sdlywjl666 wrote:
> Dear all,
> I would like to know whether positive or negative values of the phase
> spectrum indicate that the time series leads or lags.
> In my work, x and y have peak nearly at the same
> frequency,(eg:f=1/56);and the coherency is peak where f=1/56,the phase is 0.5
>
On Mon, 23 Nov 2009 14:03:11 -0700 Greg Snow
wrote:
> If you need a function to reproducibly generate predictions, then
> use loess to generate a set of predictions for a reasonably dense set
> of x-values, then use approxfun or splinefun to create a function to
> interpolate for you. Then th
Peter Dalgaard wrote:
sdlywjl666 wrote:
Dear all,
I would like to know whether positive or negative values of the phase spectrum indicate that the time series leads or lags.
In my work, x and y have peak nearly at the same frequency,(eg:f=1/56);and
the coherency is peak where f=1/56,the ph
On Mon, 23 Nov 2009 12:21:03 -0500 David Winsemius
wrote:
> > I would be happy with a simple one, that just mapped negative values
> > to water colours and positive values to land colours.
>
> Searching with the strategy "color positive negative zero" in r-search
> and limiting it to r-help
On Tue, 24 Nov 2009, David Scott wrote:
Peter Dalgaard wrote:
sdlywjl666 wrote:
Dear all, I would like to know whether positive or negative values of the
phase spectrum indicate that the time series leads or lags.
In my work, x and y have peak nearly at the same
frequency,(eg:f=1/56);and
-- Forwarded message --
From: kumar kk
Date: Tue, Nov 24, 2009 at 2:29 PM
Subject: R- bioconductor -- help
To: r-help-boun...@r-project.org
How can we analyse text file using bioconductor(R).
How can we import text file for analysis.
Thanks
[[alternative HTML version de
On Tue, Nov 24, 2009 at 8:42 AM, Karl Ove Hufthammer wrote:
> On Mon, 23 Nov 2009 12:21:03 -0500 David Winsemius
> wrote:
>> > I would be happy with a simple one, that just mapped negative values
>> > to water colours and positive values to land colours.
>>
>> Searching with the strategy "color p
On 11/24/2009 07:42 PM, Karl Ove Hufthammer wrote:
On Mon, 23 Nov 2009 12:21:03 -0500 David Winsemius
wrote:
I would be happy with a simple one, that just mapped negative values
to water colours and positive values to land colours.
Searching with the strategy "color positive negat
ychu066 wrote:
anyone know how to add text in the Trellis plot panel ?? i want to add things
eg: dot dot dot. in the headrer of the panel.
eg: http://old.nabble.com/file/p26486579/hist1.png hist1.png
see panel.text()
cheers,
Paul
--
Drs. Paul Hiemstra
Department of Physical Geography
Fac
Gary wrote:
Hi R Users,
I'm interested in plotting a grouped boxplot (please see attached file for
sample). Can anyone suggest a function{package} which can help me achieve
this.
Your attachment did not pass the list's filters. Anyway, see ?boxplot.
Uwe Ligges
Thanks,
Gary
---
kumar kk wrote:
-- Forwarded message --
From: kumar kk
Date: Tue, Nov 24, 2009 at 2:29 PM
Subject: R- bioconductor -- help
To: r-help-boun...@r-project.org
How can we analyse text file using bioconductor(R).
How can we import text file for analysis.
You may want to ask a qu
Readers,
Scenario: data x consists of one column;
1
2
3
data y;
4
5
6
Is it possible to write to file such that the file is:
1,4
2,5
3,6
using the write.file function? I have tried the command:
write(x,file="file.csv",ncolumns=1,append=TRUE,sep=",")
write(y,file="file.csv",ncolumns=1,append=TR
On Tue, Nov 24, 2009 at 10:02 AM, Fredrik Johansson wrote:
> I have an issue when making a wireframe plot. I can't find any way to
> change the number of ticks on the labels. I try to set it in the code
> below with z.ticks=1, but that doesn't work. Is there anything that
> works? (Note. I need to
Hi
try ggplot2. It has some functionality to make groups of boxplots.
