df$dt - as.Date(df$t)
Thank you, David, but I need a *time* value. day was a confusing special
case; how about min?
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On 22.11.2010 07:44, Roslina Zakaria wrote:
Hi r-users,
I would like my axes to intersect at (0,0). I tried xaxs=i,yaxs=i but it
does not change anything. I hope anybody can help me with this problem. Here
is my code.
use
par(xaxs=i, yaxs=i)
and then the rest of your code.
UWe
Hello
I want to build a classification tree for a binary response variable
while the condition for the final tree should be :
The total misclassification for each group (zero or one) will be less then
10% .
for example: if I have in the root 100 observations, 90 from group 0 and 10
from group 1,
On 22.11.2010 08:24, rnick wrote:
Hello everyone,
I am trying to built an xts object and i have run into some problems on the
data handling. I would really appreciate if someone could help me with the
following:
1) I have a OHLC dataset with Time and date in different columns. How could
i
On 22.11.2010 08:32, meytar wrote:
Hello
I want to build a classification tree for a binary response variable
while the condition for the final tree should be :
The total misclassification for each group (zero or one) will be less then
10% .
for example: if I have in the root 100
After importing a table with M variables and N records, I'd like to
calculate chi-square statistics, say, between N1, N2; N1, N3, ..., N1, Ni,
and then N2, N3, ... N2, Ni, ..., Ni-1, Ni. Two loops should be ok but the
manual online help don't show a systematic way to do so but instead show
-Original Message-
From: jas4710 wata...@post.com
To: r-help@r-project.org
Sent: Mon, Nov 22, 2010 4:11 pm
Subject: [R] how to loop through variables in R?
After importing a table with M variables and N records, I'd like to
calculate chi-square statistics, say, between N1, N2; N1,
my csv file is very simple - just one line for purpose of this test:
0{TAB}0
and read function is this:
csvdata = read.csv(file=d:/s/test.csv,head=FALSE,sep=\t)
then error comes:
Error in source(d:/test.csv) :
d:/test.csv:1:9: unexpected numeric constant
1: 0 0
but when I change
the problem shows up only in console when script is loaded thru source() and
separator character is eighter tab or space, strangely, when I'm running
script directly form file in text environment everything is ok.
[I'm reposing this because my previous post didn't get on the list because
double
Dimitri Shvorob wrote:
df$dt - as.Date(df$t)
Thank you, David, but I need a *time* value. day was a confusing special
case; how about min?
Your original question was NOT clear on this point... it was not David's
fault your question was confusing, and you haven't even hinted at an
wata...@post.com wrote:
-Original Message-
From: jas4710 wata...@post.com
To: r-help@r-project.org
Sent: Mon, Nov 22, 2010 4:11 pm
Subject: [R] how to loop through variables in R?
After importing a table with M variables and N records, I'd like to
calculate chi-square statistics,
On Sun, Nov 21, 2010 at 12:43:21PM -0800, wangwallace wrote:
here is the data frame:
a b c A B C
[1,] 1 2 3 4 5 6
[2,] 7 8 9 10 11 12
[3,] 13 14 15 16 17 18
a, b, c are type I variables
A, B, C are type II variables
each row represent the data from one
Dear R experts, beginners and everyone else,
I'm calculating cumulative periodogram using the command cpgram
[1] from the MASS library. Here is a short example with the lh
(hormone level) dataset:
library(MASS)
plot(lh,type=l,ylab=value,xlab=time, main=Hormone Levels (lh))
spectrum(lh,
madr wrote:
my csv file is very simple - just one line for purpose of this test:
0{TAB}0
and read function is this:
csvdata = read.csv(file=d:/s/test.csv,head=FALSE,sep=\t)
then error comes:
Error in source(d:/test.csv) :
d:/test.csv:1:9: unexpected numeric constant
1: 0 0
but
code:
op -
par(bg='black',fg='gray',col='gray',col.axis='gray',col.lab='gray',col.main='gray',col.sub='gray',mai=c(0,0,0,0),
tck = 0.01, mgp = c(0, -1.4, 0), mar=c(0,0,0,0))
plot(x,y,ylim=c(-20,20),xlim=c(min(x),max(x)),pch='X',col = rgb(1,1,1,
0.5),yaxt=n, ann=FALSE)
abline(v=c(min(x),max(x)),
i found solution myself:
par(xaxs = i, yaxs = i) - it sets axis ranges to actual data ranges
sorry for question but maybe this will be easier to find if someone would be
searching for this
--
View this message in context:
Hi!
