Dear All,
I'm trying to construct confidence interval for an additive quantile regression
model.
In the quantreg package, vignettes section: Additive Models for Conditional
Quantiles
http://cran.r-project.org/web/packages/quantreg/index.html
It describes how to construct the intervals, it
Hi,
I have a igraph graph object.
g - watts.strogatz.game(1, 100, 5, 0.05)
If I have the summary of g, it prints
summary(g)
Vertices: 100
Edges: 500
Directed: FALSE
No graph attributes.
No vertex attributes.
No edge attributes.
How to print only the number of edges in g?
--
View this
Hi all:
I have a question about the sample size calculation.
It's a pilot study,which includes 2 groups(low,high),3 time point(3,6,9
monthes).Each person has 3 results which according to the
3 time points.So it's a longitudinal study.
I want to calculate the minimum sample size from the pilot
On Mon, 21 Mar 2011, Shaunak Bangale wrote:
Prof Ripley,
Thanks for the first reply. Yes, I am using windows xp.
The problem that I am facing is:
I want to use RPostgreSQL and xtable packages together.
R 2.11.1 has RPostgreSQL but not xtable. R 2.12.2 has xtable but not
RPostgreSQL.
I suppose
On Mon, 21 Mar 2011, Bogaso Christofer wrote:
Dear all, can somebody guide me how to install the package RQuantLib, for
which windows binary is not available. I have tried installing it with R CMD
INSTALL in my windows vista machine (I have Rtools installed), however it
stopped due to an error
Last Friday we learned that R is accepted again for the Google Summer of Code.
R's ideas are at
http://rwiki.sciviews.org/doku.php?id=developers:projects:gsoc2011
On that page is a link to our google groups list for mentors and prospective
students.
See http://www.google-melange.com/ for the
On Sun, Mar 20, 2011 at 10:02:10PM -0700, kparamas wrote:
Hi,
I have a igraph graph object.
g - watts.strogatz.game(1, 100, 5, 0.05)
If I have the summary of g, it prints
summary(g)
Vertices: 100
Edges: 500
Directed: FALSE
No graph attributes.
No vertex attributes.
No edge
On Sun, Mar 20, 2011 at 11:49:05PM -0500, Sparks, John James wrote:
Dear R Users,
I am working with gsub for the first time. I am trying to remove some
characters from a string. I have hit the problem where the period is the
shorthand for 'everything' in the R language when what I want to
?ecount
Peter Ehlers
On 2011-03-20 22:02, kparamas wrote:
Hi,
I have a igraph graph object.
g- watts.strogatz.game(1, 100, 5, 0.05)
If I have the summary of g, it prints
summary(g)
Vertices: 100
Edges: 500
Directed: FALSE
No graph attributes.
No vertex attributes.
No edge attributes.
How
On 03/21/2011 04:33 AM, Janko Thyson wrote:
...
Hi Janko,
As Dieter said, Crantastic is an opportunity for R users to give both
quickie ratings and reviews of packages. I have to say that doing a
review isn't trivial. I feel that I should use a package for a while
before I can review it, and
Dennis: Thank you so much! I got it now - it just works perfectly. Thanks a lot!
Anna
2011/3/21 Dennis Murphy djmu...@gmail.com:
Hi:
To amplify Ista's and David's comments:
(1) You should not be inputting separate vectors into lm(), especially if
you intend to do prediction. They should be
Dennis: thank you so much! I got it now and it works just perfectly.
Thanks a lot to the others too!
Anna
2011/3/21 Dennis Murphy djmu...@gmail.com:
Hi:
To amplify Ista's and David's comments:
(1) You should not be inputting separate vectors into lm(), especially if
you intend to do
Apologies for cross-posting
We would like to announce a mixed effects modelling course in Halifax,
Canada. June 2011.
For details, see: http://www.highstat.com/statscourse.htm
Kind regards,
Alain Zuur
__
R-help@r-project.org mailing list
Dear all, I have three vectors x-1:n, y-1:m and z-2:(n+m). I need to
find all combinations of x and y that add up a given value of z, e.g.,
for z==3 the combinations will be list(c(1,2),c(2,1)).
