On Mon, 24 May 2010, Samuel Dennis wrote:
I am attempting to import dates in the following format to R:
5/20/2010 6:45:32 PM
Unfortunately I am unable to get the AM/PM function (%p) to work correctly
under either 2.11.0 or 2.8.1.
strptime(5/20/2010 6:45:32 PM, %m/%d/%Y %I:%M:%S %p)
[1] NA
I am trying to display a table with traitr. I am using the function tableitem
apart of traitr. I am not sure how to enter it. I enter my data as a table
in R (as list2) but im not sure how to use that function tableitem(list2)
but that doesnt seem to work. I would rather not edit it just display
Dear Changbin,
I want to know how to select the optimal decision threshold from the ROC
curve?
Depends on what optimal means. I think there are a bunch of different criteria
used:
- point closest to the ideal model
- point furthest from the guessing model
- these criteria may include costs,
Dear List,
I am making a list of all the files in a folder and I want to exclude
one file called proj.current. This is the 31st file in a folder.
Currently I use the command:
tdirs - list.files(pattern=proj.)[-31]
However I would like to exclude it based on its name and not the position.
Any
Hi all, I need to minimize following function :
dat - matrix(rnorm(2), ncol=2)
targetFn - function(x) {
dat - as.matrix(dat)
dat1 - 1*dat[,1] - (x^2)*dat[,2]
return(sd(dat1)) }
i.e. I want ro find for which x the value of targetFn will be minimum,
Hi all.
I began examining the R source code in the last few days, for a better
understanding of its structure. I read the manuals and digged deeply (maybe not
enough?) into the source code, but I couldn't totally understand how
.Primitive() works. Its effects, if I understand well, are quite
Dear list,
I am trying to obtain diagnostic plots for mixed effects models using the lme4
package to create the models and the inspect.lmer (model) or inspect (model)
function in the asuR package to create diagnostic plots.
I get the following error message when I try to run the example:
On Mon, May 24, 2010 at 9:03 AM, Stefano Baraldo
stefano.bara...@gmail.com wrote:
Hi all.
I began examining the R source code in the last few days, for a better
understanding of its structure. I read the manuals and digged deeply (maybe
not enough?) into the source code, but I couldn't
Hello
On 5/24/10, Joanne Hosking joanne.hosk...@pms.ac.uk wrote:
I am using R version 2.11.0, asuR_0.08-24, and lme4_0.999375-33
You might want to try asuR_0.10 [1]. The CRAN version seems badly outdated.
Liviu
[1] http://www.evolution.unibas.ch/teaching/r_course/asuR.htm
Bogaso wrote:
Hi all, I need to minimize following function :
dat - matrix(rnorm(2), ncol=2)
targetFn - function(x) {
dat - as.matrix(dat)
dat1 - 1*dat[,1] - (x^2)*dat[,2]
return(sd(dat1)) }
i.e. I want ro find for which x the value of
I have the data like this:
dummy
State Months No
1xxxJan 1
2xxxJan 2
3xxxJan 1
4yyyJan 1
5yyyJan 2
6yyyJan 1
7zzzJan 3
8zzzJan 1
9zzzJan 2
10 xxxFeb 3
11 xxxFeb 4
12 xxxFeb 2
13 yyyFeb
On 05/24/2010 05:40 PM, Daisy Englert Duursma wrote:
Dear List,
I am making a list of all the files in a folder and I want to exclude
one file called proj.current. This is the 31st file in a folder.
Currently I use the command:
tdirs- list.files(pattern=proj.)[-31]
However I would like to
Hi,
I would like to receive help for the following matter:
If I'm dealing with a numeric vectors containing increasing elements.
i.e.
a-c(1,2,2,2,2,3,3,3,4,4,4,5,5,6,7,7,7)
There exist an efficient way to obtain an vector that indicates the position
of the changing element of a?
