a hierarchical method is used, there are never more
than 2 branches for a node. Therefore, the reordering does not give the
expected result. I will have to try
Hi,
I am trying to estimate a VECM without constant using the
following code:
data(finland)
sjf - finland
sjf.reg-ca.jo(sjf, type = c(eigen), ecdet = c(none), K =
2,spec=c(transitory), season = NULL, dumvar = NULL)
cajools(sjf.reg)
While the cointegration test does not use a constant, it is
Hi all,
I have been chipping away at a problem I encountered in calculating
rates per year from a moderately large data file (46412 rows). When I
ran the following command, I got obviously wrong output:
interval-
c(NA,as.numeric(diff(
strptime(mkdf$MEAS_DATE,%d/%m/%Y)))/365.25)
The values
hello
i am trying to decipher a dendrogram i have from performing a 'tree'. (attached
file)
my response variable is factored - low, medium and high threat and the 8
explanatory variables are numeric values.
i could do with some help to understand what the values 0.25, 0.5 and 0.75
are on
Or perhaps:
xtabs(V3 ~ V2 + V4, data=x)
On 20/03/2008, Ravi S. Shankar [EMAIL PROTECTED] wrote:
Hi R users,
I have a dataframe in the below format
xyz 01/03/200715.25USD
xyz 01/04/200715.32USD
Hi,
Given matrix A of 4 cols.
1 a 0 4
1 b 5 8
2 a 0 3
2 b 4 7
I have another matrix B of 3 cols. How to assign (a or b) to the rows such
that in each row its 1st value must match the 1st col. of A, 2nd and 3rd
values must lie between 3rd and 4rd cols (inclusive) of A
1 2 3 - a
2 4 5 - b
2 0 3
Daniel Brewer wrote:
Hello,
I have a series of labels that I want to place on a plot with a log
scale y axis. I want these labels to be equally spaced vertically as
seen on the plot.
I have been trying this:
ylab - 160 - log2(1:length(labels))
but that does not seem to work (where
You are throwing away the clue in your use of as.numeric.
First. strptime returns a POSIXlt value, which you will convert to POSIXct
when you do arithetic (using diff()). Why are you doing that? So
foodate-factor(c(1/7/1991,1/8/1991,1/8/1991,3/8/1991))
diff(strptime(foodate,%d/%m/%Y))
Time
Hello
(Sorry if this appears twice, had some mail problems...)
I have a number of different data sets, each loaded as a matrix. I'd
like to plot them in a way that the data in the first column of each
matrix is plotted on the same pair of axes.
What I'm doing now is to call plot() for the data
Hello,
Perhaps, you should chose another toy example closer to the reality.
Cases with exactly same distance rarely occur in the field. You
should, at least, add some random error:
datamatrix - matrix(c(2,2,2.5,2,1.5,2,2,1.5,2,2.5,
6,2,6.5,2,5.5,2,6,1.5,6,2.5, 4,4,4.5,4,3.5,4,4,3.5,4,4.5) +
There may be a less baroque way of doing it, but does this do what you want?
Say you have a data.frame called dat:
dat
x1 x2 Longevity
1 -1.9582519 a 4
2 0.8724081 b 2
3 -0.9150847 c 5
# now create a new long data.frame:
dat.long -
Ben Bolker bolker at ufl.edu writes:
Jean-Baptiste Ferdy Jean-Baptiste.Ferdy at univ-montp2.fr writes:
Dear R users,
I want to explain binomial data by a serie of fixed effects. My
problem is that my binomial data are spatially correlated. Naively,
I thought I could found
Prof Brian Ripley wrote:
You are throwing away the clue in your use of as.numeric.
