I think you are looking for this:
x=rnorm(6,10,1)
e=rnorm(6,0,1)
y=x+e
plot(y~x,xlim=c(min(x)-2,max(x)+2),ylim=c(min(y)-2,max(y)+2))
text(x,y,pos=1,labels=c(Prof,CEO,Janitor,Admin,Farmer,Fire
Chief))
HTH,
Daniel
-
cuncta stricte discussurus
-
Richard Liu wrote:
I'm new to R. I'm working with the text mining package tm. I have
several plain text documents in a directory, and I would like to read all
the files with extension .txt in that directory into a vector, one text
document per vector element. That is, v[1] would be the
Thank you! This is what i needed!
I did not realize i could replicate my factor and then tabulate, but it makes
sense!
Thank you once again!
- Original Message
From: William Dunlap wdun...@tibco.com
To: eugen pircalabelu eugen_pircalab...@yahoo.com; r-help@r-project.org
Sent:
Hi all. I'd like to define an object within a function based on an argument
to that function.
Specifically, I've got:
do.something-function(input){
id-substring(input,3,3)
j-list1
if(id==2)j-list2
if(id==3)j-list3
if(id==4)j-list4
...}
Instead of all these if() arguments, I was hoping to use
I'm new to R. I'm working with the text mining package tm. I have several
plain text documents in a directory, and I would like to read all the files
with extension .txt in that directory into a vector, one text document per
vector element. That is, v[1] would be the first document, v[2] the
Hi,
Â
I'm a student in China, and I never used R before.
Â
I'm now wondering how to simulate a sample of Markov chain of ,say 500
entries with a certain transition matrix.Â
Â
Thanks a lot.
___
好ç©è´ºå¡çä½
On 10/13/2009 09:59 AM, AJ83 wrote:
I need to create a function to find all the prime numbers in an array. Can
anyone point me in the right direction?
Thank you.
AJ
There is isprime in package gmp.
data.frame( number = 1:10, is.prime = isprime( 1:10 ) 1,
is.probably.prime = isprime(1:10)
library(gmp)
?isprime
/Gustaf
On Tue, Oct 13, 2009 at 9:59 AM, AJ83 aljense...@gmail.com wrote:
I need to create a function to find all the prime numbers in an array. Can
anyone point me in the right direction?
Thank you.
AJ
--
View this message in context:
Marianne:
I would like to start some R workshops at King's College London, and
to do so, I would like to use the Use R! logo at
http://www.agrocampus-ouest.fr/math/useR-2009//useR%21%202008_fichiers/useR-middle.png
Since it seems to be difficult to get a shell account at KCL, I also went
ahead
Richard Liu wrote:
I'm new to R. I'm working with the text mining package tm. I have several
plain text documents in a directory, and I would like to read all the files
with extension .txt in that directory into a vector, one text document per
vector element. That is, v[1] would be the first
Hi
I tried to do similar thing and did get great answer from Alberto Monteiro
http://tolstoy.newcastle.edu.au/R/e4/help/08/01/0682.html
However I finally managed to do it by slicing space by combination of
image and contour together with putting numbers on contour. Then I used
scizors and
Veerappa Chetty wrote:
Hi,Can I use reorder function with barchart as in dotchart? Here are
some
codes which do not work for me.
.. example remove
As your example is not self-contained (it should be), I cannot show it with
your data.
My preferred way is to reorder outside, because it
I need to create a function to find all the prime numbers in an array. Can
anyone point me in the right direction?
Thank you.
AJ
--
View this message in context:
http://www.nabble.com/Function-to-find-prime-numbers-tp25868633p25868633.html
Sent from the R help mailing list archive at
Dear David,
Thanks again for your input! I realize that I did a bad job of
explaining this in my first email, but the setup is that in Finland
persons who die are sampled with a different probability (1) from
those who live (.5). This was done by the Finnish data protection
authorities to protect
Hi Community R
I need to make a stepwise using F statistics as a criteria to choose
variables.I have 3 independant variables and one dependant variable, and I need
to choose the best model fitting to my data using F statistics. The problem is
I haven't found any package to do such operation.
On Tue, 2009-10-13 at 14:43 +0800, 刘哲 wrote:
Hi,
I'm a student in China, and I never used R before.
