Many thanks to you both. I have now filed away for future reference the 2
factor tapply as well as the extremely useful looking plyr library. And the
code worked beautifully :-)
On 24 Aug 2010, at 19:47, Abhijit Dasgupta, PhD aikidasgu...@gmail.com
wrote:
The paste-y argument is my usual
Hello,
I want to know how do R calculates the number of intervals between
tick-marks in the y axis in a plot.
I'm making a three y-axes plot and this information would help me a lot.
Thanks in advance.
Antonio Olinto
Thanks Josh and Karl. function dnrm() works well for my purpose.
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I'm in the process of converting some S3 methods to S4 methods.
I have this function :
setGeneric(enrichmentCalc, function(rs, organism, seqLen,
...){standardGeneric(enrichmentCalc)})
setMethod(enrichmentCalc, c(GenomeDataList, BSgenome), function(rs,
organism, seqLen, ...) {
...
Rhelpers:
I'm trying to make a barchart of a 2-group dataset
(barchart(x~y,data=data,groups=z,horizontal=FALSE)). My problem is
that I can't, for the life of me, seem to get rid of the inter-bar
space -- box.ratio set to 1 doesn't do much. Any ideas? I'd
ideally want zero space between the
Hi,
I would like to emphasize (zoom) the zone of a nomogram where the
probability are 0.01
(nomogram built with nomogram, Design).
As a consequence, I don't need to draw the part of the Total points
axis with score 60 equivalent in my case to a linear predictor 4.5
- As far as I know, this is
Thanks a lot for the nice explanation. however, you mention that it will be
nicer if there is data. yes you are right it be very kind of you if you
include a simple example. where my data are:
x1-c(11.5,9.38,9.3,9.8,9,9.06,9.42,8.8,9.05,8.14,8.2,7.59,6.92,6.47,7.12,
Hi
without other details it is probably impossible to give you any reasonable
advice. Do you have your data already in R? What is their form? Are they
in 2 columns in data frame? How did you get them paired?
So without some more information probably nobody will invest his time as
it seems no
Thanks to Mark Leeds and Dennis Murphy for their suggestions. The function
arima.sim() only simulates stationary series without a trend, so the best
approach appears to be to add the simulated stationary part to the trend as
follows:
Temp - arima.sim(n=N.Years.Forecast, list(ar=AR.Coef,
On Wed, 2010-08-25 at 07:12 +0800, elaine kuo wrote:
Dear List,
I have a richness data distributing across 20 N to 20 S latitude. (120 E-140
E longitude).
I would like to draw the richness in the north hemisphere and a regression
line in the plot
(x-axis: latitude, y-axis: richness in
Dear all,
I am using an R 2.10 installation on a Windows 203 server that I have no
control over. After a multi-day run I found that it was
terminated/crashed. Is there any log kept by R where I could see whether
something/what happened? The same process has been run beofre on a
smaller
Maybe
perp.slope = -1/slope
abline(cy - cx*perp.slope, perp.slope)
where cx, cy are x- and y-coordinate of C, resp., and slope the slope you
calculated for the line through A and B
Am 24.Aug.2010 um 0:04 schrieb CZ:
Hi,
I am trying to draw a perpendicular line from a point to two
Dear Mr Petr Pikal
I am extremely sorry for the manner I have raised the query. Actually that was
my first post to this R forum and in fact even I was also bit confused while
drafting the query, for which I really owe sorry to all for consuming the
precious time. Perhaps I will try to redraft
Good afternoon!
It may seem trivial to some/most of You, but I found it difficult to properly
include a C++-based .dll into a package that I want to build for usage in R. I
read through the Writing R extensions... R administration ...
instructions, but it seems I did not grasp the bigger
Ben Bolker bbolker at gmail.com writes:
Bertolt Meyer bmeyer at sozpsy.uzh.ch writes:
Hello lmer() - users,
A call to the lmer() function causes my installation of R (2.11.1 on
Mac OS X 10.5.8) to crash and I am trying to figure out the problem.
[snip snip]
detach(package:nlme)
hi,
also, make sure you have set the aspect ratio to 1:1 when plotting (asp=1).
