You need to parse it before you evaluate it.
eval(parse(text = avar))
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jeremiah H. Savage
Sent: Wednesday, 30 June 2010 3:45 PM
To: r-help@r-project.org
Subject: [R] evaluate a
http://r.789695.n4.nabble.com/file/n2272669/FT20100626_%2420_%2B_%242_Sit_%26_Go_-_%28169112900%29_-_Summary.txt
FT20100626_%2420_%2B_%242_Sit_%26_Go_-_%28169112900%29_-_Summary.txt
I have a lot of experience with Stata, but I'm new to R. I'm trying to read
the attached file into R on my mac.
When I click the attachment here in the forum, it looks funny.
When I open it in TextEdit, it looks like this:
Full Tilt Poker Tournament Summary $20 + $2 Sit Go (169112900) Hold'em No
Limit
Buy-In: $20 + $2
Buy-In Chips: 1500
6 Entries
Total Prize Pool: $120
Tournament started: 2010/06/27
Hi Elaine,
in general, stepwise selection is a very bad idea:
Whittingham, M. J.; Stephens, P. A.; Bradbury, R. B. Freckleton, R. P.
Why do we still use stepwise modelling in ecology and behaviour? Journal
of Animal Ecology, 2006, 75, 1182-1189
HTH
Stephan
elaine kuo schrieb:
Dear list,
On Tue, 2010-06-29 at 21:27 -0500, Lidia Dobria wrote:
Dear All:
I apologize for asking such an elementary question, but I could not
find an adequate response on line. I am hoping to receive some help
with the interpretation of the Intercept coefficient in the gam model
below.
I1
On Wed, 2010-06-30 at 09:13 +0200, Stephan Kolassa wrote:
Hi Elaine,
in general, stepwise selection is a very bad idea:
Whittingham, M. J.; Stephens, P. A.; Bradbury, R. B. Freckleton, R. P.
Why do we still use stepwise modelling in ecology and behaviour? Journal
of Animal Ecology,
On Mon, Jun 28, 2010 at 6:32 PM, Doris Brockmann
brock...@supagro.inra.fr wrote:
How can I insert mathematical expressions for variable names in a lattice
parallel plot? I tried to implement mathematical expressions in varnames,
however, without success.
For example, neither
On Wed, 30-Jun-2010 at 11:06AM +1200, Paul Murrell wrote:
Hi
On 6/30/2010 2:17 AM, Jinsong Zhao wrote:
Hi there,
I am a Chinese R user. I hope to display Chinese character in a plot,
and than save it in PostScript format. I have read the article titled
Non-Standard Fonts in PostScript and
Hi Dennis,
Thank you for your answer.
Are you sure that the following commands are working?
library(FrF2)
plan - FrF2(8, 3, factor.names=c(T,C,K), default.level=c(-,+),
randomize = FALSE)
y - c(60,72,54,68,52,83,45,80)
plan - add.response(plan, y)
MEPlot(plan)
IAPlot(plan)
I get the following
Hi,
I have a list which is basically a database of zoo multivariate objects:
x.Date - as.Date(2003-02-01) + c(1:100) - 1
x - zoo(rnorm(100), x.Date)
z - zoo(rnorm(100), x.Date)
y - zoo(rnorm(100), x.Date)
k - zoo(rnorm(100), x.Date)
a-merge(x,z)
b-merge(y,k)
Dear all (copying the package author),
I have a question on the vlmc package. I am trying to model a time series,
where each element can take one of 11 values (the result of some clustering).
When I run the following command (synthetic data to facilitate self-contained
example) I get the
I'm guessing this is a FAQ but I can't find it and that it is probably
not exclusive R related but relevant so I thought I'd ask:
When I view the PDF output from Sweave (e.g. Example 1 from the author's
web site at [1]) on a Linux system using the standard PDF viewer [2],
the circles for the
Hi,
Another option would be the tikzDevice package, which lets you process
all the text of your plot with LaTeX. I think the XeTeX variant might
be the most straight-forward to mix different fonts using this
approach.
