Manuel Morales wrote:
I'm trying to fit a model like beta[trt]/(1+alpha*x) where the data
include some grouping factor. The problem is that the estimate for alpha
is undefined for some of the treatments - any value greater than 20 is
equally good and a step function would suffice.
Tony Breyal wrote:
Is there an alternative website which uses a similar structure to
google groups? I had a quick browse on the R Wiki
(http://wiki.r-project.org/rwiki/doku.php?id=links:links) but didn't
see a page with this sort of info.
For reading and searching, nothing beats
P.Dalgaard wrote:
IF TYPE='TRUCK' and count=12 THEN VEHICLES=TRUCK+((CAR+BIKE)/2.2);
vehicles - ifelse(TYPE=='TRUCK' count=12, TRUCK+((CAR+BIKE)/2.2), NA)
Read both versions to an audience, and you will have to admit that this is
one of the cases where SAS is superior.
Dieter
I appreciate that you are trying to help me but I don't fully understand your
point. At one point I did say ... the intercept is not significantly
different from zero. I admit I also said dropping the intercept term
which in my loose application of terminology means force the intercept to a
value
Let say, I have following matrix :
dat - matrix(rnorm(40), 2, 20)
Now I want to partition this like this :
dat1 - dat[1,]
dat2 - dat[2,]
But point is that, dat1 and dat2 become vector object. How can I force them
to be matrix object with dimension (1x20) ?
Thanks,
--
View this message in
Dieter Menne wrote:
P.Dalgaard wrote:
IF TYPE='TRUCK' and count=12 THEN VEHICLES=TRUCK+((CAR+BIKE)/2.2);
vehicles - ifelse(TYPE=='TRUCK' count=12, TRUCK+((CAR+BIKE)/2.2), NA)
Read both versions to an audience, and you will have to admit that this is
one of the cases where SAS is
Bogaso wrote:
Let say, I have following matrix :
dat - matrix(rnorm(40), 2, 20)
Now I want to partition this like this :
dat1 - dat[1,]
dat2 - dat[2,]
But point is that, dat1 and dat2 become vector object. How can I force
them to be matrix object with dimension (1x20) ?
To
Hi All,
Does anyone could help me to find the right way to do the following:
I fixed this linear model: lm(Obs~ A1 + A2 + A3 + A4 -1, data=data);
where Ai are land cover classes areas.
I have then the Ai coefficients, the structure of the residuals (it can be
approximated by a normal
I'm not sure we should measure superiority by how well a statement parses into
English. If this were true, we would all be programming in COBOL.
Simon.
Simon Blomberg, BSc (Hons), PhD, MAppStat.
Lecturer and Consultant Statistician
School of Biological Sciences
The University of Queensland
see
?[
and notice the 'drop' argument.
So in your example try
dat[1, , drop=FALSE]
hth,
Kingsford
On Tue, Jun 23, 2009 at 1:13 AM, Bogasobogaso.christo...@gmail.com wrote:
Let say, I have following matrix :
dat - matrix(rnorm(40), 2, 20)
Now I want to partition this like this :
Simon Blomberg-4 wrote:
I'm not sure we should measure superiority by how well a statement parses
into English. If this were true, we would all be programming in COBOL.
P.Dalgaard wrote:
IF TYPE='TRUCK' and count=12 THEN VEHICLES=TRUCK+((CAR+BIKE)/2.2);
vehicles -
Dear List,
Sharepoint sites are used more and more often by researchers as a
platform to share all the information in a joint research project.
Typically, they can be accessed only by a Hypertext Transfer Protocol
Secure (HTTPS) URL.
We are investigating whether it is possible to read and write
On 22/06/2009 9:21 PM, Michael wrote:
Thanks a lot! There is no MSVC project for R on Windows?
I don't know of one.
Duncan Murdoch
On Mon, Jun 22, 2009 at 5:32 PM, Duncan Murdochmurd...@stats.uwo.ca wrote:
On 22/06/2009 6:52 PM, Michael wrote:
Hi all,
I am thinking of extending a
hello,
I have downloaded conjoint.R and missing the design(). can any one send it to
me so I can perform the conjoint analysis in R.
