Re: [R] R-help, please

Hi Kim, this sounds like a homework question which is not meant for this list, I don't believe you need a package for this, but you may find the ifelse function along with the sum()function useful. You can get more information by typing ?ifelse and ?sum into R. Regards, Rhydwyn Rhydwyn

Re: [R] Running GCV Optimization under Ridge Regression

Hi John/R-users, - I have attached the data set in the mail in .txt format, can be read using read.table(). Kindly let me know please if this is not sufficient. - Also, to specify the modeling scheme I am stuck at: 1. Have numerical regressors GDP, HPA and FX to predict the variable

Re: [R] ERROR - non-conformable arguments

Hi Do not use attachment, copy result of dput(object) to your mail instead. This enables us to see how your data really look like. I get different error. > widesII(used, available, avknown = TRUE, alpha = 0.05) Error in widesII(used, available, avknown = TRUE, alpha = 0.05) : used and

Re: [R] How to coerce a parameter in nls?

I posted a suggestion to use nlmrt package (function nlxb to be precise), which has masked (fixed) parameters. Examples in my 2014 book on Nonlinear parameter optimization with R tools. However, I'm travelling just now, or would consider giving this a try. JN On 15-09-20 01:19 PM, Jianling

[R] Fwd: gdal_translate and gdalwarp question

Hello, I have some doubts on the usage of some gdal tools. After converting a hdf file to tif I want to reproject to SIRGAS2000 and clip between lats of 22 to 29 S and lats of 40 to 50 W. HDF file can be downloaded at https://app.box.com/s/16cf7qv6af6gsz1v66staori2mtneu0r Basically I'm

Re: [R] Running GCV Optimization under Ridge Regression

No data. Please have a look at http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example and http://adv-r.had.co.nz/Reproducibility.html John Kane Kingston ON Canada > -Original Message- > From: lordpree...@gmail.com > Sent: Tue, 22 Sep 2015 01:19:38

Re: [R] vector manipulations -- differences

Use ?mappy and ?rep.int > x[unlist(mapply(":",2:4,4))] - x[rep.int(1:3,3:1)] [1] 3 7 20 4 17 13 Cheers, Bert Bert Gunter "Data is not information. Information is not knowledge. And knowledge is certainly not wisdom." -- Clifford Stoll On Mon, Sep 21, 2015 at 2:17 PM, Dan D

Re: [R] R-help, please

It looks like you sent the e-mail in HTML. It is unreadable. You must sent e-mail to R-help in plain text not HTML John Kane Kingston ON Canada > -Original Message- > From: le4...@mweb.co.za > Sent: Mon, 21 Sep 2015 16:14:41 +0200 > To: r-help@r-project.org > Subject: Re: [R] R-help,

Re: [R] R-help, please

Your question looks very much like homework and this list does not do homework for people. Talk to your instructor. cheers, Rolf Turner On 22/09/15 02:14, le4...@mweb.co.za wrote: Good day, My name is Kim Nguyen and please I need your help with: How to calculate the PASS rate of the

Re: [R] How to coerce a parameter in nls?

Hello, Gabor, Thanks again for your suggestion. And now I am trying to improve the code by adding a function to replace the express "Rm1 * ref.1 + Rm2 * ref.2 + Rm3 * ref.3 + Rm4 * ref.4 + Rm5 * ref.5 + Rm6 * ref.6" because I have some other dataset need to fitted to the same model but with more

Re: [R] extract from data.frame (indexing)

And the action is? John Kane Kingston ON Canada > -Original Message- > From: nico.gutierr...@gmail.com > Sent: Mon, 21 Sep 2015 16:48:45 +0200 > To: r-help@r-project.org > Subject: [R] extract from data.frame (indexing) > > Hi All, > > I need to do the following operation: > > >

Re: [R] How to coerce a parameter in nls?