HTH,
baptiste
On 29 June 2010 16:17, Jinsong Zhao jsz...@mail.hzau.edu.cn
help([[)
e.g.
plot(test[[2]])
Hope this helps
Allan
On 30/06/10 10:09, Research wrote:
Hi,
I have a list which is basically a database of zoo multivariate objects:
x.Date - as.Date(2003-02-01) + c(1:100) - 1
x - zoo(rnorm(100), x.Date)
z - zoo(rnorm(100), x.Date)
y -
On 6/30/2010 1:14 AM, Daniel Chen wrote:
Hi,
I am a long time SPSS user but new to R, so please bear with me if my
questions seem to be too basic for you guys.
I am trying to figure out how to analyze survey data using logistic
regression with multiple imputation.
I have a survey data
Hi,
I have the following problem:
I have a large dataframe where each row is specified by two numerical value
(one 1:25 and the other one large specific number (e.g. 203043)). I have a
list of 60 categories which are also assigned to one of the first numerical
value (1:25) but have a range for
I am doing calculations in a loop and then plotting the results by adding a
point to each of 2 charts at the end of the loop. Its very informative as
you can see the progression through time.
My problem is, if I have 2 plots, I don't know how to get the focus back to
the first plot.
On Wed, 2010-06-30 at 10:19 +0100, Allan Engelhardt wrote:
I'm guessing this is a FAQ but I can't find it and that it is probably
not exclusive R related but relevant so I thought I'd ask:
When I view the PDF output from Sweave (e.g. Example 1 from the author's
web site at [1]) on a Linux
The first issue of the second volume of The R Journal will shortly be
available at jour...@r-project.org/current.html. Thanks to everyone
involved.
Peter Dalgaard
Editor-in-chief
--
Peter Dalgaard
Center for Statistics, Copenhagen Business School
Phone: (+45)38153501
Email: pd@cbs.dk
On 06/30/2010 10:42 AM, Pablo Cerdeira wrote:
Hi All,
this is my first mail here.
I'm trying to plot a multiline chart grouping values with no success. I have
read a lot in the official Wiki and also searched via Google, but I did not
find anything.
I'm importing some data from a cvs file.
Hi,
I have the following problem:
I have a large dataframe where each row is specified by two numerical value
(one 1:25 and the other one large specific number (e.g. 203043)). I have a
list of 60 categories which are also assigned to one of the first numerical
value (1:25) but have a range for
Or you could use ggplot2
library(ggplot2)
Dataset - read.csv(file.csv, header=TRUE)
ggplot(Dataset, aes(x = YEAR, y = CASES, colour = AREA)) + geom_line()
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en
Thank you Gavin, this is useful. The work-around for me then is to
quickly run
pdf(test.pdf)
plot(0:25, pch=0:25)
dev.off()
to see which pch values are not safe (unsafe.pch - c(1, 10, 13, 16,
19, 20, 21)) and make sure I never use them. (The first four, btw.,
corresponds to the symbols
A simpler option is probably to put
echo=FALSE=
pdf.options(useDingbats = FALSE)
@
near the top of the Sweave document.
Thanks again!
Thank you Gavin, this is useful. The work-around for me then is to
quickly run
pdf(test.pdf)
plot(0:25, pch=0:25)
dev.off()
to see which pch values are
There are titanic datasets in R binary format at
http://biostat.mc.vanderbilt.edu/DataSets
Note that the aregImpute function in the Hmisc package streamlines many
of the steps, in conjunction with the fit.mult.impute function.
Frank
On 06/30/2010 05:02 AM, Chuck Cleland wrote:
On
In addition to the tips above, you may want to chek out:
http://www.stat.columbia.edu/~gelman/arm/missing.pdf
2010/6/30 Chuck Cleland cclel...@optonline.net
On 6/30/2010 1:14 AM, Daniel Chen wrote:
Hi,
I am a long time SPSS user but new to R, so please bear with me if my
questions seem
On Jun 30, 2010, at 1:14 AM, Daniel Chen wrote:
Hi,
I am a long time SPSS user but new to R, so please bear with me if my
questions seem to be too basic for you guys.
I am trying to figure out how to analyze survey data using logistic
regression with multiple imputation.
I have a survey
You could just open two devices.
See ?dev.cur for an example.
