Dear Sandra,
R^2 is just a ratio between the amount of error explained between two
models.
PRE (proportional reduction in error) = R^2 = (SSE model C - SSE model
A)/SSE model C.
This is sometimes expressed as (SSEc-SSEa)/SSEc = SSR/SSEc |SSR=sum squared
reduced
Given your example with some
I'm sorry for what I'm sure is a terribly simple question. I have a large
dataframe along these lines:
S- 1:3
d- data.frame(cbind(S=rep(paste('S',S,sep=),each=30),
trial=rep(1:3,each=10),
FactorA=rep(paste('L',1,sep=),each=30), Acc=
c(rep(1,each=20),rep(0,each=10)),
Sample=rep(1:10,3),
Dear All,
I have a problem running this program on R. Z is a matrix of spline which is
random
fit-lme(anc~X,random=pdIdent(~Z))
Error in getGroups.data.frame(dataMix, groups) :
Invalid formula for groups
What I have done wrong?
__
Hi, you should be able to do most of your summaries using tapply() or
aggregate().
for your example,
tapply(d$Acc,list(d$Sample),table)
Here tapply takes Acc, splits it by Sample, and then tables Acc (which
returns how many 0s/1s were observed in variable Acc for each stratum of
Sample).
Hello.
I have a small problem when I want to display a dendrogram for about 450
varieties.
The label of theses varieties is too big and we can not see thems well.
How can I do to resize the label smaller?
Can you help me please?
Thanks.
[[alternative HTML version deleted]]
Hi, as pointed out previously, the problem is in using the canned routine
(lm) without including an intercept term. Here is a working, generic example
with commented code.
#Simulate data
x=rnorm(100)
e=rnorm(100)
y=x+e
#Create X matrix with intercept
X=cbind(1,x)
#Projection matrix
Try this:
v - letters; windows - 5; shift - 2
e - embed(v, window)
e[seq(1, nrow(e), shift), window:1]
On Mon, Jun 14, 2010 at 11:46 PM, david hilton shanabrook
davidshanabr...@me.com wrote:
basically I need to create a sliding window in a string. a way to explain
this is:
v -
Hi Elyakhlifi,
You can try this:
hc - hclust(dist(USArrests), ave)
plot(hc, cex = .5)
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il
Dear list I have two different data frame
the first one is like this
CLUSTER year variablevalue
m1 2006 EC01 4
m1 2007 EC01 5
m2 2006 EC01
apropos (merge)
Cheers, Claudia
n.via...@libero.it wrote:
Dear list I have two different data frame
the first one is like this
CLUSTER year variablevalue
m1 2006 EC01 4
m1 2007 EC01
Hello all,
I am trying to create a Clustergram in R.
(More about it here: http://www.schonlau.net/clustergram.html)
And to produce a picture similar to what is seen here:
http://www.schonlau.net/images/clustergramexample.gif
I was able (more or less) to write the R code for creating the image,
Hi all,
I've got a simple 3D plot as follows...
xx - seq(-20,20,.5)
yy - seq(-20,20,.5)
zFunc - function(x,y){3*x^2*y}
z - outer(xx,yy,zFunc)
persp(xx,yy,z,theta=30,phi=30,ticktype=detailed)
Just beautiful!
My question is how do I constrain the plot to only display x^2 = y = 1?
Thanks in
Nick Torenvliet wrote:
Hi all,
I've got a simple 3D plot as follows...
xx - seq(-20,20,.5)
yy - seq(-20,20,.5)
zFunc - function(x,y){3*x^2*y}
z - outer(xx,yy,zFunc)
persp(xx,yy,z,theta=30,phi=30,ticktype=detailed)
Just beautiful!
My question is how do I constrain the plot to only
Hello,
If I want to see how, say, apply function is written, how would I be
able to do that?
Just typing apply at the prompt does not work.
Thank you for help!
Sergey
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Sergey Goriatchev wrote:
Hello,
If I want to see how, say, apply function is written, how would I be
able to do that?
Just typing apply at the prompt does not work.
