Thanks!
It worked! There is another problem I want to subset the matrix 'red'
in following manner:
dim(red)
23688 164
a=red[1:23688,1:4]
b=red[1:23688,5:8]
c=red[1:23688,9:12]
..
..
z=red[1:23688,161:164]
If there any efficient way to do
Thanks Joris and Peter. Sorry for not giving enough details. I have tried
your suggestions and the problem is solved. Thank you. :)
JorisMeys wrote:
The minimum of a character vector is returned according to the unicode
or ascii code values, but I guess that's not what Chris is looking
Hi R users,
I just play with a small data set (from SAS) by using the boot with glm. But
I don't know what I did wrong. Would someone please give me a hint?
require(boot)
carc-read.table(file=C:\\Documents and
Settings\\admin\\Desktop\\drug.txt,header=T)
carc
n cc car age
1 500 42 S
Thanks for that again. That almost works, except that lines are drawn
between non-empty bins (in various degrees of diagonality), so absent
points (important here) don't show clearly. It's not a huge issue, so I
might leave it, unless there is a simple way around this.
cheers
Dan
On Tue,
Readers,
I have tried to use a plotmath command to add the temperature degree
sign (i.e. ᵒ C) to the axis label of a graph:
x-(1:10)
y-(200:191)
plot(x~y,ylab=expression(*degree~C))
Error: syntax error, unexpected '*', expecting ',' in
plot(x~y,ylab=expression(*
According to plotmath manual,
On Thu, Oct 1, 2009 at 7:26 PM, Martin Renner
martin.ren...@stonebow.otago.ac.nz wrote:
try pdftk. Not quite on the fly but should do the trick. (I saw this on
this list a little while ago)
pdftk compresses the pdf internally - it is still a pdf, can be opened as a
pdf, and is not an
Hi,
You cannot start with a * in expression(). Try this,
plot(x~y,ylab=expression(~degree~C))
or even, as a short-cut,
plot(x~y,ylab=~degree~C)
HTH,
baptiste
2009/10/2 e-letter inp...@gmail.com:
Readers,
I have tried to use a plotmath command to add the temperature degree
sign (i.e. ᵒ
Rainer,
if you are willing to patch the R source, then a solution might be the
R connection patch, see
http://wiki.r-project.org/rwiki/doku.php?id=developers:r_connections_api
It is a bit outdated, but with a little work I could use it for R
2.9.2 and works fine.
Best,
Gabor
On Fri, Oct 2, 2009
Dear list members,
I am looking for an alternative function for a two-way ANOVA in the case of
variance heterogeneity. For one-way ANOVA, I found oneway.test(), but I
didn't find anything alike for two-way ANOVA. Does anyone have a suggestion?
Thank you!
Maike Luhmann
Freie Universität Berlin
On Fri, Oct 2, 2009 at 9:02 AM, Gábor Csárdi csa...@rmki.kfki.hu wrote:
Rainer,
if you are willing to patch the R source, then a solution might be the
R connection patch, see
http://wiki.r-project.org/rwiki/doku.php?id=developers:r_connections_api
It is a bit outdated, but with a little
Hi
I want to change a control parameter for an nls () as I am getting an error
message step factor 0.000488281 reduced below 'minFactor' of 0.000976562.
Despite all tries, it seems that the control parameter of the nls, does not
seem to get handed down to the function itself, or the error
Hi,
Is there a way to set the scale of a plot (i.e. number of axis units
per centimeter) when you output it to postscript? If not, how am I
supposed to plot graphs with different axis limits to the same scale?
They just get resized to fit the paper so that graphs which show a
smaller number of
On Thu, 01-Oct-2009 at 10:13AM -0700, jamesmcc wrote:
|
| This is the first time I've encountered R having difficulty with package and
| R version compatibility. I cant believe no one has fixed generally so that
| your version of R can get the latest package appropriate to that version.
| How
Hi
If you use a Microsoft OS and you just want to do a °C in the text there is
the alternative of using ASCII
Just press the keys Alt-248. Have used it for a number of years with success.
Also applies to other characters and without having to go to plotmath etc
You just need to be careful of
Dear list,
using package proxy.
In one situation, the dissimilarity between two vectors based on
method=correlation returns a value of 1.9. That should not happen, should it?