I'm now wondering how to simulate a sample of Markov chain of ,say 500
entries with a certain transition matrix.
Thanks a lot.
Hi
Well the naive script for you problem is something
Can anybody help me on how to boxplot multiple groups with different color?
Say, I have 3 groups of data, each group with 2 boxes, and I'd like to have
the following layout in the boxplot:
red, red, green, green, blue, blue
thanks in advance.
--
View this message in context:
Dear All
I was installed GridR package in R. I am trying to execute UCS; it is my
project in client side.
grid.init(service=local,debug=FALSE, localTmpDir=GridRTmp/)
grid.apply(x,UCS, wait=TRUE,,check=TRUE)
But this shows error, that is given below.
*cannot load local function/variable: to
Hallo,
I am trying to plot dates in x-axis. The format of my dates are in dd/mm/.
At first I install zoo package. After R reads my file, I change the default
format of dates to the format that I have,
myfile-read.csv
DATE-as.Date(DATE,format=%d/%m/%Y)
up till now everything goes ok; when
Thanks very much Gabor! Worked like a treat. Good to know that the na's
really mess up the ifelse function.
Thanks again.
Gabor Grothendieck wrote:
The problem is that ifelse does not work the way you might think (see
value section of ?ifelse) and basically should not be used with three
Dear List
I want to plot multiple time series (several outcomes) with dates at intervals
on the x axis and a legend.
Is it possible to use axis.Date to get dates, at intervals in my case, on the
x axis of a (multiple) time series plot.
The axis.Date in the code below doesn't produce any dates
Paul Hiemstra wrote:
file_list = list.files(/where/are/the/files)
obj_list = lapply(file_list, FUN = yourfunction)
yourfunction is probably either read.table or some read function from
the tm package. So obj_list will become a list of either data.frame's or
tm objects.
The
Hello All,
Does anyone know if it is possible to add an additional X-axis data to a
chart?
For example, if I have plotted a bar chart of mean height on the Y-axis and
have male and female on the X-axis. I want to add automatically the number
of samples (N) for males and number of samples for
Hi all,
I was wondering whether it is possible to use the lapply() function
to alter the value of the input, something in the spirit of :
a1-runif(100)
a2-function(i){
a1[i]-a1[i-1]*a1[i];a1[i]
}
a3-lapply(2:100,a2)
Something akin to a for() loop, but using the lapply() infrastructure.
I
Here is a solution using ggplot2
n - 1000
dataset - data.frame(A = rep(1:6, n), B = rep(gl(3, 2), n))
dataset$C - with(dataset, rnorm(n) * as.numeric(B) + A)
library(ggplot2)
dataset$A - factor(dataset$A)
#with default colours
ggplot(dataset, aes(x = A, y = C, colour = B)) + geom_boxplot()
#with
I guess I didn't mention that I'm trying to do this in ggplot2 where I have
my color set up via:
geom_point(aes(colour = Date))
Not sure how to implement your suggestion within the confines of ggplot2.
Jim Lemon-2 wrote:
On 10/10/2009 06:41 PM, Jim Lemon wrote:
Oops, should be:
installing on Ubuntu, how to do it and have people found it to be glitchy?
which is easier , binary install or from source ?
With the source install, are you less likely to have a dependencies issue ?
( Ubuntu does the GCC install seamlessly, but has no mention of R )
I'm sure there's a really cool way to do this with plyr, although I
don't know if my particular plyr version is much better. Anyway here
it is:
cmbine - read.csv(textConnection('names, mass, classes
apple,0.50,1
tiger,100.00,2
pencil,0.01,3
chicken,1.00,2
banana,0.15,1
pear,0.30,1'))
It's not glitchy, and you install it just like any other program. If
you want the latest version you can follow the instructions here:
http://cran.r-project.org/bin/linux/ubuntu/. Otherwise sudo aptitude
install r-base r-base-dev will do the trick.
On Tue, Oct 13, 2009 at 7:46 AM, Robert Wilkins
Normal021falsefalse
false
MicrosoftInternetExplorer4
Dear R-helpers,
I was wondering whether
?mtext should help.
