FYI: If you use LaTex, you can work out on something between R and LaTex.
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On Wed, Sep 8, 2010 at 5:49 AM, Philipp Pagel p.pa...@wzw.tum.de wrote:
Dear expeRts,
?xyplot says: In general, giving a high value of ‘layout[3]’ is not
wasteful because blank pages are never created.
But the following example does generate blank pages - well except for
the ylab:
Hi,
does anybody know of some plotting function or an easy way to
generate + symbols with individually settable bar lengths?
I tried just combining | and - as pch and setting the size via cex,
but that doesn't really work since the two symbols have different default
lengths. Is there a
Hi Peng, Gabor Peter,
Thank you very much for replying me so soon. I will try it right now!
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Hello David,
You could also have a look to the ascii package :
http://eusebe.github.com/ascii/
With asciidoc (http://www.methods.co.nz/asciidoc/), or one of other
markup languages supported (restructuredtext, txt2tags, or textile),
you can obtain good results.
For example, vignettes of the book
Hello everyone.. Is there any graphical tool to help me see what is inside a
matrix? I have 100x100 dimensions matrix and as you already know as it does not
fit on my screen R splits it into pieces.
I would like to thank you in advance for your help
Best Regards
Alex
This sounds interesting, thank you. I'll have a look.
jason
Dr. Iasonas Lamprianou
Assistant Professor (Educational Research and Evaluation)
Department of Education Sciences
European University-Cyprus
P.O. Box 22006
1516 Nicosia
Cyprus
Tel.: +357-22-713178
Fax: +357-22-590539
Honorary
On 09-Sep-10 06:41:34, Rainer Machne wrote:
Hi,
does anybody know of some plotting function or an easy way to
generate + symbols with individually settable bar lengths?
I tried just combining | and - as pch and setting the size via cex,
but that doesn't really work since the two symbols have
Hello dear R help members (and also Yihui and Romain),
There are currently 28 R bloggers (out of the 117
R-bloggershttp://www.r-bloggers.com/I know of) that are using
wordpress.com for publishing their R code (and I suspect this number will
increase with time).
WordPress.com doesn't support R
Hi
I've recently started using Emacs as my text editor for writing R script.
I am looking for a feature which I have seen on the standard R text editor
for Mac OS. In the Mac OS editor when you start typing a function, the
possible arguments for that function appear at the bottom of the
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On 09/09/10 07:47, David Scott wrote:
I am investigating some approaches to reproducible research. I need in
the end to produce .html or .doc or .docx. I have used hwriter in the
past but have had some problems with verbatim output from R. Tables
On Wed, Sep 8, 2010 at 6:26 PM, Michael Bernsteiner
dethl...@hotmail.com wrote:
@Barry: Yes it is the Rosenbrock Function. I'm trying out some thing I found
here: http://math.fullerton.edu/mathews/n2003/PowellMethodMod.html
@Ravi: Thanks for your help. I will have a closer look at the BB
Hi,
The TeachingDemos package has a my.symbols() function that you could use with
you own glyph.
HTH,
baptiste
On Sep 9, 2010, at 9:36 AM, (Ted Harding) wrote:
On 09-Sep-10 06:41:34, Rainer Machne wrote:
Hi,
does anybody know of some plotting function or an easy way to
generate +
Dear David
I have tried odfWeave and I find it quite useful for the purpose.
I would recommend you give it a try. It comes with simple example files
along with installation.
You might have some difficulty in getting the zip files and path
configurations set, which is a pre-requisite, but I am
Dear Group
Does anybody have an example data and R Script for analysis of Maxdiff
study in R.
Thanks Regards
Vijayan Padmanabhan
What is expressed without proof can be denied without proof - Euclide.
Can you avoid printing this?
Think of the environment before printing the email.
