Dieter Menne wrote:
Henrik Wahren wrote:
How can one or more levels be removed from a factor of a data frame. There
was a similar post on how to do this when a factor meets some criterion
(e.g. = 2), but I can¹t seem to get that solution to work.
Here, I simply want to drop some levels.
Hi all,
I wonder what the difference is between the functions prcomp and the PCA
plotting method used in example 3 from the fastICA package. They give totally
different plots. The reason for asking is that I've earlier used prcomp, but
now I should do an ICA, and I guess I cannot compare
Tan, Richard wrote:
Hello, can someone help? How come
gsub(\bINDS\b,INDUSTRIES,ADVANCED ENERGY INDS)
[1] ADVANCED ENERGY INDS
It does, but you need to escape it:
gsub(\\bINDS\\b,INDUSTRIES,ADVANCED ENERGY INDS)
Uwe Ligges
not ADVANCED ENERGY INDUSTRIES
Thanks.
Richard
Peng Yu wrote:
According to Amazon review, 'Statistical Models in S' is a key
reference for understanding the methods implemented in several of
S-PLUS' high-end statistical functions, including 'lm()', predict()',
'design()', 'aov()', 'glm()', 'gam()', 'loess()', 'tree()',
'burl.tree()',
Hi,
You can ad it yourself:
http://stat.ethz.ch/mailman/listinfo/r-help
-Ista
On Wed, Nov 11, 2009 at 12:57 AM, 杨江伟 jwyan...@gmail.com wrote:
thanks a lot
--
Pleasure should be subordinate to duty.
[[alternative HTML version deleted]]
__
Dear R helpers
Suppose I have a following data
y - c(9.21, 9.51, 9.73, 9.88, 10.12. 10.21)
t - c(0, 0.25, 1, 3, 6, 12)
I want to find out the polynomial which fits y in terms of t i.e. y = f(t) some
function of t.
e.g. y = bo + b1*t + (b2 * t^2) + (b3 * t^3) + .. and so on.
Dear Robert,
Thanks for the information.
I tried this but it still did not work well.
I will try some other option.
Nana Browne
There is no key to happiness. The door is always open.
--- On Tue, 11/10/09, Robert J. Hijmans
Hello,
I have the following data and would like to get some hints on how to analyze
tis data, nested analysis?
Habitats: 2 (Seagrass meadows and sandy bottoms)
Seasons: 4 (Winter, Spring, Summer and Autumn)
Locations: 4 (2 locations for for each habitat and season)
Replicates: 3 replicates
Le mercredi 11 novembre 2009 à 10:22 +0100, Uwe Ligges a écrit :
Peng Yu wrote:
According to Amazon review, 'Statistical Models in S' is a key
reference for understanding the methods implemented in several of
S-PLUS' high-end statistical functions, including 'lm()', predict()',
Emmanuel Charpentier wrote:
Le mercredi 11 novembre 2009 à 10:22 +0100, Uwe Ligges a écrit :
Peng Yu wrote:
According to Amazon review, 'Statistical Models in S' is a key
reference for understanding the methods implemented in several of
S-PLUS' high-end statistical functions, including
Hi all,
I wanted to have a seasonality study like whether a particular month has
significant effect as compared to others. Here is my data :
0.10499 0 0 1 0 0 0 0 0 0
0 0
0.00259 0 0 0 1 0 0 0
Try this:
x - read.table(textConnection(idcode1code2 p
+ 148 0.1
+ 157 0.9
+ 218 0.4
+ 262 0.2
+ 243 0.6
+ 356 0.7
+
hi,
I'm mustafa. I'm a master student Dokuz Eylül University in
Izmir/Turkey.
nbsp;
I focus on Statistical programming language R. I learn architecture
of R. But i don't find out any material in internet.
Would you like tonbsp;help me this subject? If you have
documentations, would you like to
Your script works very well. Thank you very much.