Thanks Prof. Nash, Sorry for late reply. I am learning and trying to use your nlmrt package since I got your email. It works good to mask a parameter in regression but seems does work for my equation. I think the problem is that the parameter I want to mask is a group-specific parameter and I

Re: [R] How to coerce a parameter in nls?

Express the formula in terms of simple operations like this: # add 0/1 columns ref.1, ref.2, ..., ref.6 dproot2 <- do.call(data.frame, transform(dproot, ref = outer(dproot$ref, seq(6), "==") + 0)) # now express the formula in terms of the new columns library(nlmrt) fitdp1<-nlxb(den ~ (Rm1 *

Re: [R] Extract from data.frame

Nico, I expect there are many better ways to do this, but this does work: max_row <- (1:nrow(df))[which.max(df$Amount)] mean(df$Amount[max_row + c(-1, 0, 1)]) > max_row <- (1:nrow(df))[which.max(df$Amount)] > mean(df$Amount[max_row + c(-1, 0, 1)]) [1] 151.6667 R. Mark Sharp, Ph.D. Director of

Re: [R] how to add 1 + 1 with the interface between R and C

I think is time to learning Rcpp! :-) thank you (Peter Dalgaard and Dirk Eddelbuettel ) by the examples! the more simples are often more informatives... cleber Em 21/09/2015 12:36, Dirk Eddelbuettel escreveu: peter dalgaard gmail.com> writes: C is call by value and k and res are

Re: [R] Extract from data.frame

Note the following problems: 1. " max_row <- (1:nrow(df))[which.max(df$Amount)]" This is a bit silly. max_row <- which.max(df$Amount) will do. See ?which.max 2. What happens if the max is the first or last row? e.g. > dat <- data.frame(a=runif(5),b=1:5) > max_row<- which.max(dat$b) >

Re: [R] Download showing as exploit

On 21/09/2015 10:30 AM, Tim Kingston wrote: > > Hi , > > I work for the NHS, and our IT service has been unable to download as its > anti-virus software says it contains an exploit. > > Is this normal? Is there a way around this? > > Kind regards, > > Tim Kingston > You don't say what

Re: [R] Extract from data.frame

On Mon, Sep 21, 2015 at 9:52 AM, Nico Gutierrez wrote: > Hi All, > > I need to do the following operation from data.frame: > > df <- data.frame(Year = c("2001", "2002", "2003", "2004", "2005", "2006", > "2007"), Amount = c(150, 120, 175, 160, 120, 105, 135)) >

Re: [R] ggplot2 will not install after system upgrade

On Thu, 2015-09-03 at 16:47 -0400, Ista Zahn wrote: > Hi Jeff, > Your chances of getting a useful response will increase if you > provide > some additional information. For example, which version of R? Which > version of ggplot2? What sequence of commands produces the error? > What > _exactly_

Re: [R] How to coerce a parameter in nls?

Thanks Gabor, That works good to rewrite the express the formula! Thanks a lot! Regards, Jianling On 21 September 2015 at 10:43, Gabor Grothendieck wrote: > Express the formula in terms of simple operations like this: > > # add 0/1 columns ref.1, ref.2, ..., ref.6 >

Re: [R] Trees (and Forests) with packages 'party' vs. 'partykit': Different results

Achim, thank you very much for your help, this really cleared up a number of issues. As for the differences in results between the party and partykit implementations of ctree, I guess that the situation is indeed as you assumed. Four out of five variables have p-values <2.2e-16. (However, it is

Re: [R] R-help, please

Good day, My name is Kim Nguyen and please I need your help with: How to calculate the PASS rate of the data in the table below, with PASS in a single subject if value>=50 and PASS will be given if PASS 3 out of 4 subjectsWhich package will I need to use in this analysis ID Literacy Maths

Re: [R] how to add 1 + 1 with the interface between R and C

peter dalgaard gmail.com> writes: > C is call by value and k and res are pointers. You need a dereferencing step or nothing with happen. Try > > *res = *k + 1; Or you use Rcpp which writes the glue code. Save the following into a file: #include // [[Rcpp::export]] int adder(int x, int y) {