Thanks in advance for your help.
__
Dear Russ,
Why not use simply
pH - c(area1 = 4.5, area2 = 7, mud = 7.3, dam = 8.2, middle = 6.3)
That notation is IMHO the most readable for students.
Best regards,
Thierry
ir. Thierry Onkelinx
Instituut voor
dear all, thanks
it helped a lot, the problem was that I should treat my data
as set of species, not samples, so as output I get 4087*4087 matrix, which
afterwards will be applied for PCO,
the thing was, that in cause of big number of values, programm do not show
all
computed distances and
hello! this is one of the two functions i use
pen.mle-function(x){ ax-x[32:40]
indice-x[1:31]
bx-x[41:49]
amlebind1-matrix(rep(ax,31),nrow=9,ncol=31)
mv-(-(defunciones*log((exp(amlebind1+bx%*%t(indice)))*poblacion)-((exp(amlebind1+bx%*%t(indice)))*poblacion)))
Hello,
I have a large dataset of the form
subj var1 var2
001100200
001120226
001130238
001140245
001150300
002110205
002125209
003101233
003115254
I would like to perform linear regression of var2 on var1 for each
On Mar 20, 2011, at 10:24 PM, Man Zhang wrote:
Dear All,
I'm trying to construct confidence interval for an additive quantile
regression
model.
In the quantreg package, vignettes section: Additive Models for Conditional
Quantiles
Thank you for your answer!
the message that gives as result is 0, successful completion
so that point wouldnt be the problem
sorry if my english its not good (i speak spanish!)
thanks!
--
View this message in context:
On Mar 21, 2011, at 5:25 AM, Marcel Curlin wrote:
Hello,
I have a large dataset of the form
subj var1 var2
001100200
001120226
001130238
001140245
001150300
002110205
002125209
003101233
003115254
I would like to
On Mon, Mar 21, 2011 at 04:08:50AM -0700, Julio Rojas wrote:
Dear all, I have three vectors x-1:n, y-1:m and z-2:(n+m). I need to
find all combinations of x and y that add up a given value of z, e.g.,
for z==3 the combinations will be list(c(1,2),c(2,1)).
Dear Julio:
Try the following.
Dear all,
I sometimes use the following function:
Curry - function(FUN,...) {
# by Byron Ellis,
https://stat.ethz.ch/pipermail/r-devel/2007-November/047318.html
.orig - list(...)
function(...) do.call(FUN,c(.orig,list(...)))
}
... and have thought it might be convenient to have a
On Sun, Mar 20, 2011 at 2:42 PM, Bogaso Christofer
bogaso.christo...@gmail.com wrote:
Dear all, can somebody guide me how to install the package RQuantLib, for
which windows binary is not available. I have tried installing it with R CMD
INSTALL in my windows vista machine (I have Rtools
i´ve tried with optimx
these are the results
pleae help me with this... i´m triying to understand what they mean...
lcmleQN
Hoi All,
I am trying to append collums to a data frame in a for loop. I read in
tables, do some processing and then write the result to a data.frame. But,
the thing I want is, that the results are appended to the data frame in
stead of overwriting the results of the prevous table.
It has to look
Sorry for posting too much!
i found that in Nelder-Mead the result is 1
i run this algorith too many times with several data
maybe the problem is that
i have to give a bigger number of iterations
Lucía
--
View this message in context:
Hoi All,
I am trying to append collums to a data frame in a for loop. I read in
tables, do some processing and then write the result to a data.frame. But,
the thing I want is, that the results are appended to the data frame in
stead of overwriting the results of the prevous table.
It has to look
I forgot to say I need it to work in a for loop because it will be used for
over 35 files. I previously programmed it in the most unorthodox way
possible:
setwd(J:/Stage/Datasets2/Datasets/outData)
data1-read.table(AR1000900A_N_241110_(Mapping250K_Nsp)_2,Mapping250K_Nsp,CNprobes.tab
I don't think I understand. Can you work up a dummy example that will
run independent of your actual data, and produce the problem? This
will help everyone diagnose the problem. Naively this sounds like an
indexing problem.
