Why does the output in the following say 2 and not 6?
count.fields(textConnection(LL1532Ap,ABC# Depot-A+,,1971,8,2
+ LL1532Ap,ABC# Depot-A+,Bhutan,1971,6,1
+ LL1532Ap,ABC# Depot-A+,China,1971,17,1
+ LL1532Ap,ABC# Depot-A+,China,1971,33,1
+ LL1532Ap,ABC# Depot-A+,HongKong,1971,16,2
+
On 26-03-2012, at 08:16, Ashish Agarwal wrote:
Why does the output in the following say 2 and not 6?
count.fields(textConnection(LL1532Ap,ABC# Depot-A+,,1971,8,2
+ LL1532Ap,ABC# Depot-A+,Bhutan,1971,6,1
+ LL1532Ap,ABC# Depot-A+,China,1971,17,1
+ LL1532Ap,ABC# Depot-A+,China,1971,33,1
+
OMG.
I think it uses comment character # as default in the argument.
comment.char = #
How do I turn it off?
On Mon, Mar 26, 2012 at 11:56 AM, Berend Hasselman b...@xs4all.nl wrote:
On 26-03-2012, at 08:16, Ashish Agarwal wrote:
Why does the output in the following say 2 and not 6?
On 26-03-2012, at 08:26, Berend Hasselman wrote:
On 26-03-2012, at 08:16, Ashish Agarwal wrote:
Why does the output in the following say 2 and not 6?
count.fields(textConnection(LL1532Ap,ABC# Depot-A+,,1971,8,2
+ LL1532Ap,ABC# Depot-A+,Bhutan,1971,6,1
+ LL1532Ap,ABC#
comment.char = NULL does not work.
Is there any way to make it NULL rather than having a specific character
like '%'?
On Mon, Mar 26, 2012 at 12:06 PM, Berend Hasselman b...@xs4all.nl wrote:
comment.char = #
How do I turn it off?
???
How about comment.car=% for example?
Berend
On 26-03-2012, at 08:40, Ashish Agarwal wrote:
comment.char = NULL does not work.
Is there any way to make it NULL rather than having a specific character like
'%'?
Why don't you try something?
comment.char=
looks quite obvious and worth a try.
Berend
On 26-03-2012, at 08:33, Ashish Agarwal wrote:
OMG.
I think it uses comment character # as default in the argument.
comment.char = #
How do I turn it off?
???
How about comment.car=% for example?
Berend
__
R-help@r-project.org mailing
thanks. works very well.
On Mon, Mar 26, 2012 at 12:12 PM, Berend Hasselman b...@xs4all.nl wrote:
On 26-03-2012, at 08:40, Ashish Agarwal wrote:
comment.char = NULL does not work.
Is there any way to make it NULL rather than having a specific character
like '%'?
Why don't you try
dbh is the column name. What is the name of your data?
Lets assume your data is called YOUR_DATA
then try:
with(YOUR_DATA, hist(dbh))
OR
hist(YOUR_DATA$dbh)
OR
hist(YOUR_DATA[, dbh])
etc...
bamboohydraulics wrote
Dear all
I am a BEGINNER and have R on my Mac. I saved my excel
On Mar 25, 2012, at 2:43 PM, ritwi...@isical.ac.in wrote:
Thanks David, your suggestion works fine.btw I have another
question..If I set (n,m) little bit large, say (n=20,m=10), R
cannot
handle the large data frame generated through expand.grid.Is
there
any way to increase
Hi,
I'm trying to use the excel.link package to write data to excel
spreadsheets. I've installed the RDCOMClient package as required but get the
error:
package 'RDCOMClient' is not installed for 'arch=x64'
I'm on Rx64 2.13.0.
I assume it means the RDCOMClient package does not work on the x64
Hello,
my question is if anyone has any good ideas how to create a Markov Chain
from ordered data. So, I have some sort of time series, and if value1
happens as time1 and value2 happens at time2 I record this as an update to
the probability transition matrix. The problem is that I cannot
The test you are requesting is ***MEANINGLESS***. The ``effect value''
of a single
level is ill-defined (or in the more usual parlance, not estimable).