Did you try taking out P7, which is text? Moreover, if you get a message
saying ' the standard deviation is zero', it means that the entire column is
constant. By definition, the covariance of a constant with a random variable
is 0, but your data consists of values, so cor() understandably throws
Hi,
I have an implementation where I transfer data records via shared memory to an
R program. If anyone has prior experience, I'd like to find out which would be
faster
1) storing data records in shared memory as they are(in a matrix) and then use
the Rcpp::wrap to convert them to R
Dear Group
I was referring to a conjoint analysis scenario using R from the paper
referred below:
Agricultural Information Research 17(2),2008,86-94
available online at www.jstage.jst.go.jp/
This paper describes the data modelling of a conjoint study design based
on conditional logit
Hi:
When you need to search for a function in R, rely on our good friend, the
package sos:
library(sos)
findFn('elastic net')
found 23 matches; retrieving 2 pages
HTH,
Dennis
On Wed, Sep 8, 2010 at 6:58 PM, jjenkner jjenk...@web.de wrote:
Hello Lai!
You can try the elastic net which is a
On Thu, 2010-09-09 at 09:16 +0430, Jan private wrote:
Dear list,
I am from an engineering background, accustomed to work with tolerances.
For example, I have measured
Q = 0.15 +- 0.01 m^3/s
H = 10 +- 0.1 m
and now I want to calculate
P = 5 * Q * H
and get a value with a
Hi!
I think you've got already all useful solutions, but I usually just
change mfrow to c(2,2).
There is then free space left, but I usually edit my graphs in
Illustrator anyway.
Ivan
Le 9/8/2010 21:01, (Ted Harding) a écrit :
Greetings, Folks.
I'd appreciate being shown the way out of
Hi:
One possibility is a heatmap, although there are other approaches.
x - matrix(sample(1:100, 1, replace = TRUE), nrow = 100)
image(x)
xx - apply(x, 1, sort) # sorts the rows of x
image(xx)
# ggplot2 version:
library(ggplot2)
ggplot(melt(x), aes(x=X1, y=X2, fill=value)) + geom_tile() +
thank you for your answers, but my problem is that i want plot the function
guete for the variables p_11 and p_12 between zero and one. that means that
i also want to plot p_11=0.7 and p_12=0.3. but with a=0.4 and b=0.6 and
p_11=seq(0,a,0.05*a) and p_12=seq(0,b,0.0*b) i cannot do that.
i hope you
Dear list,
I get some strange results with daply from the plyr package. In the
example below, the average age per municipality for employed en
unemployed is calculated. If I do this using tapply (see code below) I
get the following result:
no yes
A NA 36.94931
B
Dear all,
I would like some help to writing the likelihood function for the
continuous-time markov model, even if it can be calculated with the msm
package, I need to know how it is calculated
Thank you
Luis
[[alternative HTML version
Dear all, R offers integration mechanism with different programming
languages like C, C++, Fortran, .NET etc. Therefore I am curious on,
for heavy numerical computation which language is the fastest? Is
there any study? I specially want to know because, if there is some
study saying that C is the
Dear All,
I hope this is not too off-topic.
I am wondering if there is any possibility to make an R code lazy i.e.
to prevent it from calculating quantities which are not used in the code.
As an example: you are in a rush to modify your code and at the end it
ends up with dead branches, let's
Hi:
Here's what I tried:
# data frame versions (aggregate, ddply):
aggregate(age ~ municipality + employed, data = data.test, FUN = mean)
municipality employed age
1B no 55.57407
2C no 44.67463
3A yes 41.58759
4B yes
Dear all
I wonder if anyone has heard of confidence intervals around p-values...
Any pointer would be highly appreciated.
Best
Fer
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PLEASE do read the posting guide
dear all
I wonder if anyone has heard of confidence intervals around p-values...
Any pointer would be highly appreciated.
Best
Fer
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PLEASE do read the posting guide
Hello Bernardo,
-
If I understood your problem this script solve your problem:
q-0.15 + c(-.1,0,.1)
h-10 + c(-.1,0,.1)
5*q*h
[1] 2.475 7.500 12.625
-
OK, this solves the simple example.