Regards
Petr
r-help-boun...@r-project.org napsal dne 24.11.2009 03:33:49:
> Hi R Users,
>
> I'm interested in plotting a grouped boxplot (please see attached file
for
> sample). Can anyone suggest a function{package} which
Hi there,
I have a set of data that looks like this:
As1988<-c(1254.0, 22.0, 4.2, 1081.0, 35.0, 6.0, 1772.0, 192.0, 7.6)
The mean of this (as calculated by R) is: 485.9778
The median of this (as calculated by R) is: 35
If I then make a beanplot(As1988), I find that the beanline (average)
Jens,
2009/11/23 koj :
> library(xlsReadWrite)
> Everything is fine, but the format of the export is not the best. For
> example, I every time have to adjust the column width. Furthermore there is
> no possibility to highlight some cell or make them colourful.
Auto-col is supported by the underly
Great, that's it! Thanks a lot! I didn't find that.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contai
Hi!
Unfortunately the version loaded on the office server is 2.6.0 (for some
undisclosed so called policy decision by my adamant IT dept. who are not
willing to upgrade), I need to use YieldCurve package compatible with this
version. On my standalone machine I have R 2.9 loaded and hence I have
You can not append a column. Best bet, read the old file in, do a
'cbind', write the object back out.
On Tue, Nov 24, 2009 at 5:59 AM, e-letter wrote:
> Readers,
>
> Scenario: data x consists of one column;
> 1
> 2
> 3
>
> data y;
> 4
> 5
> 6
>
> Is it possible to write to file such that the fil
Julia Cains wrote:
Hi!
Unfortunately the version loaded on the office server is 2.6.0 (for some
undisclosed so called policy decision by my adamant IT dept. who are not
willing to upgrade), I need to use YieldCurve package compatible with this
version. On my standalone machine I have R 2.9
On 24/11/2009, jim holtman wrote:
> You can not append a column. Best bet, read the old file in, do a
> 'cbind', write the object back out.
>
> On Tue, Nov 24, 2009 at 5:59 AM, e-letter wrote:
>> Readers,
>>
>> Scenario: data x consists of one column;
>> 1
>> 2
>> 3
>>
>> data y;
>> 4
>> 5
>> 6
Dear Uwe Ligges,
Sir, I am extremely sorry for not mentioning about the windows environment. I
am new to R and trying to learn R besides having to attend my regular
commitments. Thanks a lot for your guidance again Sir.
Regards
Julia
Only
Here is the way to get the required output:
> x <- data.frame(a=1:3)
> write.csv(x, file='tempxx.csv', row.names=FALSE)
> # new data
> newData <- data.frame(b=4:6)
> # read old data back in
> oldData <- read.csv('tempxx.csv')
> # cbind the new data
> write.csv(cbind(oldData, newData), file='tempxx
Hi all,
Does any of you know how to make a decision tree when the data set contains
factors and numericals?
I've got a data frame with 3 columns, where y and x1 are numerical and x2
contains factors. Is it possible to use the rpart package, and in that case
how? Otherwise, is there another
Hi all,
Anyone experienced in the LaTeX format?
I'm trying to use the xtable package to create nice anova tables, but how do I
do to produce a pdf from the resulting LaTeX table? I've tried WinShell and
MiKTeX, but I couldn't get any of them working...
Here's an example of the output
On Nov 24, 2009, at 8:50 AM, Joel Fürstenberg-Hägg wrote:
Does any of you know how to make a decision tree when the data set
contains factors and numericals?
I've got a data frame with 3 columns, where y and x1 are numerical
and x2 contains factors. Is it possible to use the rpart package
Joel Fürstenberg-Hägg wrote:
Hi all,
Anyone experienced in the LaTeX format?
I'm trying to use the xtable package to create nice anova tables, but how do I
do to produce a pdf from the resulting LaTeX table? I've tried WinShell and
MiKTeX, but I couldn't get any of them working...
Hi Joel,
that's a LaTeX issue you have there, nothing wrong with R.
You should post your message on a LaTeX Forum about how to use LaTeX.
http://www.latex-community.org/
Regards
Benoit
-Message d'origine-
De : r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] De
l
Joel,
You should consider using Sweave:
http://www.stat.umn.edu/~charlie/Sweave/ -or-
http://en.wikipedia.org/wiki/Sweave
Regards,
Tom
Joel Fürstenberg-Hägg wrote:
Hi all,
Anyone experienced in the LaTeX format?