Stephen
On Mon, Mar 21, 2011 at 7:56 AM, Who Am I?
1. Try using set.seed for better reproducibility.
2. Does this really work for you? I get
mydf - data.frame(x, y,id)
mod2-lme(y ~ x + x*(x-1), random=~x|id,
+ data=mydf)
Error in lme.formula(y ~ x + x * (x -1), random = ~x | id, data = mydf) :
nlminb problem, convergence error code
Yes, your optimx result tells me that Nelder-Mead did not converge. It was
terminated because it exceeded the maximum number of iterations allowed. In
optimx you can increase the `itnmax' argument from its default value to
accomplish this.
Ravi.
On Mon, Mar 21, 2011 at 8:46 AM, Kenn Konstabel lebats...@gmail.com wrote:
Dear all,
I sometimes use the following function:
Curry - function(FUN,...) {
# by Byron Ellis,
https://stat.ethz.ch/pipermail/r-devel/2007-November/047318.html
.orig - list(...)
function(...)
Dear R helpers,
Suppose I have stock returns data of say 1500 companies each for say last 4
years. Thus I have a matrix of dimension say 1000 * 1500 i.e. 1500 columns
representing companies and 1000 rows of their returns.
I need to find the correlation matrix of these 1500 companies.
So I
Sweave is very useful, and I'm gradually getting used to it.
I've just been battling Sweave over the re-use of code chunks. As I am
pretty ignorant in the byways of both Sweave and R, this took a chunk of
time to sort out. Here is what I learned:
If one re-uses a code chunk, then Sweave (but not
I´m triying to give you more information
-other function (the problem its the same with both)
pen.wls-function(x){ ax-x[32:40]
indice-x[1:31]
bx-x[41:49]
awlsbind1-matrix(rep(ax,31),nrow=9,ncol=31)
indice-as.vector(indice-mean(indice))
bx-as.vector(bx/sum(bx))
me-(awlsbind1+bx%*%t(indice))
I can't reproduce your work, but I think you just need
regionMatchABCDE[,i] - cbind(regionMatch[,10:18])
instead of
regionMatchABCDE - cbind(regionMatch[,10:18])
within the for loop
Scott
On Monday, March 21, 2011 at 7:36 AM, Who Am I? wrote:
Hoi All,
I am trying to append collums to a
Hi all,
I am new user in R, I am trying to to use paste function to concatenate
strings which has been fetched from database table(postgres database), the
following are my code:
when i do:
sqlFetch(channel,'transactions')
outputs are following(only parts, there are around 200 transactions in
Dear posters,
I have a question concerning binary data analysis. I have presence absence
data of 5 sampling sessions within 3 years, of 12 fields. Each field had 12
traps. I would like to analyse the data with a Generalized Estimating
Equations (GEE) Model in R. For the abundance data I used a gls
Hello everyone,
I'd like to ask you a question again, basically focusing on referring to
different objects.
Let's suppose we create the following databases this way:
id -c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3)
a
Hello everyone,
I'd like to ask you a question again, basically focusing on referring to
different objects.
Let's suppose we create the following databases this way:
id -c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3)
a
On Mon, Mar 21, 2011 at 2:53 PM, Gabor Grothendieck ggrothendi...@gmail.com
wrote:
On Mon, Mar 21, 2011 at 8:46 AM, Kenn Konstabel lebats...@gmail.com
wrote:
Dear all,
I sometimes use the following function:
Curry - function(FUN,...) {
# by Byron Ellis,
Inline below.