But what if the example is not that simple. E.g.
P = 5 * q/h
Here, to get the maximum
NewJerseyR
Mango Solutions is pleased to announce the inaugural meeting of NewJerseyR a
networking and social event for all local and regional R users.
Thank you to those of you already registered to attend the first NewJerseyR
meeting on Thursday 16th September and to those of you who have
On 08/09/2010 11:46 PM, Philippe Grosjean wrote:
On 08/09/10 19:25, David Winsemius wrote:
On Sep 8, 2010, at 1:18 PM, telm8 wrote:
Hi,
I am having some strange problem with detecting try-error. From what I
have read so far the following statement:
try( log(a) ) == try-error
should yield
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On 09/09/10 12:26, Christofer Bogaso wrote:
Dear all, R offers integration mechanism with different programming
languages like C, C++, Fortran, .NET etc. Therefore I am curious on,
for heavy numerical computation which language is the fastest? Is
Dear R-users,
May be there is something that I am not understanding, missed or else...
Why do these operations yield these results?
25%/%0.2
[1] 124
25%%0.2
[1] 0.2
I would expect (although I know that what I do expect and what is really
intended in the code may be different things)
25/0.2
Dear all,
does anyone know how to define the structure of the required samples using
function createDataPartition, meaning proportions of different types of
variable in the partition?
Smth like this for iris data:
createDataPartition(y = c(setosa = .5, virginica = .3, versicolor = .2),
times =
On 09/09/2010 12:01 AM, Erin Hodgess wrote:
Dear R People:
I keep getting the Error in normalizePath(path) : while trying to
obtain the necessary packages to use with the Applied Spatial
Statistics with R book.
I turned off the Firewall (from McAfee) but am still getting the same message.
2010/9/9 José M. Blanco Moreno jmbla...@ub.edu:
Dear R-users,
May be there is something that I am not understanding, missed or else...
Why do these operations yield these results?
25%/%0.2
[1] 124
25%%0.2
[1] 0.2
I would expect (although I know that what I do expect and what is really
On 09/09/2010 6:27 AM, Lorenzo Isella wrote:
Dear All,
I hope this is not too off-topic.
I am wondering if there is any possibility to make an R code lazy i.e.
to prevent it from calculating quantities which are not used in the code.
As an example: you are in a rush to modify your code and at
try this:
myData
sample1.id1 sample1.id2 sample2.id1 sample1.id3 sample3.id1
sample1.id4 sample2.id2
11 2 2 1 1
1 1
21 2 2 2 1
2 1
31 2
On 09/09/2010 7:56 AM, Barry Rowlingson wrote:
2010/9/9 José M. Blanco Moreno jmbla...@ub.edu:
Dear R-users,
May be there is something that I am not understanding, missed or else...
Why do these operations yield these results?
25%/%0.2
[1] 124
25%%0.2
[1] 0.2
I would expect (although I
Another vote for org-mode here. In addition the advantages the
other posts mentioned, you get multiple export engines (html, latex, ...)
all built in.
On 09/09/2010 12:47 AM, David Scott wrote:
I am investigating some approaches to reproducible research. I need in
the end to produce .html or
On Wed, Sep 8, 2010 at 4:48 AM, Dimitri Shvorob
dimitri.shvo...@gmail.com wrote:
I was able to aggregate (with sqldf, at least), after saving and re-loading
the dataframe. My first guess was that h (and/or price?) now being a factor
- stringsAsFactors = T by default - made the difference, and
Did you read the documentation before you read the code?