--- On Tue, 10/13/09, spidermonkeydp gbabo...@gmail.com wrote:
From: spidermonkeydp gbabo...@gmail.com
Subject: [R] Adding additional X-axis data to charts, e.g. N values
To: r-help@r-project.org
Received: Tuesday, October 13, 2009, 6:06 AM
Hello All,
Does
Lucas Sevilla García wrote:
Hi Community R
I need to make a stepwise using F statistics as a criteria to choose variables.I have 3 independant variables and one dependant variable, and I need to choose the best model fitting to my data using F statistics. The problem is I haven't found any
*Hi all,
*
*Assume that I have the following data set with tow variables and I want
count the number of observation with identical values
*
**
*x1 x2*
* 1 1 *
* 1 0 *
* 0 1*
* 0 1*
* 0 0*
* 1 1*
* 0 1
*
I want the following output
**
*
*
*n1=3 # number of identical
Try this;
DF - as.data.frame(matrix(rnorm(60), 10))
boxplot(DF, col = rep(seq(ncol(DF)) + 1, each = 2))
On Tue, Oct 13, 2009 at 2:11 AM, kennyPA tao...@yahoo.com wrote:
Can anybody help me on how to boxplot multiple groups with different color?
Say, I have 3 groups of data, each group with 2
On 13 October 2009 at 07:46, Robert Wilkins wrote:
| installing on Ubuntu, how to do it and have people found it to be glitchy?
|
| which is easier , binary install or from source ?
|
| With the source install, are you less likely to have a dependencies issue ?
|
| ( Ubuntu does the GCC
Try this:
table(Reduce(`==`, DF))
On Tue, Oct 13, 2009 at 9:20 AM, Ashta sewa...@gmail.com wrote:
*Hi all,
*
*Assume that I have the following data set with tow variables and I want
count the number of observation with identical values
*
**
*x1 x2*
* 1 1 *
* 1 0 *
* 0 1*
Or try this :
x1=c(1,1,0,0,0,1,0)
x2=c(1,0,1,1,0,1,1)
DF=cbind(x1,x2)
ifelse(DF[,1]==DF[,2],1,0)
your n1 is :
sum(ifelse(DF[,1]==DF[,2],1,0))
your n2 is :
dim(DF)[1]-sum(ifelse(DF[,1]==DF[,2],1,0))
Maybe not an elegant way, but hope this help.
Julien GRASSOT
Data Analysis Department
Flamel
library(Hmisc) spss.get may do it but it's been some time since I used it.
--- On Sat, 10/10/09, Orvalho Augusto orvaq...@gmail.com wrote:
From: Orvalho Augusto orvaq...@gmail.com
Subject: [R] SPSS long variable names
To: r-help@r-project.org
Received: Saturday, October 10, 2009, 12:14 PM
Dear R-users,
I am trying to plot in the same map both NUTS 2 (i.e. regional) and NUTS 3
(i.e. provincial) boundaries for Italy
but I couldn't find how to plot more than one level boundary in the same map.//
//
I have shapefile both for regions and provinces in Italy and I tried to use the
Thank you so much, relist and SIMPLIFY both work.
See more comments below ...
On 10/12/2009 5:35 PM, Charles C. Berry wrote:
On Mon, 12 Oct 2009, Magnus Torfason wrote:
I want to achieve the following:
l - list( list(a=1,b=2), list(a=3,b=4))
l[[]][a] - 5:6
See
?relist
something
oops, library(sos) after install.packages(sos) and before
findFn(mark-recapture) ...
--
View this message in context:
http://www.nabble.com/Introduction-to-mark-recapture-analysis-in-R--tp25871729p25872847.html
Sent from the R help mailing list archive at Nabble.com.
Anne Link wrote:
Normal021falsefalse
false
MicrosoftInternetExplorer4
Dear R-helpers,
Thanks for the answer.
Hmisc uses read.spss from the foreign package. And so it does not
solve my trouble.
I need to read the long names on the SPSS dataset.
Caveman
On Tue, Oct 13, 2009 at 3:01 PM, John Kane jrkrid...@yahoo.ca wrote:
library(Hmisc) spss.get may do it but it's been some time
Dear all
I have used permutational multivariate analysis of variance (adonis in package
vegan) based on Bray-Curtis distances to assess the signifance of carbon,
nitrogen and more complex nutrient amendments on soil microbial community
structure (microbial fatty acids).
