Since the context is missing in this message, from others this is
about 32-bit Windows.
On Thu, 15 Apr 2010, yehengxin wrote:
Thanks for your response. I found the folder to modify the compiler for C
source codes. C++ 6.0 is an old C programming environment (1994~1998) but
it is efficient.
Samuel Bravo wrote:
I'm working on a very large project in which we do many calculations which
include many types of regression such as, Liner, Quadratic, Cubic,
Exponential, Sinusoidal, and Logarithmic.
Students are often looking at the wrong place. It's not intuitive that
quadratic,
Why don't you try something like :
Xd$x=as.date(xd$x,format=%y/%m/%d).
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Christian Raschke
Sent: Thursday, April 15, 2010 8:28 PM
To: r-help@r-project.org
Subject: Re: [R]
On Fri, Apr 16, 2010 at 1:49 AM, Sharpie ch...@sharpsteen.net wrote:
Sink captures R output and directs it elsewhere- common places are a file or
device such as /dev/null
Personally it always connected with the concept of a sink in a
mathematical system as something that removes constituants
thanks thierry,
i considered this transformations already, but variance is not stabilized
and/or normality is neither achieved.
i guess i'll have to look out for non-parametrics?
best regards,
kay
--
View this message in context:
Dear group,
Here is my data.frame :
df -
structure(list(DESCRIPTION = c(PRM HGH GD ALU, PRM HGH GD ALU,
PRIMARY NICKEL, PRIMARY NICKEL, PRIMARY NICKEL, PRIMARY NICKEL,
STANDARD LEAD , STANDARD LEAD , STANDARD LEAD , STANDARD LEAD ,
STANDARD LEAD , STANDARD LEAD , STANDARD LEAD , STANDARD
thank you thomas for the helpful hint!
yours,
kay
--
View this message in context:
http://n4.nabble.com/glmer-with-non-integer-weights-tp1837179p1965827.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing
Thanks for your suggestion Tal. Unfortunately, still no luck with me ...
still get the usual error message:
Error in library(gplots) : there is no package called 'gplots' , whatever
I try to install.
This is a mystery to me with respect to why /how. I am really stuck with
that problem.
Best,
Hi Vava,
What version of R are you using? I'm not sure but I think that R will
refuse to install a package in this way if the version of gplots is
incompatiable with the version of R you're using. You can check the
depends of packages on CRAN.
Regards,
James
Vava wrote:
Thanks for your
Hello,
how can I return the name of a variable, say a$b, from a function?
fun - function(x){
return(substitute(x));
}
a - data.frame(b=1:10);
fun(a$b)
... returns a$b, but this is a type language, thus I can't use it as a
character string, can I? How?
Thanks for help,
Sören
I have a problem with the merge function:
I need to merge the data.frames that you will find as arrachmente...I try all
the possible combinationsbut none seems to work properly
Does anyone knows how to do it??
thanks
__
R-help@r-project.org
Hi,
I generated an R package but at running R CMD check, I got the following error
message for the first data file:
*** installing help indices
Building/Updating help pages for package 'jamda'
Formats: text html latex example
f1 texthtmllatex example
Dear users,
I am using R in UBUNTU , but the version is 9.1. How can I upgrade it to R
10.1?
--
Arindam Fadikar
M.Stat
Indian Statistical Institute.
New Delhi, India
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hello everyone,
i have a question regarding the sampling process in boot().
I try to bootstrap F-values for a repeated measures ANOVA to get a confidence
interval of F-values. Unfortunately, while the aov works fine, it fails in the
boot()-function. I think the problem might be that the
Dear James,
i have tried to install the package RODBC1-3.1 with R version 2.9.0 and
2.10.1 (using Opensuse 11.1, 64bits). I have tried install.packages locally
(package downloaded and stored locally on the computer) or directly from
Internet (using different mirrors !). Same results each
carol white wrote:
Hi,
I generated an R package but at running R CMD check, I got the following error
message for the first data file:
*** installing help indices
Building/Updating help pages for package 'jamda'
Formats: text html latex example
f1 text
Assuming its the last package that you loaded detach() without
arguments will detach it.