Regds
Faisal Afzal Sddiqui
M.Phil Student
Dept. of Statistics
University of Karachi
Pakistan
+92-300-9297089
__
On Tue, Jun 23, 2009 at 8:42 AM, Bierman, Stijn stijn.bier...@wur.nlwrote:
Dear List,
Sharepoint sites are used more and more often by researchers as a
platform to share all the information in a joint research project.
Typically, they can be accessed only by a Hypertext Transfer Protocol
Dear all, I'd appreciate some advice on the following problem. I'm
attempting to analyse a nested cross-sectional design in which an
intervention was offered to a series of randomly selected (small)
communities, so the unit of randomisation is the community. All
available individuals in
This might be obvious to some, but I can't find a neat way to do it:
Say I have two (very long) numerical vectors a b of the same length
representing variable coefficients of a linear autoregression.
I want to calculate vector x defined by
x[1] - b[1]
for (n in 2:length(a)) x[n] - a[n]*x[n-1] +
Hi, you can try reading
http://cran.r-project.org/web/packages/SASmixed/vignettes/Usinglmer.pdf
If I am not mistaken, the repeated measures over time and nesting of
individuals in communities as you describe them would be captured by:
Hi,
I've a vector like this:
--
inc[,5]
[1]NANANANANANANA
[8]NANANANANANANA
[15]NANANANA
Hi,
How can I convert from 8-bit RGB color to [0-1] interval (sRGB) and
vice-versa?
Thanks in advance
Paulo E. Cardoso
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
On 6/23/2009 5:41 AM, Alfredo Alessandrini wrote:
Hi,
I've a vector like this:
--
inc[,5]
[1]NANANANANANANA
[8]NANANANANANA
alfreale wrote:
I've a vector like this:
inc[,5]
How can I extract a vector without the NA value?
inc[,5][!is.na(inc[,5])]
--
View this message in context:
http://www.nabble.com/vector-and-NA-tp24162879p24163839.html
Sent from the R help mailing list archive at Nabble.com.
Hi,
I've fitted a GARCH(1,1) for the residuals of my time serie (X).
X is an ARMA(1,1) process.
Now I want to do a n-step forecast for X, knowing these processes. How can I
do this?
I know that there's a command:
predict() for ARIMA processes and so on, but what about GARCH?
I've got:
Dieter Menne wrote:
IF TYPE='TRUCK' and count=12 THEN VEHICLES=TRUCK+((CAR+BIKE)/2.2);
vehicles - ifelse(TYPE=='TRUCK' count=12, TRUCK+((CAR+BIKE)/2.2), NA)
Read both versions to an audience, and you will have to admit that this is
one of the cases where SAS is superior.
And Peter
Hi,
I am planning to externally validate a logistic prediction model in a new
cohort. Outcome is mortality. The betacoefficients were derived from a
previous published article. It seems not possible in R to assign fixed beta
coefficients to predictors like lrm (death ~
You can also use if (cond) then {something} if you don't like ifelse()
function. See ?Control.
David
2009/6/23 Peter Flom peterflomconsult...@mindspring.com
Dieter Menne wrote:
IF TYPE='TRUCK' and count=12 THEN VEHICLES=TRUCK+((CAR+BIKE)/2.2);
vehicles - ifelse(TYPE=='TRUCK' count=12,
David Hajage-2 wrote:
You can also use if (cond) then {something} if you don't like ifelse()
function. See ?Control.
The minor difference that if() is not vectorized is a source of FAQs.
Dieter
--
View this message in context:
Hi, I have 3 lists, x, y, z and I'd like to perform a calculation over all
the lists simultaneously. If it were a single list I could use lapply, but
for more than one list I'm using a for loop. Is there an idiom that would
let me use something like lapply, but the function specified to lappy
Hi,
Grid offers several functions to help drawing such graphs,
see Paul Murrell's Can R Draw Graphs? (useR! 2006)
I came up with this, as a quick example,
vp - viewport(
x = unit(0, npc),
y = unit(0, npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))
vp2 - viewport( #
If I understand, you can use rapply for this.