I'm trying to use the xtable package to create nice anova tables, bu
2009/11/24 Joel Fürstenberg-Hägg
>
> Hi all,
>
>
>
> Anyone experienced in the LaTeX format?
>
>
>
> I'm trying to use the xtable package to create nice anova tables, but how
> do I do to produce a pdf from the resulting LaTeX table? I've tried WinShell
> and MiKTeX, but I couldn't get any of the
The new version 2.2 of our distr-family of packages has now been
available on CRAN for several days. As there were many changes we will
only sketch the most important ones here. For more details see the
corresponding NEWS files (e.g. news(package = "distr") or using function
NEWS from package s
You could try adapt this code:
yy <- c(rnorm(20,2),rnorm(35,3),
rnorm(30,2),rnorm(20,3),rnorm(4,2),rnorm(10,3))
xx <- c(1:20,1:35,1:30,1:20,1:4,1:10)
gg <- rep(c('A','B','A','B','A','B'), c(20,35,30,20,4,10))
pp <- rep(c('Cond 1','Cond 2','Cond 3'), c(55, 50, 14))
#pdf("teste.pdf")
xyplot(yy ~ x
I put that before selection but Nothing happened...I don´t know because when
I executed the code, in the console doesn´t show cat("1-24hours)...and
neither asked me Select numers of hours from de line or readline...
Peter Dalgaard wrote:
>
> yonosoyelmejor wrote:
>> Hello, I would like to ask yo
Hello, i would like to ask you another question. Is exist anymethod to
vectors that tells me the last element?That is to say,I have a vector, I
want to return the position of last element. I hope having explained.
A greeting,
Ignacio.
--
View this message in context:
http://old.nabble.com/Metho
Hello
On 11/24/09, Joel Fürstenberg-Hägg wrote:
> I'm trying to use the xtable package to create nice anova tables, but how do
> I do to produce a pdf from the resulting LaTeX table? I've tried WinShell and
> MiKTeX, but I couldn't get any of them working...
>
Take a look at the documentation
Hi,
The log of the mean is not the same as the mean of the logs, that's a
no-brainer. Guess you use the beanplot from the package with the same
name.
> beanplot(As1988,log="")
gives the correct plot.
Next time, could you provide a minimal code example we can run
ourselves? If we don't know what
yonosoyelmejor escribió:
Hello, i would like to ask you another question. Is exist anymethod to
vectors that tells me the last element?That is to say,I have a vector, I
want to return the position of last element. I hope having explained.
A greeting,
Ignacio.
vect1 <- c(1,2,3)
vect1[length(v
It isn't entirely clear what you want. Maybe one of these?
x <- runif(45) # make a test vector
length(x) # position of the last element
x[length(x)] # value of the last element
Sarah
On Tue, Nov 24, 2009 at 5:18 AM, yonosoyelmejor
wrote:
>
> Hello, i would like to ask you another
As a general observation, few, if any, statistical packages, generate
tables in the format what you might think you need or want. R is not an
exception. Then it is better to transfer the table to a spreadsheet,
shift things around, add headers, etc.. The R2HTML library is useful
for that ope
2009/11/24 Tom Backer Johnsen :
> As a general observation, few, if any, statistical packages, generate tables
> in the format what you might think you need or want. R is not an exception.
I actually find that Hmisc::latex generates tables pretty much exactly
as I want them. For me, this is one o
Hi all,
I've tried to make a decision tree for the following data set:
Level X Response
279 C 2.4728646 -9.445
341 B 0.5986398 -9.413
343 B 1.1786271 -9.413
384 D 1.4797870 -9.413
390 C 2.0364569 -9.133
391 D 0.93657
On Nov 24, 2009, at 10:20 AM, Keo Ormsby wrote:
yonosoyelmejor escribió:
Hello, i would like to ask you another question. Is exist anymethod
to
vectors that tells me the last element?That is to say,I have a
vector, I
want to return the position of last element. I hope having explained.
A
While what you say is true for base R, someone already mentioned Hmisc's latex
function, and I have written several custom functions to output tables in
LaTeX, the benefit being the elimination of manual formatting and intervention
when preparing tables. Add this in with Sweave and make files,
On Tue, 24 Nov 2009 10:14:18 -0500 Sarah Goslee
wrote:
> x <- runif(45) # make a test vector
> length(x) # position of the last element
> x[length(x)] # value of the last element
For the last one, this should be even better: tail(x, 1)
But, actually benchmarking this, it turns out
myVector <- c(seq(10),23,35)
length(myVector)
myVector[length(myVector)]
it's unclear to me which of the two you want ...