After plotting, take a look at par()$usr; it gives you the coordinates
of the plotting region.
You could use it that way:
abline(v=c(par()$usr[1], par()$usr[2])...)
Note that you can also use it like this: par(usr)[1]
HTH,
Ivan
Le 11/22/2010 11:04, madr a écrit :
code:
op-
The folder are the same, I just deleted the long path because it is
irrelevant and by mistake left /s i one of the paths, they should be
identical.
I'm running this package:
http://cran.r-project.org/bin/windows/base/R-2.12.0-win.exe on win xp 32 bit
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On 11/22/2010 01:38 PM, Luis Felipe Parra wrote:
Hello, I am putting a legend with lines in a line plot and I would like to
make the lines in the legend shorter. Does anybody knows how to do this?
Hi Felipe,
The only rather clunky way I can think of is to use pch=- instead of
lty or lwd.
Date: Mon, 22 Nov 2010 01:57:54 -0800
From: jdnew...@dcn.davis.ca.us
To: madra...@interia.pl
CC: r-help@r-project.org
Subject: Re: [R] unexpected numeric constant while reading tab delimited
csv file
madr wrote:
my csv file is very simple
code:
x - rnorm(32)
y - rnorm(32)
plot(x,y)
lines(lowess(x,y),col='red')
Now I need to sample the lowess function into matrix where one series will
be X and other will be values of lowess at particular X.
--
View this message in context:
madr wrote:
my csv file is very simple - just one line for purpose of this test:
0{TAB}0
and read function is this:
csvdata = read.csv(file=d:/s/test.csv,head=FALSE,sep=\t)
then error comes:
Error in source(d:/test.csv) :
d:/test.csv:1:9: unexpected numeric constant
1: 0 0
but
Hello I am new to RExcel and I would like to run a source code form the
excel worksheet. I would like to run the following code
source(C:\\Quantil Aplicativos\\Genercauca\\BackwardSelectionNC.r)
from the excel wroksheet. Does anybody know how to do this?
Thank you
Felipe Parra
I am using r to read and reformat data that is then saved to a text file
using sink(), the file has a number of initial lines of comments and
summary data followed by print of a data.frame with no row names.
for example
a-c(100:120)
b-c(rnorm(100:120))
c-c(rnorm(200:220))
LinkedIn
Aline Uwimana requested to add you as a connection on LinkedIn:
--
James,
J'aimerais vous inviter à rejoindre mon réseau professionnel en ligne, sur le
site LinkedIn.
Aline
Accept invitation from Aline Uwimana
On Mon, Nov 22, 2010 at 2:24 AM, rnick nikos.rachma...@gmail.com wrote:
Hello everyone,
I am trying to built an xts object and i have run into some problems on the
data handling. I would really appreciate if someone could help me with the
following:
1) I have a OHLC dataset with Time and
Dears users,
A new version of Tinn-R was released today. Below details:
2.3.7.0 (Nov/22/2010)
* Bug(s) fixed:
- A bug related with the intermittent loose of connection
(or appear to freeze) with Rgui.exe was fixed.
* The versions 2.3.6.4, 2.3.6.5, 2.3.6.6 and 2.3.6.7
Hello, I am trying to use RExcel and I would like to know if it is possible
to use in excel the following function I made for R
Pron = function(path=C:\\Quantil Aplicativos\\Genercauca\\V5\\){
library(timeSeries)
library(maSigPro)
### CARGAR FUNCIONES
?options
width
options(width = 1000)
On Mon, Nov 22, 2010 at 7:22 AM, Nevil Amos nevil.a...@gmail.com wrote:
I am using r to read and reformat data that is then saved to a text file
using sink(), the file has a number of initial lines of comments and summary
data followed by print of a
A simple alternative is to use at to contrl plot locations:
boxplot( ..., at=rev(1:nlevels(depthM)))
which just rearranges where they are plotted.
Example:
set.seed(1023)
x - gl(5, 5)
y-rnorm(25)
boxplot(y~x, horizontal=TRUE)
boxplot(y~x, at=rev(1:nlevels(x)), , horizontal=TRUE)
Steve E
Hello everyone,
when I commit a plot using console(command line?) plot works fine. I have
created a function that plots based on the input. This function is called
plot_shad. When I call this function alone in the command line I get my plot.