The correlation is normally the cos() of the angle between the two vectors
That dissimilarity
Any clue?
On Fri, 2009-10-02 at 00:42 +, KABELI MEFANE wrote:
Thanks
But it seems like you don't get my problem.Do you mean that there is
something wrong with the code as it seems like what you are doing is
suggesting different ways to write a code.
Will i get to use the variable that have
A quick google on 'normality test' (no quotes) gives
http://en.wikipedia.org/wiki/Normality_test. This gives you a few more tests
than the KS test.
Cheers,
Colin.
Steve Lianoglou wrote:
Hi,
I think you can also use a qq-plot to do the same, no? You won't get a
statistic score + p.value,
On 02/10/2009 4:07 AM, Ben Kenward wrote:
Hi,
Is there a way to set the scale of a plot (i.e. number of axis units
per centimeter) when you output it to postscript? If not, how am I
supposed to plot graphs with different axis limits to the same scale?
They just get resized to fit the paper so
On Fri, Oct 2, 2009 at 11:10 AM, Duncan Murdoch murd...@stats.uwo.ca wrote:
I don't think there's a simple way to specify the exact relationship, but
you can do it with some work.
Thanks Duncan. That's what I was beginning to suspect, nice to have
confirmation, even if it will mean a bit of
Hi,
It looks like lattice or ggplot2 might make this easier, but I'm not
entirely sure I understood the problem, short of an example.
Best,
baptiste
2009/10/2 Duncan Murdoch murd...@stats.uwo.ca:
On 02/10/2009 4:07 AM, Ben Kenward wrote:
Hi,
Is there a way to set the scale of a plot (i.e.
Here is one way to do it. BTW 'a'-'z' won't work because there are 41
splits. Use a list instead:
red - matrix(seq(23688 * 164), nrow=23688, ncol=164)
# create indices
indx - split(1:164, cut(1:164, 41))
# now split matrix
newMatrix - lapply(indx, function(x) red[, x])
str(newMatrix)
On Thu, 2009-10-01 at 10:18 -0700, awayguy wrote:
yes, halo thank you.
my measure data:
v2 - c(0, 2, 4, 6, 6.2, 6.4, 6.6, 6.8, 7, 7.2, 7.4, 7.6, 7.8, 8, 10, 12,
14)
ph2 - c(12.10, 11.94, 11.68, 11.11, 10.91, 10.74, 10.47, 9.71, 7.1, 4.24,
3.3, 3.08, 2.98, 2.86, 2.33, 2.11, 1.98)
with
Thanks! Jim
It solved my problem.
Best
Amit
On Fri, Oct 2, 2009 at 11:19 AM, jim holtman jholt...@gmail.com wrote:
Here is one way to do it. BTW 'a'-'z' won't work because there are 41
splits. Use a list instead:
red - matrix(seq(23688 * 164), nrow=23688, ncol=164)
# create indices
indx
try this:
x - read.table(textConnection(x1 x2 x3
+ A 11.5
+ B 20.9
+ B 32.7
+ C 71.8
+ D 71.3), header=TRUE)
closeAllConnections()
do.call(rbind, lapply(split(seq(nrow(x)), x$x1), function(.row){
+ x[.row[which.min(x$x2[.row])],]
+ }))
x1 x2 x3
A A 1
Hello there
after I became familiar with R and Design of Experiments, I tried to
make a fourier transform with kzft but failed. I don't understand
kzft.pdf right.
I tried:
t-1:1000
x-cos(2*pi*(1/100)*t)
kzft.x1-kzft(x,200,1,0.005)
x1-2*Re(kzft.x1$tf[,2]) //Is it Re because it's complex? What
dear all,
I have some very long strings and would like to break up each long string
into multiple strings with a fixed length, e.g. to break up
abcdefghijkl
into
abc, def, ghi, jkl
I tried a couple of commands but was not successful. Any help will be
appreciated.
Best,
Jimmy
--
View this
Hello *
i have to rename a lot of variables, and, given that they have regular name
constructs, I would like to use regexps.
Here's a dump of my head(names(df))
varnames - c(id.quest, txt.1.3, col1.1.3, col2.1.3, col3.1.3,
col4.1.3, col5.1.3, txt.2.3, col1.2.3, col2.2.3, col3.2.3,
col4.2.3,
Hi, R-users,
I have a problem: Because there are few files which can't be readed
into R completely, so on the following subsequence programme, I use
write.table, which creates the NA files for those incomplete files
autimatically.