First. strptime returns a POSIXlt value, which you will convert to
POSIXct when you do arithetic (using diff()). Why are you doing that? So
foodate-factor(c(1/7/1991,1/8/1991,1/8/1991,3/8/1991))
Hello,
I try to write parts of my code in C to accelerate the for-loops. But
basic operations I want to do in R (e.g. start cluster). My R code looks
something like this:
library(Rmpi)
mpi.spawn.Rslaves()
mpi.remote.exec()
dyn.load(test.so)
erg - .Call(test, )
mpi.close.Rslaves()
Roger Bivand wrote:
Ben Bolker bolker at ufl.edu writes:
Jean-Baptiste Ferdy Jean-Baptiste.Ferdy at univ-montp2.fr writes:
Dear R users,
I want to explain binomial data by a serie of fixed effects. My
problem is that my binomial data are spatially correlated. Naively,
I thought I
On Wed, Mar 19, 2008 at 3:02 PM, Ben Bolker [EMAIL PROTECTED] wrote:
Jean-Baptiste Ferdy Jean-Baptiste.Ferdy at univ-montp2.fr writes:
Dear R users,
I want to explain binomial data by a serie of fixed effects. My problem is
that my binomial data are spatially correlated. Naively,
Emmanuel Levy [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:
Dear David,
Thanks a lot for pointing out kde2d, just tried it out but the
problem is that it indeed takes the density of points into account,
which I dont want.
For example, if in an region of surface S I've got 10,000
Hello everyone,
Many thanks to Terry Therneau for giving me a solution for my previous problem
re coxme function.
Now, I am using a bigger dataset to fit the same model; random treatment effect
nested within centre. I used the command
coxme(Surv(time, status) ~ factor(treat), data=data1,
[EMAIL PROTECTED] wrote:
I'd like to compare length-weight regressions among years. Any information
would be appreciated.
a. gray
fisheries consultant
Your message is rather cryptic for a general statistical audience,
whereas I'm sure in a fisheries group everybody would understand what
dear R-tists,
im an struggling with labeling ticks of the axis in a ggplot.
i would like to print the text associated with the ticks being ploted
with a 90 degree angle.
how can i possibly do this?
cheers.
bernd.
~
Bernd Ebersberger
Management Center
Ravi S. Shankar [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:
Hi R users,
I have a dataframe in the below format
xyz 01/03/200715.25USD
xyz 01/04/200715.32USD
xyz
Hello,
I try to write parts of my code in C to accelerate the for-loops. But
basic operations I want to do in R (e.g. start cluster). My R code looks
something like this:
library(Rmpi)
mpi.spawn.Rslaves()
mpi.remote.exec()
dyn.load(test.so)
erg - .Call(test, )
mpi.close.Rslaves()
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Douglas Bates wrote:
| On Wed, Mar 19, 2008 at 3:02 PM, Ben Bolker [EMAIL PROTECTED] wrote:
| Jean-Baptiste Ferdy Jean-Baptiste.Ferdy at univ-montp2.fr writes:
|
|
| Dear R users,
|
| I want to explain binomial data by a serie of fixed
Relatively new to R, I'm trying to do a relatively simple task. I have
data set that has several variables arranged by SubjID and visit, with
multiple observations for that combination. I do linear regression on
those multiple observations, then generated a set of interpolated values
from the
I want to draw a little subplot (overview) into my detailed plot. It
should be placed in say the top right corner and have the size of some
legend (like legend(x=topright, inset=0.03, ...)
#main plot
plot(rnorm(100))
#give little density in corner
I'm trying to get R, Sweave, ESS and XEmacs or emacs all installed and
working together on my Windows XP Pro system. I've got R 2.6.0 working
just fine, installed from the R Windows installer. I also have
CYGWIN_NT-5.1 with XEmacs 21.4 working okay. Can anyone point me to any
documentation on how
Hi Everyone,
I am trying to do a time series regression using the lm function. However,
according to the durbin watson test the errors are autocorrelated. And then
I tried to use the gls function to accomodate for the autocorrelated errors.
My question is how do I know what ARMA process (order) to
Hi Everyone,
One more information to my question. I am trying to do a time series
regression using the lm function. *My intention is to investigate the
relationship between a dependent time series variable and several
independent time series variables.* According to the durbin watson test the
Hi Kevin,
Go here:
http://vgoulet.act.ulaval.ca/en/ressources/emacs/
and get Vincent Goulet's Emacs for Windows.