‘%%’ and ‘x %/% y’ can be used for non-integer ‘y’, e.g. ‘1 %/%
0.2’, but the results are subject to rounding error and so may be
platform-dependent. Because the IEC 60059 representation of ‘0.2’
is a binary fraction slightly larger than
Hi Tim,
This works out of the box for me, with ESS 5.11 and Emacs 23.1
-Ista
On Thu, Sep 9, 2010 at 4:07 AM, Tim Elwell-Sutton tesut...@hku.hk wrote:
Hi
I've recently started using Emacs as my text editor for writing R script.
I am looking for a feature which I have seen on the standard R
Fernando Marmolejo Ramos fernando.marmolejoramos at adelaide.edu.au writes:
Dear all
I wonder if anyone has heard of confidence intervals around p-values...
Any pointer would be highly appreciated.
No, and my reflex is that it seems like a bad idea.
If you are using p-values as an
On 09/09/2010 6:44 AM, Fernando Marmolejo Ramos wrote:
Dear all
I wonder if anyone has heard of confidence intervals around p-values...
That doesn't really make sense. p-values are statistics, not
parameters. You would compute a confidence interval around a population
mean because that's
The first release of RNiftyReg, an R package for registration
(alignment and resampling) of medical images, is now available on CRAN
[1]. It may also be useful for other 3D array-like data sets.
RNiftyReg is built on top of the NiftyReg library [2], and is written
in a mixture of C, C++ and R. It
Dear Colleague,
The 10th ICANNGA conference, to be held April 14-16 2011 in Ljubljana,
Slovenia, is fast approaching and with it the paper submission deadline,
which is October 1st, 2010.
Let us kindly invite you to visit our web page: www.icannga.com, where
all the details on ICANNGA, its
daply(data.test, .(municipality, employed), function(d){mean(d$age)} )
employed
municipality no yes
A 41.58759 44.67463
B 55.57407 43.82545
C 43.59330 NA
The .drop argument has a different meaning in daply. Some R functions have
Hello,
I have a bar plot where I am already using colour to distinguish one set
of samples from another. I would also like to highlight a few of these
bars as ones that should be looked at in detail. I was thinking of
using hatching, but I can't work out how or if you can have a background
Look at my.symbols in the TeachingDemos package.
-Original Message-
From: Rainer Machne r...@tbi.univie.ac.at
Sent: Thursday, September 09, 2010 12:42 AM
To: R-help@r-project.org R-help@r-project.org
Subject: [R] plot symbol +, but with variable bar lenghts
Hi,
does anybody know of
Josh,
I liked your idea of setting the repo in the .Rprofile file, so I tried it:
r - getOption(repos)
r[CRAN] - http://cran.stat.ucla.edu;
options(repos = r)
rm(r)
And now when I open R I get an error:
Error in r[CRAN] - http://cran.stat.ucla.edu; :
cannot do complex assignments in base
Hi
I want to do boosted regression(classification) tree for categorical response
(with 7 levels). Can I do this by GBM package?
please help me?
Thanks alot
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
I'm having trouble determining the bounds of my current graph. I know how
to set the bounds up front (ylim xlim in most cases), but I would rather
be able to dynamically see what was chosen to use in later code.
Example:
library(maps)
map('state','Indiana')
map.axes()
??Something that lets me
It would help if you included a bit of sample data. See ?dput as a way of doing
this.
Also a good place to start is by looking at the package reshape. Have a look
at http://had.co.nz/reshape/ for some information on the package.
--- On Wed, 9/8/10, Jonathan Finlay jmfinl...@gmail.com wrote:
For the compiled languages, it depends heavily on the compiler. This
sort of comparison is rendered moot by the huge variety of compiler and
hardware specific optimizations. My suggestion is to use C, or possibly
C++ in conjunction with Rcpp, as these are most compatible with R. Also,
C and C++
On 9 September 2010 at 13:26, Rainer M Krug wrote:
| -BEGIN PGP SIGNED MESSAGE-
| Hash: SHA1
|
| On 09/09/10 12:26, Christofer Bogaso wrote:
| Dear all, R offers integration mechanism with different programming
| languages like C, C++, Fortran, .NET etc. Therefore I am curious on,
|
On Sep 9, 2010, at 10:07 AM, Isamoor wrote:
I'm having trouble determining the bounds of my current graph. I
know how
to set the bounds up front (ylim xlim in most cases), but I would
rather
be able to dynamically see what was chosen to use in later code.