HTH,
baptiste
On 25 August 2010 10:20, Benno Pütz pu...@mpipsykl.mpg.de wrote:
Maybe
perp.slope = -1/slope
abline(cy - cx*perp.slope, perp.slope)
where cx, cy are x- and y-coordinate of C, resp., and slope
On 24/08/2010, David Winsemius dwinsem...@comcast.net wrote:
On Aug 24, 2010, at 9:37 AM, e-letter wrote:
Readers,
According to the documentation for the function 'plotmath' there is no
apparent possibility to add the percent sign (%) to a plot function,
Where did you see an assertion
Yes, I do want the labels on the x-axis but the problem arises when the
y-axis is logarithmic presumably because the position labels on the x-axis
still needs to be defined in terms of x and y coordinates.
The simplified examples below should make the problem clearer.
I can't see a way of
Hm
r-help-boun...@r-project.org napsal dne 25.08.2010 09:43:26:
Dear Mr Petr Pikal
I am extremely sorry for the manner I have raised the query. Actually
that was
my first post to this R forum and in fact even I was also bit confused
while
drafting the query, for which I really owe sorry
Hi
I am using repeated meaturement data for my project and I want to use quantile
regression with multilevel or panel data in R.
I dont find the basic version of software in R, so I have difficulty in using
it.
I would also appreciate if anyone more proficient in R could help me how to run
Dario Strbenac d.strbe...@garvan.org.au
on Wed, 25 Aug 2010 13:00:03 +1000 (EST) writes:
I'm in the process of converting some S3 methods to S4 methods.
I have this function :
setGeneric(enrichmentCalc, function(rs, organism, seqLen,
...){standardGeneric(enrichmentCalc)})
On 08/25/2010 09:12 AM, elaine kuo wrote:
Dear List,
I have a richness data distributing across 20 N to 20 S latitude. (120 E-140
E longitude).
I would like to draw the richness in the north hemisphere and a regression
line in the plot
(x-axis: latitude, y-axis: richness in the north
On Wed, 2010-08-25 at 09:32 +0100, e-letter wrote:
On 24/08/2010, David Winsemius dwinsem...@comcast.net wrote:
On Aug 24, 2010, at 9:37 AM, e-letter wrote:
Readers,
According to the documentation for the function 'plotmath' there is no
apparent possibility to add the percent sign
Hi Jonathan lees
How to use this code and after installing ProfessR package
autoemail(eadd, sfile, hnote = Exam Results)
thanks
veepsirtt
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Martin,
On Wed, Aug 25, 2010 at 10:17 AM, Loos, Martin martin.l...@eawag.ch wrote:
Good afternoon!
It may seem trivial to some/most of You, but I found it difficult to
properly include a C++-based .dll into a package that I want to build for
usage in R. I read through the Writing R
On 08/25/2010 01:37 PM, Tim Elwell-Sutton wrote:
Hi Jim
Thanks for this. The staxlab function seems very useful. Unfortunately, the
rotation option doesn't seem to work for me when the y-axis is on a log
scale. It will stagger the labels but not rotate them. There's no error
message. On a linear
Hi:
Here's a ggplot2 version of your graph. Since you didn't include the dates,
I had to make them up, and it may have some consequence with respect to your
times because yours don't appear to be exactly equally spaced.
I created two data frames - an 'original' one that contains both series in
Woow, it is amazing,
thank you very much.
yes i forget to attach the dates, however, the dates in my case is every 16
days.
so how i can use 16 day interval instead of month in by option.
cheers,
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Dear Mr Petr PIKAL
After reading the R code provided by you, I realized that I would have never
figured out how this could have been done. I am going to re-read again and
again your code to understand the logic and the commands you have provided.
Thanks again from the heart for your kind advice.
Dear R Gurus,
I am currently working on the two dataset ( A and B), they both have the
same fields:ID , REGION, OFFICE, CSTART, CEND, NCYCLE, STATUS and
CB.
I want to merge the two data set by ID. The problem I have is that the
in data A, the ID's are unique. However in the data set B,
Hi Ruru's,
score.items in package psych is very handy for scoring test items. It has the
structure score.items(keys,items).
For instance:
score.items(c(1,1,1),data.frame(a1=rep(1,5),a2=rep(1,5),a3=rep(1,5)))$scores
correctly gives 1 on each case.
But if key -1,0,1 the following happens
Yes -
please look at the function IDandEM.R
(This stand for IDentification and EMail)
in there it has a complete function that uses
the autoemail function - I use this all the time.
There is a logical option (SEND)
on whether to actually mail the
file to the recipient.