The dummy.coef()
procedure suggested by Gabor gives you point estimates *subject to the
constraints*
imposed by the contrasts used. The
Petr, thanks! I've now got a function I can work with. Regards!
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Hi!
I have two dimensional dataset which has and I need to decide if a point
lies in some confidence level. If a point has low confidence/density
it can be anomaly which I need to find.
For example:
#load library
library(sm)
#get some data
x.locs = c(74, 74.5, 75, 77,74.5)
y.locs = c(64,
Hi Camille,
Probably you have to check wether there is any infinte value in x.
Or calculate something like that for your x-axis:
x[1:(ll-1)]+diff(x)/2
Regards,
Pascal
- Mail original -
De : Camille Leclerc camille.lecl...@ymail.com
À : r-help@r-project.org
Cc :
Envoyé le : Lundi 26
Hi guys,
I'm quite new to R but quite enthousiastic. I'm trying to rewrite a bit of
code in order to make it faster, so instead of nesting for loops I'm trying
some apply functions. Since it's a combination of lists of matrices and
other matrices, I would like to use lapply() on the list and
To my understanding, library(bigmemory) should allow us to create a matrix
larger than 2GB (say 17,000 by 17,000) by temporarily storing the data on
harddisk. But I try the following codes to create such a matrix.
library(bigmemory)
A - big . matrix (17000 , 17000 , type =double, init = 0)
I am a novice R user.
I would like to be able to graph some simple piecewise functions/functions
with domain restrictions in R, but I'm having trouble defining such
functions. For example, I would like to define the following function:
f(x)={x^2 if -1xx; 1 if 2x3}
Notably, the function is
In the package lasso2, there is a Prostate Data. To find coefficients in the
prostate cancer example we could impose L1 constraint on the parameters.
code is:
data(Prostate)
p.mean - apply(Prostate, 5,mean)
pros - sweep(Prostate, 5, p.mean, -)
p.std - apply(pros, 5, var)
pros - sweep(pros,
Thank you, Dr. Therneau... I got a similar answer from Dr. Lumley:
On Mar 24, 2012, at 4:05 PM, Thomas Lumley wrote:
As far as I know there isn't any theoretical justification for the
t-distribution but it empirically works better.
You can get tests with a t or F reference distribution
by the way 0.44 is the optimal choice of lasso constrain.
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Dear all
I am a BEGINNER and have R on my Mac. I saved my excel file as .txt file, I
have just one column with first row as the column name. My file when read by
R looks like this. After reading the table I try to make a histogram by
hist(dbh), it says object dbh not found. What am I doing
It 'exactly means' what it says. We have no idea who installed it from
the sources, and you need to take that up with them (or yourself, if it
were you).
Please do follow the posting guide and give the 'at a minimum'
information required. (Your R is seriously obsolete, and you were asked
Need to fix up the file having 6 and 7 columns to be read as 6 columns
only. Here is the working. Can somebody please let me know how do I
maintain the order in which rows were read and append the two files into
one:
count.fields(textConnection(LL1532Ap,ABC# Depot-A+,,1971,8,2
LL1532Ap,ABC#
On 24/03/12 09:08, iliketurtles wrote:
Hi,
I am mediocre at R, maybe 1000 hours experience, but I received an 8GB
dataset and I don't know what to do with it. I have to do extensive analysis
over it for my Honours thesis.
I can't even import it. I've tried;
- Splitting it up using the
Does
f - function(x){
ifelse((-1 x x 1) | (2 x x 3),x^2,NA)
}
plot(f,xlim=c(-3,5))
give you what you want?
cheers,
Rolf Turner
On 26/03/12 11:08, chad.mills wrote:
I am a novice R user.
I would like to be able to graph some simple
On 2012-03-25 21:20, Sebastián Daza wrote:
Hi everyone,
I am just trying to figure out how to do a xyplot where in addition to
dots and lines I can change dots' colors according to an individual
variable (e.g., marital disruption across time, a dummy 0/1). When I
use groups specification (see
Hi,
I am trying to do plot a scatterplot matrix using pairs() from
the package graphics. There are now a few things I'd like to improve
for a better understanding.