Example:
library(maps)
On 09-Sep-10 13:21:07, Duncan Murdoch wrote:
On 09/09/2010 6:44 AM, Fernando Marmolejo Ramos wrote:
Dear all
I wonder if anyone has heard of confidence intervals around
p-values...
That doesn't really make sense. p-values are statistics, not
parameters. You would compute a confidence
Yes, Barry, we are aware of this issue. It is caused by printing to console
from FORTRAN in one of the optimization codes, ucminf. If we set trace=FALSE
in optimx, this problem goes away.
Ravi.
Ravi Varadhan, Ph.D.
On Sep 9, 2010, at 6:50 AM, Jan private wrote:
Hello Bernardo,
-
If I understood your problem this script solve your problem:
q-0.15 + c(-.1,0,.1)
h-10 + c(-.1,0,.1)
5*q*h
[1] 2.475 7.500 12.625
-
OK, this solves the simple example.
But what if the example is not that
q-0.15 + c(-.1,0,.1)
h-10 + c(-.1,0,.1)
5*q/h[3:1]
[1] 0.02475248 0.0750 0.12626263
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Sent from the R help mailing list archive at Nabble.com.
Thank you Dennis,
You identified a factor (text column) that I was concerned with.
I simplified my example to try and factor out possible causes. I
eliminated the recurring values in columns (which were not the columns
that caused problems). I produced three examples with simple data sets.
Hello Daniel,
something like that might work:
x - runif(6)
marker1 - rep(c(red, blue), 3)
marker2 - c(rep(0,5), 10)
barplot(x, col = marker1)
barplot(x, density = marker2, add=T)
But I'd be interested if you learn about other solutions...
-Heinrich.
-Ursprüngliche Nachricht-
Von:
On Sep 9, 2010, at 6:50 AM, Jan private wrote:
Hello Bernardo,
-
If I understood your problem this script solve your problem:
q-0.15 + c(-.1,0,.1)
h-10 + c(-.1,0,.1)
5*q*h
[1] 2.475 7.500 12.625
-
OK, this solves the simple example.
But what if the example is not that
I have a little package I've been using to write template blog posts (in
HTML) with embedded R code. It's quite small but very flexible and
extensible, and aims to do something similar to Sweave and brew. In
fact, the package is heavily influenced by the brew package, though
implemented quite
Hi
you has to provide some more info about x e.g. str(x)
x-data.frame(price=1, h=Sys.time())
r-help-boun...@r-project.org napsal dne 08.09.2010 10:18:52:
Mnay thanks fr suggestions. I am afraid this is one tough daatframe...
t = sqldf(select h, count(*) from x group by h)
Error in
Jan private jrheinlaen...@gmx.de wrote in message
news:1284029454.2740.361.ca...@localhost.localdomain...
Hello Bernardo,
-
If I understood your problem this script solve your problem:
q-0.15 + c(-.1,0,.1)
h-10 + c(-.1,0,.1)
5*q*h
[1] 2.475 7.500 12.625
-
OK, this
2010/9/8 David Winsemius dwinsem...@comcast.net
I hope you mean only two factors and an n x m table.
Yes David I like say factor, but am new here.
--
Jonathan.
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__
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On Sep 9, 2010, at 13:52 , Duncan Murdoch wrote:
On 09/09/2010 12:01 AM, Erin Hodgess wrote:
Dear R People:
I keep getting the Error in normalizePath(path) : while trying to
obtain the necessary packages to use with the Applied Spatial
Statistics with R book.
I turned off the Firewall
Can you set the multinomial prob. to zero for p1+p2+p3 != 1 if you have to
use the multinomial distribution in guete(). Otherwise, I would say the
problem/guete() itself is problematic.