On Mon, Mar 21, 2011 at 8:18 AM, kellysong song.q...@student.dit.ie wrote:
Hi all,
I am new user in R, I am trying to to use paste function to concatenate
strings which has been fetched from database table(postgres database), the
following are my code:
when i do:
Hi Bodnar,
The R way is to put the data frames in a list:
id -c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3)
a -c(3,1,3,3,1,3,3,3,3,1,3,2,1,2,1,3,3,2,1,1,1,3,1,3,3,3,2,1,1,3)
b -c(3,2,1,1,1,1,1,1,1,1,1,2,1,3,2,1,1,1,2,1,3,1,2,2,1,3,3,2,3,2)
c
Hi:
I have a template preamble file for Sweave; near the bottom, I put in this
commented code some time ago so I would never forget it:
%% --
%% IMPORTANT NOTE
%% All Sweave tokens MUST begin in column 1 or they will be
On Mon, Mar 21, 2011 at 12:20 PM, Kenn Konstabel lebats...@gmail.com wrote:
On Mon, Mar 21, 2011 at 2:53 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Mon, Mar 21, 2011 at 8:46 AM, Kenn Konstabel lebats...@gmail.com
wrote:
Dear all,
I sometimes use the following function:
On Mon, Mar 21, 2011 at 8:34 AM, Vincy Pyne vincy_p...@yahoo.ca wrote:
Dear R helpers,
Suppose I have stock returns data of say 1500 companies each for say last 4
years. Thus I have a matrix of dimension say 1000 * 1500 i.e. 1500 columns
representing companies and 1000 rows of their
Hi,
From the following pseudo-code (tweaked from another user):
library(lattice)
variable-sample(rep(1:2,100))
individual-rep(1:3, length(variable))
group-rep(LETTERS[1:2],length(variable)/2)
mydata-data.frame(variable,individual,group)
individual-as.factor(individual)
group-as.factor(group)
On Mon, Mar 21, 2011 at 3:50 AM, Shaunak Bangale
shaunak.bang...@mu-sigma.com wrote:
Prof Ripley,
Thanks for the first reply. Yes, I am using windows xp.
The problem that I am facing is:
I want to use RPostgreSQL and xtable packages together.
R 2.11.1 has RPostgreSQL but not xtable. R 2.12.2
On 3/20/2011 12:19 PM, David.Epstein wrote:
I like Sweave, which I consider to be a great contribution. I have just
written a .Rnw document that comes to about 6 pages of mixed code and
mathematical explanation. Now I want to turn the R code into a function. My
R code currently contains
Thanks Mr Langfelder,
Definitely I will go through the packages you have suggested. Actually, I will
be multiplying three matrices of the order (1 X 1500)%*%(1500 X 1500) %*%
(1500, 1) giving me one value at the end.
I will be starting my process in a couple of days time and in between will
Hi, everybody,
I have a problem and need your help.
There are two columns that look like this:
[1,] t f
[2,] f t
[3,] t f
[4,] t t
[5,] f f
I just want to generate the third column based on these two columns. First,
I randomly choose one of the two columns, say, the first
Thank you for your suggestion Allan. I should have paid attention to
the posting instructions.
Pls find below the sample code from the ?splsda in the caret package.
Note: It used to work fine in R v2.8.1, but this error shows up now,
given that I've modified the code on how the splsda or
Hi Guys
I want to apply a clustering algo to my dataset in order to find the
regions points(X,Y) which have similar values(percent_GC and
mean_phred_quality). Details below.
I have sampled 1% of points from my main data set of 85 million
points. The result is still somewhat large 800K points
Hi,
I'm trying to read a subset of a netcdf file into R, but although I'm
relatively experienced using R, I'm still new to netCDF files, so this may
be a very simple/stupid question!
I've included an example of the type of file I'm looking at here.
Ravi please look my last mail.
I tried again, and in my last mail i described the results, i reach the
convergence but the values are still very diferent.
thank you so much!
Lucía
--
View this message in context:
http://r.789695.n4.nabble.com/BFGS-and-Neldear-Mead-tp3388017p3394334.html
Sent
Hi list,
I have problems with the as.numeric function. I have imported probabilities
from external data, but they are classified as factors as str() shows.
Therefore my goal is to convert the colum from factor to numeric level with
keeping the decimals.
I have googled the problem for a while
I have a very similar error that cropped up when I upgraded to R 2.12 and
persists at R 2.12.1. I am running R on Windows XP and OO is at version 3.2. I
did not make any changes to my R code or ODF code or configuration to produce
this error. Only upgraded R.