Then I tried to use another function as
I found it, it was SO simple:
lowessline - lowess(x,y)
write.csv(lowessline, loess.csv)
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Alex, this may be FAQ 7.22
Claudia
On 11/22/2010 02:19 PM, Alaios wrote:
Hello everyone,
when I commit a plot using console(command line?) plot works fine. I have
created a function that plots based on the input. This function is called
plot_shad. When I call this function alone in the
Hi,
For RExcel I would suggest subscribing;
http://mailman.csd.univie.ac.at/listinfo/rcom-l
They have a website on;
http://rcom.univie.ac.at/
B.R.
Stephen L
- Original Message
From: Luis Felipe Parra felipe.pa...@quantil.com.co
To: r-help r-help@r-project.org
Sent: Mon, November
Dear Claudia,
I would like to thank you for your reply, according to 7.22 I have to put some
print() statement inside my function. What I do not understand is where to put
this line (at the beginning or at the end of the code?) I tried both but I get
error message.
Moreover I would like to ask
LinkedIn
Yann Lancien requested to add you as a connection on LinkedIn:
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James,
J'aimerais vous inviter à rejoindre mon réseau professionnel en ligne, sur le
site LinkedIn.
Yann
Accept invitation from Yann Lancien
Hi
Im trying to merge 2 data frames using merge but I dont get the result i
want
Lets make this a small test as my data set is to big to put in here :).
t1-data.frame(a=c(1,2,3,4,5,6),b=c(11,11,NA,11,11,11))
t1-data.frame(a=c(1,2,3,4,5,8),b=c(12,12,12,12,12,32))
this gives me:
t1
a b
1 1
merge(t1,t2, by=a, all.x = TRUE)
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium
Research Institute for Nature and Forest
team
On 2010-11-21 18:38, Luis Felipe Parra wrote:
Hello, I am putting a legend with lines in a line plot and I would like to
make the lines in the legend shorter. Does anybody knows how to do this?
I think the segment length is still hard-coded in legend().
Last July there was a request to
This feature has been added in survival 2.36-1, which is now on CRAN.
(2.36-2 should appear in another day or so)
Terry T.
-begin included message
I was trying to use predict.coxph to calculate martingale residuals on
a test
data, however, as pointed out before
Thx alot mate.
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Hi R-people:
Working in geoRglm, it shows me, according to AIC criterion, that the
non-spacial model describes the process in a better way. It's the first time
that I'm facing up to.
These are my results:
OP2003Seppos.AICnonsp-OP2003Seppos.AICsp
#[1] -4
Dear all,
I recently started using the kohonen package for my thesis project. I
have a very simple question which I cannot figure out by myself:
When I execute the following example code, from the paper of Wehrens
and Buydens (http://www.jstatsoft.org/v21/i05/paper):
R library(kohonen)
Loading
see below.
2010/11/21 Uwe Ligges lig...@statistik.tu-dortmund.de:
On 21.11.2010 18:13, Kjetil Halvorsen wrote:
?save.image
And at this point it has been running with one cpu at 100% for over an
hour!
It's OK to take an hour (due to memory - disc IO) if it uses swap space
heavily.
Date: Mon, 22 Nov 2010 12:03:54 -0300
From: kjetilbrinchmannhalvor...@gmail.com
To: lig...@statistik.tu-dortmund.de
CC: r-help@r-project.org
Subject: Re: [R] ?summaryRprof running at 100% cpu for one hour ...
see below.
2010/11/21 Uwe Ligges :
Hi folks,
I have circular data that I'd like to model as a mixture of a uniform
and a Von Mises centered on zero. The data are from 2 groups of human
participants, where each participant is measured repeatedly within
each of several conditions. So, the data frame would look something
like:
Hello,
I am trying to recursively append some data from multiple files into a
common object
For this, I am using in a loop
NewObject - rbind(NewObject,tempObject)
For the first loop, obviously there is no NewObject ... so I wanted to do
NewObject - tempObject[0,]
Now when it loops again I
Dear R Helpers,
I have attempted optim function to solve a two-dimensional optimization
problem. It took around 25 second to complete the procedure.
However, I want to reduce the computation time: less than 7 second. Is there
any optimization function in R which is very rapid?
Best Regards,
2010/11/20 Marcin Gomulka mrgo...@gmail.com
I'd rather do this with a dedicated
package function ( like axis() ).
Probably you have to write your own function, or tune up manually plot.
plot(the_data$eventtime, abs(the_data$impact), type=h, frame.plot=FALSE,
axes =
FALSE, xlab=,ylab=,
Using:
summaryRprof(memory=both)
did the trick, thank you. I had not been using that setting when calling
summaryRprof.