Well, it is supposed to work, and it works for me. So you need to tell us what
does not work means, and all the info the
On Tue, 2010-06-15 at 14:20 +0200, Sergey Goriatchev wrote:
Hello,
If I want to see how, say, apply function is written, how would I be
able to do that?
Just typing apply at the prompt does not work.
In what sense does it not work? If I do this, I get:
apply
function (X, MARGIN, FUN, ...)
i've just installed the packagexlsx,which is used for read,write,format
Excel 2007 files, as i loaded the package ,i was told to intall the package
rJava, the problem was that i didn't have a JAVA platform on my computer, so
i have to install JAVA JDK first, my problem is ,after i 've installed
Erik, I see the following when I type apply at the prompt:
apply
standardGeneric for apply defined from package base
function (X, MARGIN, FUN, ...)
standardGeneric(apply)
environment: 0x03cad7d0
Methods may be defined for arguments: X, MARGIN, FUN
Use showMethods(apply) for currently
On Tue, Jun 15, 2010 at 9:47 AM, Farhad Shokoohi stat...@gmail.com wrote:
Dear All,
I have a problem running this program on R. Z is a matrix of spline which is
random
fit-lme(anc~X,random=pdIdent(~Z))
Error in getGroups.data.frame(dataMix, groups) :
Invalid formula for groups
What I
My current solution is to use a constant jitter (based on seq) on all the
k number of clusters, but that causes glitches in the produced image (run my
code to see).
What are the glitches? It looks pretty good to me. (I'm not sure if
the colour does anything apart from make it pretty though).
Sergey Goriatchev wrote:
Erik, I see the following when I type apply at the prompt:
apply
standardGeneric for apply defined from package base
function (X, MARGIN, FUN, ...)
standardGeneric(apply)
environment: 0x03cad7d0
Methods may be defined for arguments: X, MARGIN, FUN
Use
On Tue, 2010-06-15 at 14:38 +0200, Sergey Goriatchev wrote:
Erik, I see the following when I type apply at the prompt:
apply
standardGeneric for apply defined from package base
Looks like you have something loaded in your workspace (or have created
something) that has altered the usual
This is also an interesting discussion to read in this respect :
http://tolstoy.newcastle.edu.au/R/e8/help/09/10/1228.html
Cheers
Joris
On Mon, Jun 14, 2010 at 5:55 PM, Karl-Dieter Crisman kcris...@gmail.com wrote:
Looking for a recommended package that handles prime number computations.
I'm
Maybe I have to much stuff loaded in the workspace, Gavin, you are right:
sessionInfo()
R version 2.10.1 (2009-12-14)
i386-pc-mingw32
locale:
[1] LC_COLLATE=German_Switzerland.1252
LC_CTYPE=German_Switzerland.1252
LC_MONETARY=German_Switzerland.1252
[4] LC_NUMERIC=C
Hello
Where could I find examples on how to work with the time index in a
timeseries or zoo series?
Let say I've got this series
DATA
1990-01-01 10:00:00 0.900
1990-01-01 10:01:00 0.910
1990-01-01 10:03:00 0.905
1990-01-01 10:04:00 0.905
1990-01-01 10:05:00 0.890
Dear John,
Great thanks,
I would appreciate if any expert can throw more light on it.
Thanks in advance,
Best Regards,
Yogesh
On 6/14/10, John Kane jrkrid...@yahoo.ca wrote:
Hi Yogesh,
I think you accidentelly replied only to me and not to the mailing list.
I'd suggest that you copy your
Hi Daniel, thanks for your reply. Unfortunately, that is not doing what I
need. In the example I sent, there are three subjects (S1, S2 S3). Each
subject has 3 trials worth of data and each trial has 10 samples. What I
want to return is the accuracy rate for each subject. The answer is
Hello,
In one of my functions, I need to extract the hour from a date.
For example:
as.POSIXlt(2010-03-27 02:00:00)$hour gives 2 as expected.
It works for all the dates I've tested except the following one which is in
my list of dates:
as.POSIXlt(2010-03-28 02:00:00)$hour which gives 0.