HTH, Joh
yonosoyelmejor wrote:
>
> Hello, i would like to ask you another question. Is exist anymethod to
> vectors that tells me the last element?That is to say,I have a v
Dear R gurus and users,
I seem to have problem finding the right tool for plotting convex hulls over
2D plots, after a cluster analysis. In fact I would like to draw a convex hull
in 2D for a generic group of points. I found a "convhulln", but this doesn't
seem
to give me a convex hull. Here is wh
I can't reproduce the error you have. With me, it runs all fine. In
fact, readline apparently flushes automatically, as I didn't have to
use the flush.console() at all.
test.r
---
cat("1- 24horas\n")
cat("2- 12horas\n")
cat("3- 8horas\n")
selection<-readline(prompt="\nSelecciona numero de h
If had done a little searching before posting, you surely would have found
this link
https://stat.ethz.ch/pipermail/r-help/2008-July/169149.html
which describes how to create .xls files that are customized any way that
you desire.
Kevin Wright
On Mon, Nov 23, 2009 at 7:02 AM, koj wrote:
>
> De
Thx Chris, extending the margins worked like a charm. It would be nice
though if the plot function would take the length of the labels into
account as well, but I guess I'm just being too much of a spoiled kid
here ;-)
Cheers
Joris
On Thu, Nov 19, 2009 at 6:46 AM, Chris Campbell wrote:
> On Mon,
Try this:
plot(Y)
polygon(Y[chull(Y),])
On Tue, Nov 24, 2009 at 1:58 PM, wrote:
> Dear R gurus and users,
> I seem to have problem finding the right tool for plotting convex hulls over
> 2D plots, after a cluster analysis. In fact I would like to draw a convex hull
> in 2D for a generic group
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Karl Ove Hufthammer
> Sent: Tuesday, November 24, 2009 1:11 AM
> To: r-h...@stat.math.ethz.ch
> Subject: Re: [R] Loess Fit
>
> On Mon, 23 Nov 2009 14:03:11 -0700 Greg Snow
> wr
-Original Message-
From: Henrique Dallazuanna [mailto:www...@gmail.com]
Sent: Tue 24/11/2009 16:10
To: Foadi, James (Imperial Coll.,RAL,DIA)
Cc: r-help@r-project.org
Subject: Re: [R] convex hull for cluster analysis
Try this:
plot(Y)
polygon(Y[chull(Y),])
Yes! Lovely!
Thanks.
J
D
You should really learn at least basic SAS yourself. Don't abandon R, but if
you use R only because it is the only program you know, then you are making an
uninformed decision. If you learn SAS and still prefer R (I do) then it is an
informed decision and much better. And your teachers are no
Hello,
I use:
R version 2.9.2 (2009-08-24)
Copyright (C) 2009 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
on Ubuntu 9.10, I usually run R from ESS (5.4 on current Unbuntu) from
Emacs-22.2.1. But I also tried the following from the console and it
gave the same results.
I have
On Thu, Oct 15, 2009 at 4:11 AM, Fearghas MacGregor
wrote:
> I'd recommend "The Elements of Statistical Learning" by Hastie, Tibshirani,
> and Friedman. There's a lot of good information on clustering, as well as a
> wealth of info on many other apsects of classification, machine learning,
> etc.
Hello, R users,
I have a dataset that looks like this:
id var1 var2
1 1 3
2 3 1
3 2 1
4 1 2
5 2 3
I want to split one column to two columns with 1 = 1 and 1, 2 = 1 and 2, 3 =
2 and 2:
id var1.1 var1.2 var2.1 va
Hi Listers,
I am producing some graphics that the commands are in a FUNCTION...
The problem is that I end up viewing just last graphic and in my FUNCTION
there are 4 graphics with the PAR command function... Like those below...
How do I view/get the other 3 graphics? Any help?
Thanks in advance...
Hello Everyone
I am new to R
I would like to know how to deal with Time Variable. If I have a column of
containing Time data in the format of hh:mm:ss such as 00:56:45, 01:24:36,
01:41:25, and so on..