I don't want those NA files.
My programes formats looks like:
Readers,
I am unable to plot a label consisting of both subscript text and
percentage (%) symbol:
x-(1:10)
y-(200:191)
plot(x~y,ylab=expression(~degree~C),xlab=expression(x[2]~%))
Error: syntax error, unexpected ERROR in
plot(x~y,ylab=expression(~degree~C),xlab=expression(x~%)
It seems that %
try this:
a - paste(letters, collapse='')
# partitions into lengths of 4
indx - seq(1, nchar(a), 4)
a.p - sapply(indx, function(x) substring(a, x, x+3))
a.p
[1] abcd efgh ijkl mnop qrst uvwx yz
On Fri, Oct 2, 2009 at 5:36 AM, J Chen jiaxuan.c...@mdc-berlin.de wrote:
dear all,
I have
try this: (?try)
name_c-Sys.glob(C:/Documents and Settings/lma/My
Documents/habitdata/*/calllog/*)
for (i in 1:length(name_c)){
log1-try(readLines(name_c[i]))
if (inherits(log1, 'try-error')) next # skip if error
write.table(Temps, file=paste(C:/Documents and
Dear Maike,
You could use the Anova() function in the car package with a
heteroscedasticity-consistent coefficient covariance matrix (via the
argument white.adjust=TRUE).
Regards,
John
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
Try this:
x=c(rep(1,3),rep(3,2))
x
[1] 1 1 1 3 3
duplicated(x) | duplicated(x, fromLast=TRUE)
[1] TRUE TRUE TRUE TRUE TRUE
On Thu, Oct 1, 2009 at 10:42 PM, Peng Yu pengyu...@gmail.com wrote:
Hi,
x=c(rep(1,3),rep(3,2))
x
[1] 1 1 1 3 3
duplicated(x)
[1] FALSE TRUE TRUE FALSE TRUE
Try this:
library(gsubfn)
s - abcdefghijkl
strapply(s, ...)[[1]]
[1] abc def ghi jkl
On Fri, Oct 2, 2009 at 5:36 AM, J Chen jiaxuan.c...@mdc-berlin.de wrote:
dear all,
I have some very long strings and would like to break up each long string
into multiple strings with a fixed length,
But it misses the last set if not a multiple of the subset length:
library(gsubfn)
s - abcdefghijklm
# no 'm'
strapply(s, ...)[[1]]
[1] abc def ghi jkl
On Fri, Oct 2, 2009 at 7:58 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
Try this:
library(gsubfn)
s - abcdefghijkl
try this,
plot(x~y,ylab=expression(~degree~C),xlab=expression(x[2]~%))
baptiste
2009/10/2 e-letter inp...@gmail.com:
Readers,
I am unable to plot a label consisting of both subscript text and
percentage (%) symbol:
x-(1:10)
y-(200:191)
You need perl=TRUE:
gsub(^col(\\d{1,2}).(\\d{1,2}).(\\d{1,2}), dom\\3.rig\\2.col\\1,
varnames, perl=TRUE)
[1] id.questtxt.1.3 dom3.rig1.col1
dom3.rig1.col2 dom3.rig1.col3 dom3.rig1.col4 dom3.rig1.col5
[8] txt.2.3 dom3.rig2.col1 dom3.rig2.col2
dom3.rig2.col3
dot (.) matches anything so be sure to escape it so that it only
matches a literal dot in your regular expression.
On Fri, Oct 2, 2009 at 5:39 AM, Luca Braglia brag...@poleis.eu wrote:
Hello *
i have to rename a lot of variables, and, given that they have regular name
constructs, I would
That part wasn't specified so we can't say what the required behavior
is in that case; however, if a non-multiple of 3 were possible and if
the short string is to be emitted at the end then we can just add to
the regular expression:
library(gsubfn)
s - paste(letters, collapse = )
strapply(s,
As is typical with R there are often other ways. Here is another
approach that determines the rows of interest with tapply and min,
converts those minimums into logical targets with %in%, and extracts
them from x using indexing:
x[x$x2 %in% tapply(x$x2, x$x1, min), ]
x1 x2 x3
There are multiple routes to robust statistics, but the quick answer
to this question is probably friedman.test
I seem to remember a CRAN Task View on the area of Robust Statistics.