I have identified
Josuah Rechtsteiner wrote:
Dear List,
I am trying to connect from R 2.9.2 on Win XP SP3 to a remotely
installed PostgreSQL DB (8.3.7 on Ubuntu Server 9.04). Everything seems
to be properly installed, as I can connect to the DB from within Excel
and RKWard (running on another machine).
But
Perhaps:
Yooze R!
On second thought, probably not quite right for King's College.
Then?
dig R!
--
David
On Oct 9, 2009, at 3:46 PM, Marianne Promberger wrote:
Dear list,
I would like to start some R workshops at King's College London, and
to do so, I would like to use the Use R! logo
On Tue, 13 Oct 2009, AJ83 wrote:
I need to create a function to find all the prime numbers in an array. Can
anyone point me in the right direction?
It depends a bit on how big the numbers are. If the array is large but the numbers are not very large the
fastest approach is probably to
Dear R users,
How do I drop multiplication terms from a formula using update?
e.g.
forml=as.formula(Surv(time, status) ~ x1+x2+A*x3+A*x4+B*x5+strata(sex))
#I would like to drop all instances of variable A (the main effect and its
interactions). The following:
updated.forml=update(forml, ~ . -A)
On Tue, Oct 13, 2009 at 6:57 AM, Ista Zahn istaz...@gmail.com wrote:
I'm sure there's a really cool way to do this with plyr, although I
don't know if my particular plyr version is much better. Anyway here
it is:
cmbine - read.csv(textConnection('names, mass, classes
apple,0.50,1
Well here is one more brain-teaser related to assigning stuff into a
list of list. What if I need to create a new list of empty lists? I have
actually got a solution to this problem:
l = list(list())
for ( i in sequence(length-1) )
{
l = list(unlist(l,recursive=FALSE),
I think there is a much simpler explanation.
The survey design object has eight observations, two per country. With a sample size of two per
country it is hardly surprising that country-specific estimates are not very precise. The actual data has
hundreds of thousands of observations per
Can I use (a) the logo and/or (b) the slogan for the KCL R workshops?
I think it is quite clear from my website that this is neither about
the Springer book series nor about an R user conference.
No, sorry, the logo/name should be used exclusively for the Springer series
and the R User
On 10/13/2009 03:48 PM, Magnus Torfason wrote:
l = list(list())
for ( i in sequence(length-1) )
{
l = list(unlist(l,recursive=FALSE), list())
}
About this :
rep( list(list()), 3 )
[[1]]
list()
[[2]]
list()
[[3]]
list()
Romain
--
Romain Francois
Professional R
Live and learn ...
Thank you!
On 10/13/2009 9:57 AM, Romain Francois wrote:
On 10/13/2009 03:48 PM, Magnus Torfason wrote:
l = list(list())
for ( i in sequence(length-1) )
{
l = list(unlist(l,recursive=FALSE), list())
}
About this :
rep( list(list()), 3 )
[[1]]
Try this:
replicate(3, list())
On Tue, Oct 13, 2009 at 10:48 AM, Magnus Torfason
zulutime@gmail.com wrote:
Well here is one more brain-teaser related to assigning stuff into a list of
list. What if I need to create a new list of empty lists? I have actually
got a solution to this problem:
Hi! All,
I have large correlation matrix Cor. I wish to calculate average
correlation coefficient for this matrix.
Is there any function in R to do this?
Thanks in advance.
Amit
__
R-help@r-project.org mailing list
Hello,
I have several dataframes of identical structure. Each dataframe has one
dependent variable and several independent variables. Two different
functions are used to describe the relationships among all the
dataframes. Some parameters that are to be obtained from regression are
shared by all
bartjoosen wrote:
Hi,
Is it possible to share the code on this list?
I'm also interested (and maybe others to)
Or are you planning to make a package?
Best regards
Bart
Ted.Harding-2 wrote:
On 12-Oct-09 13:33:17, Ted Harding wrote:
On 12-Oct-09 13:24:01, Terry Therneau
Sorry to be so blunt, but I cannot believe PSPP can't save a dataset
as a .csv file for example. That should be the prefered format to
transport a dataset to any other statistical package, including R. csv
files are universal.