Not sure how cygwin enters into the picture; you don't need it for
either R, [X]Emacs, nor ESS. In fact, if you ever plan to build packages
on Windows having cygwin installed can
Kevin,
Save yourself a lot of trouble and use my modified version of GNU
Emacs available from
http://vgoulet.act.ulaval.ca/en/emacs
and also linked from the ESS home page. It comes bundled with ESS and
AUCTeX, so the only other thing you will need to install for the
purposes you
Hi Markus --
Usually comm is an argument with default value in the mpi.* functions,
so implicitly the user is managing these, e.g., by default, using comm
1. Presumably you'll have an R wrapper to .Call that has a default
argument comm=1, and will passs this to the C level.
Martin
Markus
Jim and Vincent, thank you both so much. Vincent, I really appreciate the time
and effort you've put into this project. I was hoping for exactly what you've
provide. Thanks, again.
-Kevin
-Original Message-
From: Vincent Goulet [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 20, 2008
Your entering into a complex danger zone here because you really need to
check first if all the dependent and independent variables are stationary.
Otherwise, your lm results are meaningless ( you're estimation a spurious
regression ). I would look at Bernhard Pfaff's yellow book or any other
bereket weldeslassie wrote:
Hi Everyone,
One more information to my question. I am trying to do a time series
regression using the lm function. *My intention is to investigate the
relationship between a dependent time series variable and several
independent time series variables.* According
Not exactly clear on the transformation that you want to do. In your
example, '1 2 3 - a', where does the '2 3' come from since I don't
see a value of 2 in the 3rd 4th columns. So a better explanation of
what you are trying to do would be help and show where the values came
from in each case.
Use the arima function with the xreg option that is a vector or matrix of
external regressors. Use AIC or BIC when identifying the error process.
Hannu
On Thu, Mar 20, 2008 at 5:54 PM, bereket weldeslassie [EMAIL PROTECTED]
wrote:
Hi Everyone,
One more information to my question. I am trying
Dear all
I use ggplot2 extensively for my plotting routines and rexcel to have the
best of two worlds. (RExcel v 1.75 and R (D)Com v. 2.5)
I can run my ggplot functions, such as qplot(...), in scratchpad mode, but
not in Macro nor Worksheet functions mode.
I have tried the following in Macro
Hi Everyone,
I am trying to do a time series regression using the lm function. However,
according to the durbin watson test the errors are autocorrelated. And then
I tried to use the gls function to accomodate for the autocorrelated errors.
My question is how do I know what ARMA process (order) to
Hi,
I have a question about computing shortest Euclidean distances between
two data frames of spatial points...
I have 2 dataframes (not yet converted to spatial class)
Sewers-data.frame(x=c(10,20,35,50),y=c(100,150,200,300))
transect - data.frame(x=seq(from=0, to=50, by=1),y=seq(from=100,
I don't if is this what you want, but:
plot(rnorm(100))
par(fig=c(0, 1/2, 0, 1/2), new=T)
plot(seq(-2,2,length=300),dnorm(seq(-2,2,length=300)),type=l, axes =
F, xlab=, ylab=)
On 20/03/2008, Thomas Steiner [EMAIL PROTECTED] wrote:
I want to draw a little subplot (overview) into my detailed
perfect, exactly what I was looking for. Thanks a lot!
many eggs to you...
Thomas
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
Does the logLik function applied to a glm and glm.nb (from MASS
package) calculate the complete log-likelihoods, or does it drop the
constant terms of the equation? (Its not clear from the associated help
pages, and Ive found no reference from searching the R help mailing list)
Thank
Dave Depew ddepew at sciborg.uwaterloo.ca writes:
Hi,
I have a question about computing shortest Euclidean distances between
two data frames of spatial points...