I could find averages for this column using the Chron package. But now I
need to plot a gr
I am sure you are right. I myself have not looked at the LaTeX function
in Hmisc, that really sounds interesting, and thank you. On the other
hand I had the impression (which may be wrong) that the original
question was posed by someone with not too much experience. If that is
the case the s
Gérald Jean wrote:
> Hello,
>
> I use:
>
> R version 2.9.2 (2009-08-24)
> Copyright (C) 2009 The R Foundation for Statistical Computing
> ISBN 3-900051-07-0
>
> on Ubuntu 9.10, I usually run R from ESS (5.4 on current Unbuntu) from
> Emacs-22.2.1. But I also tried the following from the console
Hi Michael,
Looking at the help for beanplot(), note that the 'log' option defaults to
'auto' which means the function will automatically log-transform data like
yours. This also implies that the mean it shows is the geometric mean, not the
arithmetic mean. As you note, the transformation do
Back in March Soren Vogel asked exactly the same thing:
Here is the solution that was offered then. (He offered a dataset as
requested in the Posting Guide.) ... with only a minor adjustment:
g <- rep.int(c("A", "B", "C", "D"), 125)
t <- rnorm(5000)
a <- sample(t, 500, replace=TRUE)
b <- sam
Doesn't the APA package in LaTeX help in this situation?
--Chris Ryan
Original message
>Date: Tue, 24 Nov 2009 18:24:52 +0100
>From: Tom Backer Johnsen
>Subject: Re: [R] From R to LaTeX to pdf?
>To: Erik Iverson
>Cc: "r-help@r-project.org" , Joel Fürstenberg-Hägg
>
>
>I am sure y
Tom Backer Johnsen wrote:
As a general observation, few, if any, statistical packages, generate
tables in the format what you might think you need or want. R is not an
exception. Then it is better to transfer the table to a spreadsheet,
shift things around, add headers, etc.. The R2HTML libr
Try this:
cbind(x$id, t(do.call(rbind, lapply(x[-1], sapply, switch, '1' =
c(1,1), '2' = c(1, 2), '3' = c(2, 2)
On Tue, Nov 24, 2009 at 1:51 PM, Lisaj wrote:
>
> Hello, R users,
>
> I have a dataset that looks like this:
>
> id var1 var2
> 1 1 3
> 2 3 1
> 3 2
On Nov 24, 2009, at 11:52 AM, MarcioRibeiro wrote:
Hi Listers,
I am producing some graphics that the commands are in a FUNCTION...
The problem is that I end up viewing just last graphic and in my
FUNCTION
there are 4 graphics with the PAR command function... Like those
below...
How do I v
Not very elegant but this does the trick:
df <- cbind( var1=c(1,3,2,1,2), var2=c(3,1,1,2,3) )
out <- df
out[ which(df==1, arr.ind=T) ] <- "1&1"
out[ which(df==2, arr.ind=T) ] <- "1&2"
out[ which(df==3, arr.ind=T) ] <- "2&2"
outlist <- apply(out, 2, strsplit, split="&")
do.call( "cbind.data.fram
Hi,
how can I make tests like Dunnett and Duncan using R?
Thanks,
--
Silvano Cesar da Costa
Departamento de Estatística
Universidade Estadual de Londrina
Fone: 3371-4346
__
R-help@r-project.org mailing list
https:/
www.rseek.org is great for finding functions/packages that perform
specific tests.
Sarah
On Tue, Nov 24, 2009 at 1:09 PM, Silvano wrote:
> Hi,
>
> how can I make tests like Dunnett and Duncan using R?
>
> Thanks,
>
--
Sarah Goslee
http://www.functionaldiversity.org
__
Hi all,
I have a dataframe that has one observation per case.
for example:
CaseStartyear Endyear
A 1979 1989
B 1950 1955
I would like to create a dataframe in which each case has
multiple observations corresponding to the start and end
There are multiple ways, some are OS specific (and I don't see where you told
us that).
Some things to try:
par(ask=TRUE)
# or
pdf('tempfile.pdf')
yourfunctionhere()
dev.off()
# or
par(mfrow=c(2,2))
# or
Windows(record=TRUE)
# or
Look at the help for the function creating the plots, som
Try this;
with(x, data.frame(Case = rep(Case, (Endyear - Startyear) + 1),
Year = unlist(mapply(seq, Startyear, Endyear
On Tue, Nov 24, 2009 at 4:14 PM, Joseph Magagnoli wrote:
> Hi all,
> I have a dataframe that has one observation per case.