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Sent
On Sep 8, 2010, at 7:32 PM, Jonathan Finlay wrote:
Thanks David, gmodels::Crosstable partially work because can show
only 1 x 1
tablen
CrossTable(x,y,...)
I need something how can process at less 1 variable in X an 10 in Y.
A further thought (despite a lack of clarification on what your
I am following up on an old post. Please, comment:
it appears that
predict(glm.model,type=response,se.fit=T)
will do all the conversions and give se on the scale of the response. This
only takes into account the error in parameter estimation. what a
prediction interval is meant to be usually
g = head(x)
dput(g)
structure(list(price = c(500L, 500L, 501L, 501L, 500L, 501L),
size = c(221000L, 2000L, 1000L, 13000L, 3000L, 3000L), src = c(R,
R, R, R, R, R), t = structure(list(sec = c(24.133,
47.096, 12.139, 18.142, 10.721, 28.713), min = c(0L, 0L,
1L, 1L, 2L, 2L),
Hi, thank you very much for the help.
one more quick question: is that, my predictor variable should be coded as
'factor' when using either 'lm' or 'glm'?
sincerely,
karena
--
View this message in context:
Thanks a lot!
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R-help@r-project.org mailing list
Well, the attachment was a dud. Try this:
http://biostatmatt.com/R/markup_0.0.tar.gz
-Matt
On Thu, 2010-09-09 at 10:54 -0400, Matt Shotwell wrote:
I have a little package I've been using to write template blog posts (in
HTML) with embedded R code. It's quite small but very flexible and
Dear all,
I have a barplot upon which I hope to superimpose horizontal lines extending
across the width of each bar. I am able to partly achieve this through the
following set of commands:
positions - barplot(bar_values, col=grey)
par(new=TRUE)
plot(positions, horiz_values, col=red, pch=_,
Hi everyone.
I'm trying to break the y axis on a plot. For instance, I have 2 series
(points and a loess). Since the loess is a continuous set of points, it
passes in the break section. However, with gap.plot I cant plot the loess
because of this (I got the message some values of y will not be
Dear list,
I read in ?plotmath that I can use bgroup to draw scalable delimiters
such as [ ] and ( ). The same technique fails with however, and I
cannot find a workaround,
grid.text(expression(bgroup(,atop(x,y),)))
Error in bgroup(, atop(x, y), ) : invalid group delimiter
Regards,
baptiste
The image function will create a plot with the values transformed to colors. Or
the View function (note the capitol V) will let you look at it in a spreadsheet
like window with scrollbars.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
I think your main problem is that you have your time as POSIXlt which
is a multiple valued vector. I converted the 't' to POSIXct, removed
the other POSIXlt value and created a 'h' as the character for the
hour and it works fine:
str(g)
'data.frame': 6 obs. of 5 variables:
$ price: int 500
hello
I think I've found a bug
I don't know if it's a chron bug or a R one.
(05/12/05 23:00:00) +1/24 gives
(05/12/05 24:00:00)
instead of
(05/13/05 00:00:00)
it looks like the same but it's not because when you get the date of this
datetime it says day 12 instead of 13.
Please, forward it
Dear R community (and Duncan more specifically),
I can't work out how to make additional light sources work in rgl.
Here is the example.
First I create a cube and visualize it:
cubo - cube3d(col=black)
shade3d(cubo)
Next I position the viewpoint at theta=0 and phi=30:
view3d(theta=0,phi=30)
On Wed, 8 Sep 2010, Paul Johnson wrote:
run it with factor() instead of ordered(). You don't want the
orthogonal polynomial contrasts that result from ordered if you need
to compare against Stata.