On Thu, Apr 15, 2010 at 1:45 PM, Prof. John C Nash nas...@uottawa.ca wrote:
Brian Ripley pointed out that the library() documentation (third screen,
however) says that library() and require() check current
Hi,
I'm not sure I understand what you want exactly. My best guess is that you
want something like
op=ddply(DF, c(DESCRIPTION), summarise, POSITION=
sum(QUANITY),DATE=max(CREATED.DATE), CLOSING.PRICE =
CLOSING.PRICE[CREATED.DATE == max(CREATED.DATE)])
op - unique(op)
Does that do it?
-Ista
On
Hi everyone!
I am very new to R and I am having some difficulties.
My data set looks something like this:
ABCD E
cat monkey cat dogcat
cat
__
Hi Sören
Somehow this feels dirty, but you can do
fun - function(x){
result - capture.output(print(substitute(x)))
return(result);
}
-Ista
On Fri, Apr 16, 2010 at 5:26 AM, soeren.vo...@eawag.ch wrote:
Hello,
how can I return the name of a variable, say a$b, from a function?
fun -
Hi Arindam,
Follow the instructions at http://lib.stat.cmu.edu/R/CRAN/bin/linux/ubuntu/
-Ista
On Fri, Apr 16, 2010 at 5:54 AM, arindam fadikar
arindam.fadi...@gmail.comwrote:
Dear users,
I am using R in UBUNTU , but the version is 9.1. How can I upgrade it to R
10.1?
--
Arindam Fadikar
Hi everyone!
I am very new to R and I am having some difficulties.
My data set looks something like this:
subjectA B C
D E
1 cat monkey cat
dog cat
2 cat
When I pass your command line, here is what I get :
op=ddply(df,c(DESCRIPTION),summarise,POSITION=sum(QUANITY),DATE=max(CREAT
ED.DATE),SETTLEMENT=CLOSING.PRICE[CREATED.DATE=max(CREATED.DATE)])
op
DESCRIPTION POSITION DATE SETTLEMENT
1 PRIMARY NICKEL0 2010-03-10 NA
2 PRM
On 16/04/2010 5:26 AM, soeren.vo...@eawag.ch wrote:
Hello,
how can I return the name of a variable, say a$b, from a function?
Use deparse(substitute(x)), not just substitute(x). By the way, to be
picky, a$b is not the name of a variable. It is an expression that
extracts the b element of
Hi Laura,
Usually this kind of thing is easier if you put your data into a long
format. I would use something like
Dat - read.table(textConnection(subject A B C D E
1 cat monkey cat dog cat
2 cat cat cat cat dog), header=TRUE)
library(reshape)
m.Dat - melt(Dat, id=subject)
xtabs(~subject+value,
It works for me...
DF -
+ structure(list(DESCRIPTION = c(PRM HGH GD ALU, PRM HGH GD ALU,
+ PRIMARY NICKEL, PRIMARY NICKEL, PRIMARY NICKEL, PRIMARY NICKEL,
+ STANDARD LEAD , STANDARD LEAD , STANDARD LEAD , STANDARD LEAD ,
+ STANDARD LEAD , STANDARD LEAD , STANDARD LEAD , STANDARD LEAD ,
+ SPCL
Excellent!! You saved me hours and hours of turning around and around.
TY so much.
From: Ista Zahn [mailto:istaz...@gmail.com]
Sent: Friday, April 16, 2010 1:37 PM
To: arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] data frame manipulation
It works for me...
DF -
+
Hi,
I'm testing rKward and it's become a great GUI for R on linux, mainly
for new linux users. I'm not a new linux user and I use Emacs for my own
R's script. But I always try new GUIs or IDEs for to recommend to my
students. The most dificult for new R and Linux users is: I have
installed R
I have a problem with the merge command.