1) My scatterplot uses two log-scaled axis...as I
don't know how to set them in pairs() I calculated the log before but now
the
On 26-03-2012, at 00:17, MBoersma wrote:
Hi guys,
I'm quite new to R but quite enthousiastic. I'm trying to rewrite a bit of
code in order to make it faster, so instead of nesting for loops I'm trying
some apply functions. Since it's a combination of lists of matrices and
other matrices,
On similar lines, how do I assign the position of the an occurence of a
value say 7 in a data vector to another data vector?
nFields
[1] 6 6 6 6 6 6 7 7 6 6 6 7 6 6 6 6
I need the output data vector showing occurence of 7 as:
[1] 7 8 12
I tried following but both has errors
xFields7 - NULL
for
Please help to solve that problem:
filter and merge 2 big Df's by=t_chr in sec.
require(zoo)
t1=2012-03-25 17:00:00.0
t2=2012-03-25 17:00:05.0
t1_POSIXlt-strptime(t1, %Y-%m-%d %H:%M:%OS)#
t2_POSIXlt-strptime(t2, %Y-%m-%d %H:%M:%OS)#
#
On 26-03-2012, at 11:34, Ashish Agarwal wrote:
On similar lines, how do I assign the position of the an occurence of a
value say 7 in a data vector to another data vector?
nFields
[1] 6 6 6 6 6 6 7 7 6 6 6 7 6 6 6 6
I need the output data vector showing occurence of 7 as:
[1] 7 8 12
I
Dear list,
I am getting an error message with pin and I am not quiet sure how to fix it.
library(maps)
op-par(mar=c(1,1,1,1))
map(xlim=c(-40,-45),ylim=c(60,65), boundary=T, fill=T, col='gray95')
Error in par(pin = p) :
invalid value specified for graphical parameter pin
par(pin)
par(pin)
On Sun, Mar 25, 2012 at 10:20 PM, Thomas Adams thomas.ad...@noaa.gov wrote:
Gabor,
Thank you for your help -- it did help me a lot. However, with my data:
lead_time cycle r_squared fcst_date
1 6 0 5.405095e-02 07/31/2010
2 12 0 5.521620e-06 07/31/2010
3
On 12-03-26 7:17 AM, Aurelie Cosandey Godin wrote:
Dear list,
I am getting an error message with pin and I am not quiet sure how to fix it.
library(maps)
op-par(mar=c(1,1,1,1))
map(xlim=c(-40,-45),ylim=c(60,65), boundary=T, fill=T, col='gray95')
Error in par(pin = p) :
invalid value
Should of seen that! It works now.
Thank you Duncan,
Aurelie
On 2012-03-26, at 8:39 AM, Duncan Murdoch wrote:
On 12-03-26 7:17 AM, Aurelie Cosandey Godin wrote:
Dear list,
I am getting an error message with pin and I am not quiet sure how to fix
it.
library(maps)
I cannot for the life of me figure this out:
What's the parameter to fill in with color circles made with circles()? col
changes the line color, but all I see in the help is a reference to additional
graphic parameters, and no examples via google.
Thanks!
John Muccigrosso
I have a question regarding NA in randomForest (in R). I have a dataset
which include both numerical and non-numerical variables, and the data
includes some NA. I tried to use na.roughfix but then i get an error
message na.roughfix only works for numeric or factor. I also tried
rfImpute but this
Your data set probably has character variables. You can transform them
into factors before running na.roughfix.
Weidong Gu
On Mon, Mar 26, 2012 at 8:17 AM, silje skår silje@gmail.com wrote:
I have a question regarding NA in randomForest (in R). I have a dataset
which include both numerical
Gabor,
That does it! I can't thank you enough
Many thanks,
Tom
On Mon, Mar 26, 2012 at 7:22 AM, Gabor Grothendieck ggrothendi...@gmail.com
wrote:
On Sun, Mar 25, 2012 at 10:20 PM, Thomas Adams thomas.ad...@noaa.gov
wrote:
Gabor,
Thank you for your help -- it did help me a lot.