-Peter Ehlers
On 2010-06-30 4:26, pdb wrote:
I am doing calculations in a loop and then plotting the results by adding a
point to each of 2 charts at the end of the loop. Its very informative as
you can see the progression
CA == Constantinos Antoniou constantinos.antoniou.rli...@gmail.com
on Wed, 30 Jun 2010 12:07:16 +0300 writes:
CA == Constantinos Antoniou constantinos.antoniou.rli...@gmail.com
on Wed, 30 Jun 2010 12:07:16 +0300 writes:
CA Dear all (copying the package author),
CA I have a
On Wed, 2010-06-30 at 13:26 +0100, Allan Engelhardt wrote:
A simpler option is probably to put
echo=FALSE=
pdf.options(useDingbats = FALSE)
@
Hi Allan,
You're on Linux, so is there a reason why this won't work in a shell:
touch ~/.fonts.conf
vim ~/.fonts.conf
replace vim with your
On Jun 30, 2010, at 12:21 AM, ARR wrote:
http://r.789695.n4.nabble.com/file/n2272669/FT20100626_%2420_%2B_%242_Sit_%26_Go_-_%28169112900%29_-_Summary.txt
FT20100626_%2420_%2B_%242_Sit_%26_Go_-_%28169112900%29_-_Summary.txt
I have a lot of experience with Stata, but I'm new to R. I'm
Hello again,
I merge different zoo time series with prices at different dates. This
returns a multivariate zoo object with NA's at various points i.e.,
2010-02-28 NA NA NA NA 850.2 2444.4 NA
NA NA NA NA NA NA
2010-03-01 61.1 55.3
Esteemed R Users,
Would some one be patient enough to explain the variation i see when
creating .pdf file output for my plots? FYI- my goal is produce the
highest quality .pdf output from the R 'command line' as opposed to
using the menu of the acitve graphics window.
Im using 32bit WinXP.
Hello,
I am trying to find the analytical solution to this differential equation
dR/dt = k1*R (1-(R/Rmax)^k2); R(0) = Ro
k1, k2, and Rmax are parameters that need to fitted, while Ro is the
baseline value (which can be fitted or fixed). The response (R) increases
initially at an exponential rate
Good question pdb,
I would suggest you to use:
par(bg = white)
In the beginning of the code,
But it doesn't solve the general problem of how to get the lines to be
properly aligned.
I am curious for the answer from betteR people.
Best,
Tal
Contact
Here it is:
read.inputs-function(infile) {
for (counter in 1:length(input.list)) {
seek(infile,where=0,origin='start')
newline-readLines(infile,n=1)
while(length(newline)0) {
if(!is.na(grep(as.character(input.list[[counter]][1]),newline)[1])) {
break
}
Hi,
I'm starting use the R Package and I have some .R scripts. How
can I run these .R scripts.
Conrado
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hi,
I am trying to consume a web service that returns a JSON string, however,
when I run
fromJSON(s)
Error: '\/' is an unrecognized escape in character string starting http:\/
because the string s contains a single backslash, which is the JSON escape
character, but R expects 2 backslashes, I
Dear list,
I have a vector of letter strings as follow:
LETTERS[c(1:7,9,15,18:25)]
[1] A B C D E F G I O R S T U V W X Y
I need to find sequences of length 11, which are made from all possible
permutations with repetition (not the unique ones) of the letter string A with
the other
On 2010-6-30 17:20, baptiste auguie wrote:
Hi,
Another option would be the tikzDevice package, which lets you process
all the text of your plot with LaTeX. I think the XeTeX variant might
be the most straight-forward to mix different fonts using this
approach.
HTH,
baptiste
Thank you
On 2010-6-30 7:06, Paul Murrell wrote:
Hi
On 6/30/2010 2:17 AM, Jinsong Zhao wrote:
Hi there,
I am a Chinese R user. I hope to display Chinese character in a plot,
and than save it in PostScript format. I have read the article titled
Non-Standard Fonts in PostScript and PDF Graphics,
On 2010-6-30 16:24, Patrick Connolly wrote:
On Wed, 30-Jun-2010 at 11:06AM +1200, Paul Murrell wrote:
Hi
On 6/30/2010 2:17 AM, Jinsong Zhao wrote:
Hi there,
I am a Chinese R user. I hope to display Chinese character in a plot,
and than save it in PostScript format. I have read the article
Could you please provide a small reproducible example of the input you
have and output you'd like, as the posting guide asks for? There most
likely is much simplified way to do what you want, avoiding for loops
and therefore `break` altogether.
