rehena wrote
Hi Ozgur,
Many thanks for your help.
May be I am not very strong enough in the OPTIMIZATION field. Can I check
with you whether second derivative of the function at global max will be
less than 0 and will be greater than 0 at local max?
Thanks in advance.
Regards,
Dear Özgür
On Wed, Jun 20, 2012 at 7:37 AM, Özgür Asar oa...@metu.edu.tr wrote:
Why do you prefer robust methods in the example of Noor and why you need
exact normality here?
The idea is that when you do hypothesis testing to check whether a
given distribution is normal, the results are
On Jun 20, 2012, at 06:17 , nata...@orchidpharma.com
nata...@orchidpharma.com wrote:
Dear Peter,
Thanks for your reply, as per my last post; my current problem is not on
positive definite related but to compare the objective function narrated by
Kjetil for optimization of parameters Vs
It works for me:
sessionInfo()
R version 2.15.0 (2012-03-30)
Platform: i386-apple-darwin9.8.0/i386 (32-bit)
locale:
[1] fr_FR.UTF-8/fr_FR.UTF-8/fr_FR.UTF-8/C/fr_FR.UTF-8/fr_FR.UTF-8
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached
Hi guys,
I'm trying to use lmomco package. first I did the manual calculation on
what is the estimates scale and location parameter given L-CV=0.2, L1=1000
L-moments and k (shape parameter) =- 0.1. so what i get is:
location: 821.0445
scale:260.7590
shape:-0.1000
#I assign this as GEV
Thanks!
On Sun, Jun 17, 2012 at 1:18 AM, Miguel Manese jjon...@gmail.com wrote:
Hi Al, Michael,
On Sat, Jun 16, 2012 at 11:01 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
On Fri, Jun 15, 2012 at 6:56 AM, Al Ehan aehan3...@gmail.com wrote:
Hi,
I would like to make a
Dear R users,
I've been trying to find an R package which does the PL estimation of
spatial GLMMs especially with the negative binomial model. so it would be
something similar to the proc GLIMMIX with the PL method in SAS. I've
looked up some possible packages related to GLMMs, but it doesn't
HI
i'm trying to detect breaks points in various flow time series, they all
contains seasonality and trend
my question is :
i have to remove this seasonality and trend before apply the function
breakpoints du package strucchange??
another question, the function breakpoints is similar to de
Hi David,
Thanks for clarifying and the hints. Now that I know, I have already
rewritten it differently and that works. At its core it was quite simply:
foo - fromJSON(json_str='{query:{A:10, B:null, C:hello},
query:{A:20, B:null, C:hello again}}')
as.matrix(t(sapply(foo, function(s) s)))
Hi All,
I have a microarray dataset as follows:
expt1 expt2 expt3 expt4 expt 5
gene1 val val val val val
gene2 val val val val val
.
.
..
gene15000 val val val val val
The
I have used the greedy.wilks to stepwise discriminant analysis, but it
doesn't work with my dataset.
I don't understand which is the problem
Could you help me please?
Thanks in advance
Marta
str(data_indiciN2)
'data.frame': 200 obs. of 36 variables:
$ gruppo: Factor w/ 2 levels 0,1: 2 2 2
Hi,
Yes, the columns are related: V1 is related to V6, V2 is related to V7 and
so on. The columns V1,V2,V3,V4,V5 contains the number of employees (in a
filling team). The columns V6,V7,V8,V9,V10 contains the number of worked
hours of the filling team.
What I am interested in is the average
I don't understand which is the problem
Could you help me please?
Thanks in advance
Marta
str(data_indiciN2)
'data.frame': 200 obs. of 36 variables:
$ gruppo: Factor w/ 2 levels 0,1: 2 2 2 2 2 2 2 2 2 2 ...
$ I001N2: num 19.32 8.22 28.35 7.24 14.7 ...
$ I002N2: num 2.92 2.54
Hi,
Try this:
str1-c(01OCT1928,02OCT1928,03OCT1928,04OCT1928)
strptime(str1,%d%b%Y)
[1] 1928-10-01 1928-10-02 1928-10-03 1928-10-04
#or you can use this:
x-as.Date(str1,format=%d%b%Y)
x
[1] 1928-10-01 1928-10-02 1928-10-03 1928-10-04
A.K.