In this case
Mango Solutions is pleased to announce that we will be running an Introduction
to R course in Bath on the 24th and 25th June; there are currently a couple of
places still available on this course for anyone interested in learning about
R, the programming language
Thanks a lot for the help. I am quite new to R and every bit of
information is very valuable for me.
Best wishes
Juan A. Balbuena
El 21/05/2010 17:05, ONKELINX, Thierry [via R] escribioacute;:
Have a look at ?varClasses. You could you something like
varIdent(form =
~ 1|areatrai)
On 05/24/2010 07:44 PM, Mohan L wrote:
I have the data like this:
dummy
State Months No
1xxxJan 1
2xxxJan 2
3xxxJan 1
4yyyJan 1
5yyyJan 2
6yyyJan 1
7zzzJan 3
8zzzJan 1
9zzzJan 2
10 xxxFeb 3
11 xxx
On 5/24/2010 6:02 AM, speretti wrote:
Hi,
I would like to receive help for the following matter:
If I'm dealing with a numeric vectors containing increasing elements.
i.e.
a-c(1,2,2,2,2,3,3,3,4,4,4,5,5,6,7,7,7)
There exist an efficient way to obtain an vector that indicates the
Hi,
is this what you need?
b - c(NA, a[1:length(a)-1]) # shift values of a one step to the right
which(a-b == 1)
On Monday 24 May 2010 12:02:55 pm speretti wrote:
Hi,
I would like to receive help for the following matter:
If I'm dealing with a numeric vectors containing increasing
Try this:
which(diff(a) 0) + 1
[1] 2 6 9 12 14 15
On Mon, May 24, 2010 at 6:02 AM, speretti sabrina.pere...@gmail.com wrote:
Hi,
I would like to receive help for the following matter:
If I'm dealing with a numeric vectors containing increasing elements.
i.e.
On 2010-05-23 18:16, Zack Holden wrote:
Dear list,
I'd like to use path.analysis in the package agricolae in batch format on
many files, retrieving the path coefficients for each run and appending them
to a table. I don't see any posts in the help files about this package or
the path.analysis
Thank you !
Great answers...now it seems very easy...
As usual...a the obviousness of a solution depends on how you face the
problem...
Thank you for help me in find the good approaches...
--
View this message in context:
Hi Mohan,
Try this:
table(dummy$State,dummy$Months)
Jim
Thanks for your time.
table(dummy$State,dummy$Months)
in this case the state column becomes the row index. I want the state name
as the first column. There may be a way to do it.
Thanks Rg
Mohan L
[[alternative HTML
Dear R list,
I have a function specifying my log-likelihood, and now I need to set the
constraint that *alpha kappa*, could anyone help me with setting this in
my function?
the function is defined as follows:
mll - function(param){
n - length(x)
psi - numeric(n)
psi[1] - 1.0
a0 -
hi,
I am using R version 2.10.0.when i am trying to retrieve the previous used
R commands
by using â and â keys,but i get the output like this
^[[A^[[A^[[A^[[B^[[C^[[A.
can any one tell me how i can solve this problem.
--
Regards
Ab Rauf Shah
--
Regards
Ab Rauf Shah
[[alternative
On 05/24/2010 02:14 AM, Claudia Beleites wrote:
Dear Changbin,
I want to know how to select the optimal decision threshold from the ROC
curve?
Depends on what optimal means. I think there are a bunch of different
criteria used:
- point closest to the ideal model
- point furthest from the
Dear group,
I have a function, let's call it myfun, wich give me a list of result:
R1,R2,R3...
There is a loop in this function to get my results. Here is the structure of
my function:
Myfun-function()
{
For (i in X ){
---instructions-
Ri
{
{
All Results (R1,R2...) are
Thank you Barry!
Telling the truth, I found the function definition this morning too... I really
don't know how could I have missed it (I've been searching for it for a pair of
days...). I work on a Mac and I'm learning to use Unix systems in general, so
I'm not very accustomed to grep and
When there is a constraint like this, it is often the case that the
likelihood function may the value zero. Hence, the log-likelihood may
take the value -Inf. You could impose this constraint with something
like
if( kappa = alpha ) {
ll - -Inf
} else
ll - n*log(alpha/gamma(kappa))+
Dear R-help list members,
I have a statistical question regarding the Random Forest function (RF) as
applied to ecological prediction of species presences and absences.