Cable, Samuel B Civ USAF AFMC AFRL/RVBXI wrote:
Hi,
I have written a code in R for classifying microarray data using naive
bayes, the code is given below:
library(e1071)
train-read.table(Z:/Documents/train.txt,header=T);
test-read.table(Z:/Documents/test.txt,header=T);
cl - c(c(rep(ALL,10), rep(AML,10)));
cl - factor(cl)
model -
Dear R Users (particularly tsDyn package users),
I am very new in the use of R and the contributed packages in need of
urgent assistance (see attachment for the explanation of the problem).
Could someone assist me on conducting threshold cointegration test in R
using the tsDyn package. I have
Method 3:
pdf(file=my_plot.pdf, paper=a4)
dev.off()
The `pdf` function opens a *new* graphics device, you then send output
to the device before calling dev.off(), e.g.,
pdf(file = my_plot.pdf)
plot(1:10, 1:10)
dev.off()
-yields a .pdf file of 1kb (same plot example) and returns
You don't say what package fromJSON is in, or give us the ability to
reproduce the error, since we don't know what 's' is. If those two
pieces of information are possible to give to the list, it will be much
easier to help.
dabd wrote:
Hi,
I am trying to consume a web service that returns
Welcome to a new world. You're using the _programming language_ R with
thousands of packages, and first of all you should be reading the
introduction material thoroughly :
http://cran.r-project.org/doc/manuals/R-intro.pdf
http://cran.r-project.org/doc/contrib/Owen-TheRGuide.pdf
Regarding your
On Jun 30, 2010, at 9:08 AM, jorge.conr...@cptec.inpe.br wrote:
Hi,
I'm starting use the R Package and I have some .R scripts. How
can I run these .R scripts.
?source
... and re-read Introduction to R.
Conrado
__
Please follow the posting guide and tell us minimally what your
operating system is.
You might find:
http://cran.r-project.org/doc/manuals/R-intro.html#Scripting-with-R
or
http://code.google.com/p/batchfiles/#PROGRAM_LIST
useful.
jorge.conr...@cptec.inpe.br wrote:
Hi,
I'm
Read the Posting Guide. Your attachment apparently did not meet the
requirements therein.
On Jun 30, 2010, at 10:52 AM, Setlhare Lekgatlhamang wrote:
Dear R Users (particularly tsDyn package users),
I am very new in the use of R and the contributed packages in need of
urgent assistance
Yes, there is an analytical solution.
Here is how you do it:
bernoulli_anal - function(t, R0, Rmax, a, b) {
# Note: a, b, R0, Rmax all have to be positive (strictly 0)
R1 - R0 / Rmax
k - R1^b / (1 - R1^b)
R - Rmax / (1 + exp(-a*b*t)/k)^(1/b)
return(R)
}
R0 - 1
Rmax - 2
a - 0.5
b - 1.0
t -
On Wed, Jun 30, 2010 at 11:57 AM, Yen Ngo yen.ng...@yahoo.se wrote:
Dear list,
I have a vector of letter strings as follow:
LETTERS[c(1:7,9,15,18:25)]
[1] A B C D E F G I O R S T U V W X Y
I need to find sequences of length 11, which are made from all possible
permutations with
So...
You really should give the results of sessionInfo().
There are (at least) two naive Bayes functions. I'm assuming that you
are using the one in klaR.
Look at the manual page ? predict.NaiveBayes: the output is A list
with the conditional a-posterior probabilities for each class and the
On 30-Jun-10 15:48:39, Barry Rowlingson wrote:
On Wed, Jun 30, 2010 at 11:57 AM, Yen Ngo yen.ng...@yahoo.se wrote:
Dear list,
I have a vector of letter strings as follow:
LETTERS[c(1:7,9,15,18:25)]
_[1] A B C D E F G I O R S T U V W X
Y
I need to find sequences of length 11, which are
see
?cut
?interaction
HTH,
Chuck
On Wed, 30 Jun 2010, LogLord wrote:
Hi,
I have the following problem:
I have a large dataframe where each row is specified by two numerical value
(one 1:25 and the other one large specific number (e.g. 203043)). I have a
list of 60
Thank you Erik!