I don't
Yes I had a data.frame but did not named the categorical variable class and
the numerical one var. It is working now.
However I would like to do a comparison with several classes and variables.
Is there a way of doing this? Or do I have to do a Wilcox.test for every
variable?
Thanks
Marie.
--
On Tue, 2010-06-15 at 14:56 +0200, Sergey Goriatchev wrote:
Maybe I have to much stuff loaded in the workspace, Gavin, you are right:
OK, so now do
showMethods(apply)
And R should list out the available methods. See which package
(re)defines apply.
But it is likely going to be simpler to
showMethods(apply)
Function: apply (package base)
X=ANY
X=missing
(inherited from: X=ANY)
X=timeSeries
On Tue, Jun 15, 2010 at 15:10, Gavin Simpson gavin.simp...@ucl.ac.uk wrote:
On Tue, 2010-06-15 at 14:56 +0200, Sergey Goriatchev wrote:
Maybe I have to much stuff loaded in the workspace,
Dear all,
Currently I am trying to integrate a function which depends on four
variables, two of which are given, one is given in the integrate function,
so there is one variable to integrate on.
The code is as follows:
Pmatrix =
function(th) {
P = matrix(nrow=6, ncol=6, data=0)
Hi Hadley,
Thanks for replying.
The glitches are the cases where you would have a bundle of lines belonging
to a specific cluster, but had spaces between them (because the place of one
of the lines was saved for another line that in the meantime moved to
another cluster).
I just came up with a
Dear All,
I revise my question about the problem I have.
Take a look at the article
http://www.jstatsoft.org/v09/i01
and download the attached code.
try to run one of the codes for example section 2.1 in R
here is the code
fossil - read.table(fossil.dat,header=T)
x - fossil$age
y -
On 15.06.2010 13:45, PtitBleu wrote:
Hello,
In one of my functions, I need to extract the hour from a date.
For example:
as.POSIXlt(2010-03-27 02:00:00)$hour gives 2 as expected.
It works for all the dates I've tested except the following one which is in
my list of dates:
On Tue, Jun 15, 2010 at 8:27 AM, skan juanp...@gmail.com wrote:
Hello
Where could I find examples on how to work with the time index in a
timeseries or zoo series?
Let say I've got this series
DATA
1990-01-01 10:00:00 0.900
1990-01-01 10:01:00 0.910
1990-01-01 10:03:00 0.905
Dear all,
I would like to write some tests for my R package, and the usual
'tests' directory seemed like a good solution, but there is something
I cannot understand.
It is possible to supply .Rout.save files with the expected output for
the tests, which is great. But since the tests are not run
The glitches are the cases where you would have a bundle of lines belonging
to a specific cluster, but had spaces between them (because the place of one
of the lines was saved for another line that in the meantime moved to
another cluster).
I think that display looked just fine!
I just came
In context below:
On Jun 15, 2010, at 4:20 AM, Yogesh Tiwari wrote:
Dear John,
Great thanks,
I would appreciate if any expert can throw more light on it.
Thanks in advance,
Best Regards,
Yogesh
On 6/14/10, John Kane jrkrid...@yahoo.ca wrote:
Hi Yogesh,
I think you accidentelly replied
Frank,
The trouble is that your integrand function `int' is not vectorized. You
can use `Vectorize' or `sapply' to rectify this.
int.vec = function(theta, s, a, lambda) {
sapply(theta, function(t,s,a,lambda) int(t,s,a,lambda), s=s, a=a,
lambda=lambda)
}
I use two PCs for my R programming, one Win32 and one Linux (Ubuntu 10).
In Windows I use Tinn-R to save my code and occasionally I am unable to
open a Tinn-R saved file in Ubuntu. If I try to open in gedit I get a
message that gedit has not been able to detect the character encoding.
To correct
On Jun 15, 2010, at 7:45 AM, PtitBleu wrote:
Hello,
In one of my functions, I need to extract the hour from a date.
For example:
as.POSIXlt(2010-03-27 02:00:00)$hour gives 2 as expected.
It works for all the dates I've tested except the following one
which is in
my list of dates:
Hi Hadley,
I wrapped the code into a function.