On Tue, Jun 23, 2009 at 9:11 AM, Rajarshi Guha rajarshi.g...@gmail.comwrote:
Hi, I have 3 lists, x, y, z and I'd like to perform a calculation over all
the lists simultaneously. If it were a single list I could use lapply, but
for more than one
On Jun 23, 2009, at 3:08 AM, Chris Friedl wrote:
I appreciate that you are trying to help me but I don't fully
understand your
point.
The point is that in very few applications can one legitimately
exclude an intercept. In this situation (stepwise regression) I am
able to think of a
Hello,
There was a recent discussion [R] Predict GARCH [1].
Liviu
[1] http://www.nabble.com/Predict-GARCH-td23962363.html#a23962363
On Tue, Jun 23, 2009 at 1:02 PM, Ana Ramosaritara...@gmail.com wrote:
Hi,
I've fitted a GARCH(1,1) for the residuals of my time serie (X).
X is an ARMA(1,1)
I would like to use a Latent Class model to estimate utilities for segments.
I think the package poLCA can be used but I didn't find any example about
discrete choice models. So how can I do it?
Thank you
Nathalie
Re?evez
Henrique Dallazuanna wrote:
If I understand, you can use rapply for this.
Actually, I think you want mapply.
--
View this message in context:
http://www.nabble.com/an-idiom-to-handle-i%27th-element-of-a-set-of-lists-simultaneously-tp24164839p24165046.html
Sent from the R help
On Jun 23, 2009, at 6:28 AM, jeweetwel wrote:
Hi,
I am planning to externally validate a logistic prediction model in
a new
cohort. Outcome is mortality. The betacoefficients were derived from a
previous published article. It seems not possible in R to assign
fixed beta
coefficients to
On Jun 23, 2009, at 7:40 AM, David Hajage wrote:
You can also use if (cond) then {something} if you don't like ifelse()
function. See ?Control.
Had you followed you own advice, you should have seen why this is
completely misleading in the curret context.
cond
A length-one logical vector
David Winsemius wrote:
On Jun 23, 2009, at 3:08 AM, Chris Friedl wrote:
The point is that in very few applications can one legitimately
exclude an intercept. In this situation (stepwise regression) I am
able to think of a way to make the intercept just another covariate,
but I
Dear R users and Dear authors of the distr package and sequels
I am trying to use the (very nice) package distrMod as I want to
implement maximum likelihood (ML) fit of some univariate data for which
I have derived a theoretical continuous density (pdf). As it is a
parametric density, I guess
Dieter Menne wrote:
P.Dalgaard wrote:
IF TYPE='TRUCK' and count=12 THEN VEHICLES=TRUCK+((CAR+BIKE)/2.2);
vehicles - ifelse(TYPE=='TRUCK' count=12, TRUCK+((CAR+BIKE)/2.2), NA)
Read both versions to an audience, and you will have to admit that this is
one of the cases where SAS is
Frank E Harrell Jr wrote:
Here's a case where SAS is clearly not superior:
IF type='TRUCK' AND count12 THEN vehicles=truck+(car+bike)/2.2;
If count is missing, the statement is considered TRUE and the THEN is
executed. This is because SAS considers a missing as less than any
A point of history:
Both the commercial CART program and the rpart() function are based on the
book Classification and Regression Trees (Breiman, Friedman, Olshen, Stone,
1984). As a reader/commentator on one of the early drafts I got to know the
material well. CART started as a large
Frank, would you feel comfortable giving us the reference to the NEJM article
with the 'missing vs ' error ? I'm sure that things like this happen
fairly often, and I'd like to use this example in teaching
thanks, david freedman
Frank E Harrell Jr wrote:
Dieter Menne wrote:
P.Dalgaard
Paulo Cardoso wrote:
How can I convert from 8-bit RGB color to [0-1] interval (sRGB) and
vice-versa?