That works nicely now. The file size in (in kilobytes) is equal to the
FileSave AsPDF method.
Still curious why the file sizes (in Kb), differ by a factor of ~2
between the two methods:
pdf()
dev2bitmap(method = pdf)
I'm just *assuming* here that file size is inidcative of
On Jun 30, 2010, at 12:27 PM, Charles C. Berry wrote:
see
?cut
?interaction
I had been thinking that findInterval or expand.grid might also be
useful, but was really waiting for a test data preparation to emerge.
--
David.
HTH,
Chuck
On Wed, 30 Jun 2010, LogLord
On 2010-06-30 8:38, Tal Galili wrote:
Good question pdb,
I would suggest you to use:
par(bg = white)
In the beginning of the code,
But it doesn't solve the general problem of how to get the lines to be
properly aligned.
I am curious for the answer from betteR people.
Best,
Tal
Instead of
On 03/ 1/10 12:23 AM, Sharpie wrote:
John Maindonald wrote:
I came across this notice of an upcoming webinar. The issues identified
in the
first paragraph below seem to me exactly those that the R project is
designed
to address. The claim that most research software is barely fit for
Just one small additional note below ...
Bert Gunter
Genentech Nonclinical Biostatistics
But a lot of academics are not going to waste their time documenting code
properly, so others can reap the benefits of it. They would rather get on
with
the next project, to get the next paper.
--
On Wed, Jun 30, 2010 at 10:05 AM, Research risk2...@ath.forthnet.gr wrote:
Hello again,
I merge different zoo time series with prices at different dates. This
returns a multivariate zoo object with NA's at various points i.e.,
2010-02-28 NA NA NA NA 850.2 2444.4 NA
Hi,
I am looking for a way to find the lower envelope of points on a plot,
preferably specifying what percentage of points should be allowed to lie
outside the envelope. There must be a straightforward way to do this,
but I do not seem to be able to find it. I would greatly appreciate any
Greg,
Just a quick one to say thanks for helping me out with my 2-y axis query --
your solution works a treat.
However, 2 extension points I was wondering if you could help with:
- 1/ Is there any way to invert the 2nd y axis -- i.e. highest entry at the
bottom of the axis? I can see that
I'm having problems with this example, it is posted with reproduceable code
below, both with the normal 0-6 scale and the desired 3-6 scale (with bars
removed). How can I get the graph to have the desired 3-6 scale without
removing the bars. Thanks!
#Data
Hi,
I have written a code in R for classifying microarray data using naive
bayes, the code is given below:
library(e1071)
train-read.table(Z:/Documents/train.txt,header=T);
test-read.table(Z:/Documents/test.txt,header=T);
cl - c(c(rep(ALL,10), rep(AML,10)));
cl - factor(cl)
model -
Hi,
How can I get double quotes embedded in the string?
Example:
--
str1 - 'xyz'
## desired output
# abcxyz
qr2 - paste('abc',str1,sep='')
print(qr2)
-
Actual output:
[1] abc\str\
I also tried putting an escape sequence before the quote, but couldn't get the
Dear R community,
I am new to R, a reforming SAS user :) I am running R 2.10.1 on a Windows XP
machine. I would like to write linear functions of my coefficient parameter
estimates from a glm, but am having a difficult time understanding the
parameterization R uses. In the toy example
Jim,
Thanks for the reply and your help on this.
In short, it's close but not quite there. In the plot you've produced, I'm
looking to get the trinagular points plotted over the top of the bar chart.
Does that make sense?
Just so you know, there are 2 other considerations:
- 1/ ideally, I'd
Hi Erik,
The reported problem is with the rjson package.
Then I tried with RJSONIO, which worked fine and aparently is faster.
Thanks.
On Wed, Jun 30, 2010 at 4:05 PM, Erik Iverson er...@ccbr.umn.edu wrote:
You don't say what package fromJSON is in, or give us the ability to
reproduce the
Paul -
When you print a string, it escapes the quotes with a
backslash. That's a property of the print() function,
not the string itself.