Cheers
Joris
On Tue, Oct 13, 2009 at 3:30 PM, Orvalho Augusto
On 10/13/2009 10:13 AM, Amit Kumar wrote:
Hi! All,
I have large correlation matrix Cor. I wish to calculate average
correlation coefficient for this matrix.
Is there any function in R to do this?
Thanks in advance.
cormat - cor(iris[,1:4])
corlowtri - cormat[lower.tri(cormat)]
corlowtri
Thanks guys for the greaty ideia!!
I am fool because I did not realize that before.
Caveman
On Tue, Oct 13, 2009 at 4:41 PM, joris meys jorism...@gmail.com wrote:
Just for clarity : the csv format will solve your problem, as the
restrictions on the variable names will only depend on the
Hi,
Is it possible to share the code on this list?
I'm also interested (and maybe others to)
Or are you planning to make a package?
Best regards
Bart
Ted.Harding-2 wrote:
On 12-Oct-09 13:33:17, Ted Harding wrote:
On 12-Oct-09 13:24:01, Terry Therneau wrote:
-- begin included
- Original Message -
From: Robert Baer rb...@atsu.edu
To: Orvalho Augusto orvaq...@gmail.com
Sent: Tuesday, October 13, 2009 9:52 AM
Subject: Re: [R] SPSS long variable names
I am wondering if there is a patch for the SPSS reading
code on the
foreign package, in order to be able to
On Oct 13, 2009, at 6:07 AM, Laust wrote:
Dear David,
Thanks again for your input! I realize that I did a bad job of
explaining this in my first email, but the setup is that in Finland
persons who die are sampled with a different probability (1) from
those who live (.5). This was done by the
I have 5 datasets. I would like to choose a basis spline with same knots in
GAM function in order to obtain same basis function for 5 datasets.
Moreover, the basis spline is used to for an interaction of two covarites.
The `knots' argument to `gam' allows you to fix the knot locations used
On Tue, Oct 13, 2009 at 2:41 PM, Thomas Lumley tlum...@u.washington.edu wrote:
On Tue, 13 Oct 2009, AJ83 wrote:
I need to create a function to find all the prime numbers in an array. Can
anyone point me in the right direction?
This almost sounds like a homework problem to me... So here's a
On Oct 13, 2009, at 7:33 AM, Kaveh Vakili wrote:
Hi all,
I was wondering whether it is possible to use the lapply() function
to alter the value of the input, something in the spirit of :
a1-runif(100)
a2-function(i){
a1[i]-a1[i-1]*a1[i];a1[i]
}
a3-lapply(2:100,a2)
Neither a1 nor 2:100 are
No!
That is variable labels.
Caveman
On Tue, Oct 13, 2009 at 4:52 PM, Robert Baer rb...@atsu.edu wrote:
I am wondering if there is a patch for the SPSS reading
code on the
foreign package, in order to be able to read long variable
names.
Right now read.spss() just trunc the names to 8
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Ashta
Sent: Tuesday, October 13, 2009 5:20 AM
To: R help
Subject: [R] Counting
*Hi all,
*
*Assume that I have the following data set with tow
variables and I want
Free Introductory R Course Taught Over the Web
The course is designed for natural resource managers and is open to all
who are interested without charge. Audio of the presentations is available
either using your computer speakers and optional microphone or headset or
by calling a phone bridge
Neither a1 nor 2:100 are lists, so it would seem that sapply would be more
appropriate.
The difference between lapply and sapply is the output, not the input.
Hadley
--
http://had.co.nz/
__
R-help@r-project.org mailing list
Sadlly exportation to csv or another format is not implemented yet:
http://www.gnu.org/software/pspp/manual/html_node/Not-Implemented.html
Caveman
On Tue, Oct 13, 2009 at 4:41 PM, joris meys jorism...@gmail.com wrote:
Just for clarity : the csv format will solve your problem, as the
On Oct 13, 2009, at 8:00 AM, Anne-Katrin Link wrote:
I was wondering whether there are any good books and/or
website
links that introduce mark-recapture analysis in R. In particular, I am
interested in exploratory data analysis of resighting data and how to
create capture histories
Dear All,
Maybe it is a silly question. But I wasn't able to find it from manual
or R site search.