The IDandEM function
Hi, I am (trying) to write a script that will execute a set of functions and
then to write some of the output data frames to file. I am wanting to be
able to just change a single object and have this them populate through the
functions etc. I have no trouble making this work when the function is
down vote favorite
Hello
I have a zoo series. It lasts 10 years and its frequency is 15min.
I'd like to get a new zoo series (or vector) with the same number of
elements, whith each element equal to the first element of the day. That's,
The first element everyday is repeated
Hi:
Let's start with the data:
str(test.data)
'data.frame': 100 obs. of 4 variables:
$ StudentID: num 17370 17370 17370 17370 17379 ...
$ GroupID : num 1 1 1 1 1 1 1 1 1 1 ...
$ Time : num 1 2 3 4 1 2 3 4 1 2 ...
$ Score: num 76.8 81.8 89.8 92.8 75.9 ...
Both StudentID and
Dear list,
I got some surprising results when using the svytotal routine from the
survey package with data containing missing values.
Some example code demonstrating the behaviour is included below.
I have a stratified sampling design where I want to estimate the total
income. In some strata
First you need to clarify what you'd like to happen when the ID in B
is not unique. What do you want the resulting dataframe to look
like?
Some possible answers involve using different options for merge() or
using unique() to remove duplicates from B before merging. But
at least to me, merge or
On Wed, Aug 25, 2010 at 7:43 AM, skan juanp...@gmail.com wrote:
I have a zoo series. It lasts 10 years and its frequency is 15min.
I'd like to get a new zoo series (or vector) with the same number of
elements, whith each element equal to the first element of the day. That's,
The first element
Oh dear. No there isn't. I do a lot of very long runs, and have learned to write
out intermediate steps. Depending on what you are doing, saving the RData
file periodically may be appropriate, or writing out a csv file of
results so far,
or even just printing something to the output file (if you
On Wed, Aug 25, 2010 at 7:56 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Wed, Aug 25, 2010 at 7:43 AM, skan juanp...@gmail.com wrote:
I have a zoo series. It lasts 10 years and its frequency is 15min.
I'd like to get a new zoo series (or vector) with the same number of
elements,
Hello,
http://www.rseek.org is extremely useful if you know what you want to do but
not how to do it. Going there and putting quantile regression with multilevel
data into the search box returns many references to functions and packages
that may be of use.
This list can't do much more for you
ALSO I have had a play with cat() but have also not got this to
work
e.g.
write(x, file = cat(input.variable.name , file = , sep = _data.txt, ),
...)
but this does not seem to work and I'm sure it is not the correct use of
cat()
Thanks.
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What do you want to happen when there are duplicates?
A:
ID X
1 a
2 b
3 c
B:
ID Y
1 x
2 y
2 z
What happens to ID 1? 2? 3? in your desired output?
The all.x and all.y options might be of use.
Sarah
On Wed, Aug 25, 2010 at 8:00 AM, Mangalani Peter Makananisa
pmakanan...@sars.gov.za
I'm a bit confused by your question, but you might just want paste:
paste(input.variable.name, data.txt, sep=_)
Sarah
On Wed, Aug 25, 2010 at 8:06 AM, josquint josqu...@unimelb.edu.au wrote:
ALSO I have had a play with cat() but have also not got this to
work
e.g.
write(x,
Hi Sarah,
thank you very much for your answer. I have been spitting things out on
screen, but unfortunately I have not run it as a batch log, but in the
interactive window, so when the GUI crashed I was left without trace...
I guess I should google how to run it from a batch.
I should also
Hi,
On Wed, Aug 25, 2010 at 8:11 AM, Martin Tomko martin.to...@geo.uzh.ch wrote:
Hi Sarah,
thank you very much for your answer. I have been spitting things out on
screen, but unfortunately I have not run it as a batch log, but in the
interactive window, so when the GUI crashed I was left
Dear R-experts!
I am currently running a meta-analysis with the help of the great metafor
package. However I have some difficulties setting up my raw data to enter it
to the meta-analysis models.
I have a group of subjects that have been measured in two continuous
variables (A B). I have the
On Wed, Aug 25, 2010 at 7:43 AM, skan juanp...@gmail.com wrote:
down vote favorite
Hello
I have a zoo series. It lasts 10 years and its frequency is 15min.
I'd like to get a new zoo series (or vector) with the same number of
elements, whith each element equal to the first element of
Almost. You'll need to handle the duplicate ID yourself since R has
no way of knowing which one(s) to change to NA. As I already suggested, you
can use unique() in conjunction with whatever logical rules you require
for choosing those values.