--
David Winsemius
On Oct 2, 2009, at 3:05 AM, Maike Luhmann wrote:
Dear list members,
I am looking for an
You can use aggregate:
aggregate(x[,c('x2','x3')], x['x1'], min)
On Fri, Oct 2, 2009 at 12:43 AM, Kavitha Venkatesan
kavitha.venkate...@gmail.com wrote:
Hi,
I have a data frame that looks like this:
x
x1 x2 x3
A 1 1.5
B 2 0.9
B 3 2.7
C 7 1.8
D 7 1.3
I want
Hi List,
Does any one know what package I need to use in order to fetch/get a large
sized dataframe from SQL? I have already used sqldf package which is good
for fetching large sized csv files.
Thanks
Alireza
[[alternative HTML version deleted]]
After some more digging (grep alist R-devel/ ), I've come up with this,
tools:::as.alist.symbol(x)
sugar = function(fun, id = id){
ff - formals(fun)
if( id %in% names(ff))
stop(paste(id, is part of args(fun)))
new.arg - tools:::as.alist.symbol(id)
formals(fun) - c(unlist(ff), new.arg)
Dear All,
how can I create a list in the \value{} section of an Rd file? The
things I have tried:
1.
\value{
text text
\item more text
\item even more
}
*** Syntax error: \item in
/-
\item more text
\item even more\-
2.
\value{
text text
\item{more text}
\item{even more}
}
This
On Fri, Oct 2, 2009 at 4:24 AM, jim holtman jholt...@gmail.com wrote:
try this:
x - read.table(textConnection(x1 x2 x3
+ A 1 1.5
+ B 2 0.9
+ B 3 2.7
+ C 7 1.8
+ D 7 1.3), header=TRUE)
closeAllConnections()
do.call(rbind, lapply(split(seq(nrow(x)), x$x1),
Dear list,
here is the code that generates the problem:
library(proxy)
scot-read.csv(scot.csv,header=TRUE)
scot24_climate-scot24[,1105:1109]
# Scotland
dist_scot24_climate-
dist(scot24_climate,method=correlation,diag=TRUE,upper=TRUE)
max(dist_scot24_climate)
is 1.9. I do not think it should
You can try using RODBC, it allows you to connect to databases using the ODBC
driver.
I had some difficulties using it with the postgresSQL driver in the past,
because of some apparent incompatibility with the native postrgesSQL ODBC
driver. I think the problem where solved by the new ODBC
I have more than three lines in one and I want to add a legend for each
line
abline( m1, col = 'red' )
ablime( m2, col = 'blue' )
abline( m3, col = 'purple' )
How can I add a legend? . Is it also possible to increase the thickness of
the lines?
Thanks
[[alternative HTML version
On Fri, Oct 2, 2009 at 3:46 PM, Ashta sewa...@gmail.com wrote:
I have more than three lines in one and I want to add a legend for each
line
abline( m1, col = 'red' )
ablime( m2, col = 'blue' )
abline( m3, col = 'purple' )
How can I add a legend? .
Surprisingly, it is the legend()
On Oct 2, 2009, at 9:46 AM, Ashta wrote:
I have more than three lines in one and I want to add a legend for
each
line
abline( m1, col = 'red' )
ablime( m2, col = 'blue' )
abline( m3, col = 'purple' )
How can I add a legend? . Is it also possible to increase the
thickness of
the lines?
But the problem is that the dataframe size in sql is large, therefore odbc
can sqlQuery() can not handel it.
On Fri, Oct 2, 2009 at 2:14 PM, Corrado ct...@york.ac.uk wrote:
You can try using RODBC, it allows you to connect to databases using the
ODBC
driver.
I had some difficulties using it
Confint doesn't work if you have a multi-dimensional dependent variable.
Kind regards
Joris
On Fri, Oct 2, 2009 at 4:29 AM, smith_cc smith...@yahoo.com wrote:
I am unable to calculate confidence intervals for the slope estimate in a
quasibinomial glm using confint(). Below is the output and
I think you can specify the number of rows to be loaded at a time. It was
quite a while ago. Try reading
?sqlQuery
?odbcConnect
I have loaded quite large tables.