I have to merge two dataframe that looks like the following example:
CODPROD N1 N3 N4
23 3 55 4
24 5 6736
25
I have some questions about the use of weights in binomial glm as I am
not getting the results I would expect. In my case the weights I have
can be seen as 'replicate weights'; one respondent i in my dataset
corresponds to w[i] persons in the population. From the documentation
of the glm method, I
Hi
r-help-boun...@r-project.org napsal dne 16.04.2010 14:00:09:
I have a problem with the merge command.
I have to merge two dataframe that looks like the following example:
CODPROD N1 N3 N4
23 3 55 4
24
Try this:
library(plyr)
rbind.fill(DF1, DF2)
On Fri, Apr 16, 2010 at 8:00 AM, n.via...@libero.it n.via...@libero.it wrote:
I have a problem with the merge command.
I have to merge two dataframe that looks like the following example:
CODPROD N1 N3 N4
23
Hi Christoph,
Christoph Knapp wrote:
Hi all,
I'm just tried to start analysing some micro-array chips. And R was
asking for this package. When I tried to install it it says that:
Using R version 2.10.1, biocinstall version 2.5.10.
Installing Bioconductor version 2.5 packages:
[1]
l...@stat.uiowa.edu wrote:
The current issue of JCGS (Vol 18 No 1,
http://pubs.amstat.org/toc/jcgs/19/1) has an editorial on including
animations, 3D visualizations, and movies in on-line PDF files
supporting JCGS articles. The online supplements to the editorial
include examples. The 3D
Hi all,
I'd like to use the Hmisc::summarize function, but it uses a function (FUN)
of a single vector argument to create the statistical summaries.
Consider an easy case: I'd like to compute the correlation between two
variables in my dataframe, grouped according to other variables in the same
Jan,
It looks like you did not understand the line For a binomial GLM prior
weights are used to give the number of trials when the response is the
proportion of successes.
Weights must be a number of trials (hence integer). Not a proportion of
a population. Here is an example that clarifies the
Hello all ,
Does any one know how to use the neural networks package for time series
prediction ? Have you a similar example in R language ?
thanks in advance
David
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Dear group,
Here is my df :
futures -
structure(list(CONTRAT = c(WHEAT May/10 , WHEAT May/10 ,
WHEAT May/10 , WHEAT May/10 , COTTON NO.2 May/10 , COTTON NO.2 May/10
,
COTTON NO.2 May/10 , PLATINUM Jul/10 , SUGAR NO.11 May/10 ,
SUGAR NO.11 May/10 , SUGAR NO.11 May/10 , SUGAR NO.11 May/10
You can do something like this after the output from opfut
opfut - data.frame(opfut$CONTRAT,opfut$POSITION,opfut$SETTLEMENT)
names(opfut) - c('CONTRAT','POSITION','SETTLEMENT')
opfut
Felipe D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US Fish Wildlife Service
California,
Hello all,
I have searched the archives for a similar problem to no avail. I
could use your help.
I have a bunch of vectors organized into two matrices, x and y. These
vectors (as rows) consist of combinations of elements such that order
does not matter.
I want to create a third matrix from
Thanks for your reply, I just want to get the figure like y1.jpg using the
data from y1.txt.
Through the figure I want to obtain the split point like y1.jpg, and
consider 2.5 as the plit point. This figure is drawn by other people, I
just want to draw it using R, but I can not, so I hope,
Hi every one I’m new to R and I cant figure our how to use the loop to do the
following task, any help would be very kind of every one.
I have a file called (table3.txt) that contains over 1000 row and over 40
columns.
So for example first row would look like that
Deafness, EYA4, DIAPH1,
Dear all,
I need to read an image (mostly jpg) and split the channel of this image to
an colour channel calculation like this:
sqrt(R²+G²+B²)
Do you have an idea what package I need to use for it, and is it possible?