Dear all,
I have a data-set of 91 variables.
It is related with a qualitative analysis I made to analyse a few
phenomena. For this reason the questions are grouped in 10 clusters, since
they express different phenomena of the analysis. I made the subset to
collect the questions and represent the
On 26/03/2012 8:09 AM, John D. Muccigrosso wrote:
I cannot for the life of me figure this out:
What's the parameter to fill in with color circles made with circles()? col changes the
line color, but all I see in the help is a reference to additional graphic
parameters, and no examples via
Hello, I didn't quite understand what you need, but maybe you can have a look
here:
www.slideshare.net/whitish/textmining-with-r
R code fragments are in appendixes of the presentation.
Hope this will help,
-Alex
From: r-help-boun...@r-project.org
Hi All,
I need to scale variable of tokens (several words per observation) to be able
to use it for svm().
For example, i have varible x4=(how,grow,tree)
Any ideas how to scale to use in svm()?
Thank you,
-Alex
[[alternative HTML version deleted]]
Dear all,
I am trying to conduct an enhanced version of factor analysis with a
SPSS interface that allows to use R. This approach has been suggested in
the recent article:
Basto, M. and J.M. Pereira An SPSS R-Menu for Ordinal Factor Analysis.
Journal of Statistical Software 46, pp. 1-29.
Hi everyone,
does anyone know, which test of uniformity is run under the command
range.circular() in the circular statistics package? It didn't say anything in
the description of this command.
Your help would be appreciated a lot.
Benedikt
[[alternative HTML version deleted]]
Hello,
I have two different dataset, and wanted to join the two.
For example I have a table of codes of cities, and other with with the
codes of travels, [source for the destine].
what he wanted was to have a new data.frame with all the information
city-data.frame(city=Barcelona,cod=1)
Hi,
I'm using the SEM package to estimate a model with a binary variabele as
dependent variable.
In the literature I have to use then the correlation matrix, made by
function hetcor(). Literature also says that the standard errors are not
correct then.
My question is if somebody knows what the
Hi R-help users..
I mistakenly posted a now rejected bug report
(https://bugs.r-project.org/bugzilla3/show_bug.cgi?id=14855), but the
subject still bugs me..!
If I have a package called MyPackage with C code inside, then library
or require(MyPackage) will call loadNamespace() which will look for
Yihui is correct that an error is generated. I should have mentioned that this
is
something I wanted to show in a vignette, and I got 103 characters as the
length of the
maximal line from a sink() file. Yihui's use of nchar is more elegant.
Thus the question remains of how to avoid margin
It isn't quite clear to me that cod in data frame city and pos in
travel are are actually the same index, but if so then you can easily
use merge() for this task.
Sarah
On Mon, Mar 26, 2012 at 5:41 AM, MSousa ricardosousa2...@clix.pt wrote:
Hello,
I have two different dataset, and wanted to
Please provide your code as is requested in the posting guidelines.
At a guess, you have read in your data into a data.frame called dhb with a
variable called dhb.
Try hist(dhb$dhb) and see what happens.
To see a bit more of what you've got try
str(dhb) to see what the sdtructure of the data
On similar lines, how do I assign the position of the an occurence of a
value say 7 in a data vector to another data vector?
nFields
[1] 6 6 6 6 6 6 7 7 6 6 6 7 6 6 6 6
I need the output data vector showing occurence of 7 as:
[1] 7 8 12
which(nFields==7)
Regards
Petr
I tried
On 26/03/2012 6:24 AM, Henrik Alsing Friberg wrote:
Hi R-help users..
I mistakenly posted a now rejected bug report
(https://bugs.r-project.org/bugzilla3/show_bug.cgi?id=14855), but the
subject still bugs me..!
If I have a package called MyPackage with C code inside, then library
or
On 26/03/2012 7:32 AM, Till Below wrote:
Dear all,
I am trying to conduct an enhanced version of factor analysis with a
SPSS interface that allows to use R. This approach has been suggested in
the recent article:
Basto, M. and J.M. Pereira An SPSS R-Menu for Ordinal Factor Analysis.