[R] Extract from data.frame

Hi All, I need to do the following operation from data.frame: df <- data.frame(Year = c("2001", "2002", "2003", "2004", "2005", "2006", "2007"), Amount = c(150, 120, 175, 160, 120, 105, 135)) df[which.max(df$Amount),] #to extract row with max Amount. Now I need to do 3 years average around the

[R] Download showing as exploit

Hi , I work for the NHS, and our IT service has been unable to download as its anti-virus software says it contains an exploit. Is this normal? Is there a way around this? Kind regards, Tim Kingston Sent from my HTC [[alternative HTML version deleted]]

Re: [R] HELP IN GRAPHS - slip screen (URGENT)

Hi Rosa, I think I understand more or less what you want, but the example below uses made up data as I do not have access to your files. The following code should produce a block of eight plots with the y axes on the leftmost plots only and the x axes on the bottom row only. I think I have what

[R] Accounting for correlated random effects in coxme with matrix from a phylogeny rather than pedigree

Hello All, I have a problem with running the mixed effects Cox regression model using a distance matrix from a phylogeny rather than a pedigree. I searched previous posts and didn't find any directly relevant previous posts. I am interested in using a mixed effects Cox regression model to

[R] extract from data.frame (indexing)

Hi All, I need to do the following operation: Year Amount Amount.1 1 2001150 150 2 2002120 120 3 2003175 175 4 2004160 160 5 2005120 120 6 2006105 105 7 2007135 135 [[alternative HTML version deleted]]

Re: [R] how to add 1 + 1 with the interface between R and C

> On 21 Sep 2015, at 04:03 , Cleber N.Borges wrote: > > Dear useRs, > > I would like some help on how to make the sum of 1 + 1 > but using the interface between A and C. > > the function call does .call lock and close the R. > > Thank you for any help it. Either you

Re: [R] R code help!

Hi Jean, Thank you so much! Steve On Sat, Sep 19, 2015 at 1:02 PM, Adams, Jean wrote: > Here's one way to save your results, using a list of lists and a for() > loop. > > nsim <- 100 > outputs <- vector("list", nsim) > for(i in 1:nsim) { > outputs[[i]] <- sim.f(p.s=.05,

Re: [R] Extract from data.frame

year <- df$Year[ which.max( df$Amount)] df[ df$Year %in% (as.numeric( as.character( year)) + -1:1), ] Year Amount 2 2002120 3 2003175 4 2004160 On Mon, Sep 21, 2015 at 04:52:46PM +0200, Nico Gutierrez wrote: > Hi All, > > I need to do the following operation from data.frame: > >

Re: [R] extracting a value from XML

Hi Bob, Thanks, can you help me undestand why it starts with //observation and how you know that it is a node? Glenn On Sep 21, 2015, at 01:56 PM, boB Rudis wrote: This is how (one way) in both the xml2 package and XML package: library(xml2) library(XML) txt <- ' ' doc

Re: [R] How to coerce a parameter in nls?

I've not used it for group data, and suspect that the code to generate derivatives cannot cope with the bracket syntax. If you can rewrite the equation without the brackets, you could get the derivatives and solve that way. This will probably mean having a "translation" routine to glue things

Re: [R] How to coerce a parameter in nls?