On Friday 02 October 2009 14:59:59 Dr. Alireza Zolfaghari wrote:
But the problem is that the dataframe size in sql is large,
Thank you very much!!
To trouble you again: I cannot do the sum and i have looked at several package
since startng with this problem. I have a very large code just to do simple
random, normal stratified sampling with proportional allocation and Dollar
stratification with Neyman allocation
Did you ever get a response on this? I have been having a similar problem.
Thanks,
Sarah
antje-4 wrote:
Hi there,
I was using Open/Save-dialogs from the package svDialogs (SciViews). But
now
the package has dissapeared? How do I have to set up my R-installation to
further use these
On Oct 1, 2009, at 6:06 AM, KABELI MEFANE wrote:
Dear Helpers
I have a sample frame and i have sampled from it using three methods
and now i want to calculate the statistics but i only get the
population parameters.
H - matrix(rnorm(100, mean=5, sd=5000))
Hello,
Now, the *bundle* SciViews has disappeared from CRAN, but the *package*
svDialogs is still there.
Best,
Philippe
..°}))
) ) ) ) )
( ( ( ( (Prof. Philippe Grosjean
) ) ) ) )
( ( ( ( (Numerical Ecology of Aquatic Systems
) )
Hi guys,
I need your help.
I would like to select a subset from a dataset.
This is the dimension of the dataset.
dim(data1)
[1] 72 36 1916
so, it's like.. there are 1916 of 72 * 36 matrix. == looks like 72 * (
36*1916 )
**
*1)*
And I would like to select the first 72*36 matrix. This is
Download the package to your hard drive from here:
http://cran.r-project.org/web/packages/svDialogs/
Then install directly using install.packages (for instructions on doing
this, type ?install.packages)
Just tried it, worked fine for me.
Hi there,
I was using Open/Save-dialogs from the
Hi,
On Oct 2, 2009, at 10:47 AM, Hyo Lee wrote:
Hi guys,
I need your help.
I would like to select a subset from a dataset.
This is the dimension of the dataset.
dim(data1)
[1] 72 36 1916
so, it's like.. there are 1916 of 72 * 36 matrix. == looks like 72
* (
36*1916 )
**
*1)*
And I
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of jim holtman
Sent: Friday, October 02, 2009 5:09 AM
To: Gabor Grothendieck
Cc: r-help@r-project.org; J Chen
Subject: Re: [R] break up a string into strings with a fixed length
On 10/2/2009 9:05 AM, Gábor Csárdi wrote:
Dear All,
how can I create a list in the \value{} section of an Rd file? The
things I have tried:
1.
\value{
text text
\item more text
\item even more
}
*** Syntax error: \item in
/-
\item more text
\item even more\-
2.
\value{
text
On Fri, Oct 2, 2009 at 8:45 AM, David Winsemius dwinsem...@comcast.net wrote:
There are multiple routes to robust statistics, but the quick answer to
this question is probably friedman.test
I don't think friedman.test is robust to variance heterogeneity. It is
only robust to
non-normality.
Hello Again R Folk:
I have found items about this in the archives, but I’m still not getting
it right. I want to use ggplot2 with facet_grid inside a function with
user specified variables, for instance:
p - ggplot(data, aes_string(x = fac1, y = res)) + facet_grid(. ~
fac2)
Where data,
Dear All,
I'm sorry if my question does not suit with this R group.
I have recently installed R software with version 2.9.2, but i found the
program took almost 1 minute as soon as it was opened, before it can be used.
However, the previous version 2.9.1 only take few seconds after the menu
Hi, while working with decision trees and unbalanced data, I came across the
use of the Hellinger distance as an alternative to information gain [1,2],
when dealing with skewed data. Does anybody know of R implementations of
this approach to decision trees?
Thanks,
[1]
You're fine, but please do read the posting guide. What OS etc.
Where you doing anything else on the computer? Is this a RAM
limitation? I have 2.9.2 running on two flavours of linux, mac os x
and windows all 2.9.2 and there doesn't seem to be a problem.
regards,
Stephen
On Fri, Oct 2, 2009
Do you happen to have a large .Rdata file that is being loaded, or something in
your .Rprofile? Try searching for a file with that name. Or start R with a
--vanilla and see if that helps...