As I also already suggested, all.y and all.x are the
Update to the rms package which is the version now being actively
supported. New features will not be added to Design. The nomogram
function in rms separates the plotting into a plot method for easier
understanding. You can control all axes - some experimentation can
tell you if you can
On Wed, Aug 25, 2010 at 6:05 AM, abotaha yaseen0...@gmail.com wrote:
Woow, it is amazing,
thank you very much.
yes i forget to attach the dates, however, the dates in my case is every 16
days.
so how i can use 16 day interval instead of month in by option.
Here's one way using the lubridate
Hi ,
thanks, the lower.tri idea is I guess the best way. Will try that.
Cheers
Martin
On 8/25/2010 2:21 PM, Sarah Goslee wrote:
Hi,
On Wed, Aug 25, 2010 at 8:11 AM, Martin Tomkomartin.to...@geo.uzh.ch wrote:
Hi Sarah,
thank you very much for your answer. I have been spitting things out
Dear R community,
I am a beginner using the sciplot package to graph barplots. I would like to be
able to graph two x factors (Sampling.year and Period).
Sampling.year: 2006, 2007, 2008, 2009
Period: First, Second, Total
The parameter group is the different species I looked at. They
On Aug 25, 2010, at 4:32 AM, e-letter wrote:
On 24/08/2010, David Winsemius dwinsem...@comcast.net wrote:
On Aug 24, 2010, at 9:37 AM, e-letter wrote:
Readers,
According to the documentation for the function 'plotmath' there
is no
apparent possibility to add the percent sign (%) to a
thanks
I'll try them,
Why do you use the brackets in zz[] ?
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On Aug 24, 2010, at 7:05 PM, Antonio Olinto wrote:
Hello,
I want to know how do R calculates the number of intervals between
tick-marks in the y axis in a plot.
?axTicks # and then look at the other citations and the code as needed
I'm making a three y-axes plot and this information
Hi
This is probably more of a statistics question than a specific R
question, although I will be using R and need to know how to solve the
problem in R.
I have several sets of data (ejection fraction measurements) taken in
various ways from the same set of (~400) patients (so it is paired data).
On Wed, Aug 25, 2010 at 9:48 AM, skan juanp...@gmail.com wrote:
thanks
I'll try them,
Why do you use the brackets in zz[] ?
So it stays a zoo object with the same index. We are only replacing
the data part.
__
R-help@r-project.org mailing list
Take a look at pretty function.
On Tue, Aug 24, 2010 at 8:05 PM, Antonio Olinto aolint...@bignet.com.brwrote:
Hello,
I want to know how do R calculates the number of intervals between
tick-marks in the y axis in a plot.
I'm making a three y-axes plot and this information would help me a
Hi
well, I will add some explanation
r-help-boun...@r-project.org napsal dne 25.08.2010 11:24:38:
Dear Mr Petr PIKAL
After reading the R code provided by you, I realized that I would have
never
figured out how this could have been done. I am going to re-read again
and
again your code to
Dear all,
I have run into a problem when running some code implemented in the
Bioconductor panp-package (applied to my own expression data), whereby gene
expression values of known true negative probesets (x) are interpolated onto
present/absent p-values (y) between 0 and 1 using the *approxfun -
On Aug 25, 2010, at 3:57 PM, Sandy Small wrote:
Hi
This is probably more of a statistics question than a specific R
question, although I will be using R and need to know how to solve the
problem in R.
I have several sets of data (ejection fraction measurements) taken in
various ways from
On Aug 25, 2010, at 8:57 AM, Sandy Small wrote:
Hi
This is probably more of a statistics question than a specific R
question, although I will be using R and need to know how to solve the
problem in R.
I have several sets of data (ejection fraction measurements) taken in
various ways from
Hi useRs,
I'm trying for the first time to use a sem. The model finally runs,
but gives a warning saying :
In sem.default(ram = ram, S = S, N = N, param.names = pars, var.names
= vars, : Could not compute QR decomposition of Hessian.
Optimization probably did not converge.
I found in
Hi all,
I have read posts of heat map creation but I am one step prior --
Here is what I am trying to do and wonder if you have any tips?
We are trying to map sequence reads from tumors to viral genomes.