I made it so all the lines would always start from the cluster mean.
And I tried to give more meaning to the colors by giving the
color according the the order of the first principal component of that
observation.
What do you think ?
Tal
#
On Jun 15, 2010, at 9:05 AM, Frankvb wrote:
Dear all,
Currently I am trying to integrate a function which depends on four
variables, two of which are given, one is given in the integrate
function,
so there is one variable to integrate on.
The code is as follows:
Pmatrix =
function(th) {
Almost continuously I get some variant of the following message
fillingb up my R console:
bubble(data1, logvol)
?variogram
** (evince:2799): WARNING **: DBus error
org.freedesktop.DBus.Error.Failed: Unable to set metadata key
** (evince:2799): WARNING **: DBus error
Hello,
I am using the recode() function in Rcmdr and the result is not what I
expect so I am almost sure I did something wrong but what...
test - data.frame(x=1:10)
library(car)
recode(test$x,'1:5=0 ; else=1', as.factor.result=TRUE)
[1] 0 0 0 0 0 1 1 1 1 1
Levels: 0 1
BUT
Hello,
I am reading Using The foreach Package document and I have tried the
following:
-
sessionInfo()
R version 2.10.1 (2009-12-14)
i386-pc-mingw32
locale:
[1] LC_COLLATE=German_Switzerland.1252
Greetings!
I would like to be able to specify a fixed (say) lower limit
for plotting, while leaving the upper limit floating, when
plotting. The context is that the maximum in the data to be
plotted is unpredictable, being the consequence of a simulation,
whereas I know that it cannot be less than
Dear Alain,
I'm afraid that I can't duplicate your problem. First, there is no recode
function in the Rcmdr package; it uses recode from car.
Here's a record of my Rcmdr session, using the recode dialog to generate the
recode command:
test$variable - recode(test$x, '1:5=0; else=1; ',
Dear Alain,
Taking a stab in the dark here but I find that if my original column is
a factor then recode won't work for me. Would a simple ifelse statement
not do the same thing?
test$variable - ifelse(test$x=1 test$x=5,0,1)
On 15/06/2010 16:53, John Fox wrote:
Dear Alain,
I'm afraid
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of
ted.hard...@manchester.ac.uk
Sent: Tuesday, June 15, 2010 8:49 AM
To: r-h...@stat.math.ethz.ch
Subject: [R] Unspecified [upper] xlim/ylim?
Greetings!
I would like to be
This solution also seems to be the fastest of the proposed options for
this data set:
library(rbenchmark)
benchmark(columns = c(test, elapsed, relative), order = elapsed,
apply =apply(iris[, -5], 2, tapply, iris$Species, mean),
with = with(iris, rowsum(iris[, -5],
On Mon, 14 Jun 2010, david hilton shanabrook wrote:
basically I need to create a sliding window in a string. a way to explain this
is:
v -
c(a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y)
window - 5
shift - 2
I want a matrix of characters with window columns filled with v by filling
Dear Natalie,
recode() does work for factors; is it possible that you haven't put the
level names in quotes? Example:
(f - factor(rep(letters[1:3], 3)))
[1] a b c a b c a b c
Levels: a b c
recode(f, c('a', 'b') = 'A'; else='B' )
[1] A A B A A B A A B
Levels: A B
Best,
John
I found out what the problem is: when I start R Commander, some plug-ins
are automatically loaded and it seems that the problem comes from the
RcmdrPlugin.Export, more precisely from the Hmisc package (the plug-in
depends on it) which contains a recode() function too with the following
Hello Hadley, Tormod and every one else.
I just published a post on my blog, giving the code and presenting an
example of it's use (on the Iris data set)
http://www.r-statistics.com/2010/06/clustergram-a-graph-for-visualizing-cluster-analyses-r-code/
I welcome any comments (pitfalls, suggestions
On 15-Jun-10 16:01:24, William Dunlap wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of
ted.hard...@manchester.ac.uk
Sent: Tuesday, June 15, 2010 8:49 AM
To: r-h...@stat.math.ethz.ch
Subject: [R] Unspecified [upper]
Gábor Csárdi wrote:
Dear all,
I would like to write some tests for my R package, and the usual
'tests' directory seemed like a good solution, but there is something
I cannot understand.