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Thank you for your answer. I'm using Win XP with 2GB RAM in memory.
Cheers
Fir
- Original Message
From: stephen sefick ssef...@gmail.com
To: FMH kagba2...@yahoo.com
Cc: r-help@r-project.org
Sent: Fri, October 2, 2009 4:38:10 PM
Subject: Re: [R] How to speed up R with version 2.9.2?
Sorry, original replied to wrong post...
Do you happen to have a large .Rdata file that is being loaded, or something in
your .Rprofile? Try searching for a file with that name. Or start R with a
--vanilla and see if that helps...
-Original Message-
From:
Its under 5 seconds on my Vista laptop. Do you have any startup files? If
Rgui --vanilla
is much faster then your startup files are the problem.
On Fri, Oct 2, 2009 at 11:45 AM, FMH kagba2...@yahoo.com wrote:
Thank you for your answer. I'm using Win XP with 2GB RAM in memory.
Cheers
Fir
Another possibility is a very large .RData file in the directory where
you're starting R. You can try
Rgui --no-restore
(I don't have windows, so I'm not sure if this an option with RGui,
though I know it is with R.)
--sundar
On Fri, Oct 2, 2009 at 8:50 AM, Gabor Grothendieck
Yes, i noticed there are few Windows start up programs, shown by the
EasyCleaner software.
Cheers
- Original Message
From: Gabor Grothendieck ggrothendi...@gmail.com
To: FMH kagba2...@yahoo.com
Cc: stephen sefick ssef...@gmail.com;
Sent: Fri, October 2, 2009 4:50:52 PM
Subject: Re:
I was thinking of startup code in your C:\Program
Files\R\R-2.9.2\etc\Rprofile.site file or other startup R file that
you provided. See ?Startup
On Fri, Oct 2, 2009 at 12:01 PM, FMH kagba2...@yahoo.com wrote:
Yes, i noticed there are few Windows start up programs, shown by the
EasyCleaner
This should do what you want:
x-abcdefghijkl
strsplit(x, (?=...), perl=T)
HTH,
STG
--
Stefan Th. Gries
---
University of California, Santa Barbara
http://www.linguistics.ucsb.edu/faculty/stgries
__
Here is a slightly simpler version of the strapply solution with a
short string at the end:
strapply(abcdefghijk, .{1,3})[[1]]
[1] abc def ghi jk
On Fri, Oct 2, 2009 at 8:20 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
That part wasn't specified so we can't say what the required
See fortune(234)
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Noela Sánchez
Sent: Thursday, October 01,
Chad,
(inline below)
joris meys wrote:
Confint doesn't work if you have a multi-dimensional dependent variable.
Well, it will work, but not for the quasibinomial family.
The simple solution would seem to be to change your response from
the matrix cbind(,) to the vector alive/sum(alive+red)
Hello Rainer,
I think that your problem is with trying to fit a logistic model to
data that don't support that model. Removing the first two points
from your data will work (but of course it may not represent reality).
The logistic function does not exhibit the kind of minimum that
your data
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of hadley wickham
Sent: Friday, October 02, 2009 6:07 AM
To: jim holtman
Cc: r-help@r-project.org; Kavitha Venkatesan
Subject: Re: [R] split-apply question
On Fri, Oct 2, 2009
The following code is derived from a paper titled Text Mining Infrastructure
in R (http://www.jstatsoft.org/v25/i05/paper). The example below seems to
load some default documents for analysis, some sort of latin document. I
cannot for the life of me figure out to load my own document let alone
Thanks a lot David for your answer. I am sorry for being so minimal.
I wanted to produce a list/vector/table consisting each vector produced from
this code
len-20
for (n1 in seq(0,(len-1),by=1)){
f - R_event[R_event (rx[1]+ n1*300) R_event = (rx[1] + 300*(n1+1))]
//create list for each values
I want to use the .RProfile to set defaults such as text editor. Is
this a file I need to create? Also, where should I put it? I tend to
create .RData files for different projects, putting each in a different
Windows (Vista) folder. Is one .Rprofile file created that any
Dear R users,
I'm trying to fit a parametric survival model using the survreg function
with a Weibull distribution.