If you have the R/G/B values separately, divide by 255, and use function rgb
in grDevices. If you have the hex values, paste these into a string, and use
something like
col2rgb(#2C312C)
On Tue, Jun 23, 2009 at 2:26 PM, Dieter Menne
dieter.me...@menne-biomed.dewrote:
Paulo Cardoso wrote:
How can I convert from 8-bit RGB color to [0-1] interval (sRGB) and
vice-versa?
If you have the R/G/B values separately, divide by 255, and use function
rgb
in grDevices. If you
Hi
I have two irregular time series, which are of different lengths and being
and end at different times. For the common subset of time that they both
span, they should have the same values, but the values may occur at
slightly different time intervals. I am trying to line up the identical
Hello,
Collecting data I need to check in a mysql server. As the data are dependent
on each other I have to filter first.
However, I have now the problem that I find a value and would like to insert
it into a data query for the real select command. Obviously, typing 'x'
does not help as the
Your zoo object is illegal since zoo objects are not supposed to
have duplicated times; however, ignoring that if the object has
at most one NA in each row, which is the case in the example,
then this will produce a numeric vector and you can create a
new zoo object out of that:
rowSums(z, na.rm
On Jun 23, 2009, at 9:29 AM, rory.wins...@gmail.com wrote:
Hi
I have two irregular time series, which are of different lengths and
being
and end at different times. For the common subset of time that they
both
span, they should have the same values, but the values may occur at
slightly
Barry Rowlingson wrote:
8-bit color graphics often refers to a situation where each pixel is 8
bits, and the colour comes from a 256-colour palette lookup table.
If you really have a 8 bit palettized colour lookup, as Barry assumes, you
better use one of the build-in conversions, for
Hi,
I've a vector like this:
inc
[1]NANANANANANANA
[8]NANANANANANANA
[15]NANANANANANANA
[22]NANA
David Freedman wrote:
Frank, would you feel comfortable giving us the reference to the NEJM article
with the 'missing vs ' error ? I'm sure that things like this happen
fairly often, and I'd like to use this example in teaching
thanks, david freedman
@ARTICLE{gus93int,
author = {{The GUSTO
On Jun 23, 2009, at 9:50 AM, Gabor Grothendieck wrote:
Your zoo object is illegal since zoo objects are not supposed to
have duplicated times;
They were unique at the sub-second level.
however, ignoring that if the object has
at most one NA in each row, which is the case in the example,
Try this:
which(diff(is.na(inc)) 0)
On Tue, Jun 23, 2009 at 11:00 AM, Alfredo Alessandrini alfreal...@gmail.com
wrote:
Hi,
I've a vector like this:
inc
[1]NANANANANANANA
[8]NANANANANA
?is.na and its negative !is.na
Try something like this
xx - c(NA, NA, 1, 2, 3)
bb - xx[!is.na(xx)]
bb
--- On Tue, 6/23/09, Alfredo Alessandrini alfreal...@gmail.com wrote:
From: Alfredo Alessandrini alfreal...@gmail.com
Subject: [R] vector and NA
To: r-help@r-project.org
Received:
Now is ok...thanks.
Alfredo
2009/6/23 Alfredo Alessandrini alfreal...@gmail.com:
I've the NA value also between the value of the vector:
inc
[1] NA NA NA NA NA NA NA
[8] NA NA NA NA NA NA NA
On Jun 23, 2009, at 10:00 AM, Alfredo Alessandrini wrote:
Hi,
I've a vector like this:
inc
[1]NANANANANA
NANA
[8]NANANANANA
NANA
[15]NANANANA
On Tue, Jun 23, 2009 at 10:04 AM, David Winsemiusdwinsem...@comcast.net wrote:
On Jun 23, 2009, at 9:50 AM, Gabor Grothendieck wrote:
Your zoo object is illegal since zoo objects are not supposed to
have duplicated times;
They were unique at the sub-second level.