Thanky a lot
Ole
--
View this message in context:
Thanks. I don't think I would ever have worked that twist out. It is
perfect.
Guy
--
View this message in context:
http://n4.nabble.com/Problems-getting-symbols-to-show-table-data-tp1839676p1989384.html
Sent from the R help mailing list archive at Nabble.com.
Could somebody give me a pointer on how to generate a SpatialLinesDataFrame
from a dataframe, that contains lat,long coordinates as separate variables.
At the moment the data looks like this:
lat long
[1] 53. 1.
where as the SpatialLinesDataFrame consists of
Hi,
I'm trying to develop a function that will simplify the most common analyses
in my area of interest (social sciences) by computing all required
statistics at one run (for exaple in case of a factor and numeric variable:
1) normality test, then in case variable are normal 2) ANOVA 3) with
Hello,
I use format() function to get number of the week, like this:
format(tmp,'%U')
Recently, I have spotted something bizarre. For example, I have such object:
(index(tmp$x.delta['2009'][1:16]))
[1] 2009-01-02 CET 2009-01-09 CET 2009-01-16 CET 2009-01-23 CET
[5] 2009-01-30 CET
Hello,
I have a contourplot plot that shows the data I want. However, I would
like to point a certain amount of points from this plot via a
xyplot().
Example:
x - seq(pi/4, 5 * pi, length.out = 100)
y - seq(pi/4, 5 * pi, length.out = 100)
r - as.vector(sqrt(outer(x^2, y^2, +)))
grid -
Hi Arnaud,
I'm not sure how do to this with Hmis::summarize, but it's pretty easy with
plyr::ddply:
D - read.table(textConnection(V1 V2 V3
A 1-1
A 1 1
A-1-1
B 1 1
B 1 1), header=TRUE)
closeAllConnections()
corr.V2.V3 = function(x) {
out = cor(x$V2,
Thierry,
Thank you for your answer.
From the documentation it looks like it is valid to assume that the
weights can be used for replicate weights. Continuing your example:
dataset$Success2 - dataset$Success
Aggregated2 - cast(Person+Success ~ ., data = dataset, value =
Success2, fun =list(mean,
I found a way using the subset command :
opfut=subset(ddply(futures, c(CONTRAT,SETTLEMENT), summarise, POSITION=
sum(QUANTITY)),select=c(CONTRAT,POSITION,SETTLEMENT))
opfut
CONTRAT POSITION SETTLEMENT
1 SUGAR NO.11 May/10 516.5400
2 COTTON NO.2
Hi, I have a need to have 2 variables point to the same dataframe (d1), I
don't want to simply copy the dataframe ( d2-d1 ) as my understanding is that
this will create a second dataframe. Any suggestions on best practice here?
Thank You,
//
// Alex Bryant
//
Dear list members,
I am new member and fairly new into R world! I hope what I have is not
beyond the purpose of this list. I did first search for similar
experimental designs without success.
I want to perform an ANOVA analysis using the aov() function. I am not
100% sure that I have it right.
Hi Ole,
ole_roessler wrote:
I need to read an image (mostly jpg) and split the channel of this image to
an colour channel calculation like this:
sqrt(R²+G²+B²)
Do you have an idea what package I need to use for it, and is it possible?
For general image processing capabilities within R,
I
Hi,
I continue testing rKward. I dont know how to save the results from a
script execution without use copy and paste or using a rkward output system.
Now I try to understand how adapt my script do use the rKward output system.
Example:
I have this script:
--
## Carregar a
Jan,
You misread the documentation of ?glm. Note that glm works with different kinds
of families. So the first statement about weights is rather general: it holds
for most of the families. It explicitly tells you that is not the case with the
binomial family. From the documentation: For a
If I understand:
unique(t(apply(rbind(x, y), 1, sort)))
On Fri, Apr 16, 2010 at 11:05 AM, Michael Nestrud m...@ataraxis.org wrote:
Hello all,
I have searched the archives for a similar problem to no avail. I
could use your help.