RF seems to perform very well for prediction of species ranges or
prevalences. However, the problem with my dataset is a high
it works as well!
--
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Sent from the R help mailing list archive at Nabble.com.
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Hello
On 5/24/10, makhdoomi abraufs...@gmail.com wrote:
hi,
I am using R version 2.10.0.when i am trying to retrieve the previous used
R commands
by using ↑ and ↓ keys,but i get the output like this
^[[A^[[A^[[A^[[B^[[C^[[A.
can any one tell me how i can solve this problem.
It would
One solution is to create a list, then do.call.
Here is my environment:
ls()
[1] DailyPL100416 DailyPL100419 DailyPL100420 l ll
PLglobal Pos100415 Pos100416 Pos100419 Pos100420
position r
[13] resultsel selectTrad100415
Berend Hasselman wrote:
Bogaso wrote:
Hi all, I need to minimize following function :
dat - matrix(rnorm(2), ncol=2)
targetFn - function(x) {
dat - as.matrix(dat)
dat1 - 1*dat[,1] - (x^2)*dat[,2]
return(sd(dat1)) }
i.e. I want ro
You could also try the Boruta package for variable selection.
2010/5/24 Andreas Béguin chaud...@gmail.com:
Dear R-help list members,
I have a statistical question regarding the Random Forest function (RF) as
applied to ecological prediction of species presences and absences.
RF seems to
And, just for kicks, a yet another (somewhat inefficient)solution:
match(unique(a),a)
Cheers,
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of speretti
Sent: Monday, May 24, 2010 3:03
On May 24, 2010, at 8:21 AM, Mohan L wrote:
Hi Mohan,
Try this:
table(dummy$State,dummy$Months)
Jim
Thanks for your time.
table(dummy$State,dummy$Months)
in this case the state column becomes the row index. I want the
state name
as the first column. There may be a way to do it.
On 5/24/10, makhdoomi abraufs...@gmail.com wrote:
I am using R version 2.10.0,os fedora 11i terminal.when i am trying to
retrieve the previous used
There might be an issue with your terminal. Did you try with xterm?
Here accessing history items with R running in an xterm works just
fine.
I understand that everything passed to an R function is passed by
value. This would seem to include data frames, which my current
application uses heavily, both for storing program inputs, and holding
intermediate and final results. In trying to get greater performance
out of my R code, I am
If you don't modify the data frame in your function it won't
physically make a new copy.
On Mon, May 24, 2010 at 10:29 AM, gschu...@scriptpro.com wrote:
I understand that everything passed to an R function is passed by
value. This would seem to include data frames, which my current
Hi all,
here is my situation
In my experiment, I expose 10 subjects to 24 different conditions of
stimuli. Each condition is exposed to the same subject 3x.
This would make each subject have 24x3=72 data points. All the subjects
combined would have 72x10=720 data points with each condition
To: r-help@r-project.org
hi,
I am using R version 2.10.0,OS fedora 11i terminal.when i am trying to
retrieve the previous used R commands
by using â and â keys,but i get the output like this
^[[A^[[A^[[A^[[B^[[C^[[A.
can any one tell me how i can solve this problem.
--
Regards
Ab Rauf Shah
R is pretty smart about duplicating only when necessary. That is,
arguments passed to a function are copy-on-write. Also, I think (someone
more knowledgeable please correct if I'm wrong) it may be better to use
the data frame, which is just a list internally, because if you only
modify one column,
Ruijie breakaway8 at gmail.com writes:
In my experiment, I expose 10 subjects to 24 different conditions of
stimuli. Each condition is exposed to the same subject 3x.