Legen
Henrique Dallazuanna wrote:
Try this also:
xtabs(rep(p, 2) ~ rep(id, 2) + sprintf(var%d, c(code1, code2)), data =
x)
On Wed, Nov 11, 2009 at 2:10 AM, legen lege...@gmail.com wrote:
Thank you for your kind help. Your script
CAN ANYONE PLEASE HELP ME WITH THIS
i HAVE TO DO A MIXED EFFECT LINEAR MODEL WITH MY DATA DUE TO THE FACT THAT I
have pseudoreplication!
Although after reading and trying it for several times can get around due to
Error in na.fail.default(list(date = c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, :
missing
That's what I want. Many thanks for your help.
Legen
jholtman wrote:
Try this:
x - read.table(textConnection(idcode1code2 p
+ 148 0.1
+ 157 0.9
+ 218 0.4
+ 262
Hi Bogaso,
Try this
vecnames-names(test[,2:11])
fmla - as.formula(paste(test[,1] ~ , paste(vecnames, collapse= +)))
res-lm(fmla)
Regards
M
Bogaso a écrit :
Hi all,
I wanted to have a seasonality study like whether a particular month has
significant effect as compared to others. Here is my
Hi friends,
Again i don't know how to pass multiple arguments from php file to r
scripts.
Please have a look at this link ; it gives a very simple explanation of
passing variables from a PHP page to r scipts.Because i have done the same
thing.
For me with ff - on a 3 GB notebook - 3e6x100 works out of the box even without
compression: doubles consume 2.2 GB on disk, but the R process remains under
100MB, rest of RAM used by file-system-cache.
If you are under windows, you can create the ffdf files in a compressed folder.
For the
Hi Peng,
the major problem about your specific case is that when creating the
final object, we need to set dimnames() appropriately. This triggers a
copy of the object and that's where you get the error you describe.
With the current release, unfortunately, there isn't much to do
(unless
Hi all,
Does anyone know how to get the independent components and loadings from an
Independent Component Analysis (ICA), as well as principal components and
loadings from a Pricipal Component analysis (PCA) using the fastICA package? Or
perhaps if there's another way to do ICAs in R?
On Nov 11, 2009, at 7:14 AM, Bogaso wrote:
Hi all,
I wanted to have a seasonality study like whether a particular month
has
significant effect as compared to others. Here is my data :
0.10499 0 0 1 0 0 0 0 0 0
0 0
0.00259 0
Hi,
I have a matrix with positive numbers, negative numbers, and NAs. An
example of the matrix is as follows
-1 -1 2 NA
3 3 -2 -1
1 1 NA -2
I need to compute a scaled version of this matrix. The scaling method is
dividing each positive numbers in each row by the sum of positive numbers
in that
This is possibly the wrong list, but anyway ...
Using Linux Debian-4.0 Etch (regularly upgraded).
I set about installing Simon Woods' soap package -- see:
http://www.maths.bath.ac.uk/~sw283/simon/software.html
So I downloaded the tar archive soap_0.1-3.tar.gz and then ran
(as root) R CMD
Dear all,
W.XP
I recently upgraded to R2.10.0 and did what I usually do: copied all
special libraries from the old installation and then used
update.packages() on the command line. Nothing happened. Then I clicked
on the same command on the droplist which generated
The date library was written 20 or so years ago. It was a very good
first effort, but the newer Date library has superior functionality in
nearly every way. The date library is still available, for legacy
projects such as yours, but I do not advise it for new work. To answer
your specific
Dear R-users,
I have the following zoo object:
x1x2 x3 x4
x5 x6
1998-08-31 -0.0704375904 NA NA NA
NA NA
1998-09-01 0.0379028122 NA NA NA
NA
Dear all,
I will present R language and R software environment to the Statistical Society
of Serbia.
As I will doing it to professional statisticians it seems unneccesary to
me to present them how R language works in details. I am more
interested to present them with the latest facts regarding
one approach is the following:
mat - rbind(c(-1, -1, 2, NA), c(3, 3, -2, -1), c(1, 1, NA, -2))
mat / ave(abs(mat), row(mat), sign(mat), FUN = sum)
I hope it helps.