Thanks, Patrick
2010/11/20 Uwe Ligges lig...@statistik.tu-dortmund.de
On 19.11.2010 21:48, Patrick Leyshock wrote:
I'm trying to configure Version 2.12.0 or R
see below.
On Mon, Nov 22, 2010 at 12:13 PM, Mike Marchywka marchy...@hotmail.com wrote:
Date: Mon, 22 Nov 2010 12:03:54 -0300
From: kjetilbrinchmannhalvor...@gmail.com
To: lig...@statistik.tu-dortmund.de
CC: r-help@r-project.org
Subject: Re:
Stephen Liu sati...@yahoo.com
on Sat, 20 Nov 2010 00:12:07 -0800 (PST) writes:
Hi Josh and David,
Problem solved.
Both following steps work.
1)
ToothGrowth
attach(ToothGrowth)
plot(dose,len) # this step is needed. Don't close the diagram.
Otherwise
Date: Mon, 22 Nov 2010 12:41:06 -0300
Subject: Re: [R] ?summaryRprof running at 100% cpu for one hour ...
From: kjetilbrinchmannhalvor...@gmail.com
To: marchy...@hotmail.com
CC: lig...@statistik.tu-dortmund.de; r-help@r-project.org
see below.
I think you want the function ?exists
if(!exists(NewObject))
--
Jonathan P. Daily
Technician - USGS Leetown Science Center
11649 Leetown Road
Kearneysville WV, 25430
(304) 724-4480
Is the room still a room when its empty? Does the room,
the thing itself have
After my reply you sent me the following privately:
Thank you for your respond. Now I adjust the parameters which are close
to the value that I'm expected and it gives me the following message: I
tried a few combination. My question is why it said Unsuccessful
convergence but still give
Hi Jason,
You do not say what you want the alternative to do, so its hard to
know if this will be helpful. But one alternative is
dat - as.data.frame(ak.fan)
dat - melt(dat, id.vars=c(x, y))
p - ggplot(dat, aes(x=x, y=variable))
p + geom_tile(aes(fill=value))
-Ista
On Sun, Nov 21, 2010 at 9:04
Martin,
Pardon the delayed reply.
Bootstrap methods have been around for some time (late seventies?), but
their popularity seems to have exploded in correspondence with computing
technology. You should be able to find more information in most modern
books on statistical inference, but here is a
Santosh -
The simple answer to your question is to initialize
NewObject to NULL before the loop, i.e.
newObject = NULL
However, I should point out this is one of the most
inefficient ways to program in R. A far better way is
to allocate enough space for NewObject outside your
loop,
Hi,
I suggest taking a look at the plotting functions in the ggplot2
package. For example:
x - rnorm(1)
y - x+rnorm(1)
dat - data.frame(x,y)
library(ggplot2)
p - ggplot(dat, aes(x=x, y=y))
p + geom_point() # too much overplotting: compare to
dev.new()
p + geom_hex(binwidth=c(.1,.1))
DEar list members,
I am currently using Sweave with LaTeX which is great.
I can use xtable for formatting outp of tables but I have a problem setting the
number of decimals in xtables when used with dataframe.
I have found an example on the net ith matrix and it works.
For example this works
     Hi everybody,
I got a problem with the ftpUpload function from the RCurl package. My goal is
to Upload a lot of files from a local directory to a web server.
1st try :
for (i in 1:length(file)){
     ftpUpload(what=files[i],to=files[i])
}
At i=11 I get : (my server has only 10
Hi R-Users,
I am working with sm.ancova (in the package sm) and I have two problems with
the graph, which is automatically generated when sm.ancova() is run.
1-Besides of the fitted lines, the observed data appeared automatically in the
graph. I prefer that only fitted lines appear. I check
Hi everyone,
I want to plot a 3D interpolation of the concentration of aquatic
organisms. My goal would be to have the result represented as clouds
with a density proportional to the abundance of organisms, so that I
could fly (well, swim actually ;) ) through the scene and see the
patches here
I guess I would just comment that for many tasks I try
to keep the work in dedicated tools. In this case, command
line versions of curl or even wget. The reason is things
like this that come up talking to foreign entitites.
Also the learning curve can be amortized over many other
efforts that
And how about if I want to order the series from the smallest to the largest
value, keeping the date index in order to see when the values were
predominantly negative etc...