This would make each subject have 24x3=72 data points. All the subjects
combined would have 72x10=720 data points with each
On Mon, May 24, 2010 at 7:00 AM, arnaud Gaboury
arnaud.gabo...@gmail.com wrote:
One solution is to create a list, then do.call.
Here is my environment:
ls()
[1] DailyPL100416 DailyPL100419 DailyPL100420 l ll
PLglobal Pos100415 Pos100416 Pos100419 Pos100420
Noted.
I have attached a list of some data in csv format.
The first column is the SubID and the rest of the column are the mean of
each condition for the particular subject.
Average 1 is the average computed from each column in the list.
Average 2 is computed from the raw data of all the data
Hello list,
I'm trying to make sure that I'm performing a path analysis correctly
using the sem package. the figure at
http://flame.cs.dal.ca/~sstewart/regressDiag.png has a detailing of
the model.
The challenge I'm having is that reuse is an indicator (0/1) variable.
Here's the code I'm
Maybe is there a neater solution, but the function mget() does the trick. So
until further advice, I will work with your solution.
Thank you
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Monday, May 24, 2010 5:07 PM
To: arnaud Gaboury
Cc:
Do you think there is a way to add somewhere the argument row.names=NULL ? Or
should I have to write another line to remove the row.names?
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Monday, May 24, 2010 5:07 PM
To: arnaud Gaboury
Cc:
Hi All,
I'm trying to draw boxplots. I'm having a hard time to get ticks labels on
multiple panels using 'alternating' option.
# R Code:
# May not be the best example, please just look into 'scales' option
library(lattice)
data(OrchardSprays)
dta - subset(OrchardSprays, OrchardSprays$rowpos %in%
Hi all,
I have some trouble reading data from a csv file.
I used command read.delim(clipboard) to read in the data.
aalpha.data - read.delim(clipboard)
class(aalpha.data)
[1] data.frame
dim(aalpha.data)
[1] 8 25
colnames(aalpha.data)
[1] X V1 V2 V3 V4 V5 V6 V7 V8 V9 V10
Hi,
On Mon, May 24, 2010 at 11:51 AM, li li hannah@gmail.com wrote:
Hi all,
I have some trouble reading data from a csv file.
I used command read.delim(clipboard) to read in the data.
aalpha.data - read.delim(clipboard)
class(aalpha.data)
[1] data.frame
dim(aalpha.data)
[1] 8
Dear sstewart,
The model appears to reflect the path diagram, assuming that you intend to
allow the exogenous variables to be correlated and want the errors to be
uncorrelated.
This is one way to model the binary variable reuse. An alternative would be
to fit the equation for intent by
Dear group,
Here is my environment after I run a function, myfun()
myfun()
ls()
[1] allconavprix16 DailyPL100416 DailyPL100419
DailyPL100420 l llmyl PL
PLdaily PLglobal PLmonthly
[13] Pos100415 Pos100416 Pos100419
Are you sure that you have the same number of data points in each of
the summary cells that you show in your csv file that was sent? You
need to provide a reproducible example of all the data so we can see
what you did. The best information I can provide at this point is
that you have a bug in
On May 24, 2010, at 9:49 AM, makhdoomi wrote:
To: r-help@r-project.org
hi,
I am using R version 2.10.0,OS fedora 11i terminal.when i am trying to
retrieve the previous used R commands
by using ↑ and ↓ keys,but i get the output like this
^[[A^[[A^[[A^[[B^[[C^[[A.
can any one tell me how
My guess is that either ls(), called inside grep() or mget() is
looking in an environment you do not want it to. When you create a
function, it has it's own environment. If you want the dataframes to
be created inside the function call (which is what I think you were
doing before), you should
Hi Yves
lavaan looks like a very nice package. From the tutorial introduction
I see you create path diagrams for some of the models you describe.
How did you do this? I don't see a function for this in the package.
I know there is a path.diagram function in the sem package that uses
dot to
On 2010-05-24 9:51, li li wrote:
Hi all,
I have some trouble reading data from a csv file.