It is possible to supply .Rout.save files with the expected output for
the tests, which is great. But since
I find that sometimes the recode function in car is easier to use, while at
other times it's easier to use the recode in Hmisc. If both packages are
loaded, you can always use car::recode or Hmisc::recode to specify which
function you want.
hth,
David Freedman, CDC
--
View this message in
Hello,
I am trying to compute MLE for non-Gaussian AR(1). The error term follows a
difference poisson distribution. This distribution has one parameter
(vector[2]).
So in total I want to estimate two parameters: the AR(1) paramter (vector[1])
and the distribution parameter.
My function
Hello,
I am trying to compute MLE for non-Gaussian AR(1). The error term follows a
difference poisson distribution. This distribution has one parameter
(vector[2]).
So in total I want to estimate two parameters: the AR(1) paramter (vector[1])
and the distribution parameter.
My function is
Hi everyone,
I'm running a cox ph model on a dataset with a number of variables. Each
variable has a different number of missing data, so that coxph() drops the
individuals who are missing data at one or more variables. Because of this
dropping (totally fine btw) I want to know how many events
I can't resist
http://www.lmgtfy.com/?q=set+windows+PATH+variable
On 6/15/2010 8:37 AM, yi li wrote:
i've just installed the packagexlsx,which is used for read,write,format
Excel 2007 files, as i loaded the package ,i was told to intall the package
rJava, the problem was that i didn't
On Tue, Jun 15, 2010 at 1:54 PM, steven mosher mosherste...@gmail.com wrote:
Hi Gabor,
Not sure where to report this, but
Mac 10.5.8
R: 11.1
When you examine the zoo vignette and hit the back button, you get a hang.
I havent tested with other vignettes and cant imagine that is is specific
On 15 Jun 2010, at 18:34, Federico Calboli wrote:
I'm running a cox ph model on a dataset with a number of variables. Each
variable has a different number of missing data, so that coxph() drops the
individuals who are missing data at one or more variables. Because of this
dropping (totally
HI, Dear Greg and R community,
I have one question about the output of gbm package. the output of Boosting
should be f(x), from it , how to calculate the probability for each
observations in data set?
SInce it is stochastic, how can guarantee that each observation in training
data are selected
On Jun 15, 2010, at 1:34 PM, Federico Calboli wrote:
Hi everyone,
I'm running a cox ph model on a dataset with a number of variables.
Each variable has a different number of missing data, so that
coxph() drops the individuals who are missing data at one or more
variables. Because of
You can define a function that does just that: sum the 1s in Acc and divide
by the length of Acc. Then use tapply to apply the function for each
subject.
f=function(x){sum(as.numeric(as.character(x)))/length(x)}
tapply(d$Acc,list(d$S),f)
HTH,
Daniel
--
View this message in context:
Dear All,
I revise my question about the problem I have.
Take a look at the article
http://www.jstatsoft.org/v09/i01
and download the attached code.
try to run one of the codes for example section 2.1 in R
here is the code
fossil - read.table(fossil.dat,header=T)
x - fossil$age
y -
Hey.
Looking at EuStockMarkets[1:1860] -- the DAX.
ar() estimates an AR(1) model with \alpha_1 ~= 1 and high \sigma^2.
But forecasting from a given X_t_0 according to an AR(1) model with \alpha_1 =
1 should be X_t_0 for all X_t, t t_0 . ?
How do you do this forecasting in R?
Hi. I am trying to do a nonlinear regression on a set of data with Monod
kinetics and Haldane inhibition. I am using the following commands to do
the nonlinear regression:
dce-read.delim(data.txt, header = TRUE, sep = \t, quote=\, dec=.,
fill = TRUE, comment.char=)
Hello again,
You are right: it corresponds to the DST time transition in France (I think
you have guessed it was France from my Frenglish style - sorry about it).