I was wondering what is the corresponding time axis for survival
function outputs in survfit. I think it is survfit(...)$time,
but not 100% sure.
If it is, is it possible we could make survival
Orvalho Augusto wrote:
Sadlly exportation to csv or another format is not implemented yet:
http://www.gnu.org/software/pspp/manual/html_node/Not-Implemented.html
Caveman
That would not solve the problem anyway because you would not get labels
and other variable attributes.
Frank
On
R-2.8.0 / tcltk8.5
In windows, Rgui.exe has a directory browser that can be resized, but when I
call
tkchooseDirectory(), it is a fixed size. In linux, when I call
tkchooseDirectory() it
can be resized.
How do I get a windows version that I can resize?
[[alternative HTML version
A million thanks Peter, subsetting fixed it.
George
On Mon, Oct 12, 2009 at 11:51 PM, Peter Ehlers ehl...@ucalgary.ca wrote:
Hi George,
Your problem is not with xyplot, but with the NA occurrences in
your data. Try adding
subset = {!is.na(MSE)},
to your xyplot call, or (better), subset
Dear R developers,How I can build a histogram from matrix:
0 0.5 1
0.25 34 43 65
1 23 35 54
4 22 29 42
10 21 22 29
20 15 17 20
(first string is represented names of columns,
first column is represented names of rows)
where names of columns should be x-axis labels; respectively
to this, I want
How I can obtain graphics for response surface design,
basing on data:
x: 0.25, 1, 4, 10, 20.
y: 0, 0.5, 1
z1 (for y = 0): 45, 35, 25, 15, 10.
z2 (for y = 0.5): 50, 45, 36, 21, 17.
z3 (for y = 1): 37, 34, 22, 17, 11?
z-values should be scaled in colour (e. g. from red to blue).
I consider to use
Hi,
I am a beginner in R. I would like to know if there is any trick in using
survreg with 3-parameter weibull?
I would like to do survival analysis of failure time but not using the
2-parameter weibull which is available as one of the options in the survreg
but instead I would like to see
Hi:
I do not know why the function decostand is not found in my vegan library, I
have downloaded the package recently, and it seems to work well..Do you have
any suggestion?
Rosa.
[[alternative HTML version deleted]]
__
R-help@r-project.org
Another package that is not on CRAN or other R depository is RMark. It
works with the software MARK which does the computation. You can find
RMark at http://www.phidot.org/software/mark/rmark/
and MARK from http://www.phidot.org/software/mark/index.html
From the same site you'll find a very
see
https://stat.ethz.ch/pipermail/r-sig-ecology/2008-May/000160.html
hth,
Kingsford
On Tue, Oct 13, 2009 at 6:00 AM, Anne-Katrin Link anne.l...@gmx.de wrote:
Normal 0 21 false false
false
MicrosoftInternetExplorer4
Dear R-helpers,
I
On Tue, 13 Oct 2009, Kaveh Vakili wrote:
Hi all,
I was wondering whether it is possible to use the lapply() function
to alter the value of the input, something in the spirit of :
a1-runif(100)
a2-function(i){
a1[i]-a1[i-1]*a1[i];a1[i]
}
a3-lapply(2:100,a2)
Something akin to a for() loop,
PDXRugger wrote:
II just want to create a new object with the first two numerals of the
data. Not sure why this isnt working, consider the following:
EmpEst$naics=c(238321, 624410, 484121 ,238911, 81, 531110, 621399,
541613,
524210 ,236115 ,811121 ,236115 ,236115 ,621610 ,814110
Dear R-ers!
I have x as a variable in a data frame x.
x-data.frame(x=c(aa.bb,cc.dd.ee))
x$x-as.character(x$x)
x
I am sorry for such a simple question - but how can I replace all
periods in x$x with spaces?
sub('.', ' ', x$x) - removes all letters to the left of each period...
Thanks a lot for
As you've discovered, the . means something special in regular
expressions (and R's version of them). You need to escape it with \\:
x-data.frame(x=c(aa.bb,cc.dd.ee))
x$x-as.character(x$x)
x
x
1aa.bb
2 cc.dd.ee
sub(\\., , x$x)
[1] aa bbcc dd.ee
gsub(\\., , x$x)
[1] aa bb
You need escape the period:
gsub(\\., , x$x)
On Tue, Oct 13, 2009 at 2:26 PM, Dimitri Liakhovitski ld7...@gmail.com wrote:
Dear R-ers!