Example input file :
111 abc
111 sdf
111 xyz
1079 abc
1079 xyz
1079 xyz
hello,
i want to stack two lattice plots beneath each other using one x-axis and
sharing the same text-panels,
like:
#
library(lattice)
y1 - rnorm(100,100,10)
y2 - rnorm(100,10,1)
facs-expand.grid(Sites=rep(c(Site I,Site
Dennis,
just wow. Thank you so much. I knew it was something trivial - in this
case the variable type of the of the grouping variables. However,
something as trivial as this should not throw a segfault IMHO. I tried
subscribing to R-sig-mixed this morning, but the corresponding mail
Your problem is not completely clear to me, but perhaps something like
data - data.frame(
a = rep(c(1,2), each=10),
b = rep(c('a', 'b', 'c', 'd'), 5))
library(plyr)
daply(data, a ~ b, nrow)
does what you need.
Regards,
Jan
On Wed, Aug 25, 2010 at 4:53 PM, rtsweeney tripswee...@gmail.com
# duplicated / na.locf doesn't work
it says Error in fix.by(by.x, x) : 'by' must specify valid column(s)
if I use ifelse instead of ifelse.zoo it works but it gives me a non zoo
vector.
Myabe is because my zoo version is older.
cheers
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Hi Jokel,
If I remember correctly
1) The variance of the sum of two variables X and Y is:
var(X) + var(Y) + (2 * cov(X, Y))
If you create some sample data, you can verify this by:
var((X + Y))
2) The variance of a random variable (X) multiplied by some constant (K)
is equal to the
Kay,
doe this do what you want?
dotplot(y1+y2 ~ facs$Treatment|facs$Sites,
outer=TRUE,
scales = list(x = list(rot = 90, tck=c(1,0))),
ylab=c(y1, y2),
xlab=c(Site 1, Site 2),
strip=FALSE)
On Wed, Aug 25, 2010 at 11:04 AM, Kay Cichini
At 3:04 PM -0700 8/23/10, CZ wrote:
Hi,
I am trying to draw a perpendicular line from a point to two points.
Mathematically I know how to do it, but to program it, I encounter some
problem and hope can get help. Thanks.
I have points, A, B and C. I calculate the slope and intercept for line
Dear all,
I have an S4 class with a slot extra which is a list. I want to be
able to add an element called name to that list, containing the
object value (which can be a vector, a dataframe or another S4
object)
Obviously
setMethod(add.extra,signature=c(PM10Data,character,vector),
Hi:
You can probably do what you want in either ggplot2 or lattice, but I would
recommend at least a couple different approaches:
(1) Plot individual bar charts by combinations of year and period.
This is easy to do in both ggplot2 and lattice: in ggplot2, one
would use geom_bar(x) +
Hi Marie, this link may be helpful if you want to build it for both
architectures, 32-bit and 64-bit. I struggled with the same problem not too
long ago.
http://cran.rakanu.com/bin/macosx/RMacOSX-FAQ.html#Building-universal-package
I ended up writing a very simple Makefile to accompany [my
Hi Joris,
On Wed, Aug 25, 2010 at 11:56 AM, Joris Meys jorism...@gmail.com wrote:
Dear all,
I have an S4 class with a slot extra which is a list. I want to be
able to add an element called name to that list, containing the
object value (which can be a vector, a dataframe or another S4
Hi:
I'm just ideating here (think IBM commercial...) but perhaps a graphical
model approach might be worth looking into. It seems to me that Mr. Rhodes
is looking for clusters of banks that are under the same ownership umbrella.
That information is not directly available in a single variable, but
Hello,
I am using the package MuMI to run all the possible combinations of variables
in my full model, and select my best models. When I enter my variables in the
original model I write them like this
lm(y~ a +b +c +a:b)
However, MuMI will also use the variable b:a, which I do not want in my
exactly -
thanks a lot, richard!
kay
Zitat von RICHARD M. HEIBERGER r...@temple.edu:
Kay,
doe this do what you want?
dotplot(y1+y2 ~ facs$Treatment|facs$Sites,
outer=TRUE,
scales = list(x = list(rot = 90, tck=c(1,0))),
ylab=c(y1, y2),
xlab=c(Site 1, Site
On Wed, Aug 25, 2010 at 11:18 AM, skan juanp...@gmail.com wrote:
# duplicated / na.locf doesn't work
it says Error in fix.by(by.x, x) : 'by' must specify valid column(s)
if I use ifelse instead of ifelse.zoo it works but it gives me a non zoo
vector.
Myabe is because my zoo version is
[Sending both to the maintainer and to R-help, in case anyone else has
answers ...]