Thanks,
Marco
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On 22/11/2010 12:51 PM, JiHO wrote:
Hi everyone,
I want to plot a 3D interpolation of the concentration of aquatic
organisms. My goal would be to have the result represented as clouds
with a density proportional to the abundance of organisms, so that I
could fly (well, swim actually ;) )
Look at Predict.Plot (and possibly TkPredict) in the TeachingDemos package.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org]
Date: Mon, 22 Nov 2010 13:55:13 -0500
From: murdoch.dun...@gmail.com
To: jo.li...@gmail.com
CC: r-h...@stat.math.ethz.ch
Subject: Re: [R] Plotting a cloud/fog of variable density in rgl
On 22/11/2010 12:51 PM, JiHO wrote:
Hi everyone,
I
Thanks a lot, Matt!
I will have a look at the options you suggested.
Cheers,
Mango
--
-
Never run for the bus.
Never skip tea.
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I want to make the matrix to be indexed from row (column) 0, not 1
Can I do that? How?
Thanks
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
Alaios ala...@yahoo.com writes:
Also when I try to search in google using for example the word R inside the
search lemma I get very few results as the R confuses the search engine. When
I was looking something in matlab ofcourse it was easier to get results as
the search engine performs
Nor would I call this much of an improvement in clarity... what about
min? You want to know the minimum?
LOL. (And apologies for the insensitivity). Thank you for help, Jeff. This
works, but I am still curious to see a solution based on trunc, if anyone
can find it.
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View this message in
Q1: How can i draw LSD (Least significant difference) on a plot?
Like this...
http://r.789695.n4.nabble.com/file/n3053430/LSD.jpg
Q2: How can i draw the axis secondary scale?
Thanks for help.
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Hi,
I have struggled on this bound optimization with equality constraint by
using optim function for two days, but still fail to prepare a good input.
Can anyone help to prepare the input for my specific case? Many thanks.
Best,
Hao
On Sat, Nov 20, 2010 at 3:17 AM, Hans W Borchers [via R]
Em 22/11/2010 10:11, Luis Felipe Parra escreveu:
Hello I am new to RExcel and I would like to run a source code form the
excel worksheet. I would like to run the following code
source(C:\\Quantil Aplicativos\\Genercauca\\BackwardSelectionNC.r)
from the excel wroksheet. Does anybody know how to
Using:
summaryRprof(memory=both)
did the trick, thank you. I had not been using that setting when calling
summaryRprof.
Thanks, Patrick
2010/11/20 Uwe Ligges lig...@statistik.tu-dortmund.de
On 19.11.2010 21:48, Patrick Leyshock wrote:
I'm trying to configure Version 2.12.0 or R to do
Thank you for your prompt reply!
Yes, I meant the apparent error rate.
According to your advice, if I use rpart to build a full tree, what
pruning command will be appropriate and will able me to add as an input to
the pruning procedure the total error rate i'm looking for?
Thank you very much
I believe nobody has responded to far, so maybe this is not a wide-spread
issue. However, I have also encountered this since upgrading to R 2.12.0
(Windows 7, 64-bit). In my simulations where I use txtProgressBar(), the
problem usually disappears after the bar has progressed to a certain
I tried it. it works out perfectly. you save my life.
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Nuncio,
No, there is no requirement to subtract the mean.
It is required that the residuals are N.I.I.D. (ie constant mean and
constant variance). If you have an upward trending series, for example,
then the series would need to be deseasonalized so that it is constant.
There are many many
Hi R user,
I am a kind of an intermediate user of R. Now I am using GLM model (library
MASS, VEGUS). I used a backward stepwise logistic regression, but i got a
problem in removing those predictors which are above 0.05. I don't want to
include those variables which were above 0.05 in final
Hello,
I am trying write a script that includes a prompt for user input using
readlines(). I am running into the problem that when I run readlines() as a
single line the prompt works perfectly, but when I try to run a block of
code which includes the readline function, the script doesn't wait for
Hello everyone,
I would like to call web service in R, how can I do this? Thank you!
Gao Xia
[[alternative HTML version deleted]]
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PLEASE do read the posting
Hi everyone
I have a question about how to save a regression model in R and how to retrieve
it for making predictions in a new session.
To be more specific, I fitted a multilevel logistic regression model using the
lmer from the lme4 package. I then successfully make predictions using
Hi,
You can do it, but it would be very difficult (think reworking all
indexing yourself) and you probably should not even try (nothing else
that was expecting indexing to work as the R gods intended it to would
work once you had done your rework).