however, ignoring that if
I've the NA value also between the value of the vector:
inc
[1]NANANANANANANA
[8]NANANANANANANA
[15]NANANANANANANA
[22]
Alfredo Alessandrini wrote:
Hi,
I've a vector like this:
inc
[1]NANANANANANANA
[8]NANANANANANANA
[15]NANANANANANA
On Tue, Jun 23, 2009 at 04:00:21PM +0200, Alfredo Alessandrini wrote:
I've a vector like this:
inc
[1]NANANANANANANA
[8]NANANANANANANA
[15]NANANA
min(which(is.na(inc)==FALSE)) #index
inc[min(which(is.na(inc)==FALSE))] #value
hth
daniel
-
cuncta stricte discussurus
-
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von
You can use this:
inc[which(!is.na(inc))[1]]
On Tue, Jun 23, 2009 at 11:08 AM, Alfredo Alessandrini alfreal...@gmail.com
wrote:
I've the NA value also between the value of the vector:
inc
[1]NANANANANANANA
[8]NANA
On Tue, Jun 23, 2009 at 10:10 AM, Gabor
Grothendieckggrothendi...@gmail.com wrote:
On Tue, Jun 23, 2009 at 10:04 AM, David Winsemiusdwinsem...@comcast.net
wrote:
On Jun 23, 2009, at 9:50 AM, Gabor Grothendieck wrote:
Your zoo object is illegal since zoo objects are not supposed to
have
I think what you mean is that you want to find the position of the first
non-NA value in the vector. is.na returns a boolean vector of the NA
values, so:
xx - c(NA,NA,NA,2,3,NA,4)
which(!is.na(xx))[1]
[1] 4
The other proposed solution,
which(diff(is.na(inc)) 0)
is incorrect:
Hi
r-help-boun...@r-project.org napsal dne 23.06.2009 16:04:49:
Try this:
which(diff(is.na(inc)) 0)
Shall it be
which(diff(is.na(inc)) 0)+1
or
sum(is.na(inc))+1
or any other suitable construct with is.na
Regards
Petr
On Tue, Jun 23, 2009 at 11:00 AM, Alfredo Alessandrini
Dear colleagues,
I'm searching for methods to analyze spatial distributions of cells with
certain properties in a regular grid. For instance, consider a grid, where a
part of the cells have the property 0, and the others have the property
1. I'm looking for statistics I could use for
Hi everyone.
Probably this is statistical question rather than an R, but it involves
packages from R I am asking here since I am unable to find an answer. In the
parametric modeling packages like glmnet, lasso etc..., we are able to
obtain the coeffcients that have entered the model.
for
Dear Guillaume,
thanks for your interest in the distrMod package.
Regarding your question I took up your example and put a file under:
http://www.stamats.de/distrModExample.R
Hope that helps ...
Don't hesitate to contact me if you have further questions!
Best,
Matthias
guillaume.martin
I change the values by multiple 100 (from fraction to percentage) and then
use the same code draw the hist. Now it works fine. The y axis labeled
between 0 and 0.05.
Why using fraction (value between 0 and 1) it does not work?
Charles
charles78 wrote:
I have been trying to draw histogram
Thanks for your point of view Terry! It is always fascinating to follow
the history of the field, especially as told by someone involved with
it.
Jude Ryan
-Original Message-
From: Terry Therneau [mailto:thern...@mayo.edu]
Sent: Tuesday, June 23, 2009 9:22 AM
To: Ryan, Jude;
Hi,
I've fitted a GARCH(1,1) for the residuals of my time serie (X).
X is an ARMA(1,1) process.
Now I want to do a n-step forecast for X, knowing these processes. How can I
do this?
I know that there's a command:
predict() for ARIMA processes and so on, but what about GARCH?