If you want to see the string, use cat(). The nchar()
function is also useful:
str1 - 'xyz'
qr2 - paste('abc',str1,sep='')
print(qr2)
[1] abc\xyz\
I did a standard install of R on Fedora 13 using yum as root, which I
assumed installed both the base packages and the devel packages needed
to install R Commander (there weren't any optional packages listed on
the yum info page). My version of R is updated to the latest 2.11
version.
But,
On Jun 30, 2010, at 2:05 PM, Asha Sharma wrote:
Hi,
I am looking for a way to find the lower envelope of points on a
plot, preferably specifying what percentage of points should be
allowed to lie outside the envelope. There must be a straightforward
way to do this, but I do not seem to
OK, let me wipe the egg off of my face The problem wasn't with the
break statement, it was with how I had included my functions in the
input.list list. I promise, I pounded on this for hours and saw the
problem five minutes after I sent off the e-mail. Anybody else ever
have this happen?
Hi,
On Wed, Jun 30, 2010 at 11:44 AM, Aadhithya sistaa...@gmail.com wrote:
Hi,
I have written a code in R for classifying microarray data using naive
bayes, the code is given below:
library(e1071)
train-read.table(Z:/Documents/train.txt,header=T);
It took me some time to find this bug in my code. Is this a feature of
R? Am I doing something wrong?
a=data.frame(x=1:10,y=1:10)
b=data.frame(x=11:20,y=11:20)
z=data.frame(1:10,11:20)
a$z=z
b$z=z
rbind(a,b)
Error in `row.names-.data.frame`(`*tmp*`, value = c(1, 2, 3,
4, :
Hi,
one possibility would be to calculate the convex hull using chull(). I
believe that the hull points are returned by chull() in a clockwise
order (?), so the points between the rightmost and the leftmost point in
the chull() result are the lower half of the convex hull. Remove these
There is a Fedora mailing list for R which might be better, but some
suggestions:
On 30/06/10 20:18, Carlo Tambuatco wrote:
I did a standard install of R on Fedora 13 using yum as root, which I
assumed installed both the base packages and the devel packages needed
If you want the developer
Matthew,
The ggplot documentation pages (http://had.co.nz/ggplot2) have the following
to say under geom_bar:
A bar chart maps the height of the bar to a variable, and so the base of
the bar must always been shown to produce a valid visual comparison.
Thus, I suspect what you are trying to do
--- On Wed, 6/30/10, Cable, Samuel B Civ USAF AFMC AFRL/RVBXI
samuel.ca...@hanscom.af.mil wrote:
From: Cable, Samuel B Civ USAF AFMC AFRL/RVBXI samuel.ca...@hanscom.af.mil
Subject: Re: [R] What is wrong with this code?
To: r-help@r-project.org
Received: Wednesday, June 30, 2010, 3:41 PM
Karl,
dev2bitmap runs its output through Ghostscript, and I assume that the
difference is somehow due to that. I can't say whether Ghostscript is
decreasing the file quality or just doing something clever, though.
Jonathan
On Wed, Jun 30, 2010 at 10:30 AM, Karl Brand k.br...@erasmusmc.nl
Hi,
To be honest, what you mean by a (linear) lower envelope becomes less
and less clear to me. Take any cloud of 2-d points. The convex hull
consists of a number of these points - or alternatively, of a number of
line segments between successive ones of these points. Thus, every one
of
Anyway, I still wouldn't mind some advice on character
matching.
Thanks.
If so we need a reproducible example of what you are doing.
OK, let's say I have three strings. Str1=abc. Str2=abcd.
Str3=efgh.
I want to compare Str1 and Str2 in such a way that R detects that Str2
indeed
Cable, Samuel B Civ USAF AFMC AFRL/RVBXI wrote:
Anyway, I still wouldn't mind some advice on character
matching.
Thanks.
If so we need a reproducible example of what you are doing.
OK, let's say I have three strings. Str1=abc. Str2=abcd.
Str3=efgh.
I want to compare Str1 and Str2 in
Try this:
lapply(list(Str2, Str3), grepl, pattern = Str1)
On Wed, Jun 30, 2010 at 5:22 PM, Cable, Samuel B Civ USAF AFMC AFRL/RVBXI
samuel.ca...@hanscom.af.mil wrote:
Anyway, I still wouldn't mind some advice on character
matching.