> for example:
>
> Case
On Nov 24, 2009, at 12:53 PM, Adaikalavan wrote:
Not very elegant but this does the trick:
df <- cbind( var1=c(1,3,2,1,2), var2=c(3,1,1,2,3) )
df <- data.frame(id=1:5, df)
data.frame(id=df$id,
var1.1 = (df$var1<3) + 2*(df$var1==3), # 1 for < 3; 2
for 3
var1.2 = (d
2009/11/24 Kevin Wright :
> If had done a little searching before posting, you surely would have found
> this link
> https://stat.ethz.ch/pipermail/r-help/2008-July/169149.html
> which describes how to create .xls files that are customized any way that
> you desire.
Manually convert to html, then
Dear R-users,
in the follwing thread
http://tolstoy.newcastle.edu.au/R/help/03b/3322.html
the problem how to remove rows for predict that contain levels which are
not in the model.
now i try to do this the other way round and want to remove columns
(variables) in the model which will be lat
In my experience, it is generally due to something like this example:
as.numeric(c('1','b','2'))
[1] 1 NA 2
Warning message:
NAs introduced by coercion
There may be other operations that generate that error, I can't say
for sure. But the above example illustrates what I look for when I
Perhaps something like:
as.numeric(chron(times.=c('01:23:21','11:12:13')))
[1] 0.05788194 0.46681713
-Don
At 7:02 AM -0800 11/24/09, RanjanV wrote:
Hello Everyone
I am new to R
I would like to know how to deal with Time Variable. If I have a column of
containing Time data in the format of
Hi!
Trying to make a forecast, and get the following error message:
Error in NextMethod("[<-") : subscript out of bounds
The script is as follows:
> Forecast.A <- ts(matrix(NA, nrow=25, ncol = 1,
+ dimnames = list(c(), c("Outcome"))),
+ start = c(2006, 10), frequency = 12)
> for (i in 1:25) {
Hi,
I can't seem to figure out how to tell R to stop expanding an object. I
would like to use the literal name rather than the expanded value.
The issue occurs in a function I've been writing. The problematic part looks
like this:
# "fund" is a matrix of open, high, low, close, and volume pr
Sure,but my problem is that the script is run from the console
windows,therefore I believe that the cat or readline doesn´t work...
JorisMeys wrote:
>
> I can't reproduce the error you have. With me, it runs all fine. In
> fact, readline apparently flushes automatically, as I didn't have to
> us
I use length(myVector),but when i want to use for example
exp(x.reconstruida[length(myVector)+1:length(myVector)+9]), I need that
function returns the number of last element,would then:
if the last position of my vector is 1440
exp(x.reconstruida[1440+1:1440+9]
This is what I need, I hope havin
Dear R-helpers,
I have a dataframe that should not contain any negative values, but it does.
I wish to print the rows from my dataframe that contain a negative value in
any column. I've tried this:
> dataframe[dataframe<0,]
but it just returns a row of NAs.
I would very much appreciate any help
Try this:
DF[rowSums(DF < 0) == 0,]
On Tue, Nov 24, 2009 at 5:58 PM, Mark Na wrote:
> Dear R-helpers,
>
> I have a dataframe that should not contain any negative values, but it does.
> I wish to print the rows from my dataframe that contain a negative value in
> any column. I've tried this:
>
>>
Hi,
On Nov 24, 2009, at 2:58 PM, Mark Na wrote:
> Dear R-helpers,
>
> I have a dataframe that should not contain any negative values, but it does.
> I wish to print the rows from my dataframe that contain a negative value in
> any column. I've tried this:
>
>> dataframe[dataframe<0,]
>
> but i
On 11/24/2009 1:13 PM, novocaine wrote:
Hi,
I can't seem to figure out how to tell R to stop expanding an object. I
would like to use the literal name rather than the expanded value.
The issue occurs in a function I've been writing. The problematic part looks
like this:
# "fund" is a matr
If the last position of your vector is 1440, what do you expect to get
from 1440 + 1???
And you certainly need some parentheses in there if you expect to get a range of
values from your vector.
Perhaps you need some subtraction?