Best,
Dimitris
Hao Cen wrote:
Hi,
I have a matrix with positive numbers, negative numbers, and NAs. An
example of the matrix
mustafa_binar wrote:
hi,
I'm mustafa. I'm a master student Dokuz Eylül University in
Izmir/Turkey.
nbsp;
I focus on Statistical programming language R. I learn architecture
of R. But i don't find out any material in internet.
Would you like tonbsp;help me this subject? If you
On 11/11/2009 10:26 AM, Damjan Krstajic wrote:
Dear all,
I will present R language and R software environment to the Statistical Society
of Serbia.
As I will doing it to professional statisticians it seems unneccesary to
me to present them how R language works in details. I am more
interested
On Nov 11, 2009, at 10:36 AM, Dimitris Rizopoulos wrote:
one approach is the following:
mat - rbind(c(-1, -1, 2, NA), c(3, 3, -2, -1), c(1, 1, NA, -2))
mat / ave(abs(mat), row(mat), sign(mat), FUN = sum)
Very elegant. My solution was a bit more pedestrian, but may have some
speed
Hello,
I am searching for a function to calculate partial cumsums.
For example it should calculate the cumulative sums until a NA appears,
and restart the cumsum calculation after the NA.
this:
x - c(1, 2, 3, NA, 5, 6, 7, 8, 9, 10)
should become this:
1 3 6 NA 5 11 18 26 35 45
any
I need to get the names of the list elements when I iterate over a
list. I'm wondering how to do so?
alist=list(a=c(1,3),b=c(-1,3),c=c(-2,1))
sapply(alist,function(x){
#need to use the name of x for some subsequent process
})
__
Dear Forum
my machine runs Ubuntu 9.04. I am trying to install Biomart, what I realize
is that something is missing and it can't install XML, RCurl but I don't
know what more to do, I looked in previous posts but I did not find
infoprmation that helped.
Thanks
Andreia
biocLite(biomaRt)
Running
Hi Andreia --
Andreia Fonseca wrote:
Dear Forum
my machine runs Ubuntu 9.04. I am trying to install Biomart, what I realize
is that something is missing and it can't install XML, RCurl but I don't
know what more to do, I looked in previous posts but I did not find
infoprmation that helped.
On Wed, 11 Nov 2009 10:51:53 -0500 Duncan Murdoch murd...@stats.uwo.ca
wrote:
If you know their applications you can show how well R does there,
And do mention the (increasing) number of books available. It's only a
slight exaggeration to say that there are R books on almost any
application
Simon Seibert simon.seibert at mytum.de writes:
Good evening list,
I'm looking for an R implementation of the Shuffled Complex
Evolutionâ (SCE-UA) algorithm after Duan et al. (1993). Does anybody
know if there is an extension/ package existing that contains it?
Thanks very much for your
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Peng Yu
Sent: Wednesday, November 11, 2009 8:02 AM
To: r-h...@stat.math.ethz.ch
Subject: [R] How to get the names of list elements when
iterating over alist?
I need to get
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of smu
Sent: Wednesday, November 11, 2009 7:58 AM
To: r-help@r-project.org
Subject: [R] partial cumsum
Hello,
I am
Dear list subscriber,
suppose, I do have a minimal Sweave file 'test.Rnw':
\documentclass{article}
\begin{document}
printx=
x
@
\end{document}
Within R, I define the following function:
f - function(x){
Sweave(test.Rnw)
}
The call:
f(x = 1:10)
results in the following error message:
On Mon, Oct 19, 2009 at 7:57 PM, Peng Yu pengyu...@gmail.com wrote:
tmp - matrix(1:2)
tmp
tmp[,1,drop=FALSE]
See the above example. Is there a way to make 'drop=FALSE' as global
default, so that when I say 'tmp[,1]', R will treat it as
'tmp[,1,drop=FALSE]'?