I've got:
On Jun 23, 2009, at 10:21 AM, Peter Biber wrote:
Dear colleagues,
I'm searching for methods to analyze spatial distributions of cells
with
certain properties in a regular grid. For instance, consider a grid,
where a
part of the cells have the property 0, and the others have the
property
as.vector(na.omit(inc[,5])
?na.omit
Paolo
Hi,
I've a vector like this:
--
inc[,5]
[1]NANANANANANANA
[8]NANANANANANANA
Hi all. Suppose I have a vector of strings ie: [12384, TYU123123,
AVC3939, hhr1919, TYU0029]
Is there an efficient method that would allow me to return a vector of the
position of strings that start with TYU? So essentially, I would like to
get back in return [2, 5]. Anyways, any help with be
Try this:
s - c(12384, TYU123123,AVC3939, hhr1919, TYU0029)
grep(^TYU, s)
On Tue, Jun 23, 2009 at 11:51 AM, njhuang86 njhuan...@yahoo.com wrote:
Hi all. Suppose I have a vector of strings ie: [12384, TYU123123,
AVC3939, hhr1919, TYU0029]
Is there an efficient method that would allow me to
Hello,
I'm trying to find an algorithm to estimate a switching regression model
based on the 1990 Economics Letters paper by Ohtani/Kakimoto/Abe or the
earlier version from 1985 (Ohtani/Katayama, Economic Studies Quarterly;
assuming as a transition path a polynomial of order 1).
I found an
charles78 wrote:
I change the values by multiple 100 (from fraction to percentage) and then
use the same code draw the hist. Now it works fine. The y axis labeled
between 0 and 0.05.
Why using fraction (value between 0 and 1) it does not work?
As you have been told multiple times, densities
We got all rows by:
library(XML)
doc =
htmlParse('http://www.statcan.gc.ca/daily-quotidien/090520/t090520b1-eng.htm')
rows = xpathSApply(doc, '//table/tbody/tr')
The last row is:
row_last = rows[15]
row_last
[[1]]
trtd id=t1stub17 class=stub1 RGBShadebUnsmoothed composite
leading
Dear listserv members,
In Croissant (2008) Panel Data Econometrics in R: The plm Package the
authors seem to indicate that the nlme package for R cannot correctly handle
unbalanced panel data: Moreover, economic panel datasets often happen to be
unbalanced (i.e., they have a different
Dear All,
I have analysed time to event data for continuous variables by
considering the multivariable fractional polynomial (MFP) model and
comparing this to the untransformed and log transformed model to
determine which transformation, if any, is best. This was possible as
the Cox model was
I am running the last R version on SuSE 11.1.
I installed the Bioconductor environment following the instructions on the web.
As a consequence some
core packages from Bioconductors were installed.
I need to add some more packages. So I tried biomaRt as follows.
It does not get installed
njhuang86 wrote:
Hi all. Suppose I have a vector of strings ie: [12384, AVC_TYU123123,
ESPN_TYU, TYU_TYU, AVC3939, hhr1919, TYU0029]
Is there an efficient method that would allow me to return a vector of the
position of strings that start with TYU? So essentially, I would like to
get
Can biomaRt connect to data base http://mirecords.umn.edu; or a branch of it
... for instance the validated miRNAs list ..?
Thank you very much.
Maura
tutti i telefonini TIM!
[[alternative HTML version deleted]]
__
R-help@r-project.org
On Jun 23, 2009, at 10:25 AM, sunny vic wrote:
Hi everyone.