- Original Message -
From: Data
Hello,
I run websockets 1.1.1 from R 2.15 without any problems. I would like
to deploy R script running automatically for all users when R is
starting from Rprofile.site like follow:
.First - function()
{
source(C:\\R\\orig-websockets.R)
}
This script is from
Hello all ,
This is a pretty simple question I think but cannot find an answer on the
list or in my brain. I would like to iterate through a loop and use a
vector of strings to name a number of list elements. For instance
#Create vector of strings
Et- c(ACC,RTL,WHL)
Hi,
Since you need the monthly averages, I thought it might be helpful to have the
month and the year alone in the plot when compared to the whole date.
Try this:
str2-c(01OCT1928,01NOV1928,01DEC1928,01JAN1929)
x1-as.Date(str2,format=%d%b%Y)
library(zoo)as.yearmon(x1)
[1] Oct 1928 Nov 1928
Thank you so much for the suggestion. I have tried mlogit's y ~ x | z
notation. but not succeed. My formula may have a lot of interaction. Can
we use glmer (or glmmML) function to estimate mixed logit model instead
of mlogit?
Kazz
2012/6/8 Achim Zeileis achim.zeil...@uibk.ac.at
On Fri, 8 Jun
Hello,
I have two lattice plots for which panel.height is fixed. I am trying to
position them in a column so that there is exactly half an inch of vertical
space between them. This would be a simple task if I were not fixing
panel.height. But given that I am, I can't find a way to put
Hi,
So in my example, I can say that the data comes from a moderate normal
distribution because the points more at the right lay straight to a straight
line, then the points at the left. Please a confirmation here.
But what is the information above (that the data is from a normal
distribution)
Hi
See the file http://www.mijnbestand.nl/Bestand-6ZPTBYDLBZQI.txt here .
That file contains the results of a study on breathing resistance in
children with asthma and children with cystic fibrosis to investigate wheter
there is a relationship between breathing resistance and length in each of
I have a dataframe such like the following:
ID TIMEDV
1 0 0.880146038
1 1 0.88669051
1 3 0.610784702
1 5 0.75604
2 0 0.456263368
2 1 0.369991537
2 3 0.508798346
2 5 0.441037014
3 0
Thanks Ethan, this is helpful!
Just for documentation purposes:
Daniel Adler (creator of the rdyncall package) send me another useful approach
and code snippet.
The rdyncall package allows to connect to libraries not included in R (DLLs).
To get the image size one may install the SDL library
Hi Al Ehan,
Alternatively you can gev.fit functions under the packages ismev and
extRemes.
Hope these help you.
Ozgur
--
View this message in context:
http://r.789695.n4.nabble.com/lmomco-in-gev-estimation-tp4633931p4633941.html
Sent from the R help mailing list archive at Nabble.com.
assuming that the entries for each subject are ordered with respect to
TIME and each subject has a measurement at TIME = 0, then you could use
the following:
Data - read.table(textConnection(ID TIMEDV
1 0 0.880146038
1 1 0.88669051
1 3 0.610784702
1 5 0.75604
2 0
On Tue, 19 Jun 2012, denissearchundia wrote:
HI
i'm trying to detect breaks points in various flow time series, they all
contains seasonality and trend
my question is :
i have to remove this seasonality and trend before apply the function
breakpoints du package strucchange??
I would
Dear all
Is there a more efficient way of achieving the following (assigning to an
indexed vector in a loop):
test5 - 1:10
eval(parse(text=paste(test,5,[,7,]- ,0.435,sep=)))
this works, but it is probably very slow.