I have x as a variable in a data frame x.
x-data.frame(x=c(aa.bb,cc.dd.ee))
x$x-as.character(x$x)
x
I am sorry for such a simple question - but how can
Thanks a lot for your help, Henrique and Sarah!
Dimitri
On Tue, Oct 13, 2009 at 1:37 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
As you've discovered, the . means something special in regular
expressions (and R's version of them). You need to escape it with \\:
Hi Rosa,
It works for me on an R-fresh session:
require(vegan)
Loading required package: vegan
This is vegan 1.15-4
?decostand
sessionInfo()
R version 2.9.2 RC (2009-08-23 r49375)
i386-pc-mingw32
locale:
LC_COLLATE=English_United States.1252;LC_CTYPE=English_United
Thanks, Chuck's answer is the closest to what i want (gives the same result as
cumprod()) ...but using this function seems actually slower than the loop (is
it normal ?):
a1-runif(10)
cadd-function(x) Reduce(*, x, accumulate = TRUE)
looop-function(a1){
j-length(a1)
for(i in 2:j){
Hi,
I'm trying to model an ARMA(1,[1,4]),
i.e. I want only lags 1 and 4 of the Moving Average part.
It's the '[1,4]' part that is giving me a problem.
I've tried different arma's and arima's in different packages, namely:
packages tseries, fArma, FinTS, timeSeries, TSA, Zelig, ds1, forecast
On 10/13/2009 2:35 PM, Len Vir wrote:
Hi,
I'm trying to model an ARMA(1,[1,4]),
i.e. I want only lags 1 and 4 of the Moving Average part.
It's the '[1,4]' part that is giving me a problem.
I've tried different arma's and arima's in different packages, namely:
packages tseries, fArma, FinTS,
Here is one more that works:
gsub(., ,Start.Time, fixed = TRUE)
fixed = TRUE really helps in a lot of instances for removing specific
characters without accidently angering the regular expression gods.
Enjoy.
--- On Tue, 10/13/09, Dimitri Liakhovitski ld7...@gmail.com wrote:
From:
On Oct 13, 2009, at 12:03 PM, Muhtar Osman wrote:
Dear All,
Maybe it is a silly question. But I wasn't able to find it from manual
or R site search.
After library(survival) , the description of survfit objects will be
found with:
?survfit.object
I was wondering what is the
I'm trying to categorize a continuous variable (yes, I know that's horrible,
but I'm trying to reproduce some exercises from a textbook) and don't really
know an efficient way to do this.
I have a data frame that looks like:
surv_time relapse sex log_WBC rx
1 35 0 11.45
Dear Patrick,
Take a look at ?cut for some ideas.
HTH,
Jorge
On Tue, Oct 13, 2009 at 3:37 PM, Richardson, Patrick wrote:
I'm trying to categorize a continuous variable (yes, I know that's
horrible, but I'm trying to reproduce some exercises from a textbook) and
don't really know an
Try this:
with(anderson, cut(log_WBC, c(0, 2.3, 3, max(log_WBC)), labels =
c('low', 'medium', 'high')))
On Tue, Oct 13, 2009 at 4:37 PM, Richardson, Patrick
patrick.richard...@vai.org wrote:
I'm trying to categorize a continuous variable (yes, I know that's horrible,
but I'm trying to
On Mon, 2009-10-12 at 22:20 -0400, David Winsemius wrote:
On Oct 12, 2009, at 8:20 PM, Jason Gasper wrote:
snip /
# contour examples vis.gam(g,
view=c(x1,x2),plot.type=contour,color=heat, nlevels=20)
Warning messages:
1: In plot.window(...) : nlevels is not a graphical parameter
2: In
On Tue, 2009-10-13 at 17:06 +0200, Rosa Manrique wrote:
Hi:
I do not know why the function decostand is not found in my vegan
library, I have downloaded the package recently, and it seems to work
well..Do you have any suggestion?
Did you load it in your session for use?
Try
library(vegan)
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