I have a bunch of vectors organized into two matrices, x
Dear R-Users,
I have a big data set mydata with repeated observation and some missing
values. It looks like the format below:
userid sex item score1 score2
1 01 1 1
1 02 0 1
1 03 NA 1
1 04 1 0
2
Both versions of this should have worked, but you are right that the first
version didn't when used with `gamm', I've fixed this for mgcv 1.6-2
(`mgcv:gam' was ok). Thanks for this.
best,
Simon
On Wednesday 14 April 2010 09:03, JANSEN, Ivy wrote:
Hi,
I was reading the book on Mixed Effects
Were you expecting 01, and is that why you are puzzled?
See ?strftime and the explanation of the %U format. It depends on
where the first Sunday of the year happens to fall.
-Don
At 5:28 AM -0800 4/16/10, kafkaz wrote:
Hello,
I use format() function to get number of the week, like this:
corr.V2.V3 = function(x) {
out = cor(x$V2, x$V3)
names(out) = CORR
return(out)
}
A litte more concisely:
corr.V2.V3 = function(x) {
c(CORR = cor(x$V2, x$V3))
}
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics / Rice University
http://had.co.nz/
Dear r-list,
I have a big data set mydata with repeated observation and some missing
values. It looks like the format below:
userid sex item score1 score2
1 01 1 1
1 02 0 1
1 03 NA 1
1 04 1 0
2
On Fri, Apr 16, 2010 at 10:13 AM, bbslover dlu...@yeah.net wrote:
Thanks for your reply, I just want to get the figure like y1.jpg using the
data from y1.txt.
Through the figure I want to obtain the split point like y1.jpg, and
consider 2.5 as the plit point. This figure is drawn by other
I wrote a R script say called computeCovarMatrix.R and i want to call and
run this piece from Excel visual basic. does anyone know how to do that?
thanks,
KZ
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi Trever,
You can do it like this:
count - function(x) {
length(na.omit(x))
}
counts -
data.frame(aggregate(mydata[,4:5],by=list(mydata$userid),FUN=count))
-Ista
On Fri, Apr 16, 2010 at 10:35 AM, KDT dkaden...@gmail.com wrote:
Dear R-Users,
I have a big data set mydata with repeated
Hi all,
I am trying to analyze data coming from trajectories of moving objects. It
can be take as a two dimension time serie. The only method I've found is
this:
http://figment.cse.usf.edu/~sfefilat/data/papers/TuAT10.41.pdf
Anyone know if this method is already implemented in R of if there is
On Apr 16, 2010, at 9:28 AM, kafkaz wrote:
Hello,
I use format() function to get number of the week, like this:
format(tmp,'%U')
Recently, I have spotted something bizarre. For example, I have such
object:
(index(tmp$x.delta['2009'][1:16]))
[1] 2009-01-02 CET 2009-01-09 CET 2009-01-16
I am looking into fitting a so-called double von Bertalanffy function to fish
length-at-age data. Attempting to simplify the situation, the model looks like
this ...
Y ~ f(X; a,b,c) if x Z
Y ~ g(X; a,d,e) if x = Z
where
* f and g are non-linear functions (the traditional single von
Have a look at rcom.univie.ac.at.
We have an Excel addin which will allow you to do that.
Disclaimer: I am the author of the addin.
On 4/16/2010 4:57 PM, KZ wrote:
I wrote a R script say called computeCovarMatrix.R and i want to call and
run this piece from Excel visual basic. does anyone
On Fri, 16 Apr 2010, Fischer, Felix wrote:
Hello everyone,
i have a question regarding the sampling process in boot().
PLEASE ... provide commented, minimal, self-contained, reproducible
code. Which means something a correspondent could actually run.
But before that, a careful reading of
Dear R users,
I have a function which takes as arguments big arrays, say : w, x , y and z.
My function changes these arrays and I want them as result/output.