To get around this problem, I now use :
as.numeric(format(strptime(2010-03-28 02:00:00, format=%Y-%m-%d
%H:%M:%S), format=%H))
Hello colleagues,
I have tried to use the package biglm. I want to specify a
multivariate regression with a weight.
I have imported a large dataset with the library(bigmemory). I load
the library (biglm) and specified a regression with a weight. But I
get everytime a error message like “object
Dear R Users:
What I need to do is to plot two ellipses in the same graph (one for
each group). You can use either X1 or X2 as the X-axis and the other
variable as the Y-axis.
Also I need to show the 95% C.I. or P.I. of the overlapping part of the two
ellipses, and for each ellipse separately.
Folks:
Say I have a matrix:
test=matrix(c(1,2,3),nrow=10,ncol=3)
I would like to have an output character vector where each line is
row's values delimited by commas, e.g.:
1,2,3
2,3,1
3,1,2
...
1,2,3
What is the fastest way of doing this? I can paste() row-by-row but
this seems an
Hi All,
I am trying to turn a Matrix into a vector for analysis purposes. I need to
select only certain columns from the entire matrix for the vector (intraday
time intervals). Also I need to transpose the Matrix (so times are in rows)
stack each successive new column on top of each other
Hi Gabor,
Not sure where to report this, but
Mac 10.5.8
R: 11.1
When you examine the zoo vignette and hit the back button, you get a hang.
I havent tested with other vignettes and cant imagine that is is specific to
yours
FWIW.
Did I mention that zoo is great. Thx for your work on it.
On
Trying to get 2.11.1 built on a solaris 10 machine. This particular
machine I do not have root access so I have just created an area under
my home to use. I am currently having issues in the src/library area
most specifically with getting the datasets area built. Here is the
output form my most
apply(test, 1, paste, collapse=,)
[1] 1,2,3 2,3,1 3,1,2 1,2,3 2,3,1 3,1,2 1,2,3 2,3,1 3,1,2
[10] 1,2,3
On Tue, Jun 15, 2010 at 2:27 PM, Jonathan Greenberg
greenb...@ucdavis.edu wrote:
Folks:
Say I have a matrix:
test=matrix(c(1,2,3),nrow=10,ncol=3)
I would like to have an output
apply(test, 1, paste, collapse = ,)
On Tue, Jun 15, 2010 at 11:27 AM, Jonathan Greenberg
greenb...@ucdavis.edu wrote:
Folks:
Say I have a matrix:
test=matrix(c(1,2,3),nrow=10,ncol=3)
I would like to have an output character vector where each line is
row's values delimited by commas,
How about:
?subset
?t
?as.vector
I'm not sure transposing is really needed, but without a workable example
as requested in the posting guide (hint, hint), it's hard to say for certain.
Sarah
On Tue, Jun 15, 2010 at 1:51 PM, George Coyle gcoy...@gmail.com wrote:
Hi All,
I am trying to turn a
George Coyle wrote:
Hi All,
I am trying to turn a Matrix into a vector for analysis purposes. I need to
select only certain columns from the entire matrix for the vector (intraday
time intervals). Also I need to transpose the Matrix (so times are in rows)
stack each successive new column on
On Jun 15, 2010, at 12:11 PM, Ted Harding wrote:
On 15-Jun-10 16:01:24, William Dunlap wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of
ted.hard...@manchester.ac.uk
Sent: Tuesday, June 15, 2010 8:49 AM
To:
Dear Alain,
-Original Message-
From: Alain Guillet [mailto:alain.guil...@uclouvain.be]
Sent: June-15-10 12:25 PM
To: John Fox
Cc: r-help@r-project.org
Subject: Re: [R] Problem with the recode function
I found out what the problem is: when I start R Commander, some plug-ins
are
On 15-Jun-10 19:35:54, Marc Schwartz wrote:
On Jun 15, 2010, at 12:11 PM, Ted Harding wrote:
On 15-Jun-10 16:01:24, William Dunlap wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of
ted.hard...@manchester.ac.uk
Sent:
You need to constrain your parameters such that 0 vector[1] 1 and
vector[2] 0.