Journal
Dear all,
I would like to plot under the same plot
many curves like
mycdf-ecdf(runif(100))
plot(mycdf)
curve(mycdf,from=-1,to=1)
mycdf-ecdf(runif(200)+3)
plot(mycdf)
curve(mycdf,from=-1,to=1)
as you can see each new call to curve redraws (erases) the window. How I can
have an effect like
You can use lines() with ecdf objects or use the
not-at-all-surprisingly-named add = TRUE parameter of curve().
Michael
On Mon, Mar 26, 2012 at 10:44 AM, Alaios ala...@yahoo.com wrote:
Dear all,
I would like to plot under the same plot
many curves like
mycdf-ecdf(runif(100))
plot(mycdf)
On Mar 26, 2012, at 16:31 , Duncan Murdoch wrote:
I think you will need to ask this question in an SPSS help forum:
- Version 2.10.x of R is quite old, and is no longer supported.
- The error message is coming from SPSS, not R
and actually, it doesn't look like an error message at all,
Hi
If you went through help page you probably could find it yourself in
shorter time then you spend writing email and waited for others to write
back.
see
?plot.stepfun
Dear all,
I would like to plot under the same plot
many curves like
mycdf-ecdf(runif(100))
plot(mycdf)
On 26/03/2012 9:30 AM, John C Nash wrote:
Yihui is correct that an error is generated. I should have mentioned that this
is
something I wanted to show in a vignette, and I got 103 characters as the
length of the
maximal line from a sink() file. Yihui's use of nchar is more elegant.
Thus the
Hi Till,
you need a plug-in for SPSS to run R, which is bound to a fixed R
version. SPSS 19 uses R2.10 and SPSS 20 uses R2.12 (both not up-to-date
R versions). So you have to download this plugin (after registering on
IBM Support) for your spss version and the according R version - or
start with a
On Mar 25, 2012, at 6:17 PM, MBoersma wrote:
Hi guys,
I'm quite new to R but quite enthousiastic. I'm trying to rewrite a
bit of
code in order to make it faster, so instead of nesting for loops I'm
trying
some apply functions.
It is an urban myth that using 'apply' functions will
casperyc casperyc at hotmail.co.uk writes:
I don't know what is wrong with your Maple calculations, but I think
you should check them carefully, because:
(1) As Petr explained, the value of the integral will be 0.5
(2) The approach of Peter still works and returns : 0.4999777
(3) And the same
Hello all
This is my first posting for some years. I am back
using R again and must say I do like the language
(regarding scripting, I also use matlab, perl, and bash).
My question involves plotting a Pareto frontier in
three dimensions. This is strictly a exercise in
visualization, I make no
Thank you Peter. The problem with you solution is that it doesn't
represent the actual values of disruption. Look this example:
person - rep(1:2, each=4)
income - c(100, 120, 150, 200, 90, 100,120, 150)
disruption - c(0,0,0,1,0,1,1,0)
time - rep(c(1:4),2)
dat -
On 25.03.2012 22:10, jiefan wrote:
I have met into this problem when I tried to run panel regression by plm.
My code:
library(plm)
indus- read.csv(file=full.csv,header=TRUE)
industry-as.data.frame(indus)
reg-lm(LnTSO2 ~ LnPGDP + LnPGDP2 + LnSOES + LnCOES + LnLIMD +
LnSHOLD + LnPRIV +
Thanks a lot :)
That helped !
Alex
From: R. Michael Weylandt michael.weyla...@gmail.com
Cc: R help R-help@r-project.org
Sent: Monday, March 26, 2012 4:48 PM
Subject: Re: [R] many curves to the same plot
You can use lines() with ecdf objects or use the
Dear all,
I am printing 7 different data sets to the same plots, if I use some colors
like (red,blue,yelow...) the different datasets are easily recognized. I would
like to use some gray scale colors for distinguising the datasets. Is there any
ready set with grayscale colors (usually the
Hi All,
I need to normalize/scale string variable which represents interests of
customers (e.g., 'cycling, rollerblading, swimming' etc).
Does anybody know how to do this, I want then use it along with other numeric
variables for SVM classification.