Is there a way to set
On Wed, 11 Nov 2009 08:53:50 -0800 William Dunlap wdun...@tibco.com
wrote:
x - c(1, 2, 3, NA, 5, 6, 7, 8, 9, 10)
should become this:
1 3 6 NA 5 11 18 26 35 45
Perhaps
ave(x, rev(cumsum(rev(is.na(x, FUN=cumsum)
[1] 1 3 6 NA 5 11 18 26 35 45
Clever way of
On Nov 11, 2009, at 10:57 AM, David Winsemius wrote:
On Nov 11, 2009, at 10:36 AM, Dimitris Rizopoulos wrote:
one approach is the following:
mat - rbind(c(-1, -1, 2, NA), c(3, 3, -2, -1), c(1, 1, NA, -2))
mat / ave(abs(mat), row(mat), sign(mat), FUN = sum)
Very elegant. My solution was
I am writing a rd doc, and need to use # in a url adress. This would make:
\url{http://www..org/myfolder/#myanchor}
Of course, I suppose this will not work because # is a special character
starting a comment line in the rd dialect. I did not found a similar
example in Writing R exentions.
On Wed, 11 Nov 2009 18:11:51 +0100 Karl Ove Hufthammer k...@huftis.org
wrote:
I wish cumsum took a 'na.rm' argument, though. It would make stuff like
this much easier.
Or, more specifically, a 'na.value', which could perhaps default to
'NA' to get the current behaviour, but which one could
x=\url{http://www..org/myfolder/#myanchor};
print(x,quote=F)
Does this work for you?
Daniel
-
cuncta stricte discussurus
-
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag
I'm very familiar with C++. In this sense, it is easier for me to
learn R.oo according to your advice. On the other hand, S3 and S4 are
the most used. I'm wondering what would be the best choice for me. Do
you have any recommendation considering the pros and cons of both
ways?
Is it true that
On Wed, Nov 11, 2009 at 08:53:50AM -0800, William Dunlap wrote:
Perhaps
ave(x, rev(cumsum(rev(is.na(x, FUN=cumsum)
[1] 1 3 6 NA 5 11 18 26 35 45
it takes some time to understand how it works, but it's perfect.
thank you,
stefan
On 11/11/2009 12:09 PM, Pfaff, Bernhard Dr. wrote:
Dear list subscriber,
suppose, I do have a minimal Sweave file 'test.Rnw':
\documentclass{article}
\begin{document}
printx=
x
@
\end{document}
Within R, I define the following function:
f - function(x){
Sweave(test.Rnw)
}
The call:
f(x
To me, R is the language of choice for a rapidly increasing number
of people involved in new statistical algorithm development. If they
are happy with the tools they currently use, learning R may be a lot of
pain for little gain.
However, if they want to stay current with the
-Original Message-
From: smu [mailto:m...@z107.de]
Sent: Wednesday, November 11, 2009 9:26 AM
To: William Dunlap
Cc: r-help@r-project.org
Subject: Re: [R] partial cumsum
On Wed, Nov 11, 2009 at 08:53:50AM -0800, William Dunlap wrote:
Perhaps
ave(x,
Daniel Malter a écrit :
x=\url{http://www..org/myfolder/#myanchor};
print(x,quote=F)
Does this work for you?
Daniel
I am not working on consol mode (which would make your suggestion
straight applicable), but writing a rd documentationn (the documentation
that comes out with the
Yes, thanks for this, this is exactly what I want to do.
However, I have a remaining problem which is how to get R to understand that
each entry in my matrix is a vector of names.
I have been trying to import my text file with the names in each vector of
names enclosed in quotes and separated
Ben ,
Thanks! This worked after I updated my version of R (from 2.8.1 to 2.10) .
Best,
Spencer
On Tue, Nov 10, 2009 at 7:04 PM, Ben Bolker bol...@ufl.edu wrote:
sj ssj1364 at gmail.com writes:
I am using glmer() from lmer(lme4) to run generalized linear mixed
models. I
can't figure
On 11/11/2009 12:15 PM, Patrick Giraudoux wrote:
I am writing a rd doc, and need to use # in a url adress. This would make:
\url{http://www..org/myfolder/#myanchor}
That should work.
Of course, I suppose this will not work because # is a special character
starting a comment line in the
On Nov 11, 2009, at 1:02 PM, esterhazy wrote:
Yes, thanks for this, this is exactly what I want to do.
However, I have a remaining problem which is how to get R to
understand that
each entry in my matrix is a vector of names.