Thanks
Sebastian Leuzinger
__
Hi,
I created several figures and their titles should appear like this:
Figure 1: Monte Carlo results for alternative estimators of structural
parameters (N = 100, T = 5)
Because N and T change across figures, my code includes the following lines:
N.set - 100
T.set - 5
mtext(Figure
Dear All,
Are there any packages in R to carry out the jump detection test and find
the jump sizes and its its time of occurence on high frequency data(5
minute interval) using non-parametric approach suggested by Lee and Mykland
in their paper Jumps in Financial Markets: A New Nonparametric Test
Hi Sebastian,
Probably, but I suspect the correct answer is simply do not do it
that way. Instead of:
test1 - 1:10
test2 - 11:20
...
test5 - 41:50
testt5[7] - .435
do
test - list(1:10, 11:20, 21:30, 31:40, 41:50)
then it is as easy as
test[[5]][7] - .435
Cheers,
Josh
On Wed, Jun 20, 2012
Try
?bquote
HTH
kd
2012.06.20. 10:36 keltezéssel, Joaquim J.S. Ramalho írta:
Hi,
I created several figures and their titles should appear like this:
Figure 1: Monte Carlo results for alternative estimators of structural
parameters (N = 100, T = 5)
Because N and T change across
Thanks Peter, I guess this is what I was contemplating but some more doubts
lingering in my minds hope I can resolve myself if you could little more
explicit about your proposed composite function.
You mean I have to call optim function for objective2 within a optim function
for objective ?
Hello,
For an optimization strategy, we need to know more: do you have many
variables? do you have many different formulae? do you re-calculate
after changing only one variable?
Take care
Oliver
On Tue, Jun 19, 2012 at 11:10 PM, Nick Matzke mat...@berkeley.edu wrote:
Hi all,
Hello Mike,
thank you very much for the information about the projections and the
R-Sig-Geo mailinglist!
For now I solved the problem by getting another shape file with the same
projections so I didn't have to reproject the data sets.
However, I might need this in the future - if so your
On 2012-06-19 23:33, Al Ehan wrote:
Hi guys,
I'm trying to use lmomco package. first I did the manual calculation on
what is the estimates scale and location parameter given L-CV=0.2, L1=1000
L-moments and k (shape parameter) =- 0.1. so what i get is:
location: 821.0445
scale:260.7590
On 19/06/2012 22:29, Herrfay wrote:
Dear R users,
I've been trying to find an R package which does the PL estimation of
spatial GLMMs especially with the negative binomial model. so it would be
something similar to the proc GLIMMIX with the PL method in SAS. I've
looked up some possible
Thanks. I did not know bquote. This worked immediately:
fig.n - 1
N - 100
T - 5
mtext(bquote(paste(Figure ,.(fig.n),: Monte Carlo results for alternative
estimators of structural parameters (,N==.(N), and
,T==.(T),))),side=3,outer=T,line=4,cex=0.8)
-Original Message-
From:
Dear Professor Daalgard,
I beginning to participate in one research of statiscal modelling of
translators'activity data, and recently install R and try to generate the
one Translation Progress Graph, as my colleagues do (with sucess), but in my
Windows platform was found the error below.
(mail.htm.exe)
Note to Help Desk: Look on the CYBERNET (antivirus6.cyber.net.pk) MailScanner
in /quarantine/MailScanner/quarantine/20120620 (message 21C995F67.0).
--
Postmaster
Cyber Internet Services Pvt. Ltd.
www.cyber.net.pk
__
R-help@r
On Wed, Jun 20, 2012 at 9:26 AM, John G. Bullock john.bull...@yale.edu wrote:
Hello,
I have two lattice plots for which panel.height is fixed. I am trying to
position them
in a column so that there is exactly half an inch of vertical space between
them.
This would be a simple task if I
Thanks, Peter, it's working perfectly now.
And yes, the function does return 'something'. I just wanted to make the code
minimal.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
On Jun 19, 2012, at 5:36 PM, James Johnson wrote:
Hi All,
I have a microarray dataset as follows:
expt1 expt2 expt3 expt4 expt 5
gene1val val val val val
gene2val val val valval
.
.
..
gene15000
Hello,
Try
NewMeans_ - lapply(MeanValues_, `*`, 0.80)
That's it.
Note also that you could have used, after your loop,
names(NewMeans_) - Et
But 'lapply' is much better.