I have tried to write return(w,x,y,z), and thus to replace the previous w,
x, y and z. It does not seem to work.
What can I do ?
Thank
You can return a single object from a function. If you want multiple
values, use a list:
f - function(x,y,z){
return(list(x=x, y=y, z=z))
}
value - f(x,y,z)
# now copy the values
x - value$x
y - value$y
z - value$z
On Fri, Apr 16, 2010 at 12:02 PM, Gustave Lefou
Below
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Gustave Lefou
Sent: Friday, April 16, 2010 9:03 AM
To: r-help@r-project.org
Subject: [R] return of a function
Dear R users,
I
On Apr 16, 2010, at 12:02 PM, Gustave Lefou wrote:
Dear R users,
I have a function which takes as arguments big arrays, say : w, x ,
y and z.
My function changes these arrays and I want them as result/output.
I have tried to write return(w,x,y,z), and thus to replace the
previous w,
The easiest approach may be to just install R onto a USB drive
(flash/thumb/...) then when you go to your coworkers computer just run R from
the USB drive and show the rgl plot. I think there is also a tool to create an
animation from rgl, it is not interactive, but you could e-mail a movie
Jan,
Thierry is correct in saying that you are misusing glm(), but there is also a
numerical problem.
You are misusing glm() because your model specification claims to have
Binomial(n,p) observations with w in the vicinity of 100, where there is a
single common p but the observed binomial
Thank you for your answer. Sorry for the missing example.
In fact, i think, i solved the issue by some data-manipulations in the
function. I splitted the data (one set for each measuring time), selected the
cases at random, and then combined the two measuring times again. Results look
Hello,
EBImage is a Bioconductor package: please post on the Bioconductor
mailing list.
EBImage requires the libraries ImageMagick and GTK+ to be installed. Did
you follow the instructions of the installation manual ?
http://www.bioconductor.org/packages/release/bioc/html/EBImage.html
It
I have no idea what is happening here (not an ubunto or linux expert), but it
seems unlikely that the particular package is the main problem, rather that is
the package you happen to be on when the problem manifests. TeachingDemos does
not have any compiled code (all straight R code) and does
Hi all,
I have a difficulty to calculate the PCA scores. The PCA scores I calculated
doesn't match with the scores generated by R,
mypca-princomp(mymatrix, cor=T)
myscore-as.matrix(mymatrix)%*%as.matrix(mypca$loadings)
Does anybody know how the mypca$scores were calculated? Is my formula not
Dear R users,
I am looking for more efficient way to compute the followings
--
a - matrix(c(1,1,1,1,2,2,2,2),4,2)
b - matrix(c(1,2,3,4),4,1)
Eventually, I want to get this matrix, `c`.
c -
Try this:
sweep(a, 1, b, '/')
On Fri, Apr 16, 2010 at 2:30 PM, Kathie kathryn.lord2...@gmail.com wrote:
Dear R users,
I am looking for more efficient way to compute the followings
--
a -
On Fri, 2010-04-16 at 10:23 -0700, phoebe kong wrote:
Hi all,
I have a difficulty to calculate the PCA scores. The PCA scores I calculated
doesn't match with the scores generated by R,
mypca-princomp(mymatrix, cor=T)
myscore-as.matrix(mymatrix)%*%as.matrix(mypca$loadings)
Does
Since b is only one column, just make it a vector.
a - matrix(c(1,1,1,1,2,2,2,2),4,2)
b - c(1,2,3,4)
then
result - a/b
result
[,1] [,2]
[1,] 1.000 2.000
[2,] 0.500 1.000
[3,] 0.333 0.667
[4,] 0.250 0.500
should be what you want.
It is also
thanks a lot.
good day.