I've looked in odfWeave documentation, vignette, and poked around on
the web some, and haven't found answers yet.
1a. am I right in believing that odfWeave does not respect the
'keep.source' option? Am I
Hi:
Here are a couple of ways to render a basic 2D table. Let's call your input
data frame dat:
names(dat) - c('samp', 'sequen')
ssTab - as.data.frame(with(dat, table(samp, sequen)))
ssTab # data frame version
samp sequen Freq
1 111abc1
2 1079abc1
3 5576abc1
4
Hi Steve,
thanks for the tip. I'll definitely take a closer look at your
solution for implementation for future use. But right now I don't
have the time to start rewriting my class definitions.
Luckily, I found where exactly things were going wrong. After reading
into the documentation about
If you find yourself doing things like this often, but don't want to explicitly
set the seed, or save seeds before simulating, then you can run the following
code (or put it into .Rprofile or similar):
.Last.Random.seed - .Random.seed
addTaskCallback( function(expr, val, ok, visible){
I need the simple function for the following set of data. This is a toy
version of my data, but the error is persistent in both. To compare with
excel, I would just 1) format trendline, 2) display equation and
R-squared on chart.
I obviously tried to use a nls and wanted to use the self
... i added relation=free to account for diffferent ranges of y1 and y2:
dotplot(y1+y2 ~ facs$Treatment|facs$Sites,
outer=TRUE,
scales = list(y = list(relation=free), x = list(rot = 90,
tck=c(1,0))),
ylab=c(y1, y2),
xlab=c(Site 1, Site 2),
The multiple y axes are protecting you in this situation.
z - cbind(rnorm(100,c(1,10),1), rnorm(100,c(20,30),1))
dotplot(z[,1]+z[,2] ~ facs$Treatment|facs$Sites,
outer=TRUE,
scales = list(
y = list(
relation=free)),
ylab=c(y1, y2),
Hi,
I am new to R, and as a first exercise, I decided to try to implement an XIRR
function using the secant method. I did a quick search and saw another posting
that used the Bisection method but wanted to see if it was possible using the
secant method.
I would input a Cash Flow and Date
try the following merge command.
merge(A,B, by = intersect(names(A), names(B)), all.x=FALSE, all.y=FALSE)
or
merge(A,B, by = ID, all.x=FALSE, all.y=FALSE)
Dannemora
On Wed, Aug 25, 2010 at 5:35 AM, Mangalani Peter Makananisa
pmakanan...@sars.gov.za wrote:
Dear R Gurus,
I am currently
I have a collection of results. I use R to get the linearization presented.
how can I get R to show the equation and R^2 value on the plot area next to
the graph?
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Sent
Great ..
thanks for the to much help and i too appreciate hel p and explanation
Cheers
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Hi I'm having different outputs from GLM when using a condensed table
V1 V2 V3 Present Absent
0 0 0 3 12
0 0 1 0 0
0 1 0 0 0
0 1 1 1 0
1 0 0 7 20
1 0
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Dear Elaine
I'm developing a code to make a 3 y-axes plot. It may can help you.
Also your question leads to mine, posted yesterday: How does R
calculate the interval between tick-marks.
Below follows the code I'm developing.
Data:
ANO CKG NUP NDE
200526352158
Thanks to De-Jian and Peter. Peter's way is neat and cool!
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Hi all,
I am trying to use snow package to do a parallel MCMC. I have read a few
guides and articles, the following is that I came up with.
When I run it I got the error message:
Error in checkForRemoteErrors(lapply(cl, recvResult)) :
4 nodes produced errors; first error: could not find
Hi R users,
I am trying to use the optim function to maximize a likelihood funciton, and
I got the following warning messages.
Could anyone explain to me what messege 31 means exactly? Is it a cause for
concern?
Since the value of convergence turns out to be zero, it means that the
converging is
Dear list,
I have a csv file like below, and I have similar 150 files (responses from
150 samples) in a folder.
Id like to get the mean score of pairwise correlation score among 150
respondents by hour(0~20hour).
All I can think of is bring up two files and get the pairwise correlation
score
Oh, I forgot to say, ui.Next() is a function I defined to sample from the
proposal distribution given the current state.
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Hi,
can anyone tell me how i may find out the between-group variance and
within-group variance for multivariate case?
I have 6 Groups and 73 Variables. (with MANOVA ? wie)
dim(data)
[1] 2034 76
Thanks
Celal
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