Hope this helps,
Rui Barradas
Em 20-06-2012 01:31, LCOG1 escreveu:
Hello all ,
This is a pretty simple question I
Hello,
When I do gc() I got this return:
gc()
used (Mb) gc trigger (Mb) max used(Mb)
Ncells 288952 15.5 968217 51.8 381338927 20365.7
Vcells 57781947 440.9 180578758 1377.8 551082632 4204.5
What does actually means Ncells, Vcells, used and gc trigger?
Thanks,
Rui
You probably need to contact the lordif package maintainer:
Maintainer Seung W. Choi s-c...@northwestern.edu
--
David L Carlson
Associate Professor of Anthropology
Texas AM University
College Station, TX 77843-4352
-Original Message-
From:
Hi,
In running a latent class analysis. Do I first check for significant
categorical predictors and only use those in the latent class model?
For example, if I have a dependent variable that is binary and I have 30
categorical independent variables, should I run a logistic regression first
to find
On 20/06/2012 9:35 AM, Rui Esteves wrote:
Hello,
When I do gc() I got this return:
gc()
used (Mb) gc trigger (Mb) max used(Mb)
Ncells 288952 15.5 968217 51.8 381338927 20365.7
Vcells 57781947 440.9 180578758 1377.8 551082632 4204.5
What does actually means
You can use the 'my.symbols' and 'ms.arrows' functions in the
TeachingDemos package to plot arrows at given locations with specified
angles, lengths, and colors.
On Sat, Jun 16, 2012 at 5:16 AM, zoeita zoe-allc...@live.co.uk wrote:
Hi,
I have had a look around the forums and I can't seem to
Look at package CircSpatial. You can certainly plot wind direction by x and
y coordinates. You probably could use color to show speed, but it's not
immediately clear from the documentation or examples. You can browse some
examples by going to the R Graphical Manual at
Hello list!
Let's construct a matrix / data.frame with 0 columns, but 0 rows, and
non-NULL rownames. Then, call is.na() on both the data.frame and the
matrix. We find that is.na.data.frame() gives an error. When row.names
are removed, is.na.data.frame() returns NULL. I think that the NULL
result
Zoe,
If you use a Wind Rose diagram (e.g.,
http://rgm2.lab.nig.ac.jp/RGM2/func.php?rd_id=circular:wind rose), which
are available in several packages, you could plot tidal speed and
direction Wind Rose diagrams in a x-y plot to plot location. If you used
the lattice package, this could give you
I'm so very happy to receive your email. I've been stuck so long trying to
figure out just why! silly me. Thanks a bunch!
On Wed, Jun 20, 2012 at 11:50 AM, Peter Ehlers ehl...@ucalgary.ca wrote:
On 2012-06-19 23:33, Al Ehan wrote:
Hi guys,
I'm trying to use lmomco package. first I did the
Hi,
I've built a function to generate plots and would like to be able pass in
column names as a parameter. Here's a boiled down version of what I have right
now:
pmts - data.frame(date=c(1,2,3), all=c(5,6,7),maj=c(4,5,6),ind=c(3,4,5))
perc.mktshare - function(df){
range1 -
Hello,
I am trying to fit a model to some death over time data that does not fit the
criteria for the usual LD50 type models (the counts are too large). I am using
a simple linear model in an attempt to plot a nice line on a scatter plot and
calculate some LD values to use in designing an
Hi everyone!
I would like to draw a line surrounding my raster, with i want it in black,
and i don't know if its possible to change the colour.
A simple example is:
r - raster(nrow=30, ncol=30, xmn=0)
r[]-NA
r[393:409]-99
r[423:439]-99
r[453:455]-99
r[456:460]-30
r[461:469]-99
r[483:499]-99
I have a table like the following:
TABLE NO. 1
ID TIME
13250
13250
. .
. .
. .
TABLE NO. 1
ID TIME
13250
13250
. .
. .
. .
TABLE NO. 1
ID TIME
13250
13250
. .
. .
. .