I have 2 dataframes (not yet converted to spatial class)
Sewers-data.frame(x=c(10,20,35,50),y=c(100,150,200,300))
I expect that this is the same as FAQ 7.22, though the FAQ should probably be
updated to include ggplot as well as lattice/trellis.
Basically you need to print the graph (in some modes it is automatically
printed, so you see it, in other modes it is not autoprinted, so you see
nothing), just
Look at the subplot function in the TeachingDemos package (the
cnvrt.coords function in the same package can be used to help in finding
coordinates to place the plot).
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801)
Hi all,
This question is not really R related, rather on Statistics subject itself.
Even I did not do those using R. however still I want to post it here, because
my hope is I could get help from great statisticians who are the very active
member of this group.
My problem is to interpret
Hi all,
This question is not really R related, rather on Statistics subject itself.
Even I did not do those using R. however still I want to post it here, because
my hope is I could get help from great statisticians who are the very active
member of this group.
My problem is to interpret
Thank you, it worked perfectly.
Moti
-Original Message-
From: Chuck Cleland [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 20, 2008 10:40 AM
To: מוטי אסולין
Cc: r-help@r-project.org
Subject: Re: [R] basic help
On 3/20/2008 12:59 AM, מוטי אסולין wrote:
Hi,
I am a new R user (used SPSS
Hi,
I want to do some analysis on pcap datasets.. so is there any package which
take cares of that..
If someone has already worked on this, could you give me some tips...
thanks,
Neo23
--
View this message in context:
http://www.nabble.com/analysis-on-Pcap-dataset-tp16187570p16187570.html
Hi, everyone
I want to download a XML webpage and save it as a file in my local machine.
Is there any way to do it in R?
Thanks a lot
Gilbert
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
If you do
help.search(download)
you find
?download.file
G.
On Thu, Mar 20, 2008 at 04:51:22PM -0500, gilbert feng wrote:
Hi, everyone
I want to download a XML webpage and save it as a file in my local machine.
Is there any way to do it in R?
Thanks a lot
Gilbert
Also the XML package for processing the file once retrieved. Martin
Gabor Csardi wrote:
If you do
help.search(download)
you find
?download.file
G.
On Thu, Mar 20, 2008 at 04:51:22PM -0500, gilbert feng wrote:
Hi, everyone
I want to download a XML webpage and save it as a file
Hello
I am trying to import an *.xls spreadsheet into R. I am doing this as
follows:
read.table(file(A5_DL.xls))
But obtain the error:
Error in type.convert(data[[i]], as.is = as.is[i], dec = dec, na.strings
= character(0)) :
invalid multibyte string at '?'
So I copied it all over to
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
And if the Web page requires anything more than basic
access, e.g. if it uses a password or SSL (via https),
you can use RCurl to make more advanced, customizable
HTTP/FTP requests.
~ D.
Gabor Csardi wrote:
| If you do
|
| help.search(download)
|
andy geek_show at dsl.pipex.com writes:
I am trying to import an *.xls spreadsheet into R. I am doing this as
follows:
read.table(file(A5_DL.xls))
So I copied it all over to a text document and tried to import that, thus:
read.table(A5.txt)
The error I got then was:
Error in scan(file,
If you open the spreadsheet in Excel you can then do Save as... and
select type CSV (comma-delimited text). Once you have the data in CSV
format, you can use the R function read.csv to import the data.
Cheers,
Bryan
andy wrote:
Hello
I am trying to import an *.xls spreadsheet into R. I am
Bryan K Woods wrote:
If you open the spreadsheet in Excel you can then do Save as... and
select type CSV (comma-delimited text). Once you have the data in CSV
format, you can use the R function read.csv to import the data.
Cheers,
Bryan
andy wrote:
Hello
I am trying to import an *.xls
Hi R-Help,
Please consider the following simple case: I have a class like
setClass(myClass,
representation(x=matrix, y=character))
and I would like to use the method *[* for a *myClass* objects (but
changing the default *drop* argument from TRUE to FALSE):
setMethod([,myClass,
Hello Everyone,
I am writing programs in R from 7 months and I am able to solve most of the
errors/issues except for this current post.