I have been trying to import my text file with the names in
Dear Ana Golveia,
It is completelly impossible someone realise what kind or help you need or
what is happening. I suggest you give a look on the posting guide, mainly
that part about a minimum reproducible code with self explaining
information, etc.
Cheers
milton
On Wed, Nov 11, 2009 at 7:22
Duncan Murdoch a écrit :
On 11/11/2009 12:15 PM, Patrick Giraudoux wrote:
I am writing a rd doc, and need to use # in a url adress. This
would make:
\url{http://www..org/myfolder/#myanchor}
That should work.
Of course, I suppose this will not work because # is a special
character
Patrick Giraudoux a écrit :
Duncan Murdoch a écrit :
On 11/11/2009 12:15 PM, Patrick Giraudoux wrote:
I am writing a rd doc, and need to use # in a url adress. This
would make:
\url{http://www..org/myfolder/#myanchor}
That should work.
Of course, I suppose this will not work because #
Duncan Murdoch wrote:
Just declaring it there is the only reasonable way, i.e.
test-function(foo) {
subtest - function() {
foo - foo+1
}
subtest()
return(foo)
}
The reason you can't somehow assign it within an existing test is that
subtest is a different closure every time. Its
#Hello,
#I loaded data using read.table - I needed to convert a row in the data
frame to date class:
data
V1 V2 V3 V4
1 2008-05-19 2008-04-19 2008-03-21 2008-02-22
2 38.16999817 30.7008 36.8661 35.18999863
3 37.4754 29.9576 36.4508
This is a tricky data entry problem. The right technique will depend on the fine details of the
data, and it's not clear what those are. E.g., when you say In my first column, for example,
I have henry , it's unclear to me whether or not the double quotes are part of
the data or not - which
Hi All,
I am new to this form and new to R, having just initiated the analysis of my
first project using R. I have been working on a logistic model of land use
change and am concerned about 1) measuring spatial autocorrelation and 2)
including an autocovariate in my model.
Here is what I think
Hi,
On Nov 11, 2009, at 1:06 PM, separent wrote:
#Hello,
#I loaded data using read.table - I needed to convert a row in the
data
frame to date class:
data
V1 V2 V3 V4
1 2008-05-19 2008-04-19 2008-03-21 2008-02-22
2 38.16999817 30.7008 36.8661
On Nov 11, 2009, at 12:06 PM, separent wrote:
#Hello,
#I loaded data using read.table - I needed to convert a row in the
data
frame to date class:
data
V1 V2 V3 V4
1 2008-05-19 2008-04-19 2008-03-21 2008-02-22
2 38.16999817 30.7008 36.8661
On Nov 11, 2009, at 1:06 PM, separent wrote:
#Hello,
#I loaded data using read.table - I needed to convert a row in the
data
frame to date class:
You _should_ have given the actual code (as the Posting Guide
requests), but I would guess that you should have added either
as.is=TRUE
That is wonderful, now I think I am all set! Thanks again!
Tony Plate wrote:
This is a tricky data entry problem. The right technique will depend on
the fine details of the data, and it's not clear what those are. E.g.,
when you say In my first column, for example, I have henry , it's
William Dunlap wrote:
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of smu
Sent: Wednesday, November 11, 2009 7:58 AM
To: r-help@r-project.org
Subject: [R] partial cumsum
hi all - quick question:
i have a matrix 'y' of response values, with two explanatory variables
'x1' and 'x2'.
tested values of 'x1' and 'x2' are sitting in two vectors 'x1' and
'x2'.
i want to learn model parameters without unrolling the matrix of
response values.
example below:
# some fake
Hello,
Thank you for responding! The data is in the same format as the example I
showed earlier. The data is different from matrix to matrix, but the general
format is:
Time1Time 2 Time3 Time4
Species1 134 5
Species2 3
Hi all,
I am new to python, R and rpy2. I having few errors when I am using
'fisher.test' function where I am struck now. Please help to fix these bugs.