I used command read.delim(clipboard) to read in the data.
aalpha.data- read.delim(clipboard)
class(aalpha.data)
[1] data.frame
dim(aalpha.data)
[1] 8 25
colnames(aalpha.data)
[1] X V1
Thank you so much. You are totally right.
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Monday, May 24, 2010 6:33 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] writing function
My guess is that either ls(), called inside grep()
On 2010-05-24 9:38, Kim Jung Hwa wrote:
Hi All,
I'm trying to draw boxplots. I'm having a hard time to get ticks labels on
multiple panels using 'alternating' option.
# R Code:
# May not be the best example, please just look into 'scales' option
library(lattice)
data(OrchardSprays)
dta-
Hello!
I am running a very simple mini Monte-Carlo below using the function
tstatistic (right below this sentence):
tstatistic = function(x,y){
m=length(x)
n=length(y)
sp=sqrt( ((m-1)*sd(x)^2 + (n-1)*sd(y)^2)/(m+n-2) )
t=(mean(x)-mean(y))/(sp*sqrt(1/m+1/n))
Just thought I would add, if you want to specifically specify to look
in the function environment, you can do something like:
myfun - function(x) {
env - environment() #createa variable of the function environment
rest of your stuff
mget(grep(DailyPL,ls(, envir=env),value=TRUE),envir=env))
On 05/24/2010 06:31 PM, Michael Friendly wrote:
Hi Yves
lavaan looks like a very nice package. From the tutorial introduction
I see you create path diagrams for some of the models you describe.
How did you do this? I don't see a function for this in the package.
I know there is a path.diagram
That's an interesting idea, I got the same impression from your SEM
appendix to Companion to applied regression in the paragraph just
before Section 3.
So I could get the same results if I built the following two models:
mod1 =
Dear Sam,
-Original Message-
From: R Help [mailto:rhelp.st...@gmail.com]
Sent: May-24-10 1:04 PM
To: John Fox
Cc: r-help
Subject: Re: [R] Path Analysis
That's an interesting idea, I got the same impression from your SEM
appendix to Companion to applied regression in the
There are many ways to impose the constraint:
1. Use a constrained optimization routine (e.g. constrOptim)
2. Reparametrize alpha and kappa such that the inequality will be always
satisfied
3. Re-define your log-likelihood by putting a barrier such that the
optimization algorithm will not
On 2010-05-24 10:50, Dimitri Liakhovitski wrote:
Hello!
I am running a very simple mini Monte-Carlo below using the function
tstatistic (right below this sentence):
tstatistic = function(x,y){
m=length(x)
n=length(y)
sp=sqrt( ((m-1)*sd(x)^2 + (n-1)*sd(y)^2)/(m+n-2) )
Thanks for your help jim. I have attached the raw data to see if anyone else
can replicate my problem.
Correction: i realise my attachment was too large, I have uploaded it to
another site. The link is:
http://dl.dropbox.com/u/1443460/List%20-%20Raw%20Data.csv
Regards,
Ruijie (RJ)
He
Thanks Dennis and Peter, it worked.
On Mon, May 24, 2010 at 12:44 PM, Peter Ehlers ehl...@ucalgary.ca wrote:
On 2010-05-24 9:38, Kim Jung Hwa wrote:
Hi All,
I'm trying to draw boxplots. I'm having a hard time to get ticks labels
on
multiple panels using 'alternating' option.
# R Code:
Thanks a lot, Peter, that's exactly what I was looking for:
plot(density(tstat),xlim=c(-5,8),ylim=c(0,.4),lwd=2,col='red')
z - tstat[order(tstat)]
lines(z,dt(z,df=18),col='blue')
legend(4,.3,c(exact,t(18)),lwd=c(2,1),col=c('red','blue'))
Dimitri
On Mon, May 24, 2010 at 1:26 PM, Peter Ehlers
A quick check of you data shows that there are not the same number of
sample in each of the different conditions, therefore trying to take
the average of the averages will not work.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
1 32 31 29 30 24 23 31 32 32 31 24
Notice that only column 19 in your original had the same for the
average of the average and every entry had 32 data points.