Kathie
On Fri, Apr 16, 2010 at 1:43 PM, Henrique Dallazuanna [via R]
ml-node+2013302-929204043-67...@n4.nabble.comml-node%2b2013302-929204043-67...@n4.nabble.com
wrote:
Try this:
sweep(a, 1, b, '/')
On Fri, Apr 16, 2010 at 2:30 PM, Kathie [hidden
Hi
I am trying to read selected fields from a xml file with R using xml
package. So far I have learned the basics of this package by going
through the manual, examples, tutorial, and so on (www.omegahat.org/RSXML)
. The problem is that I am getting stuck when it comes down to more
complex
Hello All,
I am using sp and maps libraries to have a map for some fire data.
The region covered is Mississippi State in the US. Then I would like to
add a layer of ecoregion on the top (omenrik layer from
nationalatlas.gov). The problem is that the ecoregion layer is larger
than the state
i wrote a R script say called computeCovarMatrix.R and i want to call and
run this piece from Excel visual basic. does anyone know how to do that?
thanks,
KZ
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
See RExcel, http://rcom.univie.ac.at/ http://rcom.univie.ac.at/ and
especially the video demo http://rcom.univie.ac.at/RExcelDemo/
http://rcom.univie.ac.at/RExcelDemo/
Guy
--
View this message in context:
http://n4.nabble.com/run-R-script-from-Excel-VBA-tp2009478p2011942.html
Sent from the
Thanks a lot, i will try this out!
Ole
--
View this message in context:
http://n4.nabble.com/Image-RGB-calculation-tp1989864p2013203.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Thank you very much for your kind explanation. I did find my DLL compiled
using either VC++ 6.0 or Intel Compiler (almost equally fast) is
significanlty faster than that compiled using gcc (55 seconds vs. 78
seconds), the default compiler in R. I did not choose debug mode when
using gcc so I
I wonder how to further improve the optimization level of gcc. I thought
O-3 has already been the best.
--
View this message in context:
http://n4.nabble.com/Efficiency-of-C-Compiler-in-R-CMD-SHLIB-tp1934429p2008994.html
Sent from the R help mailing list archive at Nabble.com.
I'm not sure I completely understand your question, but I think the solution
to your problem is the reshape function in the reshape package. Here is a
silly example of how it would work:
V-matrix(rbinom(15,4,.5),nrow=3)
X-data.frame(A=c(A,B,C),V=V)
X
A V.1 V.2 V.3 V.4 V.5
1 A 1 2 3
Dear R-users,
I want to check if certain values are from random distribution, that includes
values between 0-1. So, it is not really normal even though shapiro.test says
it is highly normal... Can I do something like this and think that the values
given are right. z.test is from package
On Apr 16, 2010, at 11:52 AM, Thomas Stewart wrote:
I'm not sure I completely understand your question, but I think the
solution
to your problem is the reshape function in the reshape package.
Except there is no reshape function in the reshape package. Your code
works because the reshape
On Apr 16, 2010, at 12:11 PM, Atte Tenkanen wrote:
Dear R-users,
I want to check if certain values are from random distribution, that
includes values between 0-1. So, it is not really normal even though
shapiro.test says it is highly normal... Can I do something like
this and think that
arnaud chozo wrote:
Hi all,
I'd like to use the Hmisc::summarize function, but it uses a function (FUN)
of a single vector argument to create the statistical summaries.
Consider an easy case: I'd like to compute the correlation between two
variables in my dataframe, grouped according to other
Several points:
1. The Shapiro test does not tell you that something is normal or highly
normal, only that you don't have enough evidence to disprove that the data came
from a normal population (powered for a certain type of deviation from
normality).
2. The z.test function is intended to be
So ..
are you trying to figure out whether your data hasa substantial number of
outliers that call into question the adequacy of the normal distro fro your
data?
If this is the case, note that you cannot individually check the values (as you
are doing) without taking into account of the
This is an announcement of the release of an R package 'formatR',
which can help us format our R code to make it more human-readable. If
you have ugly (I mean unformatted) R code like this:
# rotation of the word Animation
# in a loop; change the angle and color
# step by step
for (i in 1:360) {
1 - 100 of 147 matches
Mail list logo