Appreciate for any advice.
-Alex
You might start with
?gray
Sarah
On Mon, Mar 26, 2012 at 12:49 PM, Alaios ala...@yahoo.com wrote:
Dear all,
I am printing 7 different data sets to the same plots, if I use some colors
like (red,blue,yelow...) the different datasets are easily recognized. I
would like to use some gray
Dear all,
I am working with large matrices (19.6 million elements * 1000 simulations)
and am trying to get around memory problems and vector length issues. I’ve
split the inputs so that the output vector length will not exceed 2^31.
Working on a 64bit machine with 80GB RAM, I still get close to
Thanks for the reply.
I am using the function you gave me.
complete.travel-merge(travel, city, by.x = Source, by.y = cod, all =
TRUE)
complete.travel-merge(travel, city, by.x = Destine, by.y = cod, all =
TRUE
The problem is that it gives the result that I want
The
this is what I do, IT READS THE TABLE, But then I am stuck, I removed the
header
read.table(nigeria slr misc/Nigeria India /DBHHISTOGRAM.txt, header=FALSE)
hist(nigeria slr misc/Nigeria India /DBHHISTOGRAM.txt$V1)
Error in nigeria slr misc/Nigeria India /DBHHISTOGRAM.txt$V1 :
$ operator is
If there is a header in your .txt-file you should have header=TRUE, if there
is no header you should have header=FALSE.
You have to save your dataset in a variable, for example:
myData-read.table(data.txt,header=TRUE)
Then you can make a histogram by:
hist(myData)
--
View this message in
You really need to read one of many beginners guides to R; but I will say
this much:
YOUR_DATA - read.table(nigeria slr misc/Nigeria India /DBHHISTOGRAM.txt,
header=TRUE)
then you should be able to plot it like I said previously.
If that still doesn't work, you need to read the posting guide
It worked perfectly!
Thank you
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thanks,
is working
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Hi:
I am trying to create a sawtooth waveform. I used the following
x - runif(500, min = -2, max = 2)
y - (1 -abs(x3))* ((x3) = 1)
combined - data.frame(x = x3, y = y3)
plot(combined)
and I get a triangular waveform, not sawtooth. Can someone give a
solution to create a sawtooth waveform?
Me again,
what I really dont understand is the behaivour of R here.
notice, elem is not written in brackets, why it is interpreted as
string and not as a variable?
I would expect an error elem not found because it is not defined as
variable, but in contrary it is accepted as column name, see
Hello,
The problem is that it gives the result that I want
Oh dear, it shouldn't?
The idea is based on the column of source and intended Identify the
cities and put a new data structure
The idea is something like this.
pos Source city Destine city_destine
1 1
Hi All,
I am trying to develop a GLM model in which the dependent data is a
proportion data with 4 categories. I want to develop this model as an
alternative method to Multinomial Logit Model for comparison of
results. Here is the sample data:
CategorySharesY x1 x2
1
The problem is that it gives the result that I want
I'm not sure that's what one would usually identify as a
problemcan you say a little more specifically what you are looking
to do?
Michael
On Mon, Mar 26, 2012 at 10:12 AM, MSousa ricardosousa2...@clix.pt wrote:
Thanks for the reply.
Hello,
Can someone please help me out with the optim() function.
# parameters
pars- c(a1= 0.9, a2= 0.7, a3= 0.06, a4=0.02)
y- c(Y=0.2, Z=0.1)
Ymax- c(0.8)
fucntion deriv
derivs - function(time, y, pars) {
with (as.list(c(y, pars)), {
dy = a1*Y*(1-Y/Ymax) - a2*(Y+0.001)
dz = a3*Y- a4*Z;
Hi,
Does anyone have any suggestions for plotting confidence intervals onto
fitted non-linear models?
Thank you for your help!