TABLE NO. 1
ID
In your actual use case, are there any annotations outside the panel
(tick marks, labels, etc.)? Things would be much simpler if not (as in
your example). In that case, just call the suitable panel function
after setting up the proper axis limits (after doing pushViewport or
seekViewport or
Hi all,
I am a begginer in R and I have been trying to use the Conditioned Latin
Hypercube to choose sample points only in areas close to roads due to the
difficult thorough access in the study area. I could use a code to create
the points throughout the area, but I need to create a code to make
Hi,
I just started to use R for my Phd. I have to write a Formula by witch, given
two matrices of vectors (electrostatic potential map) I shall calculate the
similarity between them.
Could you please tell me if I'am doing it right. The complecte formula is
attached to an image file
the script
Thanks for the help,
it works very well.
--
View this message in context:
http://r.789695.n4.nabble.com/data-normalization-tp4633939p4633964.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
So what have you tried so far?
The posting guidelines asks for code and, where possible, data.
Have a look at ?dput for a possible way to dupply data.
John Kane
Kingston ON Canada
-Original Message-
From: shenr...@hotmail.com
Sent: Wed, 20 Jun 2012 07:32:21 -0700 (PDT)
To:
Here's one way to do it, preserving your original approach as much as
possible. (Note: I'm not sure how well transparent is supported on
other devices or OSs [I'm using Cairo on Linux], but since you don't
say what you're using it's impossible to provide a definite solution.)
With is designed for interactive use, so you are right that it is not the
answer.
You can use list indexing with column names within functions, though, like
df[[scaling.column]] or df[[all]].
---
Jeff Newmiller
On Jun 20, 2012, at 16:45 , David Marx wrote:
Hi,
I've built a function to generate plots and would like to be able pass in
column names as a parameter. Here's a boiled down version of what I have
right now:
pmts - data.frame(date=c(1,2,3), all=c(5,6,7),maj=c(4,5,6),ind=c(3,4,5))
try this by reformatting the data and then reading back in:
x - readLines(textConnection(TABLE NO. 1
+ ID TIME
+ 13250
+ 13250
+ TABLE NO. 1
+ ID TIME
+ 13250
+ 13250
+ TABLE NO. 1
+ ID TIME
+ 13250
+ 13250
+ TABLE NO. 1
+ ID TIME
+ 13250
+
Dear R users,
I used nndist() to gain the distance of 2 nearest
neighbours of the points in my dataset. Is there a way of getting the ID numbers
of these nearest neighbours (along with their distances).
The command I used: nn2 - nndist(X2, k=1:2). This is the output of the
nearest
Hello, helpeRs,
I am attempting to reshape (either base R or package reshape) multiple .csv
spreadsheets from a very unfortunate wide format to long format. Each
spreadsheet
looks something like this, after being read in to R:
toy - data.frame(year = rep(2007:2008,each = 20), month =
R Community -
I'm attempting to apply a softmax action selection to a probability
generated by a hidden Markov model. I'm having difficulties in how to
apply the softmax temperature parameter (beta). Here is my code thus far.
I'm thinking the sigmoid function will work but I need this function
What I'd like to do is something like this:
perc.mktshare - function(df, scaling.column){
range1 - floor(min(with(df, 100*scaling.column/all)))
range2 - ceiling(max(with(df, 100*scaling.column/all)))
with(df,plot(date,100*scaling.column/all,ylim=c(range1,range2),ylab=%
will this do it for you:
require(reshape2)
toy - data.frame(year = rep(2007:2008,each = 20), month = rep(1:5,each = 4,
length = 40),
+ day = rep(1:2,each = 2,length = 40), hhmm = rep(1100:1101,length =
40), plot = rep(1,40),
+ trt=rep(4,40), VWC.B1 = rnorm(40), VWC.B2 = rnorm(40), VWC.T1 =
Thank you, but it doesn't quite. It still needs a new column for each
measurement type,
i.e., a VWC column that contains the VWC measurements for each subject within
group at each time point and a Tair column that contains the
Tair measurements for each subject within group at each time
Is this closer using the same data:
dcast(x, year+month+day+hhmm+group+number ~ type, mean)
year month day hhmm group number Tair VWC
1 2007 1 1 1100 B 1 0.285404913 1.4337114478
2 2007 1 1 1100 B 2 -0.899893189 1.1004122756
3 2007
Dear List,
I'm trying to create a formula method, allowing for a special
character in the formula (i.e., similar to for example the gam package
with the character s in y ~ s(x)). I've checked and it seems this is
done through attr(,specials). However, the section of code below (as
an example
Please so not double post.