You could try the `spg' function in package BB or the `L-BFGS-B' function
in optim to perform this box-constrained optimization. There are other
options as well including the `nlminb' function.
Ravi.
-Original
Have the following function that is called by the statement below. Trying to
return the two dataframes, but instead get one large list including both
tables.
ReadInputDataFrames - function() {
dbs.this= read.delim(this.txt, header = TRUE, sep = \t, quote=\,
dec=.)
dbs.that=
On Jun 15, 2010, at 4:39 PM, GL wrote:
Have the following function that is called by the statement below.
Trying to
return the two dataframes, but instead get one large list including
both
tables.
ReadInputDataFrames - function() {
dbs.this= read.delim(this.txt, header = TRUE, sep =
I would like to get the list of variables of an expression: is that
possible? I searched the help and the web without success. In
practice, given an expression like
expr = parse(text=x^2+y^3)
I would like to have a function such as:
vars(expr)
returns
c(x, y) or a list like the one returned
Hello, everyone,
There's a problem about zero in R and I really need your help.
I have a vector shown as x=c(0.1819711,0.4811463,0.1935151,0.1433675),
The sum of this vector is shown as 1 in R, but when I type 1-sum(x), the
value is not zero, but -2.220446e-16.
I can accept that this value
Hi Yen,
See
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f
HTH,
Jorge
On Tue, Jun 15, 2010 at 6:00 PM, Yen Lee wrote:
Hello, everyone,
There's a problem about zero in R and I really need your help.
I have a vector shown as
On Jun 15, 2010, at 5:45 PM, Alberto Lusiani wrote:
I would like to get the list of variables of an expression: is that
possible? I searched the help and the web without success. In
practice, given an expression like
expr = parse(text=x^2+y^3)
I would like to have a function such as:
Hello Yen,
You may find ?zapsmall helpful. If your algorithm expects 1-sum(x) to
have a lower bound of zero, then also simply setting a cutoff point
seems reasonable.
Josh
On Tue, Jun 15, 2010 at 3:00 PM, Yen Lee b88207...@ntu.edu.tw wrote:
Hello, everyone,
There's a problem about zero in R
On Tue, 2010-06-15 at 06:28 -0700, Farhad Shokoohi wrote:
Dear All,
I revise my question about the problem I have.
Take a look at the article
http://www.jstatsoft.org/v09/i01
and download the attached code.
try to run one of the codes for example section 2.1 in R
here is the code
That is
On Jun 15, 2010, at 5:07 PM, David Winsemius wrote:
On Jun 15, 2010, at 5:45 PM, Alberto Lusiani wrote:
I would like to get the list of variables of an expression: is that
possible? I searched the help and the web without success. In
practice, given an expression like
expr =
On Tue, Jun 15, 2010 at 6:00 PM, Yen Lee b88207...@ntu.edu.tw wrote:
Hello, everyone,
There's a problem about zero in R and I really need your help.
I have a vector shown as x=c(0.1819711,0.4811463,0.1935151,0.1433675),
The sum of this vector is shown as 1 in R, but when I type 1-sum(x),
Hello, everyone,
Thank you for all your kindness.
I've solved the problem through your help with the function all.equal.
Thank you very much!
Yen
-Original Message-
From: Gabor Grothendieck [mailto:ggrothendi...@gmail.com]
Sent: Wednesday, June 16, 2010 6:40 AM
To: Yen Lee
Cc:
Same for me on Mac OS X:
x - c(0.1819711,0.4811463,0.1935151,0.1433675)
1-sum(x)
[1] 0
version$version.string
[1] R version 2.11.1 Patched (2010-05-31 r52180)
Regards,
Jorge
On Tue, Jun 15, 2010 at 6:40 PM, Gabor Grothendieck wrote:
On Tue, Jun 15, 2010 at 6:00 PM, Yen Lee wrote:
hi,
could you please tell me what kind of cross validation that SVM of e1071 uses?
Cheers,
Amy
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Hello:)
I have 4 points in a 2-dimension coordinate. how can I do the regression
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thanks a lot,
Liang
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