My code for fisher.test goes this way
*from rpy2 import *
import rpy2.robjects as robjects
def fisherExact(a,b,c,d):
v = [a,b,c,d]
m =
On Nov 11, 2009, at 2:24 PM, Murat Tasan wrote:
hi all - quick question:
i have a matrix 'y' of response values, with two explanatory variables
'x1' and 'x2'.
tested values of 'x1' and 'x2' are sitting in two vectors 'x1' and
'x2'.
i want to learn model parameters without unrolling the matrix
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Bhanu Mangipudi
Sent: Wednesday, November 11, 2009 11:16 AM
To: r-help@r-project.org
Subject: [R] fisher.test negative value error
Hi all,
I am new to python, R and rpy2. I
Hello Gentlemen,
All of your answers were helpfull. Indeed, 'as.is=TRUE' or
'stringsAsFactors=FALSE' avoid importing as factors, as it did when I
imported the table without specifying anything. However, data frames will
not allow different datatypes within a single column, so, for time series, I
Milton's point is dead-on, and I would highly encourage you to give the
posting guide a look.
That said... you might try na.action = na.omit in your call to...
actually, we don't know what function you are using (see first point).
Regardless, sounds like you have missing data and na.action is
On Wed, 11 Nov 2009, Peng Yu wrote:
On Mon, Oct 19, 2009 at 7:57 PM, Peng Yu pengyu...@gmail.com wrote:
tmp - matrix(1:2)
tmp
tmp[,1,drop=FALSE]
See the above example. Is there a way to make 'drop=FALSE' as global
default, so that when I say 'tmp[,1]', R will treat it as
On Wed, 11 Nov 2009, Larry Hotchkiss wrote:
Hi,
I'm responding to the question about storage error, trying to read a 300 x
100 dataset into a data.frame.
I wonder whether you can read the data as strings. If the numbers are all one
digit, each cell would require just 1 byte instead of
I'm trying to write code to calculate partial correlations (along with
p-values). I'm new to R, and I don't know how to do this. I have searched
and come across different functions, but I haven't been able to get any of
them to work (for example, pcor and pcor.test from the ggm package).
In
I think it would be best to learn S3 first since that is a fundamental
part of R and S4 is an extension of it and also its very simple so
there is not much to learn. After that you can branch out.
On Mon, Oct 26, 2009 at 2:28 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
S3 and S4 are
The help for fastICA says:
The data matrix X is considered to be a linear combination of
non-Gaussian (independent) components i.e. X = SA where columns of
S contain the independent components and A is a linear mixing
matrix.
The value of fastICA is a list with components S (the
Hello, I'm beginning with R and I'm wondering if there's any way to display
large values (e.g. 161651654167) using my system's thousands separator or
scientific notation.
Thanks!
[[alternative HTML version deleted]]
__
R-help@r-project.org
Hi,
I'm new to R.
I've two sort of time series, one sampled every second and other every 30
minutes stored in two data.frames zy1 and zy2.
I've joined the two series using
date-merge(zy1,zy2, all.x=T,all.y=T)
when I want to make a plot, using the code below, it doesn't work.
It gives me the
Dear Michel,
The only thing you need to do is download the TSA package, and read its
document. In this document you're gonna find the command eacf, so it's as
simple as using the source TSA, and in ur Tinn-R just call the instruction
with the options you want.
I expect this information to be
When printing data.frames, R aligns columns by padding with spaces.
For example,
print(data.frame(x=c('a','bb','ccc')),right=FALSE)
x
1 a |-- vertical bar shows end of line
2 bb |-- vertical bar shows end of line
3 ccc|-- vertical bar shows end
On Nov 11, 2009, at 3:52 PM, Patricio Cuarón wrote:
Hello, I'm beginning with R and I'm wondering if there's any way to
display
large values (e.g. 161651654167) using my system's thousands
separator or
scientific notation.
Thanks!
To get scientific notation as a default for given large
Please what I already wrote in my previous message of this thread.
Also, everything in R.oo is based on S3 and it uses standard R
constructs and data types to achieve what it does.
You can submit packages based on R.oo, and there are several such
packages on CRAN, see 'Reverse dependencies' on
Stavros Macrakis wrote:
I could of course write my own print function for this, but was
wondering if there was a standard way of doing it. If not in R,
perhaps there is some way to have ESS delete the final spaces?