Kate
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thanks for the reply,
But does not the results I need. What is confusing is that when making
the first merge it gives only two cities when it should take three
travel-data.frame(pos=1,Source=1,Destine=2)
travel-rbind(travel,data.frame(pos=1,*Source=1*,Destine=3))
HI, thanks Weidong, Henrique,
this works for the example (may be a bad example, but it should be as
simple as possible),
This is however only a workaround to name the columns of a dataframe,
but is not addressing the problem itself, that is, how can I substitute
a string (used as argument in
Yes! Thanks. It was just the NA value instead of the as.null that does
the trick. Correct code for the original piecewise I stated (for those who
might be looking later) is:
f - function(x){
ifelse((-1 x x 1),x^2,ifelse((2xx3),1,NA))
}
plot(f,xlim=c(-1,3))
Hi,
*Warning: R newb here. *
I've got a 3D scatterplot (
http://www.fleetwoodswoodworks.com/scatterPlot.jpg) which I want to drape
in color, with the draped plane corresponding to the mean z values on the
plot (similar to: http://www.fleetwoodswoodworks.com/draped3Dscatterplot.jpg).
Does anyone
Hello,
I'm wondering what was the year (or year range) of collection for the
data included in the 'diamonds' dataset in ggplot2.
This information would be very helpful in interpreting the 'price' variable.
Thank you!
Marina Doucerain
__
The problem is that it gives the result that I want.
That's a new sort of problem.
You show two different merge() commands. What do you expect to happen,
vs what does happen?
Sarah
On Mon, Mar 26, 2012 at 10:12 AM, MSousa ricardosousa2...@clix.pt wrote:
Thanks for the reply.
I am using
Perhaps something like this,
x - seq(0, 10, length = 1000)
y - x %%1
Michael
On Mon, Mar 26, 2012 at 10:18 AM, mail me mailme...@googlemail.com wrote:
Hi:
I am trying to create a sawtooth waveform. I used the following
x - runif(500, min = -2, max = 2)
y - (1 -abs(x3))* ((x3) = 1)
'elem' is an attribute (the name) of the 'data' variable (bad name for
a variable), not something that is independently accessible. By very
(exceptionally!) loose analogy, think of it as being something like a
field/property of an object -- you can't get to it directly (and
that's a good thing)
On Sun, Mar 25, 2012 at 3:50 PM, stivi muhame...@wp.pl wrote:
Hello,
my question is if anyone has any good ideas how to create a Markov Chain
from ordered data. So, I have some sort of time series, and if value1
happens as time1 and value2 happens at time2 I record this as an update to
the
Fortunes candidate?!
-- Bert
On Mon, Mar 26, 2012 at 10:24 AM, Sarah Goslee sarah.gos...@gmail.com wrote:
The OP wrote
The problem is that it gives the result that I want.
Sarah's reply: That's a new sort of problem.
--
Bert Gunter
Genentech Nonclinical Biostatistics
Internal Contact
Then there's something missing in what you tell us.
# this is an awkward and inefficient way of constructing a data frame
city-data.frame(city=Barcelona,cod=1)
city-rbind(city,data.frame(city=Madrid,cod=2))
city-rbind(city,data.frame(city=Lisbon,cod=3))
Warning: This has little directly to do with R, although R and related
tools (e.g. sweave and other reproducible research tools) have a
natural role to play.
The IOM report:
http://www.iom.edu/Reports/2012/Evolution-of-Translational-Omics.aspx
that arose out of the Duke Univ. genomics testing
On 26/03/2012 1:34 PM, John Benning wrote:
Hi,
*Warning: R newb here. *
I've got a 3D scatterplot (
http://www.fleetwoodswoodworks.com/scatterPlot.jpg) which I want to drape
in color, with the draped plane corresponding to the mean z values on the
plot (similar to:
Great :)
From: Sarah Goslee sarah.gos...@gmail.com
Cc: R help R-help@r-project.org
Sent: Monday, March 26, 2012 6:51 PM
Subject: Re: [R] Predefined set of gray scale colors
You might start with
?gray
Sarah
Dear all,
I am printing 7 different data sets
Dear Researchers,
Sorry for this email but I am not a statistician, and for this I have this
problem to understand. Thanks in Advance for help and suggestions.
Gianni
I have 21 classes (00, 01, 02, 04, ,020) with different length. I did a
kruskal wall test in R with the following code
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