I'm studying the time to death of individuals from different families
and I would like to fit different shape parameters (ie 1/scale in R) for
each of the families. I looked it up
Hi,
Is there a way to set the scale of a plot (i.e. number of axis units
per centimeter) when you output it to postscript? If not, how am I
supposed to plot graphs with different axis limits to the same scale?
They just get resized to fit the paper so that graphs which show a
smaller
Dear Mr Winsemius
I am sorry to have offended any of you by the mistakes i made. The package i
loaded is sampling and there was an unwanted comma between size c(20, )and the
bracket. What i wanted was to calculate the sum of H in a sample not in the
original dataframe. If i do
sum(H) i get
Your problem lies in the use of system.file. This command looks in the
folder location of tm for specific folders. See ?system.files.
Basically, for the document example, it assigning txt to the directory
string like C:/Program Files (x86)/R/R-2.9.0/library/tm/texts/txt
Then the DirSource(txt)
I have installed, its workable in frontground mode while but background mode,
may I know how do I activate background mode? Thanks
Irina Ursachi wrote:
Dear all,
I have a question regarding background and foreground server in RExcel:
Can somebody explain the main difference between them?
Hello!
Please help - can't find any options how to remove very big spaces between
two dates containing intraday prices plotted by plot.xts. It looks like the
following: on the left side of the plot window is the first bunch of points,
the same is for the right hand side and a long line
Here is a different approach:
This example uses the default plotting device, but should work the same with
postscript or any other device. Just set the size of the paper to a standard
size, or a large enough size to fit your largest plot:
dev.new()
tmp - par('plt')
scale - 5
x - runif(100, 0,
Trying to fit a model using the Surv() with a frailty term but get the
following cryptic error message:
--
Error in frailty.brent(sqrt(x), y, lower = 0) :
Ties for max(y), I surrender
Calls: runplots ... coxpenal.fit -
Dear R-help,
First of all, thank you VERY much for any help you have time to offer. I
greatly appreciate it.
I would like to write a function that, given an arbitrary number of factors
from a data frame, tabulates the number of occurrences of each unique
combination of the factors. Cleary,
Dear all
On my system html() conversion of a `latex()' object fails. Follows a
dummy example:
require(Hmisc)
data(Angell)
.object - cor(Angell[,1:2], use=complete.obs)
tmp - latex(.object, cdec=c(2,2), title=)
class(tmp)
[1] latex
html(tmp)
/tmp/RtmprfPwzw/file7e72f7a7.tex:9: Warning:
Andrew,
Is this what you're looking for? Most likely a more elegant solution exists...
but maybe this is good enough.
## BEGIN R SAMPLE CODE
## sample data frame, 3 factors
tmp - data.frame(f1 = sample(gl(2, 50, labels = c(Male, Female))),
f2 = sample(gl(4, 25, labels =
Kabeli,
You seem to be doing your best to avoid working
your way through some introductory documentation
like An Introduction to R, which is sitting
right there on your computer.
So let's try to take it slowly, one step at a time.
#1. generate a vector of values to work with.
(forget the
I have a list of participants in a study, identified by number. I want
to randomly sort them into an arbitrary number of groups.
split(sample(1:96, 96), 1:16)
almost does it, but it only works where the division is even. Any ideas?
Thanks!
Jason Priem,
Doctoral Student,
School of Information
Dear list,
I would like to aggregate CVTimeDiff by Fish_ID and Trip and put the result
into myarray,i.e. for the example below Trip 1,9 and Fish_ID 1646 I would like
to obtain mean= (0.8104876+1.3676631)/2 and put it into myarray[1] .
mydataframe
Trip Fish_ID CVTimeDiff
1 1,9
Many thanks to both who replied, Ulrike and Petr. Indeed, some playing
with the margin-sizing options solved my problem.
All the best, Primož
2009/9/29 Ulrike Groemping groemp...@bht-berlin.de:
Hello Primoz,
with traditional graphics, you may want to use par (?par), options like mar,
mai,
Dear R Community,
I am running GLM's within the MASS library. My data are overdispersed and
I am accounting for the overdispersion by using an ANOVA 'F' test instead of
ANOVA 'Chisq'. You will have to forgive me because I am new at this, but I
am not sure if R is conducting an ANOVA 'F'
1 - 100 of 124 matches
Mail list logo