Many Thanks,
Eric
R session:
hgreatrex wrote:
Hi,
...
I've managed to extract the lat / lon variables, so I know that I could
work
out manually which pixels correspond to which location. However, it's easy
to make a mistake in such a calculation, so I thought I would check here
before reinventing the wheel.
Hi
On Mar 21, 2011, at 1:57 PM, pat...@gmx.de wrote:
Hi list,
I have problems with the as.numeric function. I have imported
probabilities from external data, but they are classified as factors
as str() shows. Therefore my goal is to convert the colum from
factor to numeric level with
Hi,
I guess you have commas as decimals in your data. Replace it to decimal
points.
Best,
Denes
On Mar 21, 2011, at 1:57 PM, pat...@gmx.de wrote:
Hi list,
I have problems with the as.numeric function. I have imported
probabilities from external data, but they are classified as
On Mon, Mar 21, 2011 at 5:57 PM, pat...@gmx.de wrote:
Hi list,
I have problems with the as.numeric function. I have imported probabilities
from external data, but they are classified as factors as str() shows.
Therefore my goal is to convert the colum from factor to numeric level with
Is there a way to do this in R? I have data in the form:
57_input 57_output 58_input 58_output etc.
can i use a for loop (i in 57:n) that plots only the outputs? I want
this to be robust so im not specifying a column id but rather
something like c++ code,
%s_input, i
is that doable in R?
On Mon, Mar 21, 2011 at 2:03 PM, Justin Haynes jto...@gmail.com wrote:
Is there a way to do this in R? I have data in the form:
57_input 57_output 58_input 58_output etc.
can i use a for loop (i in 57:n) that plots only the outputs? I want
this to be robust so im not specifying a
Try this:
sprintf(%s_%s, rep(1:58, each = 2), c(input, output))
On Mon, Mar 21, 2011 at 4:03 PM, Justin Haynes jto...@gmail.com wrote:
Is there a way to do this in R? I have data in the form:
57_input 57_output 58_input 58_output etc.
can i use a for loop (i in 57:n) that plots only
On Mar 21, 2011, at 2:59 PM, Tóth Dénes wrote:
Hi,
I guess you have commas as decimals in your data. Replace it to
decimal
points.
If that is true then the easiest fix would be to set the proper
decimal argument in read.table
?read.table # with ... , dec = , ,
--
david.
Best,
Hi
I have the following columns with dates and results, sorted by subject and
date. I'd like to compute the differences in dates and results for each
patient, based on the previous row. Obviously the last entry for each subject
should be a NA.
Which would be the best way to accomplished
Getting the correlation of a 1000 by 1500
matrix takes about 3.5 seconds on my
unimpressive Windows machine. Is that
really a tremendous amount of time?
You don't say what you are using the
correlation matrix for. It is common for
a semi-definite matrix (as you will be getting)
to cause
Hi:
It's unclear what you want for your vector of probabilities, but here's one
approach:
u$p - runif(1000)# generate a random vector of success
probabilities
samp - function(x) {
p - as.numeric(x[3]) # x will be character as constructed,
pick out the numeric value of p
-Original Message-
From: Roberto Lodeiro Muller roberto.mul...@doctor.com
To: roberto.mul...@doctor.com
Sent: Mon, Mar 21, 2011 3:37 pm
Subject: Re: [R] Computing row differences in new columns
Sorry, my data appeared badly formatted to me, so I converted it to plain text:
And just to
Dear R-users,
I have to plot a exponential distribution like the plot in the pdf
attached. I've write this code but I don't know how to draw the two lines..
Can anyone help me please?
Thank you very much
Pippo http://r.789695.n4.nabble.com/file/n3394476/exponential_smoothing.pdf
Allan and Josh,
Thanks for the help. I did
d[, sapply(d, function(x) !all(is.na(x)))]
and it worked great.
Thanks so much again!
Rita
If you think education is expensive, try ignorance--Derek Bok
Date: Sat, 19 Mar 2011 08:36:43 +
From:
(mods: can you un-flag me if I am still flagged?)