Thanks.
If so we need a reproducible example
Hi,
I'm having especially hard time today and couldn't find any
clue/answer through the internet. I hope you can help.
I'm in a process of writing a script to estimate error correction
model, and I was following an example in Bernhard Pfaff's Analysis of
Integrated and Cointegrated Time Series
Hi,
I am trying to model a score over time. This score shows a ceiling effect. I
was
willing to use a longitudinal tobit model, such as the one described by Twisk
et
al. (Twisk_Longitudinal tobit regression: A new approach to analyze outcome
variables with floor or ceiling effects_JCE_2009)
Okay, here is a reproducible example of a possible solution (actually it
probably does not do what you want but it's a start for discussion. Note it is
actual code and data which is what is needed.
===
str1 - abc
str2 - abcd
str3 - efgh
Peter Dalgaard wrote:
The first issue of the second volume of The R Journal will shortly be
available at jour...@r-project.org/current.html. Thanks to everyone
As no less than 16 people has informed me, that of course wants to be
http://journal.r-project.org/current.html
(That's what you get
On 2010-06-30 14:28, Erik Iverson wrote:
Cable, Samuel B Civ USAF AFMC AFRL/RVBXI wrote:
Anyway, I still wouldn't mind some advice on character
matching.
Thanks.
If so we need a reproducible example of what you are doing.
OK, let's say I have three strings. Str1=abc. Str2=abcd.
Have you changed the values in b.df? My reading of the original b.df in Erin's
post was that there were no common values in PATIENT_ID and ID.
--- On Tue, 6/29/10, jim holtman jholt...@gmail.com wrote:
From: jim holtman jholt...@gmail.com
Subject: Re: [R] merging/intersecting 2 data frames
Dear Martin,
Thank you very much for the (reassuring and helpful) response.
Best regards,
Costas
On Jun 30, 2010, at 3:58 PM, Martin Maechler wrote:
CA == Constantinos Antoniou constantinos.antoniou.rli...@gmail.com
on Wed, 30 Jun 2010 12:07:16 +0300 writes:
CA == Constantinos Antoniou
Hello
I have two series (that can have with different frequencies or with missing
values).
I merge them and use na.locf, getting a zoo objet with a common index and
two core columns.
How can I add this columns getting a new zoo series?
Any other way of adding two asynchronou series?
regards
I did a standard install of R on Fedora 13 using yum as root, which I
assumed installed both the base packages and the devel packages needed
to install R Commander (there weren't any optional packages listed on
the yum info page). My version of R is updated to the latest 2.11
version.
But,
Hi,
Thanks to both of you for taking the time to answer my question. I was
maybe not very clear in the way I framed my question. By plot, I meant
an x-y plot with a cloud of points which should have a linear lower
envelope. Is there a way to both plot as well as get the parameters of
the
If I just add them (without merging) I get only the common elements.
rowsum doesn't work for me
--
View this message in context:
http://r.789695.n4.nabble.com/merging-and-adding-time-series-tp2274125p2274131.html
Sent from the R help mailing list archive at Nabble.com.
Manussawee,
What type of object is series? We could help you better if we could
reproduce exactly what you are trying to do, which requires more information
(you made a good start by including data and code, though).
The output of diff is a vector (time series, ...) with length one less than
the
On 30/06/10 20:46, Michael Lachmann wrote:
It took me some time to find this bug in my code. Is this a feature of
R? Am I doing something wrong?
a=data.frame(x=1:10,y=1:10)
b=data.frame(x=11:20,y=11:20)
z=data.frame(1:10,11:20)
a$z=z
You are (kind of) assigning *two* columns from the data
Hi,
your problem is called string matching. Search for that term on
rseek.org, there are a couple of functions and packages. And Wikipedia
can tell you everything you ever wanted to know about string matching
(and more).
HTH,
Stephan
Cable, Samuel B Civ USAF AFMC AFRL/RVBXI schrieb:
On Jun 30, 2010, at 4:02 PM, Asha Sharma wrote:
Hi,
Thanks to both of you for taking the time to answer my question. I
was maybe not very clear in the way I framed my question. By plot, I
meant an x-y plot with a cloud of points which should have a linear
lower envelope. Is there a way
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