Probably this is statistical question rather than an R, but it
involves
packages from R I am asking here since I am unable to find an
answer. In the
parametric modeling packages like glmnet, lasso etc..., we are
able to
Thanks to all who replied. mapply does the trick
On Tue, Jun 23, 2009 at 8:11 AM, Rajarshi Guha rajarshi.g...@gmail.comwrote:
Hi, I have 3 lists, x, y, z and I'd like to perform a calculation over all
the lists simultaneously. If it were a single list I could use lapply, but
for more than one
plyr is a set of tools for a common set of problems: you need to break
down a big data structure into manageable pieces, operate on each
piece and then put all the pieces back together. For example, you
might want to:
* fit the same model to subsets of a data frame
* quickly calculate
Dear Mathias,
That's pretty amazing, thanks a lot ! I'll have to look all this through
because I don't easily understand why each part has to be set up, in
particular the initialize method part seems crucial and is not easy to
intuit. From what I get, the actual name we give to a parameter (my
Please ask Bioconductor questions on the Bioconductor mailing list
https://stat.ethz.ch/mailman/listinfo/bioconductor
Is the below a complete transcript of the outcome of
biocLite('biomaRt')? I would have expected to see R attempt to install
each package, and then perhaps XML failing to
Please ask Bioconductor questions on the Bioconductor mailing list
https://stat.ethz.ch/mailman/listinfo/bioconductor
Martin
mau...@alice.it writes:
Can biomaRt connect to data base http://mirecords.umn.edu; or a branch of it
... for instance the validated miRNAs list ..?
Thank you
When I do dev.new(), the resulting window comes to the front and grabs the
focus. Is there a way to prevent this so I can continue working in other
windows while the graphics are being produced?
Thanks
--
View this message in context:
I'm new to R, and have just found that score.alpha gives me noticeably
different Cronbach's Alpha values than score.items, when using the same
data frame and (as much as possible) the same options. The help page for
the former says its superseded by the latter. Is this similar to
saying that
g...@ucalgary.ca wrote:
We got all rows by:
library(XML)
doc =
htmlParse('http://www.statcan.gc.ca/daily-quotidien/090520/t090520b1-eng.htm')
rows = xpathSApply(doc, '//table/tbody/tr')
The last row is:
row_last = rows[15]
row_last
[[1]]
trtd id=t1stub17 class=stub1 RGBShadebUnsmoothed
Yes it is.
I copied and pasted all the attempted installation messages.
The installed Bioconductor environment is the latest released. Just installed
yesterday.
The dependencies ... well, should be automatically resolved.-
Thank you,
Maura
-Messaggio originale-
Da: Martin Morgan
I have a data set called datastep4 with 211484 rows and 95 columns
dim(datastep4)
[1] 211484 95
The first few column names are given below, note the first one is
RESPONDED
names(datastep4)[1:5]
[1] RESPONDED VAR_30VAR_31VAR_32VAR_33
A table of RESPONDED shows
Thanks David,
Actually, I googled quite some time before posting my question. I'm also
aware, that there are many packages for spatial data analysis. However, I
found no hint if any of them contains methods for characterizing (and I
don't mean just plotting) the distribution (e.g. pure random,
jorgusch hackl.schorsch at web.de writes:
Collecting data I need to check in a mysql server. As the data are dependent
on each other I have to filter first.
However, I have now the problem that I find a value and would like to insert
it into a data query for the real select command.
Hi I'm new to R and would like to implement a SAS-like macro variable
in R.
What I'd like to do is take the simple R code below and change the
=TEF to different letters to refer to different companies' data for
download.
# DOWNLOADS FILES FROM YAHOO INTERNET
On Tue, Jun 23, 2009 at 6:03 PM, Steve Jaffesja...@riskspan.com wrote:
When I do dev.new(), the resulting window comes to the front and grabs the
focus. Is there a way to prevent this so I can continue working in other
windows while the graphics are being produced?
That's a function of your
You can use sprintf:
u - sprintf('
http://ichart.yahoo.com/table.csv?s=%s.MCa=00b=1c=2003d=05e=23f=2009g=dignore=.csvhttp://ichart.yahoo.com/table.csv?s=TEF.MCa=00b=1c=2003d=05e=23f=2009g=dignore=.csv',
TEF)
download.file(u, 'c:\\projects\\stock data\\data\\test.csv',quiet=TRUE)
On Tue, Jun 23,
Hello R Users,
I have a question regarding fitting a model with GAM{mgcv}. I have data
from several predictor (X) variables I wish to use to develop a model to
predict one Y variable. I am working with ecological data, so have data
collected many times (about 20) over the course of two years.
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