If you don't want polynomial contrasts for ordered factors, you can just tell R
not to use
On Thu, Sep 9, 2010 at 7:05 AM, Bos, Roger roger@rothschild.com wrote:
Josh,
I liked your idea of setting the repo in the .Rprofile file, so I tried it:
r - getOption(repos)
r[CRAN] - http://cran.stat.ucla.edu;
options(repos = r)
rm(r)
And now when I open R I get an error:
Error
On Thu, Sep 9, 2010 at 11:59 AM, skan juanp...@gmail.com wrote:
hello
I think I've found a bug
I don't know if it's a chron bug or a R one.
(05/12/05 23:00:00) +1/24 gives
(05/12/05 24:00:00)
instead of
(05/13/05 00:00:00)
it looks like the same but it's not because when you get the
Hi,
If your predictor variable is categorical than it should be converted
to a factor. If it is continuous or being treated as such, you do not
need to. It is generally quite easy to do:
varname - factor(varname)
or if it is in a data frame
yourdf$varname - factor(yourdf$varname)
Cheers,
Dear all
I would like to run in R an uncertainty/sensitivity analysis. I know that these
two are performed together. I have a geochemical model where I have the inputs,
the water variables (e.g. pH, temperature, oxygen ect) and as well an output of
different variables. What I would like to do
On Thu, Sep 9, 2010 at 1:14 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
On Thu, Sep 9, 2010 at 7:05 AM, Bos, Roger roger@rothschild.com wrote:
Josh,
I liked your idea of setting the repo in the .Rprofile file, so I tried it:
r - getOption(repos)
r[CRAN] - http://cran.stat.ucla.edu;
One other case where a confidence interval on a p-value may make sense is
permutation (or other resampling) tests. The population parameter p-value
would be the p-value that would be obtained from the distribution of all
possible permutations, but in practice we just sample from that
Something strange.
Your example work but...
I have a zoo object.
I extract its element 21
index(test[21])
[1] (05/12/05 23:00:00)
index(test[21])+1/24
[1] (05/12/05 24:00:00)
Why 24:00 ?
packageDescription(chron)$Version
[1] 2.3-35
R.version.string
[1] R version 2.11.1
Hi Stephane,
When I use your sample data (e.g., test, test.number), cor() throws an
error that x must be numeric (because of the factor or character
data). Are you not getting any errors when trying to calculate the
correlation on these data? If you are not, I wonder what version of R
are you
On Thu, Sep 9, 2010 at 9:28 AM, Jakson A. Aquino jaksonaqu...@gmail.com wrote:
On Thu, Sep 9, 2010 at 1:14 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
On Thu, Sep 9, 2010 at 7:05 AM, Bos, Roger roger@rothschild.com wrote:
Josh,
I liked your idea of setting the repo in the .Rprofile
Could this be a case of faq 7.31? where rounding error means that you are
seeing a time that is slightly before midnight (but printing shows it at
midnight).
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original
I don't know.
You can look at the file, is very short.
http://r.789695.n4.nabble.com/file/n2533223/test test
--
View this message in context:
http://r.789695.n4.nabble.com/Bug-on-chron-tp2533135p2533223.html
Sent from the R help mailing list archive at Nabble.com.
Barry Rowlingson b.rowlingson at lancaster.ac.uk writes:
On Wed, Sep 8, 2010 at 1:35 PM, Michael Bernsteiner
dethlef1 at hotmail.com wrote:
Dear all,
I'm optimizing a relatively simple function. Using optimize the optimized
parameter value is worse than the starting. why?
I would
A confidence interval around the p-value makes no sense because there is
no parameter being estimated, but the sampling distribution of the p-value
makes a lot of sense. The pre-observational P-value is a random variable
that is a function of the underlying random variable being tested. That
On 09/09/2010 12:02 PM, james.fo...@diamond.ac.uk wrote:
Dear R community (and Duncan more specifically),
I can't work out how to make additional light sources work in rgl.
Here is the example.
First I create a cube and visualize it:
cubo- cube3d(col=black)
shade3d(cubo)
Next I position
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