My Task is to read a Microsoft Excel file(textE_to_affy.csv) which contains
the Microarray Expression Values collected from the Illumina Microarray
Hi Musa --
Musa Parmaksiz wrote:
Hi R-Help,
Please consider the following simple case: I have a class like
setClass(myClass,
representation(x=matrix, y=character))
and I would like to use the method *[* for a *myClass* objects (but
changing the default *drop* argument
This is a Bioconductor package, ask on the Bioc mailing list
http://bioconductor.org
More comments below...
Suprabhath wrote:
Hello Everyone,
I am writing programs in R from 7 months and I am able to solve most of the
errors/issues except for this current post.
My Task is to read a
Second try :P
I have matrix A of 4 cols:
1 a 0 4
1 b 5 8
2 a 0 3
2 b 4 7
And matrix B of 3 cols:
1 2 3
2 4 5
2 0 3
1 7 8
I would like to assign (a or b) to the rows of matrix B. The rules are that
in each row of matrix B, the 1st value must match the 1st col. of matrix A,
2nd and 3rd
Hi Martin,
Thanks for the suggestions.
If possible I would avoid defining several methods with different
signatures. For the first solution,namely
setMethod([,
signature=signature(x=myClass),
function(x, i, j, ..., drop=FALSE)
{
if (missing(i) missing(j))
Hi,
I got some errors when I attempted to build R on my Solaris 9 box. Can someone
please provide some suggestion on what to do next?
The configure process was fine expect that I got a some warning message and a
coredump at the end.
What does that affect? Can I still build it?
./configure
This should do it for you:
A
V1 V2 V3 V4
1 1 a 0 4
2 1 b 5 8
3 2 a 0 3
4 2 b 4 7
B
V1 V2 V3
1 1 2 3
2 2 4 5
3 2 0 3
4 1 7 8
B1 - B # create a copy and add a new column
B1$key -
for (i in seq(nrow(B))){
+ indx - which((B[i,1] == A[,1]) (B[i,2] = A[,3])
Do 'str' on your object and you will see that they are 'factors'. May
have gotten that way when you read them in and there was character
data in the column. To convert it back to numeric, do:
cpx_interp$HR - as.numeric(as.character(cpx_interp$HR))
On Thu, Mar 20, 2008 at 9:26 AM, Beck,
Hello,
Is there a way to easily specify the maximum value to draw a histogram
with the hist function? I have 6 histograms, but each of them is
drawn with a different frequency range (scaling them to the best
visible way), however I need all the histograms to be scaled so that
the maximum
Create an R script,name it Myggplot2 and place it on
your desktop.In excel open the vb editor and write
this code:
Sub Myggplot2()
'start R
Call rinterface.StartRServer
'Put the dataframe into R,assuming that your
'data is in sheet1 cells A1:D1
Call rinterface.PutDataframe(yourdataframename,
Hi,
type ?hist in the R prompt and look for the ylim argument.
Example:
x=rep(1:10,1:10)
hist(x,ylim=c(0,20))
Manipulate the ylim values as needed.
Cheers,
Daniel
-
cuncta stricte discussurus
-
-Ursprüngliche Nachricht-
Von: [EMAIL
If you have fitted a tree model, the diagram (which did not survive the
mailing list, of course) would have been a decision tree, not a
dendrogram.
In a decision tree, the internal nodes refer to decisions to be made as
to whether to proceed to the left or to the right at that stage. This
is
library(MASS)
methods(logLik)
[1] logLik.Arima*logLik.fitdistr* logLik.gam logLik.glm*
[5] logLik.glmmPQL* logLik.lm* logLik.negbin* logLik.nls*
[9] logLik.polr*
Non-visible functions are asterisked
glmgenerates an object of class glm, so tick!
glm.nb
82 matches
Mail list logo