What has lead you to want to index from 0? If
I do not understand the constraint x1 = x3 = x4. If this is correct, you
only have 10 unknown parameters.
If you can correctly formulate your problem, you can have a look at the
packages alabama or BB. The function `auglag' in alabama or the
function `spg' in BB may be useful.
Ravi.
Eh??? Why would you want to do that?? (R isn't C).
So the simple answer is: you can't.
The other answer is, well of course you sort of can via, e.g.
for(i in 0:9) {
z - myMatrix[i+1,]
...
}
But as Josh said, I think this falls into the class of You are just
asking for trouble, so don't
No joy for me. :(
I'd had version 0.4-1 installed previously, and re-pulling that URL and
reinstalling, plus setting RCurlOptions as specified, do not help for me.
Exactly the same behavior. It doesn't matter whether I call getGoogleAuth
directly or let getGoogleDocsConnection do it for me.
On 2010-11-22 09:47, Lucia Cañas wrote:
Hi R-Users,
I am working with sm.ancova (in the package sm) and I have two problems with
the graph, which is automatically generated when sm.ancova() is run.
1-Besides of the fitted lines, the observed data appeared automatically in the
graph. I
Hi Nate,
There may be better ways, but on the couple instances I've wanted to
wait for keyboard input I used this type of paradigm:
foo - function() {
x - 1:10
y - rnorm(10)
input - NA
while(!isTRUE(input == 1) !isTRUE(input == 2)) {
cat(Please type '1' if you want the first
On Mon, Nov 22, 2010 at 1:35 PM, Manta mantin...@libero.it wrote:
And how about if I want to order the series from the smallest to the largest
value, keeping the date index in order to see when the values were
predominantly negative etc...
If you just want to look at it in this order then:
Bert Gunter gunter.berton at gene.com writes:
Eh??? Why would you want to do that?? (R isn't C).
So the simple answer is: you can't.
The other answer is, well of course you sort of can via, e.g.
for(i in 0:9) {
z - myMatrix[i+1,]
...
}
But as Josh said, I think this falls
On Nov 22, 2010, at 10:02 AM, Ni, Melody Zhifang wrote:
Hi everyone
I have a question about how to save a regression model in R and how
to retrieve it for making predictions in a new session.
To be more specific, I fitted a multilevel logistic regression model
using the lmer from the
round() function affects all values of a matrix, I want only to round column
that is called 'y'.
--
View this message in context:
http://r.789695.n4.nabble.com/how-to-round-only-one-column-of-a-matrix-tp3054363p3054363.html
Sent from the R help mailing list archive at Nabble.com.
Apparently He who starts from 0 needn't be called unfortunate,
fortune('indexed')
baptiste
On 22 November 2010 20:59, Ben Bolker bbol...@gmail.com wrote:
Bert Gunter gunter.berton at gene.com writes:
Eh??? Why would you want to do that?? (R isn't C).
So the simple answer is: you can't.
Is this what you're looking for?
mymatrix = matrix(rnorm(15),5,3,dimnames=list(NULL,c('x','y','z')))
mymatrix
x y z
[1,] -0.4459162 -2.3936837 -0.7401963
[2,] 0.9886466 -1.3955161 -1.3390314
[3,] -0.2086743 1.7984620 -0.8532579
[4,] 1.0985411 0.9315553
Hi,
On Mon, Nov 22, 2010 at 4:51 AM, 夏高 xiagao1...@gmail.com wrote:
Hello everyone,
I would like to call web service in R, how can I do this? Thank you!
Is RCurl what you're looking for?
http://cran.r-project.org/web/packages/RCurl/index.html
-steve
--
Steve Lianoglou
Graduate Student:
Hi, I am trying to aggregate max a Date type column but have weird
result, how do I fix this?
a - rbind(
+ data.frame(name='Tom', payday=as.Date('1999-01-01')),
+ data.frame(name='Tom', payday=as.Date('2000-01-01')),
+ data.frame(name='Pete', payday=as.Date('1998-01-01')),
+
When I use the 'bugs' function from R, WinBUGS runs correctly, but R freezes.
The only way to use R after this is to stop calculations (without my file
that documents the calculation). However, I want to save the output in R so
I can use it in further models. Does anyone know how to fix this
Cathy,
How does this model look?
[(1-B**4)]Y(T) = 20.767
+[X1(T)][(1-B**4)][(+ 56.1962)] :PULSE 7/
4 I~P00028test
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