Hi,
First, I would convert the DATE column to an integer. I found this by
quick googling, perhaps as.Date is your weapon of choice:
https://stat.ethz.ch/pipermail/r-help/2008-August/169870.html
For the column generation I think you will have
Hi:
Here's one way. Calling your data frame below d,
# Function to compute consecutive differences
dif - function(x) c(diff(x), NA)
# Make sure that DATE is a Date variable
d$DATE - as.Date(d$DATE, format = '%d-%b-%y')
# Apply the function to each individual
ddply(d, 'SUBJECT', transform,
On Mar 21, 2011, at 3:38 PM, Roberto Lodeiro Muller wrote:
-Original Message-
From: Roberto Lodeiro Muller roberto.mul...@doctor.com
To: roberto.mul...@doctor.com
Sent: Mon, Mar 21, 2011 3:37 pm
Subject: Re: [R] Computing row differences in new columns
Sorry, my data appeared badly
Try this:
dat$DATE - as.Date(dat$DATE, %d-%b-%y)
dat - cbind(dat, lapply(mapply(tapply, MoreArgs = list(INDEX =
c(dat$SUBJECT, unique(dat$SUBJECT)), FUN = diff),
lapply(dat[,2:3], c, unique(dat$SUBJECT) / NA), SIMPLIFY = FALSE),
unlist))
On Mon, Mar 21, 2011 at 4:38 PM, Roberto Lodeiro Muller
On Mar 21, 2011, at 2:59 PM, Tóth Dénes wrote:
Hi,
I guess you have commas as decimals in your data. Replace it to
decimal
points.
If that is true then the easiest fix would be to set the proper
decimal argument in read.table
In this particular case, sure. If patsko happens to work
I am doing a histogram with 2 superimposed densities. However, the density
of one of the graphs is not coming out..its being erased.. Any ideas on how
to fix this problem?
--
Thanks,
Jim.
[[alternative HTML version deleted]]
__
I rarely work with dates in R, so I know very little about the
POSIXct and POSIXlt classes. I'm importing an excel file into R using
the RODBC package, and am having issues reformatting the dates.
1. The important info:
sessionInfo()
R version 2.12.2 (2011-02-25)
Platform: i386-pc-mingw32/i386
I don't think that this is the issue, but test it on a file without spaces.
On Mon, Mar 21, 2011 at 2:25 PM, rmail...@justemail.net wrote:
I have a very similar error that cropped up when I upgraded to R 2.12 and
persists at R 2.12.1. I am running R on Windows XP and OO is at version 3.2.
That's not the point. The point is that R has functions which have
side-effects and hence does not meet the strict requirements for a functional
language.
-Original Message-
From: ONKELINX, Thierry [mailto:thierry.onkel...@inbo.be]
Sent: Monday, 21 March 2011 7:20 PM
To:
I tried with no spaces in either file name and got the same error.
- Original message -
From: Max Kuhn mxk...@gmail.com
To: rmail...@justemail.net
Cc: r-help@r-project.org
Date: Mon, 21 Mar 2011 17:04:40 -0400
Subject: Re: [R] odfWeave Error unzipping file in Win 7
I don't think that
dear R experts---I am trying to figure out what the recommended way is
to merge by() results back into the original data frame. for example,
I want to have a flag that tells me whether a particular row contains
the maximum for its group.
d - data.frame(group=as.factor(rep(1:3,each=3)),
You might try
dat$F1 - format(as.Date(dat$F1), format = %b-%y)
although it rather depends on the class of F1 as it has been read.
Bill Venables.
(It would be courteous of you to give us yor name, by the way.)
-Original Message-
From: r-help-boun...@r-project.org
On 11-03-21 6:28 PM, rmail...@justemail.net wrote:
I tried with no spaces in either file name and got the same error.
Can you put together an example that produces the error without using
odfWeave? To do that, figure out what odfWeave is doing, and do it
outside of that package.