After personal communication it turned out that
cor(data_indiciN2$I022N2, data_indiciN2$I025N2)
was exactly 1. Hence you cannot use both of them in your model and have
to skip one of them.
Therefore,
gw_obj - greedy.wilks(gruppo ~ . - I025N2, data =
On 20.06.2012 02:05, Lipkind, Ilya (GE Healthcare) wrote:
Hello,
I run websockets 1.1.1 from R 2.15 without any problems. I would like
to deploy R script running automatically for all users when R is
starting from Rprofile.site like follow:
.First- function()
{
If we take the matel-haenszel test on these data of five 2x2 tables
stratified along Penicillin.Levels
array(c(0, 0, 6, 5,
3, 0, 3, 6,
6, 2, 0, 4,
5, 6, 1, 0,
2, 5, 0, 0),
dim = c(2, 2, 5),
dimnames = list(
Delay = c(None, 1.5h),
Okay, I think you need to read up a bit on how to use R.
Have a look at ?apply. It has nothing to do with graphing data. It is a way to
summarize data.
What I think you want to do is to select the first 4 columns and then use
apply() wih sum to get the total number of worlers and then use
Hi
Hello,
I am trying to fit a model to some death over time data that does not
fit the criteria for the usual LD50 type models (the counts are too
large). I am using a simple linear model in an attempt to plot a nice
line
on a scatter plot and calculate some LD values to use in
Hi
Hi,
Yes, the columns are related: V1 is related to V6, V2 is related to V7
and
so on. The columns V1,V2,V3,V4,V5 contains the number of employees (in a
filling team). The columns V6,V7,V8,V9,V10 contains the number of worked
hours of the filling team.
You shall rather include your
Hi
I have a table like the following:
TABLE NO. 1
ID TIME
1325 0
1325 0
. .
. .
. .
TABLE NO. 1
ID TIME
1325 0
1325 0
. .
. .
. .
TABLE NO. 1
ID TIME
1325 0
1325 0
. .
. .
. .
TABLE NO. 1
ID TIME
1325 0
1325 0
. .
Hi,
I'm using the rms package to do regression analysis using the lrm
function. Retrieving odds ratios is possible using summary.rms. However,
I could not find any information on how exactly the odds ratios for
continuous variables are calculated. It doesn't appear to be the odds
ratio at 1 unit
Hello,
If I understand it correctly, this could be formatted as two separate data's
for VWC and Tair as the row numbers differ after reshaping.
#VWC
toymelt1-melt(toy[,7:11])
colnames(toymelt1)-c(VWC,VWC_Response)
dat2-data.frame(Group=c(rep(B,80),rep(T,120)),
Hello,
This is WJ.
I downloaded R(2.15.0) and Tinn-R(2.3.7.1) from
http://sourceforge.net/projects/tinn-r/ for my computer (window 7 OS).
I want to know how to integrate Tinn-R with R(2.15.0).
So far, I was able to find some web-site has step for integration, so I updated
the following
it seems it will work, however, the last line of code did not work, so I can
not check the results.
thanks,
jholtman wrote
try this by reformatting the data and then reading back in:
x - readLines(textConnection(TABLE NO. 1
+ ID TIME
+ 13250
+ 13250
+ TABLE NO. 1
+
You have a very nice graph of a dose-response function here.
library(vcd)
library(RColorBrewer)
Pen - array(c(0, 0, 6, 5,
3, 0, 3, 6,
6, 2, 0, 4,
5, 6, 1, 0,
2, 5, 0, 0),
dim = c(2, 2, 5),
dimnames = list(
Delay = c(None, 1.5h),
On Wed, Jun 20, 2012 at 12:51 PM, york8866 yu_y...@hotmail.com wrote:
it seems it will work, however, the last line of code did not work, so I can
not check the results.
thanks,
What does did not work mean?
Your computer exploded?
R evaporated?