And no, we still can't tell exactly what you want. If this doesn't
a
Erik and others,
Many thanks for your assistance. Erik correctly points out that the
as.dist() coercion requires a different format than I was using. The
correct format for input to as.dist() is a square matrix, not a lower
triangle matrix. Once I had that in order, everything went much better.
I
It implies that the random intercept is perfectly collinear with the random
slope, as you suggested. I attach an example.
The data generating process of y1 has a random intercept, but no random
slope. When you fit a model with random intercept and random slope, the
correlation between the two is
Thanks Steve, this works very well!
Mark
On Tue, Nov 24, 2009 at 2:07 PM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
> Hi,
>
> On Nov 24, 2009, at 2:58 PM, Mark Na wrote:
>
> > Dear R-helpers,
> >
> > I have a dataframe that should not contain any negative values, but it
> does.
On Nov 24, 2009, at 1:44 PM, yonosoyelmejor wrote:
I use length(myVector),but when i want to use for example
exp(x.reconstruida[length(myVector)+1:length(myVector)+9]), I need
that
function returns the number of last element,would then:
if the last position of my vector is 1440
exp(x.reco
I want to perform linear regression on groups of consecutive rows--say 5 to
10 such--of two matrices. There are many such potential groups because the
matrices have thousands of rows. The matrices are both of the form:
> shp[1:5,16:20]
SL495B SL004C SL005C SL005A SL017A
-2649 1.06 0.56
On Nov 24, 2009, at 3:04 PM, Henrique Dallazuanna wrote:
Try this:
DF[rowSums(DF < 0) == 0,]
ITYM:
> DF <- data.frame(a=1:10, b=c(1:3,-4, 5:10), c=c(-1, 2:10))
>
> DF[rowSums(DF < 0) > 0,]
a b c
1 1 1 -1
4 4 -4 4
--
David
On Tue, Nov 24, 2009 at 5:58 PM, Mark Na wrote:
Dear R
Perhaps along these lines:
1st #need to decide what your group width is , so the second number
inside the extraction call will be that number minus 1:
for (x in seq(1:1000, by=6) {
temp <- na,omit( shp[x:(x+5), ] ) # Need the parens in x:(x+5)
lm( formula, data=temp)
}
Or dependi
Hi all,
Windows XP
R 2.10.0
I am trying to generate predictions from a binomial mixed model using glmer.
the models is as follows:
mod.PN <- glmer(PN_out~ as.factor(intr3) + transcode + Yr + (Yr|ID)
family=binomial,data=partset, na.action=na.omit)
where PN_out is a two column binomial variable
> But I do feel compelled to ask: Do you really get meaningful
> information from lm applied to 5 cases? Especially when the predictors
> used may not be the same from subset to subset???
Thanks again for your help David. Your question is a good one. It's a bit
complicated but here's the bas
> what is the reason why the anova() method for coxph objects does not
work when robust standard errors have been requested, e.g.,
A robust variance estimate is normally used in situations where the
model may be mis-specified, e.g., multiple events per subject.
In this case a comparison of partia
Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of David Winsemius
> Sent: Tuesday, November 24, 2009 12:22 PM
> To: yonosoyelmejor
> Cc: r-help@r-project.org
> Subject: Re: [R] Method
>
>
> On Nov 24, 2009, at 1:44 PM, yonosoyelmejor wrote:
>
Thank you for your help. But how to change the column names to var1.1,
var1.2, var2.1, and var2.2?
Lisa
Henrique Dallazuanna wrote:
>
> Try this:
>
> cbind(x$id, t(do.call(rbind, lapply(x[-1], sapply, switch, '1' =
> c(1,1), '2' = c(1, 2), '3' = c(2, 2)
>
> On Tue, Nov 24, 2009 at 1:51
You might try putting
readline('CR to continue')
between the two sets of plot commands.
-Don
At 8:52 AM -0800 11/24/09, MarcioRibeiro wrote:
Hi Listers,
I am producing some graphics that the commands are in a FUNCTION...
The problem is that I end up viewing just last graphic and in my FUNC
Dear R users,
i want to use ANOVA with a small data set, here is an example of the data:
Rich FireDe TimeS Area
8 2 4 C
92.5 7 C
51.9 2 C
7 3 4 C
82.5 0 L
2 4 3 L
9
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