On Mon, May 24, 2010 at 1:47 PM, jim holtman jholt...@gmail.com wrote:
A quick check of you data shows that there are not the same number of
sample in each of the
Hi Folks,
I created a .R file with source code that accesses functions from a R
package (example, fTrading).
I then run the created application in two different configurations:
1. I started a R session, and then ran the application using the source
(my_application.R) command, and I measured the
Thanks for your help jim. I have attached the raw data to see if anyone else
can replicate my problem.
Regards,
Ruijie (RJ)
He who has a why can endure any how.
~ Friedrich Nietzsche
On 25 May 2010 00:17, jim holtman jholt...@gmail.com wrote:
Are you sure that you have the same
Hi Duncan,
I love your plotlm3d function!
I want to plot the following data:
x
[1] 1 2 3 4 5 6 7 8 9 10
y
[1] 0.5678042 0.3986702 0.3063544 0.2554426 0.1954868 0.1238850 0.1161249
0.1689951 0.1826783 0.2406300
z
[1] 0.2558812 0.2619668 0.2585930 0.2563669 0.2588323 0.2734029
?strptime will helps.
d - as.Date(01/05/2007,%m/%d/%Y)
format(d, %A, %b %d, %Y)
[1] Friday, Jan 05, 2007
-
A R learner.
--
View this message in context:
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Sent from the R help mailing list archive at Nabble.com.
Dear R users,
I am trying to make this (3 by 10) matrix A
--A
0 0 00 1 0 0 0 0 0
0 0 00 0 1 0 0 0 0
0 0.5 0.5 0 0 0 0 0 0 0
---
from mass.func
Or:
weekdays(as.Date(2010-05-24))
HTH,
Stephan
Wu Gong schrieb:
?strptime will helps.
d - as.Date(01/05/2007,%m/%d/%Y)
format(d, %A, %b %d, %Y)
[1] Friday, Jan 05, 2007
-
A R learner.
__
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Can anyone recommend an R package that offers a two-sample Kuiper test?
Tom
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
Hi, is there a way to create one image file (like using win.metafile(), bmp(),
etc) that contained multiple pages of plots, just like what postscript() does
in creating PDF file?
Thanks
John
__
R-help@r-project.org mailing list
Hi:
Here's one way, but not especially elegant. The idea is to initialize a
matrix of zeros,
produce an index matrix from two of your objects and then assign the third
object
to the specified indices.
x - matrix(0, nrow = 3, ncol = 10)
row - rep(1:nrow(x), unname(sapply(y.covar, nrow)))
row
[1]
Dear all,
I'm trying to compare trees from different methods and originating from
different genes (thus different lengths of sequences). Problem is that I
can't really use the branch lengths, as they mean different things. If I
calculate the geodesic distance between those trees, I need to make
On May 24, 2010, at 2:32 PM, array chip wrote:
Hi, is there a way to create one image file (like using win.metafile(),
bmp(), etc) that contained multiple pages of plots, just like what
postscript() does in creating PDF file?
Thanks
John
John,
There is no notion of pages with
I am trying to calculating the treatment effect for individual subjects
(ID)
of a (score) between 2 time-points (visit) (see example below).
The data is in an unbalanced data.frame in long format with some
missing data.
I suspect that I am overlooking a very simple function, something along
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Kathryn Lord
Sent: Monday, May 24, 2010 11:16 AM
To: r-help@r-project.org
Subject: [R] Table to matrix
Dear R users,
I am trying to make this (3 by 10) matrix A
Try your same system command, but set intern=TRUE in the call and see if that
does what you want.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org
Hi all,
apologies if this has been answered before, I didn't find the answer
in the archives. I am putting together a package that I would like to
have optional functionality if another package is installed. In
normal, non-package code, I would simply write something like
if (require(qvalue))
{
Dear list,
I used rqss() in quantreg package for a piecewise linear regression. Can
someone tell me how to find the x values corresponding to the breakpoints
and the slopes for the phases before and after the breakpoints?