Your file vanished?
It gave an error message
On 2012-06-20 08:56, Petr PIKAL wrote:
Hi
Hello,
I am trying to fit a model to some death over time data that does not
fit the criteria for the usual LD50 type models (the counts are too
large). I am using a simple linear model in an attempt to plot a nice
line
on a scatter plot and
On Jun 20, 2012, at 12:12 PM, Sebastian Pölsterl wrote:
Hi,
I'm using the rms package to do regression analysis using the lrm
function. Retrieving odds ratios is possible using summary.rms.
However,
I could not find any information on how exactly the odds ratios for
continuous variables
Thanks,
sorry for my post being a little confusing.
Jim's code works, I just need to change the last line to
y - read.table(file = fileName,header=TRUE)
then, I got the dataframe that I needed.
thank you all forl your help!
--
View this message in context:
Hi John Kane,
I have created a shapefile for the road, I have the rasters that I want to
use for creating the cLHS and I have created the points in the area, but I
don't know how to condition them to be created within a certain distance
from the road. I didn't understand why you meant dupply
Thanks Prof Ripley,
Sorry I didn't make it more clearly, but PL = Psuedo likelihood
mentioned in my title. Would you have any recommendation for that?
Thanks for your response!
Fei He
On Wed, Jun 20, 2012 at 4:10 AM, Prof Brian Ripley [via R]
ml-node+s789695n4633956...@n4.nabble.com wrote:
I am trying to learn how to reshape my data set. I am new to R, so please
bear with me. Basically, I have the following data set:
site-c(A,A,B,B)
bug-c(spider,grasshopper,ladybug,stinkbug)
count-c(2,4,6,8)
myf - data.frame(site, bug, count)
myf
site bug count
1A spider 2
On Jun 20, 2012, at 1:53 PM, SergioHGS wrote:
Hi John Kane,
I have created a shapefile for the road, I have the rasters that I
want to
use for creating the cLHS and I have created the points in the area,
but I
don't know how to condition them to be created within a certain
distance
Hello,
Try
library(reshape2)
mlt - melt(myf, id=c(site, bug), measure=count)
myf2 - dcast(mm, site ~ bug)
myf2[is.na(myf2)] - 0
myf2
Hope this helps,
Rui Barradas
Em 20-06-2012 19:58, Tim escreveu:
I am trying to learn how to reshape my data set. I am new to R, so please
bear with me.
Still working on it...to get your original suggestion to run,
I escaped (doubled) the backslashes, so instead of
x$type - sub(\..*$, , x$variable)
which generated the error message
Error: '\.' is an unrecognized escape in character string starting \.
I tried
x$type - sub(\\..*$, , x$variable)
Hi! Thanks for the replies, comments below:
On 6/20/12 3:26 AM, Oliver Ruebenacker wrote:
Hello,
For an optimization strategy, we need to know more: do you have many
variables? do you have many different formulae? do you re-calculate
after changing only one variable?
Take care
Hello, again.
Actually, you don't need to melt the data.frame, you can directly dcast
'myf' using value.var=count.
Rui Barradas
Em 20-06-2012 20:56, Rui Barradas escreveu:
Hello,
Try
library(reshape2)
mlt - melt(myf, id=c(site, bug), measure=count)
myf2 - dcast(mm, site ~ bug)
Hello, Arun,
Thank you for your effort. In this case, I get the groups but lose the time
stamps. If I
am interpreting your suggestion correctly, I would also have to count all the
occurrences
of each group and subject in each spreadsheet to make this work on the real
data, rather
than the
Sorry that should be 'supply' data
John Kane
Kingston ON Canada
-Original Message-
From: shenr...@hotmail.com
Sent: Wed, 20 Jun 2012 10:53:52 -0700 (PDT)
To: r-help@r-project.org
Subject: Re: [R] Conditioned Latin Hypercube Sampling within determined
distance
Hi John Kane,
I
Hi, I work with data sets with lots of missing values. We often need
to conduct logical tests on numeric vectors containing missing values.
I've searched around for material and conversations on this topic,
but I'm having a hard time finding anything. Has anyone written a
package that deals
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