If not,
On Tue, Mar 22, 2011 at 11:42 AM, ivo welch ivo...@gmail.com wrote:
dear R experts---I am trying to figure out what the recommended way is
to merge by() results back into the original data frame. for example,
I want to have a flag that tells me whether a particular row contains
the maximum
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of ivo welch
Sent: Monday, March 21, 2011 3:43 PM
To: r-help
Subject: [R] Merging by() results back into original data frame?
dear R experts---I am trying to figure out what the
thank you, william and bill. wow, this was fast. I have been tearing
my hair out over this one, trying to work the wrong tool. (this would
make a good see also in the by function.)
Ivo Welch (ivo.we...@brown.edu, ivo.we...@gmail.com)
On Mon, Mar 21, 2011 at 7:09 PM, William Dunlap
I find it quite neat with plyr,
library(plyr)
ddply(d, .(group), transform, max=max(val))
HTH,
baptiste
On 22 March 2011 12:09, William Dunlap wdun...@tibco.com wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of ivo welch
Hi,
I am running a correlation analysis on a temporal dataset. I was wondering
if you would receive the same tau and p values running the function:
MannKendall(x), where x is the dependant variable that changes with time
as you would running:
Kendall(d,x), where x is the exact same dataset
The code is like this:
plot(0,0, type=n, xlim=c(1,15), ylim=0:1, xlab=...,
ylab=..., main=Example)
lines(1:15, line1, col=4)
lines(1:15, line2, col=2)
legend(topright, c(alpha = 0.2, alpha = 0.4), col=c(4,2), lty=1)
How can I build the vectors line1 and line2 ?
--
View this message in
Hi all,
Forgive me for this basic question. I've been doing some research and
haven't been able to figure out how to best do this yet.
I have 75 variables defined as vector time series. I am trying to create a
script to automate calculations on each of these variables, but I wasn't
sure how to
Hello All,
I need help with my dataframe, it is big but here I am using a small table
as an example.
My dataframe df looks like:
X1 X2X3
1 2011-02 0.00 96.00
2 2011-02 0.00 2.11
3 2011-02 2.00 3.08
4 2011-02 0.06 2.79
5 2011-02 0.00 96.00
6 2011-02 0.00
On Mar 21, 2011, at 5:39 PM, joe82 wrote:
Hello All,
I need help with my dataframe, it is big but here I am using a small
table
as an example.
My dataframe df looks like:
X1 X2X3
1 2011-02 0.00 96.00
2 2011-02 0.00 2.11
3 2011-02 2.00 3.08
4 2011-02 0.06
Hello all,
I am a 2 month newbie to R and am stumped. I have a data set that I've run
multivariate stats on using the manova function (I included the data set). Now
it comes time for a table of effect sizes with significance. The univariate
tests are easy. Where I run into trouble
dat - within(dat, {
X2 - ifelse(X2 50, 100-X2, X2)
X3 - ifelse(X3 50, 100-X3, X3)
})
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of joe82
Sent: Tuesday, 22 March 2011 7:40 AM
To: r-help@r-project.org
Subject:
Hi all,
Just wondering if anyone might know a way to stop R reading my survival
history that has zeros at the beginning in as scientific notation. The data
is being read in from a .txt file via read.table to be used with Rmark
I have the same issues at the moment with reading in .csv and .xls
odaniel odaniel at utas.edu.au writes:
Just wondering if anyone might know a way to stop R reading my survival
history that has zeros at the beginning in as scientific notation.
Gmane doesn't want me to quote much, but maybe
read.table(myfile.dat,colClasses=c(character,rep(numeric,2)) ?
This is what I've tried so far and just can't get it. I know I want a value of
3.93 (for Age= y and m) using mahalanobis d as an effect size for a follow up
to an MANOVA:
age.frame-data.frame(Age, Friend.Agression, Parent.Agression,
Stranger.Agression)
age.frame
Age Friend.Agression
hello,everyone:
I am now confused in multistate survival , when I want to poccess a
multistate survival analysis, I turn to R and the package 'mstate' and packege
'cmprsk'. When I come to publishing the article.
Follow requirement of the magzine, the statistic is carry out in LTA package
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