I searched the list and gather that there is another package segmented
vincent.deluard wrote:
Hi Duncan,
I love your plotlm3d function!
That's not really my function. I think I suggested some changes to it,
but I didn't write most of it.
Duncan Murdoch
I want to plot the following data:
x
[1] 1 2 3 4 5 6 7 8 9 10
y
[1]
Hi Thomas,
Thanks very much for your reply. I used svd and it worked perfectly for my
purposes!
Thanks again,
Julia
--
View this message in context:
http://r.789695.n4.nabble.com/Data-reconstruction-following-PCA-using-Eigen-function-tp2226535p2229191.html
Sent from the R help mailing list
I read somewhere (help list, documentation) that the random effects in lme4
uses sparse matrix technology.
I'd like to confirm with others that I can't use a sparse matrix as a fixed
effect? I'm getting an Invalid type (S4) error.
Thanks.
~~~
-Robin Jeffries
Dr.P.H. Candidate
Hi Duncan,
I am trying to use the plotlm3d function which I believe was written by John
Fox and later modified by Jose Claudio Faria and Duncan Murdoch. It is a
great way to plot data points in a 3D environment but I do not see how to
customize the size of the axes.
I want to plot the
I am planning to purchase a server to dedicate to running R processes. 4-5
analysts will use the server and it must have capabilities to process large
data sets fast. I am not sure if Windows or Linux based servers are better
or what specs I should be focused on for optimum production. Also is
Put some numbers on your request. How much slower was it? Did you
measure the user and system CPU? Was there a difference? Was there a
large amount of I/O or other system calls being done?
On Mon, May 24, 2010 at 2:01 PM, Peter Holt source.code.de...@gmail.com wrote:
Hi Folks,
I created a
Thanks for your help and for the info on the website. I did not know
what to call regular expressions and so I could not search for them.
Cheers!
d
On Mon, May 24, 2010 at 7:08 PM, richard.cot...@hsl.gov.uk wrote:
I am making a list of all the files in a folder and I want to exclude
one file
On Mon, May 24, 2010 at 6:24 PM, Robin Jeffries rjeffr...@ucla.edu wrote:
I read somewhere (help list, documentation) that the random effects in lme4
uses sparse matrix technology.
Yes. That is why there is such a close link between the Matrix and
lme4 packages. The sparse matrix methods in
On May 24, 2010, at 2:36 PM, vincent.deluard wrote:
Hi Duncan,
I love your plotlm3d function!
I want to plot the following data:
x
[1] 1 2 3 4 5 6 7 8 9 10
y
[1] 0.5678042 0.3986702 0.3063544 0.2554426 0.1954868 0.1238850
0.1161249
0.1689951 0.1826783 0.2406300
z
[1]
Dear All,
I have a data frame data and the below is the str of data :
$ Feb : int 1 1195 0 11 28 152 24 2 1 1470 ...
$ Mar : int 0 1212 0 17 27 184 15 1 1 1311 ...
$ Apr : int 2 1244 1 15 23 135 11 0 1 991 ...
$ May : int 2 1158 2 10 23 111 16 1 1 1237 ...
$ Jun : int 0 845 1
?round
On May 24, 2010, at 9:26 PM, Mohan L wrote:
Dear All,
I have a data frame data and the below is the str of data :
$ Feb : int 1 1195 0 11 28 152 24 2 1 1470 ...
$ Mar : int 0 1212 0 17 27 184 15 1 1 1311 ...
$ Apr : int 2 1244 1 15 23 135 11 0 1 991 ...
$ May : int 2
Hi,
I am trying to fit cubic spline to a data on mortality rate by age and year
(1900-2008). The data is noisy and hence I would like to smooth using spline
and also extrapolate beyond 2008. Data from 1900 to 1948 are very unreliable
while data from 1948 to 2008 are reliable. I would like to have
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