ESS, or more precisely emacs, can handle that. Use the M-x
quote:
x - c(1, 2, 3, NA, 5, 6, 7, 8, 9, 10)
rev(cumsum(rev(is.na(x
[1] 1 1 1 1 0 0 0 0 0 0
A more natural way to do this is
cumsum(is.na(c(NA,x[-length(x)])))
[1] 1 1 1 1 2 2 2 2 2 2
endquote
Both of which suggest the original problem could also be dealt with by
using
See the above example. Is there a way to make 'drop=FALSE' as global
default, so that when I say 'tmp[,1]', R will treat it as
'tmp[,1,drop=FALSE]'?
The following code won't change the defaults, but it would at least
let you know when you're making the mistake:
trace_all - function(fs,
On Nov 11, 2009, at 4:45 PM, Carl Witthoft wrote:
By Bill Dunlap:
quote:
x - c(1, 2, 3, NA, 5, 6, 7, 8, 9, 10)
rev(cumsum(rev(is.na(x
[1] 1 1 1 1 0 0 0 0 0 0
A more natural way to do this is
cumsum(is.na(c(NA,x[-length(x)])))
[1] 1 1 1 1 2 2 2 2 2 2
endquote
Both of which
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of hadley wickham
Sent: Wednesday, November 11, 2009 3:03 PM
To: Peng Yu
Cc: r-h...@stat.math.ethz.ch
Subject: Re: [R] Is there a way to specify drop=FALSE as the
global default?
Hello R users,
Is anyone familiar with an R function that converts a time expression (
POSIx for example ) to time (seconds/minutes) from epoch?
I was unable to find any
Best,
Alon
[[alternative HTML version deleted]]
__
try this:
x - Sys.time()
str(x)
POSIXct[1:1], format: 2009-11-11 18:40:10
x
[1] 2009-11-11 18:40:10 EST
as.numeric(x) # secs from 1/1/1970
[1] 1257982810
On Wed, Nov 11, 2009 at 6:29 PM, Alon Ben-Ari alon.ben...@gmail.com wrote:
Hello R users,
Is anyone familiar with an R function
http://code.google.com/p/ihacres/source/browse/trunk/man/SCEoptim.Rd
http://code.google.com/p/ihacres/source/browse/trunk/R/sce.R
source(http://ihacres.googlecode.com/svn/trunk/R/sce.R;)
2009/11/12 Hans W Borchers hwborch...@googlemail.com:
Simon Seibert simon.seibert at mytum.de writes:
Often I perform the same task on a series of variables in a dataframe, by
looping through a character vector that holds the names and using paste(),
eval(), and parse() inside the loop.
For instance:
thesevars-names(environmental)
environmental$ToyOutcome-rnorm(nrow(environmental))
Try this:
lm(environmental[c(ToyOutcome, thisvar)])
or
lm(ToyOutcome ~., environmental[c(ToyOutcome, thisvar)])
On Wed, Nov 11, 2009 at 6:49 PM, Jacob Wegelin jacobwege...@fastmail.fm wrote:
Often I perform the same task on a series of variables in a dataframe, by
looping through a
Hi there
Sorry for what may be a naive or dumb question.
I have the following data:
x - c(1,2,3,4) # predictor vector
y - c(2,4,6,8) # response vector. Notice that it is an exact,
perfect straight line through the origin and slope equal to 2
error - c(0.3,0.3,0.3,0.3) # I have (equal)
On Wed, Nov 11, 2009 at 8:12 PM, Stavros Macrakis macra...@alum.mit.edu wrote:
Thanks for the suggestion. I'mm familiar with the truncate-lines variable,
but that's not quite what I was looking for. I don't want the padding
spaces displayed, but I do want to see long strings at the end of the
Thanks for the suggestion. I'mm familiar with the truncate-lines variable,
but that's not quite what I was looking for. I don't want the padding
spaces displayed, but I do want to see long strings at the end of the line.
Thanks anyway,
-s
On Wed, Nov 11, 2009 at 5:40 PM, Richard
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