Apologies for replying and overlapping Gabor's contribution, which actually did the work! Best, JN On 15-09-21 01:03 PM, Jianling Fan wrote: Thanks Gabor, That works good to rewrite the express the formula! Thanks a lot! Regards, Jianling On 21 September 2015 at 10:43, Gabor

Re: [R] extracting a value from XML

The " > observation_start="2015-09-01" observation_end="2015-09-01" > units="lin" output_type="1" file_type="xml" > order_by="observation_date" sort_order="asc" count="1" offset="0" > limit="10"> > date="2015-09-01" value="0.46"/> > ' > > doc <- read_xml(txt) > xml_attr(xml_find_all(doc,

[R] Running GCV Optimization under Ridge Regression

Hi guys, I am running Ridge regression on a dataset (predicted variable = y; GDP, HPA and FX are regressors). I found that lm.ridge() can perform the ridge regression given any value of lambda (i.e. the ridge parameter). However, in order to choose the best results, I need to select the model

Re: [R] Extract from data.frame

No. On Mon, Sep 21, 2015 at 10:58 AM, John McKown wrote: > On Mon, Sep 21, 2015 at 9:52 AM, Nico Gutierrez > wrote: > >> Hi All, >> >> I need to do the following operation from data.frame: >> >> df <- data.frame(Year = c("2001", "2002",

[R] how to add 1 + 1 with the interface between R and C

Dear useRs, I would like some help on how to make the sum of 1 + 1 but using the interface between A and C. the function call does .call lock and close the R. Thank you for any help it. Cleber ### R code text_code <-" #include #include #include void

Re: [R] extracting a value from XML

This is how (one way) in both the xml2 package and XML package: library(xml2) library(XML) txt <- ' ' doc <- read_xml(txt) xml_attr(xml_find_all(doc, "//observation"), "value") doc1 <- xmlParse(txt) xpathSApply(doc1, "//observation", xmlGetAttr, "value") On Mon, Sep 21, 2015 at 2:01 PM,

[R] extracting a value from XML

Hi All, I have been trying to extract a value from XML.  I have been at it for several days off and on and I can't seem to get my head around the problem.   I basically understand the examples in R help but I cannot replicate success with the below  I tried to use xmlValue(doc,

Re: [R] Extract from data.frame

better ( if year is an vector of more than 1 element): df[ df$Year %in% outer(as.numeric( as.character( year)), -1:1, FUN='+'), ] Year Amount 2 2002120 3 2003175 4 2004160 On Mon, Sep 21, 2015 at 10:49:34PM +0200, Frank Schwidom wrote: > > year <- df$Year[ which.max( df$Amount)]

[R] vector manipulations -- differences

I need an efficient way to build a new n x (n-1)/2 vector from an n-vector x as: c(x[-1]-x[1], x[-(1:2)]-x[2], ... , x[-(1:(n-1)] - x[n-1]) x is increasing with x[1] = 0. The following works but is not the greatest: junk<-outer(x, x, '-') junk[junk>0] e.g., given x<-c(0, 3, 7, 20)

Re: [R] ERROR - non-conformable arguments

Hi all, I am sorry I forgot to attach the excel file and txt files with the test data I used for this example. I am almost sure the problem was caused by the way R is reading this data, Hope to get some help, best, Alex 2015-09-20 14:03 GMT+07:00 Alexander Moßbrucker

Re: [R-es] Resumen de R-help-es, Vol 79, Envío 16

Hola,si añades header-includes: - usepackage[utf8]{inputenc} debajo del output en la cabecera(yaml) no debes tener problemas con las tildes. También debes usar codificación utf8 dentro de RStudio. Saludos, El 21/09/2015 12:00, r-help-es-requ...@r-project.org escribió: > Envíe los

Re: [R-es] Una preguntilla

Heber, Dale una mirada a ?cbind ?file.choose "cbind" es el acronimo de "column binding" o "pegado por columnas". Básicamente toma una columna (o varias) de una matrix o data.frame y las pega con otra(s). La función fle.choose() abre la ventana que necesitas. Dentro de la funcion puedes usar

Re: [R-es] Problemas con rmarkdown

Buenos días José Antonio, Efectivamente, le quité la tilde al fichero y ya funciona perfectamente. Muchas gracias. Saludos, Conney Paola Marulanda López Profesional en Finanzas y Relaciones Internacionales www.finanzaszone.com Subject: Re: [R-es] Problemas con rmarkdown To: